stmt and setup can contain multiple statements, see #5896
[python.git] / Objects / longobject.c
blob1fe7b06b49a061a2cf9382c3139039dd3fa6fbbd
3 /* Long (arbitrary precision) integer object implementation */
5 /* XXX The functional organization of this file is terrible */
7 #include "Python.h"
8 #include "longintrepr.h"
9 #include "structseq.h"
11 #include <float.h>
12 #include <ctype.h>
13 #include <stddef.h>
15 /* For long multiplication, use the O(N**2) school algorithm unless
16 * both operands contain more than KARATSUBA_CUTOFF digits (this
17 * being an internal Python long digit, in base PyLong_BASE).
19 #define KARATSUBA_CUTOFF 70
20 #define KARATSUBA_SQUARE_CUTOFF (2 * KARATSUBA_CUTOFF)
22 /* For exponentiation, use the binary left-to-right algorithm
23 * unless the exponent contains more than FIVEARY_CUTOFF digits.
24 * In that case, do 5 bits at a time. The potential drawback is that
25 * a table of 2**5 intermediate results is computed.
27 #define FIVEARY_CUTOFF 8
29 #define ABS(x) ((x) < 0 ? -(x) : (x))
31 #undef MIN
32 #undef MAX
33 #define MAX(x, y) ((x) < (y) ? (y) : (x))
34 #define MIN(x, y) ((x) > (y) ? (y) : (x))
36 #define SIGCHECK(PyTryBlock) \
37 if (--_Py_Ticker < 0) { \
38 _Py_Ticker = _Py_CheckInterval; \
39 if (PyErr_CheckSignals()) PyTryBlock \
42 /* forward declaration */
43 static int bits_in_digit(digit d);
45 /* Normalize (remove leading zeros from) a long int object.
46 Doesn't attempt to free the storage--in most cases, due to the nature
47 of the algorithms used, this could save at most be one word anyway. */
49 static PyLongObject *
50 long_normalize(register PyLongObject *v)
52 Py_ssize_t j = ABS(Py_SIZE(v));
53 Py_ssize_t i = j;
55 while (i > 0 && v->ob_digit[i-1] == 0)
56 --i;
57 if (i != j)
58 Py_SIZE(v) = (Py_SIZE(v) < 0) ? -(i) : i;
59 return v;
62 /* Allocate a new long int object with size digits.
63 Return NULL and set exception if we run out of memory. */
65 #define MAX_LONG_DIGITS \
66 ((PY_SSIZE_T_MAX - offsetof(PyLongObject, ob_digit))/sizeof(digit))
68 PyLongObject *
69 _PyLong_New(Py_ssize_t size)
71 if (size > (Py_ssize_t)MAX_LONG_DIGITS) {
72 PyErr_SetString(PyExc_OverflowError,
73 "too many digits in integer");
74 return NULL;
76 /* coverity[ampersand_in_size] */
77 /* XXX(nnorwitz): PyObject_NEW_VAR / _PyObject_VAR_SIZE need to detect
78 overflow */
79 return PyObject_NEW_VAR(PyLongObject, &PyLong_Type, size);
82 PyObject *
83 _PyLong_Copy(PyLongObject *src)
85 PyLongObject *result;
86 Py_ssize_t i;
88 assert(src != NULL);
89 i = src->ob_size;
90 if (i < 0)
91 i = -(i);
92 result = _PyLong_New(i);
93 if (result != NULL) {
94 result->ob_size = src->ob_size;
95 while (--i >= 0)
96 result->ob_digit[i] = src->ob_digit[i];
98 return (PyObject *)result;
101 /* Create a new long int object from a C long int */
103 PyObject *
104 PyLong_FromLong(long ival)
106 PyLongObject *v;
107 unsigned long abs_ival;
108 unsigned long t; /* unsigned so >> doesn't propagate sign bit */
109 int ndigits = 0;
110 int negative = 0;
112 if (ival < 0) {
113 /* if LONG_MIN == -LONG_MAX-1 (true on most platforms) then
114 ANSI C says that the result of -ival is undefined when ival
115 == LONG_MIN. Hence the following workaround. */
116 abs_ival = (unsigned long)(-1-ival) + 1;
117 negative = 1;
119 else {
120 abs_ival = (unsigned long)ival;
123 /* Count the number of Python digits.
124 We used to pick 5 ("big enough for anything"), but that's a
125 waste of time and space given that 5*15 = 75 bits are rarely
126 needed. */
127 t = abs_ival;
128 while (t) {
129 ++ndigits;
130 t >>= PyLong_SHIFT;
132 v = _PyLong_New(ndigits);
133 if (v != NULL) {
134 digit *p = v->ob_digit;
135 v->ob_size = negative ? -ndigits : ndigits;
136 t = abs_ival;
137 while (t) {
138 *p++ = (digit)(t & PyLong_MASK);
139 t >>= PyLong_SHIFT;
142 return (PyObject *)v;
145 /* Create a new long int object from a C unsigned long int */
147 PyObject *
148 PyLong_FromUnsignedLong(unsigned long ival)
150 PyLongObject *v;
151 unsigned long t;
152 int ndigits = 0;
154 /* Count the number of Python digits. */
155 t = (unsigned long)ival;
156 while (t) {
157 ++ndigits;
158 t >>= PyLong_SHIFT;
160 v = _PyLong_New(ndigits);
161 if (v != NULL) {
162 digit *p = v->ob_digit;
163 Py_SIZE(v) = ndigits;
164 while (ival) {
165 *p++ = (digit)(ival & PyLong_MASK);
166 ival >>= PyLong_SHIFT;
169 return (PyObject *)v;
172 /* Create a new long int object from a C double */
174 PyObject *
175 PyLong_FromDouble(double dval)
177 PyLongObject *v;
178 double frac;
179 int i, ndig, expo, neg;
180 neg = 0;
181 if (Py_IS_INFINITY(dval)) {
182 PyErr_SetString(PyExc_OverflowError,
183 "cannot convert float infinity to integer");
184 return NULL;
186 if (Py_IS_NAN(dval)) {
187 PyErr_SetString(PyExc_ValueError,
188 "cannot convert float NaN to integer");
189 return NULL;
191 if (dval < 0.0) {
192 neg = 1;
193 dval = -dval;
195 frac = frexp(dval, &expo); /* dval = frac*2**expo; 0.0 <= frac < 1.0 */
196 if (expo <= 0)
197 return PyLong_FromLong(0L);
198 ndig = (expo-1) / PyLong_SHIFT + 1; /* Number of 'digits' in result */
199 v = _PyLong_New(ndig);
200 if (v == NULL)
201 return NULL;
202 frac = ldexp(frac, (expo-1) % PyLong_SHIFT + 1);
203 for (i = ndig; --i >= 0; ) {
204 digit bits = (digit)frac;
205 v->ob_digit[i] = bits;
206 frac = frac - (double)bits;
207 frac = ldexp(frac, PyLong_SHIFT);
209 if (neg)
210 Py_SIZE(v) = -(Py_SIZE(v));
211 return (PyObject *)v;
214 /* Checking for overflow in PyLong_AsLong is a PITA since C doesn't define
215 * anything about what happens when a signed integer operation overflows,
216 * and some compilers think they're doing you a favor by being "clever"
217 * then. The bit pattern for the largest postive signed long is
218 * (unsigned long)LONG_MAX, and for the smallest negative signed long
219 * it is abs(LONG_MIN), which we could write -(unsigned long)LONG_MIN.
220 * However, some other compilers warn about applying unary minus to an
221 * unsigned operand. Hence the weird "0-".
223 #define PY_ABS_LONG_MIN (0-(unsigned long)LONG_MIN)
224 #define PY_ABS_SSIZE_T_MIN (0-(size_t)PY_SSIZE_T_MIN)
226 /* Get a C long int from a long int object.
227 Returns -1 and sets an error condition if overflow occurs. */
229 long
230 PyLong_AsLong(PyObject *vv)
232 /* This version by Tim Peters */
233 register PyLongObject *v;
234 unsigned long x, prev;
235 Py_ssize_t i;
236 int sign;
238 if (vv == NULL || !PyLong_Check(vv)) {
239 if (vv != NULL && PyInt_Check(vv))
240 return PyInt_AsLong(vv);
241 PyErr_BadInternalCall();
242 return -1;
244 v = (PyLongObject *)vv;
245 i = v->ob_size;
246 sign = 1;
247 x = 0;
248 if (i < 0) {
249 sign = -1;
250 i = -(i);
252 while (--i >= 0) {
253 prev = x;
254 x = (x << PyLong_SHIFT) + v->ob_digit[i];
255 if ((x >> PyLong_SHIFT) != prev)
256 goto overflow;
258 /* Haven't lost any bits, but casting to long requires extra care
259 * (see comment above).
261 if (x <= (unsigned long)LONG_MAX) {
262 return (long)x * sign;
264 else if (sign < 0 && x == PY_ABS_LONG_MIN) {
265 return LONG_MIN;
267 /* else overflow */
269 overflow:
270 PyErr_SetString(PyExc_OverflowError,
271 "long int too large to convert to int");
272 return -1;
275 /* Get a Py_ssize_t from a long int object.
276 Returns -1 and sets an error condition if overflow occurs. */
278 Py_ssize_t
279 PyLong_AsSsize_t(PyObject *vv) {
280 register PyLongObject *v;
281 size_t x, prev;
282 Py_ssize_t i;
283 int sign;
285 if (vv == NULL || !PyLong_Check(vv)) {
286 PyErr_BadInternalCall();
287 return -1;
289 v = (PyLongObject *)vv;
290 i = v->ob_size;
291 sign = 1;
292 x = 0;
293 if (i < 0) {
294 sign = -1;
295 i = -(i);
297 while (--i >= 0) {
298 prev = x;
299 x = (x << PyLong_SHIFT) + v->ob_digit[i];
300 if ((x >> PyLong_SHIFT) != prev)
301 goto overflow;
303 /* Haven't lost any bits, but casting to a signed type requires
304 * extra care (see comment above).
306 if (x <= (size_t)PY_SSIZE_T_MAX) {
307 return (Py_ssize_t)x * sign;
309 else if (sign < 0 && x == PY_ABS_SSIZE_T_MIN) {
310 return PY_SSIZE_T_MIN;
312 /* else overflow */
314 overflow:
315 PyErr_SetString(PyExc_OverflowError,
316 "long int too large to convert to int");
317 return -1;
320 /* Get a C unsigned long int from a long int object.
321 Returns -1 and sets an error condition if overflow occurs. */
323 unsigned long
324 PyLong_AsUnsignedLong(PyObject *vv)
326 register PyLongObject *v;
327 unsigned long x, prev;
328 Py_ssize_t i;
330 if (vv == NULL || !PyLong_Check(vv)) {
331 if (vv != NULL && PyInt_Check(vv)) {
332 long val = PyInt_AsLong(vv);
333 if (val < 0) {
334 PyErr_SetString(PyExc_OverflowError,
335 "can't convert negative value to unsigned long");
336 return (unsigned long) -1;
338 return val;
340 PyErr_BadInternalCall();
341 return (unsigned long) -1;
343 v = (PyLongObject *)vv;
344 i = Py_SIZE(v);
345 x = 0;
346 if (i < 0) {
347 PyErr_SetString(PyExc_OverflowError,
348 "can't convert negative value to unsigned long");
349 return (unsigned long) -1;
351 while (--i >= 0) {
352 prev = x;
353 x = (x << PyLong_SHIFT) + v->ob_digit[i];
354 if ((x >> PyLong_SHIFT) != prev) {
355 PyErr_SetString(PyExc_OverflowError,
356 "long int too large to convert");
357 return (unsigned long) -1;
360 return x;
363 /* Get a C unsigned long int from a long int object, ignoring the high bits.
