1 /* BitSet.java -- A vector of bits.
2 Copyright (C) 1998, 1999, 2000, 2001, 2004, 2005 Free Software Foundation, Inc.
4 This file is part of GNU Classpath.
6 GNU Classpath is free software; you can redistribute it and/or modify
7 it under the terms of the GNU General Public License as published by
8 the Free Software Foundation; either version 2, or (at your option)
11 GNU Classpath is distributed in the hope that it will be useful, but
12 WITHOUT ANY WARRANTY; without even the implied warranty of
13 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
14 General Public License for more details.
16 You should have received a copy of the GNU General Public License
17 along with GNU Classpath; see the file COPYING. If not, write to the
18 Free Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
21 Linking this library statically or dynamically with other modules is
22 making a combined work based on this library. Thus, the terms and
23 conditions of the GNU General Public License cover the whole
26 As a special exception, the copyright holders of this library give you
27 permission to link this library with independent modules to produce an
28 executable, regardless of the license terms of these independent
29 modules, and to copy and distribute the resulting executable under
30 terms of your choice, provided that you also meet, for each linked
31 independent module, the terms and conditions of the license of that
32 module. An independent module is a module which is not derived from
33 or based on this library. If you modify this library, you may extend
34 this exception to your version of the library, but you are not
35 obligated to do so. If you do not wish to do so, delete this
36 exception statement from your version. */
39 import java
.io
.Serializable
;
41 /* Written using "Java Class Libraries", 2nd edition, ISBN 0-201-31002-3
42 * hashCode algorithm taken from JDK 1.2 docs.
46 * This class can be thought of in two ways. You can see it as a
47 * vector of bits or as a set of non-negative integers. The name
48 * <code>BitSet</code> is a bit misleading.
50 * It is implemented by a bit vector, but its equally possible to see
51 * it as set of non-negative integer; each integer in the set is
52 * represented by a set bit at the corresponding index. The size of
53 * this structure is determined by the highest integer in the set.
55 * You can union, intersect and build (symmetric) remainders, by
56 * invoking the logical operations and, or, andNot, resp. xor.
58 * This implementation is NOT synchronized against concurrent access from
59 * multiple threads. Specifically, if one thread is reading from a bitset
60 * while another thread is simultaneously modifying it, the results are
63 * @author Jochen Hoenicke
64 * @author Tom Tromey (tromey@cygnus.com)
65 * @author Eric Blake (ebb9@email.byu.edu)
66 * @status updated to 1.4
68 public class BitSet
implements Cloneable
, Serializable
71 * Compatible with JDK 1.0.
73 private static final long serialVersionUID
= 7997698588986878753L;
78 private static final int LONG_MASK
= 0x3f;
82 * @serial the i'th bit is in bits[i/64] at position i%64 (where position
83 * 0 is the least significant).
88 * Create a new empty bit set. All bits are initially false.
96 * Create a new empty bit set, with a given size. This
97 * constructor reserves enough space to represent the integers
98 * from <code>0</code> to <code>nbits-1</code>.
100 * @param nbits the initial size of the bit set
101 * @throws NegativeArraySizeException if nbits < 0
103 public BitSet(int nbits
)
106 throw new NegativeArraySizeException();
108 int length
= nbits
>>> 6;
109 if ((nbits
& LONG_MASK
) != 0)
111 bits
= new long[length
];
115 * Performs the logical AND operation on this bit set and the
116 * given <code>set</code>. This means it builds the intersection
117 * of the two sets. The result is stored into this bit set.
119 * @param set the second bit set
120 * @throws NullPointerException if set is null
122 public void and(BitSet bs
)
124 int max
= Math
.min(bits
.length
, bs
.bits
.length
);
126 for (i
= 0; i
< max
; ++i
)
127 bits
[i
] &= bs
.bits
[i
];
128 while (i
< bits
.length
)
133 * Performs the logical AND operation on this bit set and the
134 * complement of the given <code>set</code>. This means it
135 * selects every element in the first set, that isn't in the
136 * second set. The result is stored into this bit set and is
137 * effectively the set difference of the two.
139 * @param set the second bit set
140 * @throws NullPointerException if set is null
143 public void andNot(BitSet bs
)
145 int i
= Math
.min(bits
.length
, bs
.bits
.length
);
147 bits
[i
] &= ~bs
.bits
[i
];
151 * Returns the number of bits set to true.
153 * @return the number of true bits
156 public int cardinality()
159 for (int i
= bits
.length
- 1; i
>= 0; i
--)
162 // Take care of common cases.
171 // Successively collapse alternating bit groups into a sum.
