1 /* Safe automatic memory allocation.
2 Copyright (C) 2003, 2006-2007, 2009-2018 Free Software Foundation, Inc.
3 Written by Bruno Haible <bruno@clisp.org>, 2003, 2018.
5 This program is free software; you can redistribute it and/or modify
6 it under the terms of the GNU General Public License as published by
7 the Free Software Foundation; either version 2, or (at your option)
10 This program is distributed in the hope that it will be useful,
11 but WITHOUT ANY WARRANTY; without even the implied warranty of
12 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
13 GNU General Public License for more details.
15 You should have received a copy of the GNU General Public License
16 along with this program; if not, see <https://www.gnu.org/licenses/>. */
18 #define _GL_USE_STDLIB_ALLOC 1
26 /* The speed critical point in this file is freea() applied to an alloca()
27 result: it must be fast, to match the speed of alloca(). The speed of
28 mmalloca() and freea() in the other case are not critical, because they
29 are only invoked for big memory sizes.
30 Here we use a bit in the address as an indicator, an idea by Ondřej Bílka.
31 malloca() can return three types of pointers:
32 - Pointers ≡ 0 mod 2*sa_alignment_max come from stack allocation.
33 - Pointers ≡ sa_alignment_max mod 2*sa_alignment_max come from heap
35 - NULL comes from a failed heap allocation. */
37 /* Type for holding very small pointer differences. */
38 typedef unsigned char small_t
;
39 /* Verify that it is wide enough. */
40 verify (2 * sa_alignment_max
- 1 <= (small_t
) -1);
46 /* Allocate one more word, used to determine the address to pass to freea(),
47 and room for the alignment ≡ sa_alignment_max mod 2*sa_alignment_max. */
48 size_t nplus
= n
+ sizeof (small_t
) + 2 * sa_alignment_max
- 1;
52 char *mem
= (char *) malloc (nplus
);
57 (char *)((((uintptr_t)mem
+ sizeof (small_t
) + sa_alignment_max
- 1)
58 & ~(uintptr_t)(2 * sa_alignment_max
- 1))
60 /* Here p >= mem + sizeof (small_t),
61 and p <= mem + sizeof (small_t) + 2 * sa_alignment_max - 1
62 hence p + n <= mem + nplus.
63 So, the memory range [p, p+n) lies in the allocated memory range
64 [mem, mem + nplus). */
65 ((small_t
*) p
)[-1] = p
- mem
;
66 /* p ≡ sa_alignment_max mod 2*sa_alignment_max. */
73 # if !MALLOC_0_IS_NONNULL
86 if ((uintptr_t) p
& (sa_alignment_max
- 1))
88 /* p was not the result of a malloca() call. Invalid argument. */
91 /* Determine whether p was a non-NULL pointer returned by mmalloca(). */
92 if ((uintptr_t) p
& sa_alignment_max
)
94 void *mem
= (char *) p
- ((small_t
*) p
)[-1];