364 Returns -1 and sets an error condition if an error occurs. */
366 unsigned long
367 PyLong_AsUnsignedLongMask(PyObject *vv)
369 register PyLongObject *v;
370 unsigned long x;
371 Py_ssize_t i;
372 int sign;
374 if (vv == NULL || !PyLong_Check(vv)) {
375 if (vv != NULL && PyInt_Check(vv))
376 return PyInt_AsUnsignedLongMask(vv);
377 PyErr_BadInternalCall();
378 return (unsigned long) -1;
380 v = (PyLongObject *)vv;
381 i = v->ob_size;
382 sign = 1;
383 x = 0;
384 if (i < 0) {
385 sign = -1;
386 i = -i;
388 while (--i >= 0) {
389 x = (x << PyLong_SHIFT) + v->ob_digit[i];
391 return x * sign;
395 _PyLong_Sign(PyObject *vv)
397 PyLongObject *v = (PyLongObject *)vv;
399 assert(v != NULL);
400 assert(PyLong_Check(v));
402 return Py_SIZE(v) == 0 ? 0 : (Py_SIZE(v) < 0 ? -1 : 1);
405 size_t
406 _PyLong_NumBits(PyObject *vv)
408 PyLongObject *v = (PyLongObject *)vv;
409 size_t result = 0;
410 Py_ssize_t ndigits;
412 assert(v != NULL);
413 assert(PyLong_Check(v));
414 ndigits = ABS(Py_SIZE(v));
415 assert(ndigits == 0 || v->ob_digit[ndigits - 1] != 0);
416 if (ndigits > 0) {
417 digit msd = v->ob_digit[ndigits - 1];
419 result = (ndigits - 1) * PyLong_SHIFT;
420 if (result / PyLong_SHIFT != (size_t)(ndigits - 1))
421 goto Overflow;
422 do {
423 ++result;
424 if (result == 0)
425 goto Overflow;
426 msd >>= 1;
427 } while (msd);
429 return result;
431 Overflow:
432 PyErr_SetString(PyExc_OverflowError, "long has too many bits "
433 "to express in a platform size_t");
434 return (size_t)-1;
437 PyObject *
438 _PyLong_FromByteArray(const unsigned char* bytes, size_t n,
439 int little_endian, int is_signed)
441 const unsigned char* pstartbyte;/* LSB of bytes */
442 int incr; /* direction to move pstartbyte */
443 const unsigned char* pendbyte; /* MSB of bytes */
444 size_t numsignificantbytes; /* number of bytes that matter */
445 Py_ssize_t ndigits; /* number of Python long digits */
446 PyLongObject* v; /* result */
447 Py_ssize_t idigit = 0; /* next free index in v->ob_digit */
449 if (n == 0)
450 return PyLong_FromLong(0L);
452 if (little_endian) {
453 pstartbyte = bytes;
454 pendbyte = bytes + n - 1;
455 incr = 1;
457 else {
458 pstartbyte = bytes + n - 1;
459 pendbyte = bytes;
460 incr = -1;
463 if (is_signed)
464 is_signed = *pendbyte >= 0x80;
466 /* Compute numsignificantbytes. This consists of finding the most
467 significant byte. Leading 0 bytes are insignficant if the number
468 is positive, and leading 0xff bytes if negative. */
470 size_t i;
471 const unsigned char* p = pendbyte;
472 const int pincr = -incr; /* search MSB to LSB */
473 const unsigned char insignficant = is_signed ? 0xff : 0x00;
475 for (i = 0; i < n; ++i, p += pincr) {
476 if (*p != insignficant)
477 break;
479 numsignificantbytes = n - i;
480 /* 2's-comp is a bit tricky here, e.g. 0xff00 == -0x0100, so
481 actually has 2 significant bytes. OTOH, 0xff0001 ==
482 -0x00ffff, so we wouldn't *need* to bump it there; but we
483 do for 0xffff = -0x0001. To be safe without bothering to
484 check every case, bump it regardless. */
485 if (is_signed && numsignificantbytes < n)
486 ++numsignificantbytes;
489 /* How many Python long digits do we need? We have
490 8*numsignificantbytes bits, and each Python long digit has
491 PyLong_SHIFT bits, so it's the ceiling of the quotient. */
492 /* catch overflow before it happens */
493 if (numsignificantbytes > (PY_SSIZE_T_MAX - PyLong_SHIFT) / 8) {
494 PyErr_SetString(PyExc_OverflowError,
495 "byte array too long to convert to int");
496 return NULL;
498 ndigits = (numsignificantbytes * 8 + PyLong_SHIFT - 1) / PyLong_SHIFT;
499 v = _PyLong_New(ndigits);
500 if (v == NULL)
501 return NULL;
503 /* Copy the bits over. The tricky parts are computing 2's-comp on
504 the fly for signed numbers, and dealing with the mismatch between
505 8-bit bytes and (probably) 15-bit Python digits.*/
507 size_t i;
508 twodigits carry = 1; /* for 2's-comp calculation */
509 twodigits accum = 0; /* sliding register */
510 unsigned int accumbits = 0; /* number of bits in accum */
511 const unsigned char* p = pstartbyte;
513 for (i = 0; i < numsignificantbytes; ++i, p += incr) {
514 twodigits thisbyte = *p;
515 /* Compute correction for 2's comp, if needed. */
516 if (is_signed) {
517 thisbyte = (0xff ^ thisbyte) + carry;
518 carry = thisbyte >> 8;
519 thisbyte &= 0xff;
521 /* Because we're going LSB to MSB, thisbyte is
522 more significant than what's already in accum,
523 so needs to be prepended to accum. */
524 accum |= (twodigits)thisbyte << accumbits;
525 accumbits += 8;
526 if (accumbits >= PyLong_SHIFT) {
527 /* There's enough to fill a Python digit. */
528 assert(idigit < ndigits);
529 v->ob_digit[idigit] = (digit)(accum &
530 PyLong_MASK);
531 ++idigit;
532 accum >>= PyLong_SHIFT;
533 accumbits -= PyLong_SHIFT;
534 assert(accumbits < PyLong_SHIFT);
537 assert(accumbits < PyLong_SHIFT);
538 if (accumbits) {
539 assert(idigit < ndigits);
540 v->ob_digit[idigit] = (digit)accum;
541 ++idigit;
545 Py_SIZE(v) = is_signed ? -idigit : idigit;
546 return (PyObject *)long_normalize(v);
550 _PyLong_AsByteArray(PyLongObject* v,
551 unsigned char* bytes, size_t n,
552 int little_endian, int is_signed)
554 Py_ssize_t i; /* index into v->ob_digit */
555 Py_ssize_t ndigits; /* |v->ob_size| */
556 twodigits accum; /* sliding register */
557 unsigned int accumbits; /* # bits in accum */
558 int do_twos_comp; /* store 2's-comp? is_signed and v < 0 */
559 digit carry; /* for computing 2's-comp */
560 size_t j; /* # bytes filled */
561 unsigned char* p; /* pointer to next byte in bytes */
562 int pincr; /* direction to move p */
564 assert(v != NULL && PyLong_Check(v));
566 if (Py_SIZE(v) < 0) {
567 ndigits = -(Py_SIZE(v));
568 if (!is_signed) {
569 PyErr_SetString(PyExc_OverflowError,
570 "can't convert negative long to unsigned");
571 return -1;
573 do_twos_comp = 1;
575 else {
576 ndigits = Py_SIZE(v);
577 do_twos_comp = 0;
580 if (little_endian) {
581 p = bytes;
582 pincr = 1;
584 else {
585 p = bytes + n - 1;
586 pincr = -1;
589 /* Copy over all the Python digits.
590 It's crucial that every Python digit except for the MSD contribute
591 exactly PyLong_SHIFT bits to the total, so first assert that the long is
592 normalized. */
593 assert(ndigits == 0 || v->ob_digit[ndigits - 1] != 0);
594 j = 0;
595 accum = 0;
596 accumbits = 0;
597 carry = do_twos_comp ? 1 : 0;
598 for (i = 0; i < ndigits; ++i) {
599 digit thisdigit = v->ob_digit[i];
600 if (do_twos_comp) {
601 thisdigit = (thisdigit ^ PyLong_MASK) + carry;
602 carry = thisdigit >> PyLong_SHIFT;
603 thisdigit &= PyLong_MASK;
605 /* Because we're going LSB to MSB, thisdigit is more
606 significant than what's already in accum, so needs to be
607 prepended to accum. */
608 accum |= (twodigits)thisdigit << accumbits;
610 /* The most-significant digit may be (probably is) at least
611 partly empty. */
612 if (i == ndigits - 1) {
613 /* Count # of sign bits -- they needn't be stored,
614 * although for signed conversion we need later to
615 * make sure at least one sign bit gets stored. */
616 digit s = do_twos_comp ? thisdigit ^ PyLong_MASK :
617 thisdigit;
618 while (s != 0) {
619 s >>= 1;
620 accumbits++;
623 else
624 accumbits += PyLong_SHIFT;
626 /* Store as many bytes as possible. */
627 while (accumbits >= 8) {
628 if (j >= n)
629 goto Overflow;
630 ++j;
631 *p = (unsigned char)(accum & 0xff);
632 p += pincr;
633 accumbits -= 8;
634 accum >>= 8;
638 /* Store the straggler (if any). */
639 assert(accumbits < 8);
640 assert(carry == 0); /* else do_twos_comp and *every* digit was 0 */
641 if (accumbits > 0) {
642 if (j >= n)
643 goto Overflow;
644 ++j;
645 if (do_twos_comp) {
646 /* Fill leading bits of the byte with sign bits
647 (appropriately pretending that the long had an
648 infinite supply of sign bits). */
649 accum |= (~(twodigits)0) << accumbits;
651 *p = (unsigned char)(accum & 0xff);
652 p += pincr;
654 else if (j == n && n > 0 && is_signed) {
655 /* The main loop filled the byte array exactly, so the code
656 just above didn't get to ensure there's a sign bit, and the
657 loop below wouldn't add one either. Make sure a sign bit
658 exists. */
659 unsigned char msb = *(p - pincr);
660 int sign_bit_set = msb >= 0x80;
661 assert(accumbits == 0);
662 if (sign_bit_set == do_twos_comp)
663 return 0;
664 else
665 goto Overflow;
668 /* Fill remaining bytes with copies of the sign bit. */
670 unsigned char signbyte = do_twos_comp ? 0xffU : 0U;
671 for ( ; j < n; ++j, p += pincr)
672 *p = signbyte;
675 return 0;
677 Overflow:
678 PyErr_SetString(PyExc_OverflowError, "long too big to convert");
679 return -1;
683 double
684 _PyLong_AsScaledDouble(PyObject *vv, int *exponent)
686 /* NBITS_WANTED should be > the number of bits in a double's precision,
687 but small enough so that 2**NBITS_WANTED is within the normal double
688 range. nbitsneeded is set to 1 less than that because the most-significant
689 Python digit contains at least 1 significant bit, but we don't want to
690 bother counting them (catering to the worst case cheaply).
692 57 is one more than VAX-D double precision; I (Tim) don't know of a double
693 format with more precision than that; it's 1 larger so that we add in at
694 least one round bit to stand in for the ignored least-significant bits.
696 #define NBITS_WANTED 57
697 PyLongObject *v;
698 double x;
699 const double multiplier = (double)(1L << PyLong_SHIFT);
700 Py_ssize_t i;
701 int sign;
702 int nbitsneeded;
704 if (vv == NULL || !PyLong_Check(vv)) {
705 PyErr_BadInternalCall();
706 return -1;
708 v = (PyLongObject *)vv;
709 i = Py_SIZE(v);
710 sign = 1;
711 if (i < 0) {
712 sign = -1;
713 i = -(i);
715 else if (i == 0) {
716 *exponent = 0;
717 return 0.0;
719 --i;
720 x = (double)v->ob_digit[i];
721 nbitsneeded = NBITS_WANTED - 1;
722 /* Invariant: i Python digits remain unaccounted for. */
723 while (i > 0 && nbitsneeded > 0) {
724 --i;
725 x = x * multiplier + (double)v->ob_digit[i];
726 nbitsneeded -= PyLong_SHIFT;
728 /* There are i digits we didn't shift in. Pretending they're all
729 zeroes, the true value is x * 2**(i*PyLong_SHIFT). */
730 *exponent = i;
731 assert(x > 0.0);
732 return x * sign;
733 #undef NBITS_WANTED
736 /* Get a C double from a long int object. Rounds to the nearest double,
737 using the round-half-to-even rule in the case of a tie. */
739 double
740 PyLong_AsDouble(PyObject *vv)
742 PyLongObject *v = (PyLongObject *)vv;
743 Py_ssize_t rnd_digit, rnd_bit, m, n;
744 digit lsb, *d;
745 int round_up = 0;
746 double x;
748 if (vv == NULL || !PyLong_Check(vv)) {
749 PyErr_BadInternalCall();
750 return -1.0;
753 /* Notes on the method: for simplicity, assume v is positive and >=
754 2**DBL_MANT_DIG. (For negative v we just ignore the sign until the
755 end; for small v no rounding is necessary.) Write n for the number
756 of bits in v, so that 2**(n-1) <= v < 2**n, and n > DBL_MANT_DIG.
758 Some terminology: the *rounding bit* of v is the 1st bit of v that
759 will be rounded away (bit n - DBL_MANT_DIG - 1); the *parity bit*
760 is the bit immediately above. The round-half-to-even rule says
761 that we round up if the rounding bit is set, unless v is exactly
762 halfway between two floats and the parity bit is zero.
764 Write d[0] ... d[m] for the digits of v, least to most significant.
765 Let rnd_bit be the index of the rounding bit, and rnd_digit the
766 index of the PyLong digit containing the rounding bit. Then the
767 bits of the digit d[rnd_digit] look something like:
769 rounding bit
772 msb -> sssssrttttttttt <- lsb
775 parity bit
777 where 's' represents a 'significant bit' that will be included in
778 the mantissa of the result, 'r' is the rounding bit, and 't'
779 represents a 'trailing bit' following the rounding bit. Note that
780 if the rounding bit is at the top of d[rnd_digit] then the parity
781 bit will be the lsb of d[rnd_digit+1]. If we set
783 lsb = 1 << (rnd_bit % PyLong_SHIFT)
785 then d[rnd_digit] & (PyLong_BASE - 2*lsb) selects just the
786 significant bits of d[rnd_digit], d[rnd_digit] & (lsb-1) gets the
787 trailing bits, and d[rnd_digit] & lsb gives the rounding bit.
789 We initialize the double x to the integer given by digits
790 d[rnd_digit:m-1], but with the rounding bit and trailing bits of
791 d[rnd_digit] masked out. So the value of x comes from the top
792 DBL_MANT_DIG bits of v, multiplied by 2*lsb. Note that in the loop
793 that produces x, all floating-point operations are exact (assuming
794 that FLT_RADIX==2). Now if we're rounding down, the value we want
795 to return is simply
797 x * 2**(PyLong_SHIFT * rnd_digit).
799 and if we're rounding up, it's
801 (x + 2*lsb) * 2**(PyLong_SHIFT * rnd_digit).
803 Under the round-half-to-even rule, we round up if, and only
804 if, the rounding bit is set *and* at least one of the
805 following three conditions is satisfied:
807 (1) the parity bit is set, or
808 (2) at least one of the trailing bits of d[rnd_digit] is set, or
809 (3) at least one of the digits d[i], 0 <= i < rnd_digit
810 is nonzero.
812 Finally, we have to worry about overflow. If v >= 2**DBL_MAX_EXP,
813 or equivalently n > DBL_MAX_EXP, then overflow occurs. If v <
814 2**DBL_MAX_EXP then we're usually safe, but there's a corner case
815 to consider: if v is very close to 2**DBL_MAX_EXP then it's
816 possible that v is rounded up to exactly 2**DBL_MAX_EXP, and then
817 again overflow occurs.