172 a
= ((a
>> 1) & 0x5555555555555555L
) + (a
& 0x5555555555555555L
);
173 a
= ((a
>> 2) & 0x3333333333333333L
) + (a
& 0x3333333333333333L
);
174 int b
= (int) ((a
>>> 32) + a
);
175 b
= ((b
>> 4) & 0x0f0f0f0f) + (b
& 0x0f0f0f0f);
176 b
= ((b
>> 8) & 0x00ff00ff) + (b
& 0x00ff00ff);
177 card
+= ((b
>> 16) & 0x0000ffff) + (b
& 0x0000ffff);
183 * Sets all bits in the set to false.
189 Arrays
.fill(bits
, 0);
193 * Removes the integer <code>bitIndex</code> from this set. That is
194 * the corresponding bit is cleared. If the index is not in the set,
195 * this method does nothing.
197 * @param bitIndex a non-negative integer
198 * @throws IndexOutOfBoundsException if bitIndex < 0
200 public void clear(int pos
)
202 int offset
= pos
>> 6;
204 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
205 // so we'll just let that be our exception.
206 bits
[offset
] &= ~
(1L << pos
);
210 * Sets the bits between from (inclusive) and to (exclusive) to false.
212 * @param from the start range (inclusive)
213 * @param to the end range (exclusive)
214 * @throws IndexOutOfBoundsException if from < 0 || to < 0 ||
218 public void clear(int from
, int to
)
220 if (from
< 0 || from
> to
)
221 throw new IndexOutOfBoundsException();
224 int lo_offset
= from
>>> 6;
225 int hi_offset
= to
>>> 6;
227 if (lo_offset
== hi_offset
)
229 bits
[hi_offset
] &= ((1L << from
) - 1) | (-1L << to
);
233 bits
[lo_offset
] &= (1L << from
) - 1;
234 bits
[hi_offset
] &= -1L << to
;
235 for (int i
= lo_offset
+ 1; i
< hi_offset
; i
++)
240 * Create a clone of this bit set, that is an instance of the same
241 * class and contains the same elements. But it doesn't change when
242 * this bit set changes.
244 * @return the clone of this object.
246 public Object
clone()
250 BitSet bs
= (BitSet
) super.clone();
251 bs
.bits
= (long[]) bits
.clone();
254 catch (CloneNotSupportedException e
)
256 // Impossible to get here.
262 * Returns true if the <code>obj</code> is a bit set that contains
263 * exactly the same elements as this bit set, otherwise false.
265 * @param obj the object to compare to
266 * @return true if obj equals this bit set
268 public boolean equals(Object obj
)
270 if (!(obj
instanceof BitSet
))
272 BitSet bs
= (BitSet
) obj
;
273 int max
= Math
.min(bits
.length
, bs
.bits
.length
);
275 for (i
= 0; i
< max
; ++i
)
276 if (bits
[i
] != bs
.bits
[i
])
278 // If one is larger, check to make sure all extra bits are 0.
279 for (int j
= i
; j
< bits
.length
; ++j
)
282 for (int j
= i
; j
< bs
.bits
.length
; ++j
)
289 * Sets the bit at the index to the opposite value.
291 * @param index the index of the bit
292 * @throws IndexOutOfBoundsException if index is negative
295 public void flip(int index
)
297 int offset
= index
>> 6;
299 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
300 // so we'll just let that be our exception.
301 bits
[offset
] ^
= 1L << index
;
305 * Sets a range of bits to the opposite value.
307 * @param from the low index (inclusive)
308 * @param to the high index (exclusive)
309 * @throws IndexOutOfBoundsException if from > to || from < 0 ||
313 public void flip(int from
, int to
)
315 if (from
< 0 || from
> to
)
316 throw new IndexOutOfBoundsException();
319 int lo_offset
= from
>>> 6;
320 int hi_offset
= to
>>> 6;
322 if (lo_offset
== hi_offset
)
324 bits
[hi_offset
] ^
= (-1L << from
) & ((1L << to
) - 1);
328 bits
[lo_offset
] ^
= -1L << from
;
329 bits
[hi_offset
] ^
= (1L << to
) - 1;
330 for (int i
= lo_offset
+ 1; i
< hi_offset
; i
++)
335 * Returns true if the integer <code>bitIndex</code> is in this bit
336 * set, otherwise false.
338 * @param pos a non-negative integer
339 * @return the value of the bit at the specified index
340 * @throws IndexOutOfBoundsException if the index is negative
342 public boolean get(int pos
)
344 int offset
= pos
>> 6;
345 if (offset
>= bits
.length
)
347 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
348 // so we'll just let that be our exception.
