correctly handle newlines in the file names
[findutils.git] / mdate-sh
blob0c88e758b8cfa901dda28984c4907514b7fd6315
1 #!/bin/sh
2 # Get modification time of a file or directory and pretty-print it.
3 # Copyright 1995, 1996, 1997 Free Software Foundation, Inc.
4 # written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
6 # This program is free software; you can redistribute it and/or modify
7 # it under the terms of the GNU General Public License as published by
8 # the Free Software Foundation; either version 2, or (at your option)
9 # any later version.
11 # This program is distributed in the hope that it will be useful,
12 # but WITHOUT ANY WARRANTY; without even the implied warranty of
13 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
14 # GNU General Public License for more details.
16 # You should have received a copy of the GNU General Public License
17 # along with this program; if not, write to the Free Software Foundation,
18 # Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
20 # Prevent date giving response in another language.
21 LANG=C
22 export LANG
23 LC_ALL=C
24 export LC_ALL
25 LC_TIME=C
26 export LC_TIME
28 # Get the extended ls output of the file or directory.
29 # On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
30 if ls -L /dev/null 1>/dev/null 2>&1; then
31 set - x`ls -L -l -d $1`
32 else
33 set - x`ls -l -d $1`
35 # The month is at least the fourth argument
36 # (3 shifts here, the next inside the loop).
37 shift
38 shift
39 shift
41 # Find the month. Next argument is day, followed by the year or time.
42 month=
43 until test $month
45 shift
46 case $1 in
47 Jan) month=January; nummonth=1;;
48 Feb) month=February; nummonth=2;;
49 Mar) month=March; nummonth=3;;
50 Apr) month=April; nummonth=4;;
51 May) month=May; nummonth=5;;
52 Jun) month=June; nummonth=6;;
53 Jul) month=July; nummonth=7;;
54 Aug) month=August; nummonth=8;;
55 Sep) month=September; nummonth=9;;
56 Oct) month=October; nummonth=10;;
57 Nov) month=November; nummonth=11;;
58 Dec) month=December; nummonth=12;;
59 esac
60 done
62 day=$2
64 # Here we have to deal with the problem that the ls output gives either
65 # the time of day or the year.
66 case $3 in
67 *:*) set `date`; eval year=\$$#
68 case $2 in
69 Jan) nummonthtod=1;;
70 Feb) nummonthtod=2;;
71 Mar) nummonthtod=3;;
72 Apr) nummonthtod=4;;
73 May) nummonthtod=5;;
74 Jun) nummonthtod=6;;
75 Jul) nummonthtod=7;;
76 Aug) nummonthtod=8;;
77 Sep) nummonthtod=9;;
78 Oct) nummonthtod=10;;
79 Nov) nummonthtod=11;;
80 Dec) nummonthtod=12;;
81 esac
82 # For the first six month of the year the time notation can also
83 # be used for files modified in the last year.
84 if (expr $nummonth \> $nummonthtod) > /dev/null;
85 then
86 year=`expr $year - 1`
87 fi;;
88 *) year=$3;;
89 esac
91 # The result.
92 echo $day $month $year