820 if (Py_SIZE(v) == 0)
821 return 0.0;
822 m = ABS(Py_SIZE(v)) - 1;
823 d = v->ob_digit;
824 assert(d[m]); /* v should be normalized */
826 /* fast path for case where 0 < abs(v) < 2**DBL_MANT_DIG */
827 if (m < DBL_MANT_DIG / PyLong_SHIFT ||
828 (m == DBL_MANT_DIG / PyLong_SHIFT &&
829 d[m] < (digit)1 << DBL_MANT_DIG%PyLong_SHIFT)) {
830 x = d[m];
831 while (--m >= 0)
832 x = x*PyLong_BASE + d[m];
833 return Py_SIZE(v) < 0 ? -x : x;
836 /* if m is huge then overflow immediately; otherwise, compute the
837 number of bits n in v. The condition below implies n (= #bits) >=
838 m * PyLong_SHIFT + 1 > DBL_MAX_EXP, hence v >= 2**DBL_MAX_EXP. */
839 if (m > (DBL_MAX_EXP-1)/PyLong_SHIFT)
840 goto overflow;
841 n = m * PyLong_SHIFT + bits_in_digit(d[m]);
842 if (n > DBL_MAX_EXP)
843 goto overflow;
845 /* find location of rounding bit */
846 assert(n > DBL_MANT_DIG); /* dealt with |v| < 2**DBL_MANT_DIG above */
847 rnd_bit = n - DBL_MANT_DIG - 1;
848 rnd_digit = rnd_bit/PyLong_SHIFT;
849 lsb = (digit)1 << (rnd_bit%PyLong_SHIFT);
851 /* Get top DBL_MANT_DIG bits of v. Assumes PyLong_SHIFT <
852 DBL_MANT_DIG, so we'll need bits from at least 2 digits of v. */
853 x = d[m];
854 assert(m > rnd_digit);
855 while (--m > rnd_digit)
856 x = x*PyLong_BASE + d[m];
857 x = x*PyLong_BASE + (d[m] & (PyLong_BASE-2*lsb));
859 /* decide whether to round up, using round-half-to-even */
860 assert(m == rnd_digit);
861 if (d[m] & lsb) { /* if (rounding bit is set) */
862 digit parity_bit;
863 if (lsb == PyLong_BASE/2)
864 parity_bit = d[m+1] & 1;
865 else
866 parity_bit = d[m] & 2*lsb;
867 if (parity_bit)
868 round_up = 1;
869 else if (d[m] & (lsb-1))
870 round_up = 1;
871 else {
872 while (--m >= 0) {
873 if (d[m]) {
874 round_up = 1;
875 break;
881 /* and round up if necessary */
882 if (round_up) {
883 x += 2*lsb;
884 if (n == DBL_MAX_EXP &&
885 x == ldexp((double)(2*lsb), DBL_MANT_DIG)) {
886 /* overflow corner case */
887 goto overflow;
891 /* shift, adjust for sign, and return */
892 x = ldexp(x, rnd_digit*PyLong_SHIFT);
893 return Py_SIZE(v) < 0 ? -x : x;
895 overflow:
896 PyErr_SetString(PyExc_OverflowError,
897 "long int too large to convert to float");
898 return -1.0;
901 /* Create a new long (or int) object from a C pointer */
903 PyObject *
904 PyLong_FromVoidPtr(void *p)
906 #if SIZEOF_VOID_P <= SIZEOF_LONG
907 if ((long)p < 0)
908 return PyLong_FromUnsignedLong((unsigned long)p);
909 return PyInt_FromLong((long)p);
910 #else
912 #ifndef HAVE_LONG_LONG
913 # error "PyLong_FromVoidPtr: sizeof(void*) > sizeof(long), but no long long"
914 #endif
915 #if SIZEOF_LONG_LONG < SIZEOF_VOID_P
916 # error "PyLong_FromVoidPtr: sizeof(PY_LONG_LONG) < sizeof(void*)"
917 #endif
918 /* optimize null pointers */
919 if (p == NULL)
920 return PyInt_FromLong(0);
921 return PyLong_FromUnsignedLongLong((unsigned PY_LONG_LONG)p);
923 #endif /* SIZEOF_VOID_P <= SIZEOF_LONG */
926 /* Get a C pointer from a long object (or an int object in some cases) */
928 void *
929 PyLong_AsVoidPtr(PyObject *vv)
931 /* This function will allow int or long objects. If vv is neither,
932 then the PyLong_AsLong*() functions will raise the exception:
933 PyExc_SystemError, "bad argument to internal function"
935 #if SIZEOF_VOID_P <= SIZEOF_LONG
936 long x;
938 if (PyInt_Check(vv))
939 x = PyInt_AS_LONG(vv);
940 else if (PyLong_Check(vv) && _PyLong_Sign(vv) < 0)
941 x = PyLong_AsLong(vv);
942 else
943 x = PyLong_AsUnsignedLong(vv);
944 #else
946 #ifndef HAVE_LONG_LONG
947 # error "PyLong_AsVoidPtr: sizeof(void*) > sizeof(long), but no long long"
948 #endif
949 #if SIZEOF_LONG_LONG < SIZEOF_VOID_P
950 # error "PyLong_AsVoidPtr: sizeof(PY_LONG_LONG) < sizeof(void*)"
951 #endif
952 PY_LONG_LONG x;
954 if (PyInt_Check(vv))
955 x = PyInt_AS_LONG(vv);
956 else if (PyLong_Check(vv) && _PyLong_Sign(vv) < 0)
957 x = PyLong_AsLongLong(vv);
958 else
959 x = PyLong_AsUnsignedLongLong(vv);
961 #endif /* SIZEOF_VOID_P <= SIZEOF_LONG */
963 if (x == -1 && PyErr_Occurred())
964 return NULL;
965 return (void *)x;
968 #ifdef HAVE_LONG_LONG
970 /* Initial PY_LONG_LONG support by Chris Herborth (chrish@qnx.com), later
971 * rewritten to use the newer PyLong_{As,From}ByteArray API.
974 #define IS_LITTLE_ENDIAN (int)*(unsigned char*)&one
976 /* Create a new long int object from a C PY_LONG_LONG int. */
978 PyObject *
979 PyLong_FromLongLong(PY_LONG_LONG ival)
981 PyLongObject *v;
982 unsigned PY_LONG_LONG abs_ival;
983 unsigned PY_LONG_LONG t; /* unsigned so >> doesn't propagate sign bit */
984 int ndigits = 0;
985 int negative = 0;
987 if (ival < 0) {
988 /* avoid signed overflow on negation; see comments
989 in PyLong_FromLong above. */
990 abs_ival = (unsigned PY_LONG_LONG)(-1-ival) + 1;
991 negative = 1;
993 else {
994 abs_ival = (unsigned PY_LONG_LONG)ival;
997 /* Count the number of Python digits.
998 We used to pick 5 ("big enough for anything"), but that's a
999 waste of time and space given that 5*15 = 75 bits are rarely
1000 needed. */
1001 t = abs_ival;
1002 while (t) {
1003 ++ndigits;
1004 t >>= PyLong_SHIFT;
1006 v = _PyLong_New(ndigits);
1007 if (v != NULL) {
1008 digit *p = v->ob_digit;
1009 Py_SIZE(v) = negative ? -ndigits : ndigits;
1010 t = abs_ival;
1011 while (t) {
1012 *p++ = (digit)(t & PyLong_MASK);
1013 t >>= PyLong_SHIFT;
1016 return (PyObject *)v;
1019 /* Create a new long int object from a C unsigned PY_LONG_LONG int. */
1021 PyObject *
1022 PyLong_FromUnsignedLongLong(unsigned PY_LONG_LONG ival)
1024 PyLongObject *v;
1025 unsigned PY_LONG_LONG t;
1026 int ndigits = 0;
1028 /* Count the number of Python digits. */
1029 t = (unsigned PY_LONG_LONG)ival;
1030 while (t) {
1031 ++ndigits;
1032 t >>= PyLong_SHIFT;
1034 v = _PyLong_New(ndigits);
1035 if (v != NULL) {
1036 digit *p = v->ob_digit;
1037 Py_SIZE(v) = ndigits;
1038 while (ival) {
1039 *p++ = (digit)(ival & PyLong_MASK);
1040 ival >>= PyLong_SHIFT;
1043 return (PyObject *)v;
1046 /* Create a new long int object from a C Py_ssize_t. */
1048 PyObject *
1049 PyLong_FromSsize_t(Py_ssize_t ival)
1051 Py_ssize_t bytes = ival;
1052 int one = 1;
1053 return _PyLong_FromByteArray(
1054 (unsigned char *)&bytes,
1055 SIZEOF_SIZE_T, IS_LITTLE_ENDIAN, 1);
1058 /* Create a new long int object from a C size_t. */
1060 PyObject *
1061 PyLong_FromSize_t(size_t ival)
1063 size_t bytes = ival;
1064 int one = 1;
1065 return _PyLong_FromByteArray(
1066 (unsigned char *)&bytes,
1067 SIZEOF_SIZE_T, IS_LITTLE_ENDIAN, 0);
1070 /* Get a C PY_LONG_LONG int from a long int object.
1071 Return -1 and set an error if overflow occurs. */
1073 PY_LONG_LONG
1074 PyLong_AsLongLong(PyObject *vv)
1076 PY_LONG_LONG bytes;
1077 int one = 1;
1078 int res;
1080 if (vv == NULL) {
1081 PyErr_BadInternalCall();
1082 return -1;
1084 if (!PyLong_Check(vv)) {
1085 PyNumberMethods *nb;
1086 PyObject *io;
1087 if (PyInt_Check(vv))
1088 return (PY_LONG_LONG)PyInt_AsLong(vv);
1089 if ((nb = vv->ob_type->tp_as_number) == NULL ||
1090 nb->nb_int == NULL) {
1091 PyErr_SetString(PyExc_TypeError, "an integer is required");
1092 return -1;
1094 io = (*nb->nb_int) (vv);
1095 if (io == NULL)
1096 return -1;
1097 if (PyInt_Check(io)) {
1098 bytes = PyInt_AsLong(io);
1099 Py_DECREF(io);
1100 return bytes;
1102 if (PyLong_Check(io)) {
1103 bytes = PyLong_AsLongLong(io);
1104 Py_DECREF(io);
1105 return bytes;
1107 Py_DECREF(io);
1108 PyErr_SetString(PyExc_TypeError, "integer conversion failed");
1109 return -1;
1112 res = _PyLong_AsByteArray(
1113 (PyLongObject *)vv, (unsigned char *)&bytes,
1114 SIZEOF_LONG_LONG, IS_LITTLE_ENDIAN, 1);
1116 /* Plan 9 can't handle PY_LONG_LONG in ? : expressions */
1117 if (res < 0)
1118 return (PY_LONG_LONG)-1;
1119 else
1120 return bytes;
1123 /* Get a C unsigned PY_LONG_LONG int from a long int object.
1124 Return -1 and set an error if overflow occurs. */
1126 unsigned PY_LONG_LONG
1127 PyLong_AsUnsignedLongLong(PyObject *vv)
1129 unsigned PY_LONG_LONG bytes;
1130 int one = 1;
1131 int res;
1133 if (vv == NULL || !PyLong_Check(vv)) {
1134 PyErr_BadInternalCall();
1135 return (unsigned PY_LONG_LONG)-1;
1138 res = _PyLong_AsByteArray(
1139 (PyLongObject *)vv, (unsigned char *)&bytes,
1140 SIZEOF_LONG_LONG, IS_LITTLE_ENDIAN, 0);
1142 /* Plan 9 can't handle PY_LONG_LONG in ? : expressions */
1143 if (res < 0)
1144 return (unsigned PY_LONG_LONG)res;
1145 else
1146 return bytes;
1149 /* Get a C unsigned long int from a long int object, ignoring the high bits.
1150 Returns -1 and sets an error condition if an error occurs. */
1152 unsigned PY_LONG_LONG
1153 PyLong_AsUnsignedLongLongMask(PyObject *vv)
1155 register PyLongObject *v;
1156 unsigned PY_LONG_LONG x;
1157 Py_ssize_t i;
1158 int sign;
1160 if (vv == NULL || !PyLong_Check(vv)) {
1161 PyErr_BadInternalCall();
1162 return (unsigned long) -1;
1164 v = (PyLongObject *)vv;
1165 i = v->ob_size;
1166 sign = 1;
1167 x = 0;
1168 if (i < 0) {
1169 sign = -1;
1170 i = -i;
1172 while (--i >= 0) {
1173 x = (x << PyLong_SHIFT) + v->ob_digit[i];
1175 return x * sign;
1177 #undef IS_LITTLE_ENDIAN
1179 #endif /* HAVE_LONG_LONG */
1182 static int
1183 convert_binop(PyObject *v, PyObject *w, PyLongObject **a, PyLongObject **b) {
1184 if (PyLong_Check(v)) {
1185 *a = (PyLongObject *) v;
1186 Py_INCREF(v);
1188 else if (PyInt_Check(v)) {
1189 *a = (PyLongObject *) PyLong_FromLong(PyInt_AS_LONG(v));
1191 else {
1192 return 0;
1194 if (PyLong_Check(w)) {
1195 *b = (PyLongObject *) w;
1196 Py_INCREF(w);
1198 else if (PyInt_Check(w)) {
1199 *b = (PyLongObject *) PyLong_FromLong(PyInt_AS_LONG(w));
1201 else {
1202 Py_DECREF(*a);
1203 return 0;
1205 return 1;
1208 #define CONVERT_BINOP(v, w, a, b) \
1209 if (!convert_binop(v, w, a, b)) { \
1210 Py_INCREF(Py_NotImplemented); \
1211 return Py_NotImplemented; \
1214 /* bits_in_digit(d) returns the unique integer k such that 2**(k-1) <= d <
1215 2**k if d is nonzero, else 0. */
1217 static const unsigned char BitLengthTable[32] = {
1218 0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4,
1219 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
1222 static int
1223 bits_in_digit(digit d)
1225 int d_bits = 0;
1226 while (d >= 32) {
1227 d_bits += 6;
1228 d >>= 6;
1230 d_bits += (int)BitLengthTable[d];
1231 return d_bits;
1234 /* x[0:m] and y[0:n] are digit vectors, LSD first, m >= n required. x[0:n]
1235 * is modified in place, by adding y to it. Carries are propagated as far as
1236 * x[m-1], and the remaining carry (0 or 1) is returned.
1238 static digit
1239 v_iadd(digit *x, Py_ssize_t m, digit *y, Py_ssize_t n)
1241 Py_ssize_t i;
1242 digit carry = 0;
1244 assert(m >= n);
1245 for (i = 0; i < n; ++i) {
1246 carry += x[i] + y[i];
1247 x[i] = carry & PyLong_MASK;
1248 carry >>= PyLong_SHIFT;
1249 assert((carry & 1) == carry);
1251 for (; carry && i < m; ++i) {
1252 carry += x[i];
1253 x[i] = carry & PyLong_MASK;
1254 carry >>= PyLong_SHIFT;
1255 assert((carry & 1) == carry);
1257 return carry;
1260 /* x[0:m] and y[0:n] are digit vectors, LSD first, m >= n required. x[0:n]
1261 * is modified in place, by subtracting y from it. Borrows are propagated as
1262 * far as x[m-1], and the remaining borrow (0 or 1) is returned.
1264 static digit
1265 v_isub(digit *x, Py_ssize_t m, digit *y, Py_ssize_t n)
1267 Py_ssize_t i;
1268 digit borrow = 0;
1270 assert(m >= n);
1271 for (i = 0; i < n; ++i) {
1272 borrow = x[i] - y[i] - borrow;
1273 x[i] = borrow & PyLong_MASK;
1274 borrow >>= PyLong_SHIFT;
1275 borrow &= 1; /* keep only 1 sign bit */
1277 for (; borrow && i < m; ++i) {
1278 borrow = x[i] - borrow;
1279 x[i] = borrow & PyLong_MASK;
1280 borrow >>= PyLong_SHIFT;
1281 borrow &= 1;
1283 return borrow;
1286 /* Shift digit vector a[0:m] d bits left, with 0 <= d < PyLong_SHIFT. Put
1287 * result in z[0:m], and return the d bits shifted out of the top.
1289 static digit
1290 v_lshift(digit *z, digit *a, Py_ssize_t m, int d)
1292 Py_ssize_t i;
1293 digit carry = 0;
1295 assert(0 <= d && d < PyLong_SHIFT);
1296 for (i=0; i < m; i++) {
1297 twodigits acc = (twodigits)a[i] << d | carry;
1298 z[i] = (digit)acc & PyLong_MASK;
1299 carry = (digit)(acc >> PyLong_SHIFT);
1301 return carry;
1304 /* Shift digit vector a[0:m] d bits right, with 0 <= d < PyLong_SHIFT. Put
1305 * result in z[0:m], and return the d bits shifted out of the bottom.
1307 static digit
1308 v_rshift(digit *z, digit *a, Py_ssize_t m, int d)
1310 Py_ssize_t i;
1311 digit carry = 0;
1312 digit mask = ((digit)1 << d) - 1U;
1314 assert(0 <= d && d < PyLong_SHIFT);
1315 for (i=m; i-- > 0;) {
1316 twodigits acc = (twodigits)carry << PyLong_SHIFT | a[i];
1317 carry = (digit)acc & mask;
1318 z[i] = (digit)(acc >> d);
1320 return carry;
1323 /* Divide long pin, w/ size digits, by non-zero digit n, storing quotient
1324 in pout, and returning the remainder. pin and pout point at the LSD.