349 return (bits
[offset
] & (1L << pos
)) != 0;
353 * Returns a new <code>BitSet</code> composed of a range of bits from
356 * @param from the low index (inclusive)
357 * @param to the high index (exclusive)
358 * @throws IndexOutOfBoundsException if from > to || from < 0 ||
362 public BitSet
get(int from
, int to
)
364 if (from
< 0 || from
> to
)
365 throw new IndexOutOfBoundsException();
366 BitSet bs
= new BitSet(to
- from
);
367 int lo_offset
= from
>>> 6;
368 if (lo_offset
>= bits
.length
)
371 int lo_bit
= from
& LONG_MASK
;
372 int hi_offset
= to
>>> 6;
375 int len
= Math
.min(hi_offset
- lo_offset
+ 1, bits
.length
- lo_offset
);
376 System
.arraycopy(bits
, lo_offset
, bs
.bits
, 0, len
);
377 if (hi_offset
< bits
.length
)
378 bs
.bits
[hi_offset
- lo_offset
] &= (1L << to
) - 1;
382 int len
= Math
.min(hi_offset
, bits
.length
- 1);
383 int reverse
= ~lo_bit
;
385 for (i
= 0; lo_offset
< len
; lo_offset
++, i
++)
386 bs
.bits
[i
] = ((bits
[lo_offset
] >>> lo_bit
)
387 | (bits
[lo_offset
+ 1] << reverse
));
388 if ((to
& LONG_MASK
) > lo_bit
)
389 bs
.bits
[i
++] = bits
[lo_offset
] >>> lo_bit
;
390 if (hi_offset
< bits
.length
)
391 bs
.bits
[i
- 1] &= (1L << (to
- from
)) - 1;
396 * Returns a hash code value for this bit set. The hash code of
397 * two bit sets containing the same integers is identical. The algorithm
398 * used to compute it is as follows:
400 * Suppose the bits in the BitSet were to be stored in an array of
401 * long integers called <code>bits</code>, in such a manner that
402 * bit <code>k</code> is set in the BitSet (for non-negative values
403 * of <code>k</code>) if and only if
405 * <code>((k/64) < bits.length)
406 * && ((bits[k/64] & (1L << (bit % 64))) != 0)
409 * Then the following definition of the hashCode method
410 * would be a correct implementation of the actual algorithm:
413 <pre>public int hashCode()
416 for (int i = bits.length-1; i >= 0; i--)
418 h ^= bits[i] * (i + 1);
421 return (int)((h >> 32) ^ h);
424 * Note that the hash code values changes, if the set is changed.
426 * @return the hash code value for this bit set.
428 public int hashCode()
431 for (int i
= bits
.length
; i
> 0; )
433 return (int) ((h
>> 32) ^ h
);
437 * Returns true if the specified BitSet and this one share at least one
440 * @param set the set to check for intersection
441 * @return true if the sets intersect
442 * @throws NullPointerException if set is null
445 public boolean intersects(BitSet set
)
447 int i
= Math
.min(bits
.length
, set
.bits
.length
);
449 if ((bits
[i
] & set
.bits
[i
]) != 0)
455 * Returns true if this set contains no true bits.
457 * @return true if all bits are false
460 public boolean isEmpty()
462 for (int i
= bits
.length
- 1; i
>= 0; i
--)
469 * Returns the logical number of bits actually used by this bit
470 * set. It returns the index of the highest set bit plus one.
471 * Note that this method doesn't return the number of set bits.
473 * @return the index of the highest set bit plus one.
477 // Set i to highest index that contains a non-zero value.
479 for (i
= bits
.length
- 1; i
>= 0 && bits
[i
] == 0; --i
)
482 // if i < 0 all bits are cleared.
486 // Now determine the exact length.
488 int len
= (i
+ 1) * 64;
489 // b >= 0 checks if the highest bit is zero.
500 * Returns the index of the next false bit, from the specified bit
503 * @param from the start location
504 * @return the first false bit
505 * @throws IndexOutOfBoundsException if from is negative
508 public int nextClearBit(int from
)
510 int offset
= from
>> 6;
511 long mask
= 1L << from
;
512 while (offset
< bits
.length
)
514 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
515 // so we'll just let that be our exception.
