libjava/java/lang/e_exp.c

   1
   2 /* @(#)e_exp.c 5.1 93/09/24 */
   3 /*
   4  * ====================================================
   5  * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
   6  *
   7  * Developed at SunPro, a Sun Microsystems, Inc. business.
   8  * Permission to use, copy, modify, and distribute this
   9  * software is freely granted, provided that this notice
  10  * is preserved.
  11  * ====================================================
  12  */
  13
  14 /* __ieee754_exp(x)
  15  * Returns the exponential of x.
  16  *
  17  * Method
  18  *   1. Argument reduction:
  19  *      Reduce x to an r so that |r| <= 0.5*ln2 ~ 0.34658.
  20  *      Given x, find r and integer k such that
  21  *
  22  *               x = k*ln2 + r,  |r| <= 0.5*ln2.
  23  *
  24  *      Here r will be represented as r = hi-lo for better
  25  *      accuracy.
  26  *
  27  *   2. Approximation of exp(r) by a special rational function on
  28  *      the interval [0,0.34658]:
  29  *      Write
  30  *          R(r**2) = r*(exp(r)+1)/(exp(r)-1) = 2 + r*r/6 - r**4/360 + ...
  31  *      We use a special Reme algorithm on [0,0.34658] to generate
  32  *      a polynomial of degree 5 to approximate R. The maximum error
  33  *      of this polynomial approximation is bounded by 2**-59. In
  34  *      other words,
  35  *          R(z) ~ 2.0 + P1*z + P2*z**2 + P3*z**3 + P4*z**4 + P5*z**5
  36  *      (where z=r*r, and the values of P1 to P5 are listed below)
  37  *      and
  38  *          |                  5          |     -59
  39  *          | 2.0+P1*z+...+P5*z   -  R(z) | <= 2
  40  *          |                             |
  41  *      The computation of exp(r) thus becomes
  42  *                             2*r
  43  *              exp(r) = 1 + -------
  44  *                            R - r
  45  *                                 r*R1(r)
  46  *                     = 1 + r + ----------- (for better accuracy)
  47  *                                2 - R1(r)
  48  *      where
  49  *                               2       4             10
  50  *              R1(r) = r - (P1*r  + P2*r  + ... + P5*r   ).
  51  *
  52  *   3. Scale back to obtain exp(x):
  53  *      From step 1, we have
  54  *         exp(x) = 2^k * exp(r)
  55  *
  56  * Special cases:
  57  *      exp(INF) is INF, exp(NaN) is NaN;
  58  *      exp(-INF) is 0, and
  59  *      for finite argument, only exp(0)=1 is exact.
  60  *
  61  * Accuracy:
  62  *      according to an error analysis, the error is always less than
  63  *      1 ulp (unit in the last place).
  64  *
  65  * Misc. info.
  66  *      For IEEE double
  67  *          if x >  7.09782712893383973096e+02 then exp(x) overflow
  68  *          if x < -7.45133219101941108420e+02 then exp(x) underflow
  69  *
  70  * Constants:
  71  * The hexadecimal values are the intended ones for the following
  72  * constants. The decimal values may be used, provided that the
  73  * compiler will convert from decimal to binary accurately enough
  74  * to produce the hexadecimal values shown.