1325 It's OK for pin == pout on entry, which saves oodles of mallocs/frees in
1326 _PyLong_Format, but that should be done with great care since longs are
1327 immutable. */
1329 static digit
1330 inplace_divrem1(digit *pout, digit *pin, Py_ssize_t size, digit n)
1332 twodigits rem = 0;
1334 assert(n > 0 && n <= PyLong_MASK);
1335 pin += size;
1336 pout += size;
1337 while (--size >= 0) {
1338 digit hi;
1339 rem = (rem << PyLong_SHIFT) + *--pin;
1340 *--pout = hi = (digit)(rem / n);
1341 rem -= (twodigits)hi * n;
1343 return (digit)rem;
1346 /* Divide a long integer by a digit, returning both the quotient
1347 (as function result) and the remainder (through *prem).
1348 The sign of a is ignored; n should not be zero. */
1350 static PyLongObject *
1351 divrem1(PyLongObject *a, digit n, digit *prem)
1353 const Py_ssize_t size = ABS(Py_SIZE(a));
1354 PyLongObject *z;
1356 assert(n > 0 && n <= PyLong_MASK);
1357 z = _PyLong_New(size);
1358 if (z == NULL)
1359 return NULL;
1360 *prem = inplace_divrem1(z->ob_digit, a->ob_digit, size, n);
1361 return long_normalize(z);
1364 /* Convert the long to a string object with given base,
1365 appending a base prefix of 0[box] if base is 2, 8 or 16.
1366 Add a trailing "L" if addL is non-zero.
1367 If newstyle is zero, then use the pre-2.6 behavior of octal having
1368 a leading "0", instead of the prefix "0o" */
1369 PyAPI_FUNC(PyObject *)
1370 _PyLong_Format(PyObject *aa, int base, int addL, int newstyle)
1372 register PyLongObject *a = (PyLongObject *)aa;
1373 PyStringObject *str;
1374 Py_ssize_t i, j, sz;
1375 Py_ssize_t size_a;
1376 char *p;
1377 int bits;
1378 char sign = '\0';
1380 if (a == NULL || !PyLong_Check(a)) {
1381 PyErr_BadInternalCall();
1382 return NULL;
1384 assert(base >= 2 && base <= 36);
1385 size_a = ABS(Py_SIZE(a));
1387 /* Compute a rough upper bound for the length of the string */
1388 i = base;
1389 bits = 0;
1390 while (i > 1) {
1391 ++bits;
1392 i >>= 1;
1394 i = 5 + (addL ? 1 : 0);
1395 j = size_a*PyLong_SHIFT + bits-1;
1396 sz = i + j / bits;
1397 if (j / PyLong_SHIFT < size_a || sz < i) {
1398 PyErr_SetString(PyExc_OverflowError,
1399 "long is too large to format");
1400 return NULL;
1402 str = (PyStringObject *) PyString_FromStringAndSize((char *)0, sz);
1403 if (str == NULL)
1404 return NULL;
1405 p = PyString_AS_STRING(str) + sz;
1406 *p = '\0';
1407 if (addL)
1408 *--p = 'L';
1409 if (a->ob_size < 0)
1410 sign = '-';
1412 if (a->ob_size == 0) {
1413 *--p = '0';
1415 else if ((base & (base - 1)) == 0) {
1416 /* JRH: special case for power-of-2 bases */
1417 twodigits accum = 0;
1418 int accumbits = 0; /* # of bits in accum */
1419 int basebits = 1; /* # of bits in base-1 */
1420 i = base;
1421 while ((i >>= 1) > 1)
1422 ++basebits;
1424 for (i = 0; i < size_a; ++i) {
1425 accum |= (twodigits)a->ob_digit[i] << accumbits;
1426 accumbits += PyLong_SHIFT;
1427 assert(accumbits >= basebits);
1428 do {
1429 char cdigit = (char)(accum & (base - 1));
1430 cdigit += (cdigit < 10) ? '0' : 'a'-10;
1431 assert(p > PyString_AS_STRING(str));
1432 *--p = cdigit;
1433 accumbits -= basebits;
1434 accum >>= basebits;
1435 } while (i < size_a-1 ? accumbits >= basebits :
1436 accum > 0);
1439 else {
1440 /* Not 0, and base not a power of 2. Divide repeatedly by
1441 base, but for speed use the highest power of base that
1442 fits in a digit. */
1443 Py_ssize_t size = size_a;
1444 digit *pin = a->ob_digit;
1445 PyLongObject *scratch;
1446 /* powbasw <- largest power of base that fits in a digit. */
1447 digit powbase = base; /* powbase == base ** power */
1448 int power = 1;
1449 for (;;) {
1450 twodigits newpow = powbase * (twodigits)base;
1451 if (newpow >> PyLong_SHIFT) /* doesn't fit in a digit */
1452 break;
1453 powbase = (digit)newpow;
1454 ++power;
1457 /* Get a scratch area for repeated division. */
1458 scratch = _PyLong_New(size);
1459 if (scratch == NULL) {
1460 Py_DECREF(str);
1461 return NULL;
1464 /* Repeatedly divide by powbase. */
1465 do {
1466 int ntostore = power;
1467 digit rem = inplace_divrem1(scratch->ob_digit,
1468 pin, size, powbase);
1469 pin = scratch->ob_digit; /* no need to use a again */
1470 if (pin[size - 1] == 0)
1471 --size;
1472 SIGCHECK({
1473 Py_DECREF(scratch);
1474 Py_DECREF(str);
1475 return NULL;
1478 /* Break rem into digits. */
1479 assert(ntostore > 0);
1480 do {
1481 digit nextrem = (digit)(rem / base);
1482 char c = (char)(rem - nextrem * base);
1483 assert(p > PyString_AS_STRING(str));
1484 c += (c < 10) ? '0' : 'a'-10;
1485 *--p = c;
1486 rem = nextrem;
1487 --ntostore;
1488 /* Termination is a bit delicate: must not
1489 store leading zeroes, so must get out if
1490 remaining quotient and rem are both 0. */
1491 } while (ntostore && (size || rem));
1492 } while (size != 0);
1493 Py_DECREF(scratch);
1496 if (base == 2) {
1497 *--p = 'b';
1498 *--p = '0';
1500 else if (base == 8) {
1501 if (newstyle) {
1502 *--p = 'o';
1503 *--p = '0';
1505 else
1506 if (size_a != 0)
1507 *--p = '0';
1509 else if (base == 16) {
1510 *--p = 'x';
1511 *--p = '0';
1513 else if (base != 10) {
1514 *--p = '#';
1515 *--p = '0' + base%10;
1516 if (base > 10)
1517 *--p = '0' + base/10;
1519 if (sign)
1520 *--p = sign;
1521 if (p != PyString_AS_STRING(str)) {
1522 char *q = PyString_AS_STRING(str);
1523 assert(p > q);
1524 do {
1525 } while ((*q++ = *p++) != '\0');
1526 q--;
1527 _PyString_Resize((PyObject **)&str,
1528 (Py_ssize_t) (q - PyString_AS_STRING(str)));
1530 return (PyObject *)str;
1533 /* Table of digit values for 8-bit string -> integer conversion.
1534 * '0' maps to 0, ..., '9' maps to 9.
1535 * 'a' and 'A' map to 10, ..., 'z' and 'Z' map to 35.
1536 * All other indices map to 37.
1537 * Note that when converting a base B string, a char c is a legitimate
1538 * base B digit iff _PyLong_DigitValue[Py_CHARMASK(c)] < B.
1540 int _PyLong_DigitValue[256] = {
1541 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1542 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1543 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1544 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 37, 37, 37, 37, 37, 37,
1545 37, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24,
1546 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 37, 37, 37, 37,
1547 37, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24,
1548 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 37, 37, 37, 37,
1549 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1550 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1551 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1552 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1553 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1554 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1555 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1556 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1559 /* *str points to the first digit in a string of base `base` digits. base
1560 * is a power of 2 (2, 4, 8, 16, or 32). *str is set to point to the first
1561 * non-digit (which may be *str!). A normalized long is returned.
1562 * The point to this routine is that it takes time linear in the number of
1563 * string characters.
1565 static PyLongObject *
1566 long_from_binary_base(char **str, int base)
1568 char *p = *str;
1569 char *start = p;
1570 int bits_per_char;
1571 Py_ssize_t n;
1572 PyLongObject *z;
1573 twodigits accum;
1574 int bits_in_accum;
1575 digit *pdigit;
1577 assert(base >= 2 && base <= 32 && (base & (base - 1)) == 0);
1578 n = base;
1579 for (bits_per_char = -1; n; ++bits_per_char)
1580 n >>= 1;
1581 /* n <- total # of bits needed, while setting p to end-of-string */
1582 n = 0;
1583 while (_PyLong_DigitValue[Py_CHARMASK(*p)] < base)
1584 ++p;
1585 *str = p;
1586 /* n <- # of Python digits needed, = ceiling(n/PyLong_SHIFT). */
1587 n = (p - start) * bits_per_char + PyLong_SHIFT - 1;
1588 if (n / bits_per_char < p - start) {
1589 PyErr_SetString(PyExc_ValueError,
1590 "long string too large to convert");
1591 return NULL;
1593 n = n / PyLong_SHIFT;
1594 z = _PyLong_New(n);
1595 if (z == NULL)
1596 return NULL;
1597 /* Read string from right, and fill in long from left; i.e.,
1598 * from least to most significant in both.
1600 accum = 0;
1601 bits_in_accum = 0;
1602 pdigit = z->ob_digit;
1603 while (--p >= start) {
1604 int k = _PyLong_DigitValue[Py_CHARMASK(*p)];
1605 assert(k >= 0 && k < base);
1606 accum |= (twodigits)k << bits_in_accum;
1607 bits_in_accum += bits_per_char;
1608 if (bits_in_accum >= PyLong_SHIFT) {
1609 *pdigit++ = (digit)(accum & PyLong_MASK);
1610 assert(pdigit - z->ob_digit <= n);
1611 accum >>= PyLong_SHIFT;
1612 bits_in_accum -= PyLong_SHIFT;
1613 assert(bits_in_accum < PyLong_SHIFT);
1616 if (bits_in_accum) {
1617 assert(bits_in_accum <= PyLong_SHIFT);
1618 *pdigit++ = (digit)accum;
1619 assert(pdigit - z->ob_digit <= n);
1621 while (pdigit - z->ob_digit < n)
1622 *pdigit++ = 0;
1623 return long_normalize(z);
1626 PyObject *
1627 PyLong_FromString(char *str, char **pend, int base)
1629 int sign = 1;
1630 char *start, *orig_str = str;
1631 PyLongObject *z;
1632 PyObject *strobj, *strrepr;
1633 Py_ssize_t slen;
1635 if ((base != 0 && base < 2) || base > 36) {
1636 PyErr_SetString(PyExc_ValueError,
1637 "long() arg 2 must be >= 2 and <= 36");
1638 return NULL;
1640 while (*str != '\0' && isspace(Py_CHARMASK(*str)))
1641 str++;
1642 if (*str == '+')
1643 ++str;
1644 else if (*str == '-') {
1645 ++str;
1646 sign = -1;
1648 while (*str != '\0' && isspace(Py_CHARMASK(*str)))
1649 str++;
1650 if (base == 0) {
1651 /* No base given. Deduce the base from the contents
1652 of the string */
1653 if (str[0] != '0')
1654 base = 10;
1655 else if (str[1] == 'x' || str[1] == 'X')
1656 base = 16;
1657 else if (str[1] == 'o' || str[1] == 'O')
1658 base = 8;
1659 else if (str[1] == 'b' || str[1] == 'B')
1660 base = 2;
1661 else
1662 /* "old" (C-style) octal literal, still valid in
1663 2.x, although illegal in 3.x */
1664 base = 8;
1666 /* Whether or not we were deducing the base, skip leading chars
1667 as needed */
1668 if (str[0] == '0' &&
1669 ((base == 16 && (str[1] == 'x' || str[1] == 'X')) ||
1670 (base == 8 && (str[1] == 'o' || str[1] == 'O')) ||
1671 (base == 2 && (str[1] == 'b' || str[1] == 'B'))))
1672 str += 2;
1674 start = str;
1675 if ((base & (base - 1)) == 0)
1676 z = long_from_binary_base(&str, base);
1677 else {
1678 /***
1679 Binary bases can be converted in time linear in the number of digits, because
1680 Python's representation base is binary. Other bases (including decimal!) use
1681 the simple quadratic-time algorithm below, complicated by some speed tricks.
1683 First some math: the largest integer that can be expressed in N base-B digits
1684 is B**N-1. Consequently, if we have an N-digit input in base B, the worst-
1685 case number of Python digits needed to hold it is the smallest integer n s.t.
1687 PyLong_BASE**n-1 >= B**N-1 [or, adding 1 to both sides]
1688 PyLong_BASE**n >= B**N [taking logs to base PyLong_BASE]
1689 n >= log(B**N)/log(PyLong_BASE) = N * log(B)/log(PyLong_BASE)
1691 The static array log_base_PyLong_BASE[base] == log(base)/log(PyLong_BASE) so we can compute
1692 this quickly. A Python long with that much space is reserved near the start,
1693 and the result is computed into it.
1695 The input string is actually treated as being in base base**i (i.e., i digits
1696 are processed at a time), where two more static arrays hold:
1698 convwidth_base[base] = the largest integer i such that base**i <= PyLong_BASE
1699 convmultmax_base[base] = base ** convwidth_base[base]
1701 The first of these is the largest i such that i consecutive input digits
1702 must fit in a single Python digit. The second is effectively the input
1703 base we're really using.
1705 Viewing the input as a sequence <c0, c1, ..., c_n-1> of digits in base
1706 convmultmax_base[base], the result is "simply"
1708 (((c0*B + c1)*B + c2)*B + c3)*B + ... ))) + c_n-1
1710 where B = convmultmax_base[base].
1712 Error analysis: as above, the number of Python digits `n` needed is worst-
1713 case
1715 n >= N * log(B)/log(PyLong_BASE)
1717 where `N` is the number of input digits in base `B`. This is computed via
1719 size_z = (Py_ssize_t)((scan - str) * log_base_PyLong_BASE[base]) + 1;
1721 below. Two numeric concerns are how much space this can waste, and whether
1722 the computed result can be too small. To be concrete, assume PyLong_BASE = 2**15,
1723 which is the default (and it's unlikely anyone changes that).
1725 Waste isn't a problem: provided the first input digit isn't 0, the difference
1726 between the worst-case input with N digits and the smallest input with N
1727 digits is about a factor of B, but B is small compared to PyLong_BASE so at most
1728 one allocated Python digit can remain unused on that count. If
1729 N*log(B)/log(PyLong_BASE) is mathematically an exact integer, then truncating that
1730 and adding 1 returns a result 1 larger than necessary. However, that can't
1731 happen: whenever B is a power of 2, long_from_binary_base() is called
1732 instead, and it's impossible for B**i to be an integer power of 2**15 when
1733 B is not a power of 2 (i.e., it's impossible for N*log(B)/log(PyLong_BASE) to be
1734 an exact integer when B is not a power of 2, since B**i has a prime factor
1735 other than 2 in that case, but (2**15)**j's only prime factor is 2).
