2 * Copyright (c) 1992, 1993
3 * The Regents of the University of California. All rights reserved.
5 * This software was developed by the Computer Systems Engineering group
6 * at Lawrence Berkeley Laboratory under DARPA contract BG 91-66 and
7 * contributed to Berkeley.
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38 #pragma ident "%Z%%M% %I% %E% SMI"
42 #pragma weak __muldi3 = ___muldi3
47 * Our algorithm is based on the following. Split incoming quad values
48 * u and v (where u,v >= 0) into
50 * u = 2^n u1 * u0 (n = number of bits in `u_long', usu. 32)
58 * uv = 2^2n u1 v1 + 2^n u1 v0 + 2^n v1 u0 + u0 v0
59 * = 2^2n u1 v1 + 2^n (u1 v0 + v1 u0) + u0 v0
61 * Now add 2^n u1 v1 to the first term and subtract it from the middle,
62 * and add 2^n u0 v0 to the last term and subtract it from the middle.
65 * uv = (2^2n + 2^n) (u1 v1) +
66 * (2^n) (u1 v0 - u1 v1 + u0 v1 - u0 v0) +
69 * Factoring the middle a bit gives us:
71 * uv = (2^2n + 2^n) (u1 v1) + [u1v1 = high]
72 * (2^n) (u1 - u0) (v0 - v1) + [(u1-u0)... = mid]
73 * (2^n + 1) (u0 v0) [u0v0 = low]
75 * The terms (u1 v1), (u1 - u0) (v0 - v1), and (u0 v0) can all be done
76 * in just half the precision of the original. (Note that either or both
77 * of (u1 - u0) or (v0 - v1) may be negative.)
79 * This algorithm is from Knuth vol. 2 (2nd ed), section 4.3.3, p. 278.
81 * Since C does not give us a `long * long = quad' operator, we split
82 * our input quads into two longs, then split the two longs into two
83 * shorts. We can then calculate `short * short = long' in native
86 * Our product should, strictly speaking, be a `long quad', with 128
87 * bits, but we are going to discard the upper 64. In other words,
88 * we are not interested in uv, but rather in (uv mod 2^2n). This
89 * makes some of the terms above vanish, and we get:
91 * (2^n)(high) + (2^n)(mid) + (2^n + 1)(low)
95 * (2^n)(high + mid + low) + low
97 * Furthermore, `high' and `mid' can be computed mod 2^n, as any factor
98 * of 2^n in either one will also vanish. Only `low' need be computed
99 * mod 2^2n, and only because of the final term above.
101 static longlong_t
__lmulq(ulong_t
, ulong_t
);
104 ___muldi3(longlong_t a
, longlong_t b
)
106 union uu u
, v
, low
, prod
;
107 ulong_t high
, mid
, udiff
, vdiff
;
115 * Get u and v such that u, v >= 0. When this is finished,
116 * u1, u0, v1, and v0 will be directly accessible through the
122 u
.q
= -a
, negall
= 1;
126 v
.q
= -b
, negall
^= 1;
128 if (u1
== 0 && v1
== 0) {
130 * An (I hope) important optimization occurs when u1 and v1
131 * are both 0. This should be common since most numbers
132 * are small. Here the product is just u0*v0.
134 prod
.q
= __lmulq(u0
, v0
);
137 * Compute the three intermediate products, remembering
138 * whether the middle term is negative. We can discard
139 * any upper bits in high and mid, so we can use native
140 * ulong_t * ulong_t => ulong_t arithmetic.
142 low
.q
= __lmulq(u0
, v0
);
145 negmid
= 0, udiff
= u1
- u0
;
147 negmid
= 1, udiff
= u0
- u1
;
151 vdiff
= v1
- v0
, negmid
^= 1;
157 * Assemble the final product.
159 prod
.ul
[H
] = high
+ (negmid
? -mid
: mid
) + low
.ul
[L
] +
161 prod
.ul
[L
] = low
.ul
[L
];
163 return (negall
? -prod
.q
: prod
.q
);
171 * Multiply two 2N-bit longs to produce a 4N-bit quad, where N is half
172 * the number of bits in a long (whatever that is---the code below
173 * does not care as long as quad.h does its part of the bargain---but
176 * We use the same algorithm from Knuth, but this time the modulo refinement
177 * does not apply. On the other hand, since N is half the size of a long,
178 * we can get away with native multiplication---none of our input terms
179 * exceeds (ULONG_MAX >> 1).
181 * Note that, for ulong_t l, the quad-precision result
185 * splits into high and low longs as HHALF(l) and LHUP(l) respectively.
188 __lmulq(ulong_t u
, ulong_t v
)
190 ulong_t u1
, u0
, v1
, v0
, udiff
, vdiff
, high
, mid
, low
;
191 ulong_t prodh
, prodl
, was
;
202 /* This is the same small-number optimization as before. */
203 if (u1
== 0 && v1
== 0)
207 udiff
= u1
- u0
, neg
= 0;
209 udiff
= u0
- u1
, neg
= 1;
213 vdiff
= v1
- v0
, neg
^= 1;
218 /* prod = (high << 2N) + (high << N); */
219 prodh
= high
+ HHALF(high
);
222 /* if (neg) prod -= mid << N; else prod += mid << N; */
226 prodh
-= HHALF(mid
) + (prodl
> was
);
230 prodh
+= HHALF(mid
) + (prodl
< was
);
233 /* prod += low << N */
236 prodh
+= HHALF(low
) + (prodl
< was
);
238 if ((prodl
+= low
) < low
)
241 /* return 4N-bit product */