516 long h
= bits
[offset
];
532 * Returns the index of the next true bit, from the specified bit
533 * (inclusive). If there is none, -1 is returned. You can iterate over
534 * all true bits with this loop:<br>
536 <pre>for (int i = bs.nextSetBit(0); i >= 0; i = bs.nextSetBit(i + 1))
541 * @param from the start location
542 * @return the first true bit, or -1
543 * @throws IndexOutOfBoundsException if from is negative
546 public int nextSetBit(int from
)
548 int offset
= from
>> 6;
549 long mask
= 1L << from
;
550 while (offset
< bits
.length
)
552 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
553 // so we'll just let that be our exception.
554 long h
= bits
[offset
];
570 * Performs the logical OR operation on this bit set and the
571 * given <code>set</code>. This means it builds the union
572 * of the two sets. The result is stored into this bit set, which
573 * grows as necessary.
575 * @param bs the second bit set
576 * @throws NullPointerException if bs is null
578 public void or(BitSet bs
)
580 ensure(bs
.bits
.length
- 1);
581 for (int i
= bs
.bits
.length
- 1; i
>= 0; i
--)
582 bits
[i
] |= bs
.bits
[i
];
586 * Add the integer <code>bitIndex</code> to this set. That is
587 * the corresponding bit is set to true. If the index was already in
588 * the set, this method does nothing. The size of this structure
589 * is automatically increased as necessary.
591 * @param pos a non-negative integer.
592 * @throws IndexOutOfBoundsException if pos is negative
594 public void set(int pos
)
596 int offset
= pos
>> 6;
598 // ArrayIndexOutOfBoundsException subclasses IndexOutOfBoundsException,
599 // so we'll just let that be our exception.
600 bits
[offset
] |= 1L << pos
;
604 * Sets the bit at the given index to the specified value. The size of
605 * this structure is automatically increased as necessary.
607 * @param index the position to set
608 * @param value the value to set it to
609 * @throws IndexOutOfBoundsException if index is negative
612 public void set(int index
, boolean value
)
621 * Sets the bits between from (inclusive) and to (exclusive) to true.
623 * @param from the start range (inclusive)
624 * @param to the end range (exclusive)
625 * @throws IndexOutOfBoundsException if from < 0 || from > to ||
629 public void set(int from
, int to
)
631 if (from
< 0 || from
> to
)
632 throw new IndexOutOfBoundsException();
635 int lo_offset
= from
>>> 6;
636 int hi_offset
= to
>>> 6;
638 if (lo_offset
== hi_offset
)
640 bits
[hi_offset
] |= (-1L << from
) & ((1L << to
) - 1);
644 bits
[lo_offset
] |= -1L << from
;
645 bits
[hi_offset
] |= (1L << to
) - 1;
646 for (int i
= lo_offset
+ 1; i
< hi_offset
; i
++)
651 * Sets the bits between from (inclusive) and to (exclusive) to the
654 * @param from the start range (inclusive)
655 * @param to the end range (exclusive)
656 * @param value the value to set it to
657 * @throws IndexOutOfBoundsException if from < 0 || from > to ||
661 public void set(int from
, int to
, boolean value
)
670 * Returns the number of bits actually used by this bit set. Note
671 * that this method doesn't return the number of set bits, and that
672 * future requests for larger bits will make this automatically grow.
674 * @return the number of bits currently used.
678 return bits
.length
* 64;
682 * Returns the string representation of this bit set. This
683 * consists of a comma separated list of the integers in this set
684 * surrounded by curly braces. There is a space after each comma.
685 * A sample string is thus "{1, 3, 53}".
686 * @return the string representation.
688 public String
toString()
690 StringBuffer r
= new StringBuffer("{");
691 boolean first
= true;
692 for (int i
= 0; i
< bits
.length
; ++i
)
698 for (int j
= 0; j
< 64; ++j
)
700 if ((word
& bit
) != 0)
704 r
.append(64 * i
+ j
);
710 return r
.append("}").toString();
714 * Performs the logical XOR operation on this bit set and the
715 * given <code>set</code>. This means it builds the symmetric
716 * remainder of the two sets (the elements that are in one set,
717 * but not in the other). The result is stored into this bit set,
718 * which grows as necessary.
720 * @param bs the second bit set
721 * @throws NullPointerException if bs is null
723 public void xor(BitSet bs
)
725 ensure(bs
.bits
.length
- 1);
726 for (int i
= bs
.bits
.length
- 1; i
>= 0; i
--)
727 bits
[i
] ^
= bs
.bits
[i
];
731 * Make sure the vector is big enough.
733 * @param lastElt the size needed for the bits array
735 private void ensure(int lastElt
)
737 if (lastElt
>= bits
.length
)
739 long[] nd
= new long[lastElt
+ 1];
740 System
.arraycopy(bits
, 0, nd
, 0, bits
.length
);