1737 The computed result can be too small if the true value of N*log(B)/log(PyLong_BASE)
1738 is a little bit larger than an exact integer, but due to roundoff errors (in
1739 computing log(B), log(PyLong_BASE), their quotient, and/or multiplying that by N)
1740 yields a numeric result a little less than that integer. Unfortunately, "how
1741 close can a transcendental function get to an integer over some range?"
1742 questions are generally theoretically intractable. Computer analysis via
1743 continued fractions is practical: expand log(B)/log(PyLong_BASE) via continued
1744 fractions, giving a sequence i/j of "the best" rational approximations. Then
1745 j*log(B)/log(PyLong_BASE) is approximately equal to (the integer) i. This shows that
1746 we can get very close to being in trouble, but very rarely. For example,
1747 76573 is a denominator in one of the continued-fraction approximations to
1748 log(10)/log(2**15), and indeed:
1750 >>> log(10)/log(2**15)*76573
1751 16958.000000654003
1753 is very close to an integer. If we were working with IEEE single-precision,
1754 rounding errors could kill us. Finding worst cases in IEEE double-precision
1755 requires better-than-double-precision log() functions, and Tim didn't bother.
1756 Instead the code checks to see whether the allocated space is enough as each
1757 new Python digit is added, and copies the whole thing to a larger long if not.
1758 This should happen extremely rarely, and in fact I don't have a test case
1759 that triggers it(!). Instead the code was tested by artificially allocating
1760 just 1 digit at the start, so that the copying code was exercised for every
1761 digit beyond the first.
1762 ***/
1763 register twodigits c; /* current input character */
1764 Py_ssize_t size_z;
1765 int i;
1766 int convwidth;
1767 twodigits convmultmax, convmult;
1768 digit *pz, *pzstop;
1769 char* scan;
1771 static double log_base_PyLong_BASE[37] = {0.0e0,};
1772 static int convwidth_base[37] = {0,};
1773 static twodigits convmultmax_base[37] = {0,};
1775 if (log_base_PyLong_BASE[base] == 0.0) {
1776 twodigits convmax = base;
1777 int i = 1;
1779 log_base_PyLong_BASE[base] = log((double)base) /
1780 log((double)PyLong_BASE);
1781 for (;;) {
1782 twodigits next = convmax * base;
1783 if (next > PyLong_BASE)
1784 break;
1785 convmax = next;
1786 ++i;
1788 convmultmax_base[base] = convmax;
1789 assert(i > 0);
1790 convwidth_base[base] = i;
1793 /* Find length of the string of numeric characters. */
1794 scan = str;
1795 while (_PyLong_DigitValue[Py_CHARMASK(*scan)] < base)
1796 ++scan;
1798 /* Create a long object that can contain the largest possible
1799 * integer with this base and length. Note that there's no
1800 * need to initialize z->ob_digit -- no slot is read up before
1801 * being stored into.
1803 size_z = (Py_ssize_t)((scan - str) * log_base_PyLong_BASE[base]) + 1;
1804 /* Uncomment next line to test exceedingly rare copy code */
1805 /* size_z = 1; */
1806 assert(size_z > 0);
1807 z = _PyLong_New(size_z);
1808 if (z == NULL)
1809 return NULL;
1810 Py_SIZE(z) = 0;
1812 /* `convwidth` consecutive input digits are treated as a single
1813 * digit in base `convmultmax`.
1815 convwidth = convwidth_base[base];
1816 convmultmax = convmultmax_base[base];
1818 /* Work ;-) */
1819 while (str < scan) {
1820 /* grab up to convwidth digits from the input string */
1821 c = (digit)_PyLong_DigitValue[Py_CHARMASK(*str++)];
1822 for (i = 1; i < convwidth && str != scan; ++i, ++str) {
1823 c = (twodigits)(c * base +
1824 _PyLong_DigitValue[Py_CHARMASK(*str)]);
1825 assert(c < PyLong_BASE);
1828 convmult = convmultmax;
1829 /* Calculate the shift only if we couldn't get
1830 * convwidth digits.
1832 if (i != convwidth) {
1833 convmult = base;
1834 for ( ; i > 1; --i)
1835 convmult *= base;
1838 /* Multiply z by convmult, and add c. */
1839 pz = z->ob_digit;
1840 pzstop = pz + Py_SIZE(z);
1841 for (; pz < pzstop; ++pz) {
1842 c += (twodigits)*pz * convmult;
1843 *pz = (digit)(c & PyLong_MASK);
1844 c >>= PyLong_SHIFT;
1846 /* carry off the current end? */
1847 if (c) {
1848 assert(c < PyLong_BASE);
1849 if (Py_SIZE(z) < size_z) {
1850 *pz = (digit)c;
1851 ++Py_SIZE(z);
1853 else {
1854 PyLongObject *tmp;
1855 /* Extremely rare. Get more space. */
1856 assert(Py_SIZE(z) == size_z);
1857 tmp = _PyLong_New(size_z + 1);
1858 if (tmp == NULL) {
1859 Py_DECREF(z);
1860 return NULL;
1862 memcpy(tmp->ob_digit,
1863 z->ob_digit,
1864 sizeof(digit) * size_z);
1865 Py_DECREF(z);
1866 z = tmp;
1867 z->ob_digit[size_z] = (digit)c;
1868 ++size_z;
1873 if (z == NULL)
1874 return NULL;
1875 if (str == start)
1876 goto onError;
1877 if (sign < 0)
1878 Py_SIZE(z) = -(Py_SIZE(z));
1879 if (*str == 'L' || *str == 'l')
1880 str++;
1881 while (*str && isspace(Py_CHARMASK(*str)))
1882 str++;
1883 if (*str != '\0')
1884 goto onError;
1885 if (pend)
1886 *pend = str;
1887 return (PyObject *) z;
1889 onError:
1890 Py_XDECREF(z);
1891 slen = strlen(orig_str) < 200 ? strlen(orig_str) : 200;
1892 strobj = PyString_FromStringAndSize(orig_str, slen);
1893 if (strobj == NULL)
1894 return NULL;
1895 strrepr = PyObject_Repr(strobj);
1896 Py_DECREF(strobj);
1897 if (strrepr == NULL)
1898 return NULL;
1899 PyErr_Format(PyExc_ValueError,
1900 "invalid literal for long() with base %d: %s",
1901 base, PyString_AS_STRING(strrepr));
1902 Py_DECREF(strrepr);
1903 return NULL;
1906 #ifdef Py_USING_UNICODE
1907 PyObject *
1908 PyLong_FromUnicode(Py_UNICODE *u, Py_ssize_t length, int base)
1910 PyObject *result;
1911 char *buffer = (char *)PyMem_MALLOC(length+1);
1913 if (buffer == NULL)
1914 return NULL;
1916 if (PyUnicode_EncodeDecimal(u, length, buffer, NULL)) {
1917 PyMem_FREE(buffer);
1918 return NULL;
1920 result = PyLong_FromString(buffer, NULL, base);
1921 PyMem_FREE(buffer);
1922 return result;
1924 #endif
1926 /* forward */
1927 static PyLongObject *x_divrem
1928 (PyLongObject *, PyLongObject *, PyLongObject **);
1929 static PyObject *long_long(PyObject *v);
1931 /* Long division with remainder, top-level routine */
1933 static int
1934 long_divrem(PyLongObject *a, PyLongObject *b,
1935 PyLongObject **pdiv, PyLongObject **prem)
1937 Py_ssize_t size_a = ABS(Py_SIZE(a)), size_b = ABS(Py_SIZE(b));
1938 PyLongObject *z;
1940 if (size_b == 0) {
1941 PyErr_SetString(PyExc_ZeroDivisionError,
1942 "long division or modulo by zero");
1943 return -1;
1945 if (size_a < size_b ||
1946 (size_a == size_b &&
1947 a->ob_digit[size_a-1] < b->ob_digit[size_b-1])) {
1948 /* |a| < |b|. */
1949 *pdiv = _PyLong_New(0);
1950 if (*pdiv == NULL)
1951 return -1;
1952 Py_INCREF(a);
1953 *prem = (PyLongObject *) a;
1954 return 0;
1956 if (size_b == 1) {
1957 digit rem = 0;
1958 z = divrem1(a, b->ob_digit[0], &rem);
1959 if (z == NULL)
1960 return -1;
1961 *prem = (PyLongObject *) PyLong_FromLong((long)rem);
1962 if (*prem == NULL) {
1963 Py_DECREF(z);
1964 return -1;
1967 else {
1968 z = x_divrem(a, b, prem);
1969 if (z == NULL)
1970 return -1;
1972 /* Set the signs.
1973 The quotient z has the sign of a*b;
1974 the remainder r has the sign of a,
1975 so a = b*z + r. */
1976 if ((a->ob_size < 0) != (b->ob_size < 0))
1977 z->ob_size = -(z->ob_size);
1978 if (a->ob_size < 0 && (*prem)->ob_size != 0)
1979 (*prem)->ob_size = -((*prem)->ob_size);
1980 *pdiv = z;
1981 return 0;
1984 /* Unsigned long division with remainder -- the algorithm. The arguments v1
1985 and w1 should satisfy 2 <= ABS(Py_SIZE(w1)) <= ABS(Py_SIZE(v1)). */
1987 static PyLongObject *
1988 x_divrem(PyLongObject *v1, PyLongObject *w1, PyLongObject **prem)
1990 PyLongObject *v, *w, *a;
1991 Py_ssize_t i, k, size_v, size_w;
1992 int d;
1993 digit wm1, wm2, carry, q, r, vtop, *v0, *vk, *w0, *ak;
1994 twodigits vv;
1995 sdigit zhi;
1996 stwodigits z;
1998 /* We follow Knuth [The Art of Computer Programming, Vol. 2 (3rd
1999 edn.), section 4.3.1, Algorithm D], except that we don't explicitly
2000 handle the special case when the initial estimate q for a quotient
2001 digit is >= PyLong_BASE: the max value for q is PyLong_BASE+1, and
2002 that won't overflow a digit. */
2004 /* allocate space; w will also be used to hold the final remainder */
2005 size_v = ABS(Py_SIZE(v1));
2006 size_w = ABS(Py_SIZE(w1));
2007 assert(size_v >= size_w && size_w >= 2); /* Assert checks by div() */
2008 v = _PyLong_New(size_v+1);
2009 if (v == NULL) {
2010 *prem = NULL;
2011 return NULL;
2013 w = _PyLong_New(size_w);
2014 if (w == NULL) {
2015 Py_DECREF(v);
2016 *prem = NULL;
2017 return NULL;
2020 /* normalize: shift w1 left so that its top digit is >= PyLong_BASE/2.
