3 void eqnbox(int p1
, int p2
, int lu
)
9 b
= max(ebase
[p1
], ebase
[p2
]);
10 eht
[yyval
] = h
= b
+ max(eht
[p1
]-ebase
[p1
],
13 dprintf(".\tS%d <- %d %d; b=%g, h=%g\n", yyval
, p1
, p2
, b
, h
);
14 sh
= pad(class[rclass
[p1
]][lclass
[p2
]]);
16 printf(".nr %d \\w'\\*(%d%s'\n", p1
, p1
, sh
);
17 printf(".ds %d \\h'|\\n(09u-\\n(%du'\\*(%d\n", p1
, p1
, p1
);
19 printf(".as %d \"%s\\*(%d\n", yyval
, sh
, p2
);
20 rfont
[p1
] = rfont
[p2
];
21 rclass
[p1
] = rclass
[p2
];