  75  */
  76
  77 #include "fdlibm.h"
  78
  79 #ifndef _DOUBLE_IS_32BITS
  80
  81 #ifdef __STDC__
  82 static const double
  83 #else
  84 static double
  85 #endif
  86 one     = 1.0,
  87 halF[2] = {0.5,-0.5,},
  88 huge    = 1.0e+300,
  89 twom1000= 9.33263618503218878990e-302,     /* 2**-1000=0x01700000,0*/
  90 o_threshold=  7.09782712893383973096e+02,  /* 0x40862E42, 0xFEFA39EF */
  91 u_threshold= -7.45133219101941108420e+02,  /* 0xc0874910, 0xD52D3051 */
  92 ln2HI[2]   ={ 6.93147180369123816490e-01,  /* 0x3fe62e42, 0xfee00000 */
  93              -6.93147180369123816490e-01,},/* 0xbfe62e42, 0xfee00000 */
  94 ln2LO[2]   ={ 1.90821492927058770002e-10,  /* 0x3dea39ef, 0x35793c76 */
  95              -1.90821492927058770002e-10,},/* 0xbdea39ef, 0x35793c76 */
  96 invln2 =  1.44269504088896338700e+00, /* 0x3ff71547, 0x652b82fe */
  97 P1   =  1.66666666666666019037e-01, /* 0x3FC55555, 0x5555553E */
  98 P2   = -2.77777777770155933842e-03, /* 0xBF66C16C, 0x16BEBD93 */
  99 P3   =  6.61375632143793436117e-05, /* 0x3F11566A, 0xAF25DE2C */
 100 P4   = -1.65339022054652515390e-06, /* 0xBEBBBD41, 0xC5D26BF1 */
 101 P5   =  4.13813679705723846039e-08; /* 0x3E663769, 0x72BEA4D0 */
 102
 103
 104 #ifdef __STDC__
 105         double __ieee754_exp(double x)  /* default IEEE double exp */
 106 #else
 107         double __ieee754_exp(x) /* default IEEE double exp */
 108         double x;
 109 #endif
 110 {
 111         double y,hi,lo,c,t;
 112         int32_t k,xsb;
 113         uint32_t hx;
 114
 115         GET_HIGH_WORD(hx,x);
 116         xsb = (hx>>31)&1;               /* sign bit of x */
 117         hx &= 0x7fffffff;               /* high word of |x| */
 118
 119     /* filter out non-finite argument */
 120         if(hx >= 0x40862E42) {                  /* if |x|>=709.78... */
 121             if(hx>=0x7ff00000) {
 122                 uint32_t lx;
 123                 GET_LOW_WORD(lx,x);
 124                 if(((hx&0xfffff)|lx)!=0)
 125                      return x+x;                /* NaN */
 126                 else return (xsb==0)? x:0.0;    /* exp(+-inf)={inf,0} */
 127             }
 128             if(x > o_threshold) return huge*huge; /* overflow */
 129             if(x < u_threshold) return twom1000*twom1000; /* underflow */
 130         }
 131
 132     /* argument reduction */
 133         if(hx > 0x3fd62e42) {           /* if  |x| > 0.5 ln2 */
 134             if(hx < 0x3FF0A2B2) {       /* and |x| < 1.5 ln2 */
 135                 hi = x-ln2HI[xsb]; lo=ln2LO[xsb]; k = 1-xsb-xsb;
 136             } else {
 137                 k  = invln2*x+halF[xsb];
 138                 t  = k;
 139                 hi = x - t*ln2HI[0];    /* t*ln2HI is exact here */
 140                 lo = t*ln2LO[0];
 141             }
 142             x  = hi - lo;
 143         }
 144         else if(hx < 0x3e300000)  {     /* when |x|<2**-28 */
 145             if(huge+x>one) return one+x;/* trigger inexact */
 146         }
 147         else k = 0;
 148
 149     /* x is now in primary range */
 150         t  = x*x;
 151         c  = x - t*(P1+t*(P2+t*(P3+t*(P4+t*P5))));
 152         if(k==0)        return one-((x*c)/(c-2.0)-x);
 153         else            y = one-((lo-(x*c)/(2.0-c))-hi);
 154         if(k >= -1021) {
 155             uint32_t hy;
 156             GET_HIGH_WORD(hy,y);
 157             SET_HIGH_WORD(y,hy+(k<<20));        /* add k to y's exponent */
 158             return y;
 159         } else {
 160             uint32_t hy;
 161             GET_HIGH_WORD(hy,y);
 162             SET_HIGH_WORD(y,hy+((k+1000)<<20)); /* add k to y's exponent */
 163             return y*twom1000;
 164         }
 165 }
 166
 167 #endif /* defined(_DOUBLE_IS_32BITS) */