2021 shift v1 left by the same amount. Results go into w and v. */
2022 d = PyLong_SHIFT - bits_in_digit(w1->ob_digit[size_w-1]);
2023 carry = v_lshift(w->ob_digit, w1->ob_digit, size_w, d);
2024 assert(carry == 0);
2025 carry = v_lshift(v->ob_digit, v1->ob_digit, size_v, d);
2026 if (carry != 0 || v->ob_digit[size_v-1] >= w->ob_digit[size_w-1]) {
2027 v->ob_digit[size_v] = carry;
2028 size_v++;
2031 /* Now v->ob_digit[size_v-1] < w->ob_digit[size_w-1], so quotient has
2032 at most (and usually exactly) k = size_v - size_w digits. */
2033 k = size_v - size_w;
2034 assert(k >= 0);
2035 a = _PyLong_New(k);
2036 if (a == NULL) {
2037 Py_DECREF(w);
2038 Py_DECREF(v);
2039 *prem = NULL;
2040 return NULL;
2042 v0 = v->ob_digit;
2043 w0 = w->ob_digit;
2044 wm1 = w0[size_w-1];
2045 wm2 = w0[size_w-2];
2046 for (vk = v0+k, ak = a->ob_digit + k; vk-- > v0;) {
2047 /* inner loop: divide vk[0:size_w+1] by w0[0:size_w], giving
2048 single-digit quotient q, remainder in vk[0:size_w]. */
2050 SIGCHECK({
2051 Py_DECREF(a);
2052 Py_DECREF(w);
2053 Py_DECREF(v);
2054 *prem = NULL;
2055 return NULL;
2058 /* estimate quotient digit q; may overestimate by 1 (rare) */
2059 vtop = vk[size_w];
2060 assert(vtop <= wm1);
2061 vv = ((twodigits)vtop << PyLong_SHIFT) | vk[size_w-1];
2062 q = (digit)(vv / wm1);
2063 r = (digit)(vv - (twodigits)wm1 * q); /* r = vv % wm1 */
2064 while ((twodigits)wm2 * q > (((twodigits)r << PyLong_SHIFT)
2065 | vk[size_w-2])) {
2066 --q;
2067 r += wm1;
2068 if (r >= PyLong_BASE)
2069 break;
2071 assert(q <= PyLong_BASE);
2073 /* subtract q*w0[0:size_w] from vk[0:size_w+1] */
2074 zhi = 0;
2075 for (i = 0; i < size_w; ++i) {
2076 /* invariants: -PyLong_BASE <= -q <= zhi <= 0;
2077 -PyLong_BASE * q <= z < PyLong_BASE */
2078 z = (sdigit)vk[i] + zhi -
2079 (stwodigits)q * (stwodigits)w0[i];
2080 vk[i] = (digit)z & PyLong_MASK;
2081 zhi = (sdigit)Py_ARITHMETIC_RIGHT_SHIFT(stwodigits,
2082 z, PyLong_SHIFT);
2085 /* add w back if q was too large (this branch taken rarely) */
2086 assert((sdigit)vtop + zhi == -1 || (sdigit)vtop + zhi == 0);
2087 if ((sdigit)vtop + zhi < 0) {
2088 carry = 0;
2089 for (i = 0; i < size_w; ++i) {
2090 carry += vk[i] + w0[i];
2091 vk[i] = carry & PyLong_MASK;
2092 carry >>= PyLong_SHIFT;
2094 --q;
2097 /* store quotient digit */
2098 assert(q < PyLong_BASE);
2099 *--ak = q;
2102 /* unshift remainder; we reuse w to store the result */
2103 carry = v_rshift(w0, v0, size_w, d);
2104 assert(carry==0);
2105 Py_DECREF(v);
2107 *prem = long_normalize(w);
2108 return long_normalize(a);
2111 /* Methods */
2113 static void
2114 long_dealloc(PyObject *v)
2116 Py_TYPE(v)->tp_free(v);
2119 static PyObject *
2120 long_repr(PyObject *v)
2122 return _PyLong_Format(v, 10, 1, 0);
2125 static PyObject *
2126 long_str(PyObject *v)
2128 return _PyLong_Format(v, 10, 0, 0);
2131 static int
2132 long_compare(PyLongObject *a, PyLongObject *b)
2134 Py_ssize_t sign;
2136 if (Py_SIZE(a) != Py_SIZE(b)) {
2137 if (ABS(Py_SIZE(a)) == 0 && ABS(Py_SIZE(b)) == 0)
2138 sign = 0;
2139 else
2140 sign = Py_SIZE(a) - Py_SIZE(b);
2142 else {
2143 Py_ssize_t i = ABS(Py_SIZE(a));
2144 while (--i >= 0 && a->ob_digit[i] == b->ob_digit[i])
2146 if (i < 0)
2147 sign = 0;
2148 else {
2149 sign = (sdigit)a->ob_digit[i] - (sdigit)b->ob_digit[i];
2150 if (Py_SIZE(a) < 0)
2151 sign = -sign;
2154 return sign < 0 ? -1 : sign > 0 ? 1 : 0;
2157 static long
2158 long_hash(PyLongObject *v)
2160 unsigned long x;
2161 Py_ssize_t i;
2162 int sign;
2164 /* This is designed so that Python ints and longs with the
2165 same value hash to the same value, otherwise comparisons
2166 of mapping keys will turn out weird */
2167 i = v->ob_size;
2168 sign = 1;
2169 x = 0;
2170 if (i < 0) {
2171 sign = -1;
2172 i = -(i);
2174 /* The following loop produces a C unsigned long x such that x is
2175 congruent to the absolute value of v modulo ULONG_MAX. The
2176 resulting x is nonzero if and only if v is. */
2177 while (--i >= 0) {
2178 /* Force a native long #-bits (32 or 64) circular shift */
2179 x = (x >> (8*SIZEOF_LONG-PyLong_SHIFT)) | (x << PyLong_SHIFT);
2180 x += v->ob_digit[i];
2181 /* If the addition above overflowed we compensate by
2182 incrementing. This preserves the value modulo
2183 ULONG_MAX. */
2184 if (x < v->ob_digit[i])
2185 x++;
2187 x = x * sign;
2188 if (x == (unsigned long)-1)
2189 x = (unsigned long)-2;
2190 return (long)x;
2194 /* Add the absolute values of two long integers. */
2196 static PyLongObject *
2197 x_add(PyLongObject *a, PyLongObject *b)
2199 Py_ssize_t size_a = ABS(Py_SIZE(a)), size_b = ABS(Py_SIZE(b));
2200 PyLongObject *z;
2201 Py_ssize_t i;
2202 digit carry = 0;
2204 /* Ensure a is the larger of the two: */
2205 if (size_a < size_b) {
2206 { PyLongObject *temp = a; a = b; b = temp; }
2207 { Py_ssize_t size_temp = size_a;
2208 size_a = size_b;
2209 size_b = size_temp; }
2211 z = _PyLong_New(size_a+1);
2212 if (z == NULL)
2213 return NULL;
2214 for (i = 0; i < size_b; ++i) {
2215 carry += a->ob_digit[i] + b->ob_digit[i];
2216 z->ob_digit[i] = carry & PyLong_MASK;
2217 carry >>= PyLong_SHIFT;
2219 for (; i < size_a; ++i) {
2220 carry += a->ob_digit[i];
2221 z->ob_digit[i] = carry & PyLong_MASK;
2222 carry >>= PyLong_SHIFT;
2224 z->ob_digit[i] = carry;
2225 return long_normalize(z);
2228 /* Subtract the absolute values of two integers. */
2230 static PyLongObject *
2231 x_sub(PyLongObject *a, PyLongObject *b)
2233 Py_ssize_t size_a = ABS(Py_SIZE(a)), size_b = ABS(Py_SIZE(b));
2234 PyLongObject *z;
2235 Py_ssize_t i;
2236 int sign = 1;
2237 digit borrow = 0;
2239 /* Ensure a is the larger of the two: */
2240 if (size_a < size_b) {
2241 sign = -1;
2242 { PyLongObject *temp = a; a = b; b = temp; }
2243 { Py_ssize_t size_temp = size_a;
2244 size_a = size_b;
2245 size_b = size_temp; }
2247 else if (size_a == size_b) {
2248 /* Find highest digit where a and b differ: */
2249 i = size_a;
2250 while (--i >= 0 && a->ob_digit[i] == b->ob_digit[i])
2252 if (i < 0)
2253 return _PyLong_New(0);
2254 if (a->ob_digit[i] < b->ob_digit[i]) {
2255 sign = -1;
2256 { PyLongObject *temp = a; a = b; b = temp; }
2258 size_a = size_b = i+1;
2260 z = _PyLong_New(size_a);
2261 if (z == NULL)
2262 return NULL;
2263 for (i = 0; i < size_b; ++i) {
2264 /* The following assumes unsigned arithmetic
2265 works module 2**N for some N>PyLong_SHIFT. */
2266 borrow = a->ob_digit[i] - b->ob_digit[i] - borrow;
2267 z->ob_digit[i] = borrow & PyLong_MASK;
2268 borrow >>= PyLong_SHIFT;
2269 borrow &= 1; /* Keep only one sign bit */
2271 for (; i < size_a; ++i) {
2272 borrow = a->ob_digit[i] - borrow;
2273 z->ob_digit[i] = borrow & PyLong_MASK;
2274 borrow >>= PyLong_SHIFT;
2275 borrow &= 1; /* Keep only one sign bit */
2277 assert(borrow == 0);
2278 if (sign < 0)
2279 z->ob_size = -(z->ob_size);
2280 return long_normalize(z);
2283 static PyObject *
2284 long_add(PyLongObject *v, PyLongObject *w)
2286 PyLongObject *a, *b, *z;
2288 CONVERT_BINOP((PyObject *)v, (PyObject *)w, &a, &b);
2290 if (a->ob_size < 0) {
2291 if (b->ob_size < 0) {
2292 z = x_add(a, b);
2293 if (z != NULL && z->ob_size != 0)
2294 z->ob_size = -(z->ob_size);
2296 else
2297 z = x_sub(b, a);
2299 else {
2300 if (b->ob_size < 0)
2301 z = x_sub(a, b);
2302 else
2303 z = x_add(a, b);
2305 Py_DECREF(a);
2306 Py_DECREF(b);
2307 return (PyObject *)z;
2310 static PyObject *
2311 long_sub(PyLongObject *v, PyLongObject *w)
2313 PyLongObject *a, *b, *z;
2315 CONVERT_BINOP((PyObject *)v, (PyObject *)w, &a, &b);
2317 if (a->ob_size < 0) {
2318 if (b->ob_size < 0)
2319 z = x_sub(a, b);
2320 else
2321 z = x_add(a, b);
2322 if (z != NULL && z->ob_size != 0)
2323 z->ob_size = -(z->ob_size);
2325 else {
2326 if (b->ob_size < 0)
2327 z = x_add(a, b);
2328 else
2329 z = x_sub(a, b);
2331 Py_DECREF(a);
2332 Py_DECREF(b);
2333 return (PyObject *)z;
2336 /* Grade school multiplication, ignoring the signs.
2337 * Returns the absolute value of the product, or NULL if error.
2339 static PyLongObject *
2340 x_mul(PyLongObject *a, PyLongObject *b)
2342 PyLongObject *z;
2343 Py_ssize_t size_a = ABS(Py_SIZE(a));
2344 Py_ssize_t size_b = ABS(Py_SIZE(b));
2345 Py_ssize_t i;
2347 z = _PyLong_New(size_a + size_b);
2348 if (z == NULL)
2349 return NULL;
2351 memset(z->ob_digit, 0, Py_SIZE(z) * sizeof(digit));
2352 if (a == b) {
2353 /* Efficient squaring per HAC, Algorithm 14.16:
2354 * http://www.cacr.math.uwaterloo.ca/hac/about/chap14.pdf
2355 * Gives slightly less than a 2x speedup when a == b,
2356 * via exploiting that each entry in the multiplication
2357 * pyramid appears twice (except for the size_a squares).
2359 for (i = 0; i < size_a; ++i) {
2360 twodigits carry;
2361 twodigits f = a->ob_digit[i];
2362 digit *pz = z->ob_digit + (i << 1);
2363 digit *pa = a->ob_digit + i + 1;
2364 digit *paend = a->ob_digit + size_a;
2366 SIGCHECK({
2367 Py_DECREF(z);
2368 return NULL;
2371 carry = *pz + f * f;
2372 *pz++ = (digit)(carry & PyLong_MASK);
2373 carry >>= PyLong_SHIFT;
2374 assert(carry <= PyLong_MASK);
2376 /* Now f is added in twice in each column of the
2377 * pyramid it appears. Same as adding f<<1 once.
2379 f <<= 1;
2380 while (pa < paend) {
2381 carry += *pz + *pa++ * f;
2382 *pz++ = (digit)(carry & PyLong_MASK);
2383 carry >>= PyLong_SHIFT;
2384 assert(carry <= (PyLong_MASK << 1));
2386 if (carry) {
2387 carry += *pz;
2388 *pz++ = (digit)(carry & PyLong_MASK);
2389 carry >>= PyLong_SHIFT;
2391 if (carry)
2392 *pz += (digit)(carry & PyLong_MASK);
2393 assert((carry >> PyLong_SHIFT) == 0);
2396 else { /* a is not the same as b -- gradeschool long mult */
2397 for (i = 0; i < size_a; ++i) {
2398 twodigits carry = 0;
2399 twodigits f = a->ob_digit[i];
2400 digit *pz = z->ob_digit + i;
2401 digit *pb = b->ob_digit;
2402 digit *pbend = b->ob_digit + size_b;
2404 SIGCHECK({
2405 Py_DECREF(z);
2406 return NULL;
2409 while (pb < pbend) {
2410 carry += *pz + *pb++ * f;
2411 *pz++ = (digit)(carry & PyLong_MASK);
2412 carry >>= PyLong_SHIFT;
2413 assert(carry <= PyLong_MASK);
2415 if (carry)
2416 *pz += (digit)(carry & PyLong_MASK);
2417 assert((carry >> PyLong_SHIFT) == 0);
2420 return long_normalize(z);
2423 /* A helper for Karatsuba multiplication (k_mul).
2424 Takes a long "n" and an integer "size" representing the place to
2425 split, and sets low and high such that abs(n) == (high << size) + low,
2426 viewing the shift as being by digits. The sign bit is ignored, and
2427 the return values are >= 0.
2428 Returns 0 on success, -1 on failure.
2430 static int
2431 kmul_split(PyLongObject *n, Py_ssize_t size, PyLongObject **high, PyLongObject **low)
2433 PyLongObject *hi, *lo;
2434 Py_ssize_t size_lo, size_hi;
2435 const Py_ssize_t size_n = ABS(Py_SIZE(n));
2437 size_lo = MIN(size_n, size);
2438 size_hi = size_n - size_lo;
2440 if ((hi = _PyLong_New(size_hi)) == NULL)
2441 return -1;
2442 if ((lo = _PyLong_New(size_lo)) == NULL) {
2443 Py_DECREF(hi);
2444 return -1;
2447 memcpy(lo->ob_digit, n->ob_digit, size_lo * sizeof(digit));
2448 memcpy(hi->ob_digit, n->ob_digit + size_lo, size_hi * sizeof(digit));
2450 *high = long_normalize(hi);
2451 *low = long_normalize(lo);
2452 return 0;
2455 static PyLongObject *k_lopsided_mul(PyLongObject *a, PyLongObject *b);
2457 /* Karatsuba multiplication. Ignores the input signs, and returns the
2458 * absolute value of the product (or NULL if error).
2459 * See Knuth Vol. 2 Chapter 4.3.3 (Pp. 294-295).
2461 static PyLongObject *
2462 k_mul(PyLongObject *a, PyLongObject *b)
2464 Py_ssize_t asize = ABS(Py_SIZE(a));
2465 Py_ssize_t bsize = ABS(Py_SIZE(b));
2466 PyLongObject *ah = NULL;
2467 PyLongObject *al = NULL;
2468 PyLongObject *bh = NULL;
2469 PyLongObject *bl = NULL;
2470 PyLongObject *ret = NULL;
2471 PyLongObject *t1, *t2, *t3;
2472 Py_ssize_t shift; /* the number of digits we split off */
2473 Py_ssize_t i;
2475 /* (ah*X+al)(bh*X+bl) = ah*bh*X*X + (ah*bl + al*bh)*X + al*bl
2476 * Let k = (ah+al)*(bh+bl) = ah*bl + al*bh + ah*bh + al*bl
2477 * Then the original product is
2478 * ah*bh*X*X + (k - ah*bh - al*bl)*X + al*bl
2479 * By picking X to be a power of 2, "*X" is just shifting, and it's
2480 * been reduced to 3 multiplies on numbers half the size.
2483 /* We want to split based on the larger number; fiddle so that b
2484 * is largest.
2486 if (asize > bsize) {
2487 t1 = a;
2488 a = b;
2489 b = t1;
2491 i = asize;
2492 asize = bsize;
2493 bsize = i;
2496 /* Use gradeschool math when either number is too small. */
2497 i = a == b ? KARATSUBA_SQUARE_CUTOFF : KARATSUBA_CUTOFF;
2498 if (asize <= i) {
2499 if (asize == 0)
2500 return _PyLong_New(0);
2501 else
2502 return x_mul(a, b);
2505 /* If a is small compared to b, splitting on b gives a degenerate
2506 * case with ah==0, and Karatsuba may be (even much) less efficient
2507 * than "grade school" then. However, we can still win, by viewing
2508 * b as a string of "big digits", each of width a->ob_size. That
2509 * leads to a sequence of balanced calls to k_mul.
2511 if (2 * asize <= bsize)
2512 return k_lopsided_mul(a, b);
2514 /* Split a & b into hi & lo pieces. */
2515 shift = bsize >> 1;
2516 if (kmul_split(a, shift, &ah, &al) < 0) goto fail;
2517 assert(Py_SIZE(ah) > 0); /* the split isn't degenerate */
2519 if (a == b) {
2520 bh = ah;
2521 bl = al;
2522 Py_INCREF(bh);
2523 Py_INCREF(bl);
2525 else if (kmul_split(b, shift, &bh, &bl) < 0) goto fail;
2527 /* The plan:
2528 * 1. Allocate result space (asize + bsize digits: that's always
2529 * enough).
2530 * 2. Compute ah*bh, and copy into result at 2*shift.
2531 * 3. Compute al*bl, and copy into result at 0. Note that this
2532 * can't overlap with #2.
2533 * 4. Subtract al*bl from the result, starting at shift. This may
2534 * underflow (borrow out of the high digit), but we don't care:
2535 * we're effectively doing unsigned arithmetic mod
2536 * PyLong_BASE**(sizea + sizeb), and so long as the *final* result fits,
2537 * borrows and carries out of the high digit can be ignored.
2538 * 5. Subtract ah*bh from the result, starting at shift.
2539 * 6. Compute (ah+al)*(bh+bl), and add it into the result starting
2540 * at shift.
2543 /* 1. Allocate result space. */
2544 ret = _PyLong_New(asize + bsize);
2545 if (ret == NULL) goto fail;
2546 #ifdef Py_DEBUG
2547 /* Fill with trash, to catch reference to uninitialized digits. */
2548 memset(ret->ob_digit, 0xDF, Py_SIZE(ret) * sizeof(digit));
2549 #endif
2551 /* 2. t1 <- ah*bh, and copy into high digits of result. */
2552 if ((t1 = k_mul(ah, bh)) == NULL) goto fail;
2553 assert(Py_SIZE(t1) >= 0);
2554 assert(2*shift + Py_SIZE(t1) <= Py_SIZE(ret));
2555 memcpy(ret->ob_digit + 2*shift, t1->ob_digit,
2556 Py_SIZE(t1) * sizeof(digit));
2558 /* Zero-out the digits higher than the ah*bh copy. */
2559 i = Py_SIZE(ret) - 2*shift - Py_SIZE(t1);
2560 if (i)
2561 memset(ret->ob_digit + 2*shift + Py_SIZE(t1), 0,
2562 i * sizeof(digit));
2564 /* 3. t2 <- al*bl, and copy into the low digits. */
2565 if ((t2 = k_mul(al, bl)) == NULL) {
2566 Py_DECREF(t1);
2567 goto fail;
2569 assert(Py_SIZE(t2) >= 0);
2570 assert(Py_SIZE(t2) <= 2*shift); /* no overlap with high digits */
2571 memcpy(ret->ob_digit, t2->ob_digit, Py_SIZE(t2) * sizeof(digit));
2573 /* Zero out remaining digits. */
2574 i = 2*shift - Py_SIZE(t2); /* number of uninitialized digits */
2575 if (i)
2576 memset(ret->ob_digit + Py_SIZE(t2), 0, i * sizeof(digit));
2578 /* 4 & 5. Subtract ah*bh (t1) and al*bl (t2). We do al*bl first
2579 * because it's fresher in cache.
2581 i = Py_SIZE(ret) - shift; /* # digits after shift */
2582 (void)v_isub(ret->ob_digit + shift, i, t2->ob_digit, Py_SIZE(t2));
2583 Py_DECREF(t2);
2585 (void)v_isub(ret->ob_digit + shift, i, t1->ob_digit, Py_SIZE(t1));
2586 Py_DECREF(t1);
2588 /* 6. t3 <- (ah+al)(bh+bl), and add into result. */
2589 if ((t1 = x_add(ah, al)) == NULL) goto fail;
2590 Py_DECREF(ah);
2591 Py_DECREF(al);
2592 ah = al = NULL;
2594 if (a == b) {
2595 t2 = t1;
2596 Py_INCREF(t2);
2598 else if ((t2 = x_add(bh, bl)) == NULL) {
2599 Py_DECREF(t1);
2600 goto fail;
2602 Py_DECREF(bh);
2603 Py_DECREF(bl);
2604 bh = bl = NULL;
2606 t3 = k_mul(t1, t2);
2607 Py_DECREF(t1);
2608 Py_DECREF(t2);
2609 if (t3 == NULL) goto fail;
2610 assert(Py_SIZE(t3) >= 0);
2612 /* Add t3. It's not obvious why we can't run out of room here.
2613 * See the (*) comment after this function.
2615 (void)v_iadd(ret->ob_digit + shift, i, t3->ob_digit, Py_SIZE(t3));
2616 Py_DECREF(t3);
2618 return long_normalize(ret);
2620 fail:
2621 Py_XDECREF(ret);
2622 Py_XDECREF(ah);
2623 Py_XDECREF(al);
2624 Py_XDECREF(bh);
2625 Py_XDECREF(bl);
2626 return NULL;
2629 /* (*) Why adding t3 can't "run out of room" above.
2631 Let f(x) mean the floor of x and c(x) mean the ceiling of x. Some facts
2632 to start with:
2634 1. For any integer i, i = c(i/2) + f(i/2). In particular,
2635 bsize = c(bsize/2) + f(bsize/2).
2636 2. shift = f(bsize/2)
2637 3. asize <= bsize
2638 4. Since we call k_lopsided_mul if asize*2 <= bsize, asize*2 > bsize in this
2639 routine, so asize > bsize/2 >= f(bsize/2) in this routine.
2641 We allocated asize + bsize result digits, and add t3 into them at an offset
2642 of shift. This leaves asize+bsize-shift allocated digit positions for t3
2643 to fit into, = (by #1 and #2) asize + f(bsize/2) + c(bsize/2) - f(bsize/2) =
2644 asize + c(bsize/2) available digit positions.
2646 bh has c(bsize/2) digits, and bl at most f(size/2) digits. So bh+hl has
2647 at most c(bsize/2) digits + 1 bit.
2649 If asize == bsize, ah has c(bsize/2) digits, else ah has at most f(bsize/2)
2650 digits, and al has at most f(bsize/2) digits in any case. So ah+al has at
2651 most (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 1 bit.
2653 The product (ah+al)*(bh+bl) therefore has at most
2655 c(bsize/2) + (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 2 bits
2657 and we have asize + c(bsize/2) available digit positions. We need to show
2658 this is always enough. An instance of c(bsize/2) cancels out in both, so
2659 the question reduces to whether asize digits is enough to hold
2660 (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 2 bits. If asize < bsize,
2661 then we're asking whether asize digits >= f(bsize/2) digits + 2 bits. By #4,
2662 asize is at least f(bsize/2)+1 digits, so this in turn reduces to whether 1
2663 digit is enough to hold 2 bits. This is so since PyLong_SHIFT=15 >= 2. If
2664 asize == bsize, then we're asking whether bsize digits is enough to hold
2665 c(bsize/2) digits + 2 bits, or equivalently (by #1) whether f(bsize/2) digits
2666 is enough to hold 2 bits. This is so if bsize >= 2, which holds because
2667 bsize >= KARATSUBA_CUTOFF >= 2.
2669 Note that since there's always enough room for (ah+al)*(bh+bl), and that's
2670 clearly >= each of ah*bh and al*bl, there's always enough room to subtract
2671 ah*bh and al*bl too.
2674 /* b has at least twice the digits of a, and a is big enough that Karatsuba
2675 * would pay off *if* the inputs had balanced sizes. View b as a sequence
2676 * of slices, each with a->ob_size digits, and multiply the slices by a,
2677 * one at a time. This gives k_mul balanced inputs to work with, and is
2678 * also cache-friendly (we compute one double-width slice of the result
2679 * at a time, then move on, never bactracking except for the helpful
2680 * single-width slice overlap between successive partial sums).
2682 static PyLongObject *
2683 k_lopsided_mul(PyLongObject *a, PyLongObject *b)
2685 const Py_ssize_t asize = ABS(Py_SIZE(a));
2686 Py_ssize_t bsize = ABS(Py_SIZE(b));
2687 Py_ssize_t nbdone; /* # of b digits already multiplied */
2688 PyLongObject *ret;
2689 PyLongObject *bslice = NULL;
2691 assert(asize > KARATSUBA_CUTOFF);
2692 assert(2 * asize <= bsize);
2694 /* Allocate result space, and zero it out. */
2695 ret = _PyLong_New(asize + bsize);
2696 if (ret == NULL)
2697 return NULL;
2698 memset(ret->ob_digit, 0, Py_SIZE(ret) * sizeof(digit));
2700 /* Successive slices of b are copied into bslice. */
2701 bslice = _PyLong_New(asize);
2702 if (bslice == NULL)
2703 goto fail;
2705 nbdone = 0;
2706 while (bsize > 0) {
2707 PyLongObject *product;
2708 const Py_ssize_t nbtouse = MIN(bsize, asize);
2710 /* Multiply the next slice of b by a. */
2711 memcpy(bslice->ob_digit, b->ob_digit + nbdone,
2712 nbtouse * sizeof(digit));
2713 Py_SIZE(bslice) = nbtouse;
2714 product = k_mul(a, bslice);
2715 if (product == NULL)
2716 goto fail;
2718 /* Add into result. */
2719 (void)v_iadd(ret->ob_digit + nbdone, Py_SIZE(ret) - nbdone,
2720 product->ob_digit, Py_SIZE(product));
2721 Py_DECREF(product);
2723 bsize -= nbtouse;
2724 nbdone += nbtouse;
2727 Py_DECREF(bslice);
2728 return long_normalize(ret);
2730 fail:
2731 Py_DECREF(ret);
2732 Py_XDECREF(bslice);
2733 return NULL;
2736 static PyObject *
2737 long_mul(PyLongObject *v, PyLongObject *w)
2739 PyLongObject *a, *b, *z;
2741 if (!convert_binop((PyObject *)v, (PyObject *)w, &a, &b)) {
2742 Py_INCREF(Py_NotImplemented);
2743 return Py_NotImplemented;
2746 z = k_mul(a, b);
2747 /* Negate if exactly one of the inputs is negative. */
2748 if (((a->ob_size ^ b->ob_size) < 0) && z)
2749 z->ob_size = -(z->ob_size);
2750 Py_DECREF(a);
2751 Py_DECREF(b);
2752 return (PyObject *)z;
2755 /* The / and % operators are now defined in terms of divmod().
2756 The expression a mod b has the value a - b*floor(a/b).
2757 The long_divrem function gives the remainder after division of
2758 |a| by |b|, with the sign of a. This is also expressed
2759 as a - b*trunc(a/b), if trunc truncates towards zero.
2760 Some examples:
2761 a b a rem b a mod b
2762 13 10 3 3
2763 -13 10 -3 7
2764 13 -10 3 -7
2765 -13 -10 -3 -3
2766 So, to get from rem to mod, we have to add b if a and b
2767 have different signs. We then subtract one from the 'div'
2768 part of the outcome to keep the invariant intact. */
2770 /* Compute
2771 * *pdiv, *pmod = divmod(v, w)
2772 * NULL can be passed for pdiv or pmod, in which case that part of
2773 * the result is simply thrown away. The caller owns a reference to
2774 * each of these it requests (does not pass NULL for).
2776 static int
2777 l_divmod(PyLongObject *v, PyLongObject *w,
2778 PyLongObject **pdiv, PyLongObject **pmod)
2780 PyLongObject *div, *mod;
2782 if (long_divrem(v, w, &div, &mod) < 0)
2783 return -1;
2784 if ((Py_SIZE(mod) < 0 && Py_SIZE(w) > 0) ||
2785 (Py_SIZE(mod) > 0 && Py_SIZE(w) < 0)) {
2786 PyLongObject *temp;
2787 PyLongObject *one;
2788 temp = (PyLongObject *) long_add(mod, w);
2789 Py_DECREF(mod);
2790 mod = temp;
2791 if (mod == NULL) {
2792 Py_DECREF(div);
2793 return -1;
2795 one = (PyLongObject *) PyLong_FromLong(1L);
2796 if (one == NULL ||
2797 (temp = (PyLongObject *) long_sub(div, one)) == NULL) {
2798 Py_DECREF(mod);
2799 Py_DECREF(div);
2800 Py_XDECREF(one);
2801 return -1;
2803 Py_DECREF(one);
2804 Py_DECREF(div);
2805 div = temp;
2807 if (pdiv != NULL)
2808 *pdiv = div;
2809 else
2810 Py_DECREF(div);
2812 if (pmod != NULL)
2813 *pmod = mod;
2814 else
2815 Py_DECREF(mod);
2817 return 0;
2820 static PyObject *
2821 long_div(PyObject *v, PyObject *w)
2823 PyLongObject *a, *b, *div;
2825 CONVERT_BINOP(v, w, &a, &b);
2826 if (l_divmod(a, b, &div, NULL) < 0)
2827 div = NULL;
2828 Py_DECREF(a);
2829 Py_DECREF(b);
2830 return (PyObject *)div;
2833 static PyObject *
2834 long_classic_div(PyObject *v, PyObject *w)
2836 PyLongObject *a, *b, *div;
2838 CONVERT_BINOP(v, w, &a, &b);
2839 if (Py_DivisionWarningFlag &&
2840 PyErr_Warn(PyExc_DeprecationWarning, "classic long division") < 0)
2841 div = NULL;
2842 else if (l_divmod(a, b, &div, NULL) < 0)
2843 div = NULL;
2844 Py_DECREF(a);
2845 Py_DECREF(b);
2846 return (PyObject *)div;
2849 static PyObject *
2850 long_true_divide(PyObject *v, PyObject *w)
2852 PyLongObject *a, *b;
2853 double ad, bd;
2854 int failed, aexp = -1, bexp = -1;
2856 CONVERT_BINOP(v, w, &a, &b);
2857 ad = _PyLong_AsScaledDouble((PyObject *)a, &aexp);
2858 bd = _PyLong_AsScaledDouble((PyObject *)b, &bexp);
2859 failed = (ad == -1.0 || bd == -1.0) && PyErr_Occurred();
2860 Py_DECREF(a);
2861 Py_DECREF(b);
2862 if (failed)
2863 return NULL;
2864 /* 'aexp' and 'bexp' were initialized to -1 to silence gcc-4.0.x,
2865 but should really be set correctly after sucessful calls to
2866 _PyLong_AsScaledDouble() */
2867 assert(aexp >= 0 && bexp >= 0);
2869 if (bd == 0.0) {
2870 PyErr_SetString(PyExc_ZeroDivisionError,
2871 "long division or modulo by zero");
2872 return NULL;
2875 /* True value is very close to ad/bd * 2**(PyLong_SHIFT*(aexp-bexp)) */
2876 ad /= bd; /* overflow/underflow impossible here */
2877 aexp -= bexp;
2878 if (aexp > INT_MAX / PyLong_SHIFT)
2879 goto overflow;
2880 else if (aexp < -(INT_MAX / PyLong_SHIFT))
2881 return PyFloat_FromDouble(0.0); /* underflow to 0 */
2882 errno = 0;
2883 ad = ldexp(ad, aexp * PyLong_SHIFT);
2884 if (Py_OVERFLOWED(ad)) /* ignore underflow to 0.0 */
2885 goto overflow;
2886 return PyFloat_FromDouble(ad);
2888 overflow:
2889 PyErr_SetString(PyExc_OverflowError,
2890 "long/long too large for a float");
2891 return NULL;
2895 static PyObject *
2896 long_mod(PyObject *v, PyObject *w)
2898 PyLongObject *a, *b, *mod;
2900 CONVERT_BINOP(v, w, &a, &b);
2902 if (l_divmod(a, b, NULL, &mod) < 0)
2903 mod = NULL;
2904 Py_DECREF(a);
2905 Py_DECREF(b);
2906 return (PyObject *)mod;
2909 static PyObject *
2910 long_divmod(PyObject *v, PyObject *w)
2912 PyLongObject *a, *b, *div, *mod;
2913 PyObject *z;
2915 CONVERT_BINOP(v, w, &a, &b);
2917 if (l_divmod(a, b, &div, &mod) < 0) {
2918 Py_DECREF(a);
2919 Py_DECREF(b);
2920 return NULL;
2922 z = PyTuple_New(2);
2923 if (z != NULL) {
2924 PyTuple_SetItem(z, 0, (PyObject *) div);
2925 PyTuple_SetItem(z, 1, (PyObject *) mod);
2927 else {
2928 Py_DECREF(div);
2929 Py_DECREF(mod);
2931 Py_DECREF(a);
2932 Py_DECREF(b);
2933 return z;
2936 /* pow(v, w, x) */
2937 static PyObject *
2938 long_pow(PyObject *v, PyObject *w, PyObject *x)
2940 PyLongObject *a, *b, *c; /* a,b,c = v,w,x */
2941 int negativeOutput = 0; /* if x<0 return negative output */
2943 PyLongObject *z = NULL; /* accumulated result */
2944 Py_ssize_t i, j, k; /* counters */
2945 PyLongObject *temp = NULL;
2947 /* 5-ary values. If the exponent is large enough, table is
2948 * precomputed so that table[i] == a**i % c for i in range(32).
2950 PyLongObject *table[32] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
2951 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
2953 /* a, b, c = v, w, x */
2954 CONVERT_BINOP(v, w, &a, &b);
2955 if (PyLong_Check(x)) {
2956 c = (PyLongObject *)x;
2957 Py_INCREF(x);
2959 else if (PyInt_Check(x)) {
2960 c = (PyLongObject *)PyLong_FromLong(PyInt_AS_LONG(x));
2961 if (c == NULL)
2962 goto Error;
2964 else if (x == Py_None)
2965 c = NULL;
2966 else {
2967 Py_DECREF(a);
2968 Py_DECREF(b);
2969 Py_INCREF(Py_NotImplemented);
2970 return Py_NotImplemented;
2973 if (Py_SIZE(b) < 0) { /* if exponent is negative */
2974 if (c) {
2975 PyErr_SetString(PyExc_TypeError, "pow() 2nd argument "
2976 "cannot be negative when 3rd argument specified");
2977 goto Error;
2979 else {
2980 /* else return a float. This works because we know
2981 that this calls float_pow() which converts its
2982 arguments to double. */
2983 Py_DECREF(a);
2984 Py_DECREF(b);
2985 return PyFloat_Type.tp_as_number->nb_power(v, w, x);
2989 if (c) {
2990 /* if modulus == 0:
2991 raise ValueError() */
2992 if (Py_SIZE(c) == 0) {
2993 PyErr_SetString(PyExc_ValueError,
2994 "pow() 3rd argument cannot be 0");
2995 goto Error;
2998 /* if modulus < 0:
2999 negativeOutput = True
3000 modulus = -modulus */
3001 if (Py_SIZE(c) < 0) {
3002 negativeOutput = 1;
3003 temp = (PyLongObject *)_PyLong_Copy(c);
3004 if (temp == NULL)
3005 goto Error;
3006 Py_DECREF(c);
3007 c = temp;
3008 temp = NULL;
3009 c->ob_size = - c->ob_size;
3012 /* if modulus == 1:
3013 return 0 */
3014 if ((Py_SIZE(c) == 1) && (c->ob_digit[0] == 1)) {
3015 z = (PyLongObject *)PyLong_FromLong(0L);
3016 goto Done;
3019 /* if base < 0:
3020 base = base % modulus
3021 Having the base positive just makes things easier. */
3022 if (Py_SIZE(a) < 0) {
3023 if (l_divmod(a, c, NULL, &temp) < 0)
3024 goto Error;
3025 Py_DECREF(a);
3026 a = temp;
3027 temp = NULL;
3031 /* At this point a, b, and c are guaranteed non-negative UNLESS
3032 c is NULL, in which case a may be negative. */
3034 z = (PyLongObject *)PyLong_FromLong(1L);
3035 if (z == NULL)
3036 goto Error;
3038 /* Perform a modular reduction, X = X % c, but leave X alone if c
3039 * is NULL.
3041 #define REDUCE(X) \
3042 if (c != NULL) { \
3043 if (l_divmod(X, c, NULL, &temp) < 0) \
3044 goto Error; \
3045 Py_XDECREF(X); \
3046 X = temp; \
3047 temp = NULL; \
3050 /* Multiply two values, then reduce the result:
3051 result = X*Y % c. If c is NULL, skip the mod. */
3052 #define MULT(X, Y, result) \
3054 temp = (PyLongObject *)long_mul(X, Y); \
3055 if (temp == NULL) \
3056 goto Error; \
3057 Py_XDECREF(result); \
3058 result = temp; \
3059 temp = NULL; \
3060 REDUCE(result) \
3063 if (Py_SIZE(b) <= FIVEARY_CUTOFF) {
3064 /* Left-to-right binary exponentiation (HAC Algorithm 14.79) */
3065 /* http://www.cacr.math.uwaterloo.ca/hac/about/chap14.pdf */
3066 for (i = Py_SIZE(b) - 1; i >= 0; --i) {
3067 digit bi = b->ob_digit[i];
3069 for (j = (digit)1 << (PyLong_SHIFT-1); j != 0; j >>= 1) {
3070 MULT(z, z, z)
3071 if (bi & j)
3072 MULT(z, a, z)
3076 else {
3077 /* Left-to-right 5-ary exponentiation (HAC Algorithm 14.82) */
3078 Py_INCREF(z); /* still holds 1L */
3079 table[0] = z;
3080 for (i = 1; i < 32; ++i)
3081 MULT(table[i-1], a, table[i])
3083 for (i = Py_SIZE(b) - 1; i >= 0; --i) {
3084 const digit bi = b->ob_digit[i];
3086 for (j = PyLong_SHIFT - 5; j >= 0; j -= 5) {
3087 const int index = (bi >> j) & 0x1f;
3088 for (k = 0; k < 5; ++k)
3089 MULT(z, z, z)
3090 if (index)
3091 MULT(z, table[index], z)
3096 if (negativeOutput && (Py_SIZE(z) != 0)) {
3097 temp = (PyLongObject *)long_sub(z, c);
3098 if (temp == NULL)
3099 goto Error;
3100 Py_DECREF(z);
3101 z = temp;
3102 temp = NULL;
3104 goto Done;
3106 Error:
3107 if (z != NULL) {
3108 Py_DECREF(z);
3109 z = NULL;
3111 /* fall through */
3112 Done:
3113 if (Py_SIZE(b) > FIVEARY_CUTOFF) {
3114 for (i = 0; i < 32; ++i)
3115 Py_XDECREF(table[i]);
3117 Py_DECREF(a);
3118 Py_DECREF(b);
3119 Py_XDECREF(c);
3120 Py_XDECREF(temp);
3121 return (PyObject *)z;
3124 static PyObject *
3125 long_invert(PyLongObject *v)
3127 /* Implement ~x as -(x+1) */
3128 PyLongObject *x;
3129 PyLongObject *w;
3130 w = (PyLongObject *)PyLong_FromLong(1L);
3131 if (w == NULL)
3132 return NULL;
3133 x = (PyLongObject *) long_add(v, w);
3134 Py_DECREF(w);
3135 if (x == NULL)
3136 return NULL;
3137 Py_SIZE(x) = -(Py_SIZE(x));
3138 return (PyObject *)x;
3141 static PyObject *
3142 long_neg(PyLongObject *v)
3144 PyLongObject *z;
3145 if (v->ob_size == 0 && PyLong_CheckExact(v)) {
3146 /* -0 == 0 */
3147 Py_INCREF(v);
3148 return (PyObject *) v;
3150 z = (PyLongObject *)_PyLong_Copy(v);
3151 if (z != NULL)
3152 z->ob_size = -(v->ob_size);
3153 return (PyObject *)z;
3156 static PyObject *
3157 long_abs(PyLongObject *v)
3159 if (v->ob_size < 0)
3160 return long_neg(v);
3161 else
3162 return long_long((PyObject *)v);
3165 static int
3166 long_nonzero(PyLongObject *v)
3168 return ABS(Py_SIZE(v)) != 0;
3171 static PyObject *
3172 long_rshift(PyLongObject *v, PyLongObject *w)
3174 PyLongObject *a, *b;
3175 PyLongObject *z = NULL;
3176 long shiftby;
3177 Py_ssize_t newsize, wordshift, loshift, hishift, i, j;
3178 digit lomask, himask;
3180 CONVERT_BINOP((PyObject *)v, (PyObject *)w, &a, &b);
3182 if (Py_SIZE(a) < 0) {
3183 /* Right shifting negative numbers is harder */
3184 PyLongObject *a1, *a2;
3185 a1 = (PyLongObject *) long_invert(a);
3186 if (a1 == NULL)
3187 goto rshift_error;
3188 a2 = (PyLongObject *) long_rshift(a1, b);
3189 Py_DECREF(a1);
3190 if (a2 == NULL)
3191 goto rshift_error;
3192 z = (PyLongObject *) long_invert(a2);
3193 Py_DECREF(a2);
3195 else {
3197 shiftby = PyLong_AsLong((PyObject *)b);
3198 if (shiftby == -1L && PyErr_Occurred())
3199 goto rshift_error;
3200 if (shiftby < 0) {
3201 PyErr_SetString(PyExc_ValueError,
3202 "negative shift count");
3203 goto rshift_error;
3205 wordshift = shiftby / PyLong_SHIFT;
3206 newsize = ABS(Py_SIZE(a)) - wordshift;
3207 if (newsize <= 0) {
3208 z = _PyLong_New(0);
3209 Py_DECREF(a);
3210 Py_DECREF(b);
3211 return (PyObject *)z;
3213 loshift = shiftby % PyLong_SHIFT;
3214 hishift = PyLong_SHIFT - loshift;
3215 lomask = ((digit)1 << hishift) - 1;
3216 himask = PyLong_MASK ^ lomask;
3217 z = _PyLong_New(newsize);
3218 if (z == NULL)
3219 goto rshift_error;
3220 if (Py_SIZE(a) < 0)
3221 Py_SIZE(z) = -(Py_SIZE(z));
3222 for (i = 0, j = wordshift; i < newsize; i++, j++) {
3223 z->ob_digit[i] = (a->ob_digit[j] >> loshift) & lomask;
3224 if (i+1 < newsize)
3225 z->ob_digit[i] |=
3226 (a->ob_digit[j+1] << hishift) & himask;
3228 z = long_normalize(z);
3230 rshift_error:
3231 Py_DECREF(a);
3232 Py_DECREF(b);
3233 return (PyObject *) z;
3237 static PyObject *
3238 long_lshift(PyObject *v, PyObject *w)
3240 /* This version due to Tim Peters */
3241 PyLongObject *a, *b;
3242 PyLongObject *z = NULL;
3243 long shiftby;
3244 Py_ssize_t oldsize, newsize, wordshift, remshift, i, j;
3245 twodigits accum;
3247 CONVERT_BINOP(v, w, &a, &b);
3249 shiftby = PyLong_AsLong((PyObject *)b);
3250 if (shiftby == -1L && PyErr_Occurred())
3251 goto lshift_error;
3252 if (shiftby < 0) {
3253 PyErr_SetString(PyExc_ValueError, "negative shift count");
3254 goto lshift_error;
3256 if ((long)(int)shiftby != shiftby) {
3257 PyErr_SetString(PyExc_ValueError,
3258 "outrageous left shift count");
3259 goto lshift_error;
3261 /* wordshift, remshift = divmod(shiftby, PyLong_SHIFT) */
3262 wordshift = (int)shiftby / PyLong_SHIFT;
3263 remshift = (int)shiftby - wordshift * PyLong_SHIFT;
3265 oldsize = ABS(a->ob_size);
3266 newsize = oldsize + wordshift;
3267 if (remshift)
3268 ++newsize;
3269 z = _PyLong_New(newsize);
3270 if (z == NULL)
3271 goto lshift_error;
3272 if (a->ob_size < 0)
3273 z->ob_size = -(z->ob_size);
3274 for (i = 0; i < wordshift; i++)
3275 z->ob_digit[i] = 0;
3276 accum = 0;
3277 for (i = wordshift, j = 0; j < oldsize; i++, j++) {
3278 accum |= (twodigits)a->ob_digit[j] << remshift;
3279 z->ob_digit[i] = (digit)(accum & PyLong_MASK);
3280 accum >>= PyLong_SHIFT;
3282 if (remshift)
3283 z->ob_digit[newsize-1] = (digit)accum;
3284 else
3285 assert(!accum);
3286 z = long_normalize(z);
3287 lshift_error:
3288 Py_DECREF(a);
3289 Py_DECREF(b);
3290 return (PyObject *) z;
3294 /* Bitwise and/xor/or operations */
3296 static PyObject *
3297 long_bitwise(PyLongObject *a,
3298 int op, /* '&', '|', '^' */
3299 PyLongObject *b)
3301 digit maska, maskb; /* 0 or PyLong_MASK */
3302 int negz;
3303 Py_ssize_t size_a, size_b, size_z, i;
3304 PyLongObject *z;
3305 digit diga, digb;
3306 PyObject *v;
3308 if (Py_SIZE(a) < 0) {
3309 a = (PyLongObject *) long_invert(a);
3310 if (a == NULL)
3311 return NULL;
3312 maska = PyLong_MASK;
3314 else {
3315 Py_INCREF(a);
3316 maska = 0;
3318 if (Py_SIZE(b) < 0) {
3319 b = (PyLongObject *) long_invert(b);
3320 if (b == NULL) {
3321 Py_DECREF(a);
3322 return NULL;
3324 maskb = PyLong_MASK;
3326 else {
3327 Py_INCREF(b);
3328 maskb = 0;
3331 negz = 0;
3332 switch (op) {
3333 case '^':
3334 if (maska != maskb) {
3335 maska ^= PyLong_MASK;
3336 negz = -1;
3338 break;
3339 case '&':
3340 if (maska && maskb) {
3341 op = '|';
3342 maska ^= PyLong_MASK;
3343 maskb ^= PyLong_MASK;
3344 negz = -1;
3346 break;
3347 case '|':
3348 if (maska || maskb) {
3349 op = '&';
3350 maska ^= PyLong_MASK;
3351 maskb ^= PyLong_MASK;
3352 negz = -1;
3354 break;
3357 /* JRH: The original logic here was to allocate the result value (z)
3358 as the longer of the two operands. However, there are some cases
3359 where the result is guaranteed to be shorter than that: AND of two
3360 positives, OR of two negatives: use the shorter number. AND with
3361 mixed signs: use the positive number. OR with mixed signs: use the
3362 negative number. After the transformations above, op will be '&'
3363 iff one of these cases applies, and mask will be non-0 for operands
3364 whose length should be ignored.
3367 size_a = Py_SIZE(a);
3368 size_b = Py_SIZE(b);
3369 size_z = op == '&'
3370 ? (maska
3371 ? size_b
3372 : (maskb ? size_a : MIN(size_a, size_b)))
3373 : MAX(size_a, size_b);
3374 z = _PyLong_New(size_z);
3375 if (z == NULL) {
3376 Py_DECREF(a);
3377 Py_DECREF(b);
3378 return NULL;
3381 for (i = 0; i < size_z; ++i) {
3382 diga = (i < size_a ? a->ob_digit[i] : 0) ^ maska;
3383 digb = (i < size_b ? b->ob_digit[i] : 0) ^ maskb;
3384 switch (op) {
3385 case '&': z->ob_digit[i] = diga & digb; break;
3386 case '|': z->ob_digit[i] = diga | digb; break;
3387 case '^': z->ob_digit[i] = diga ^ digb; break;
3391 Py_DECREF(a);
3392 Py_DECREF(b);
3393 z = long_normalize(z);
3394 if (negz == 0)
3395 return (PyObject *) z;
3396 v = long_invert(z);
3397 Py_DECREF(z);
3398 return v;
3401 static PyObject *
3402 long_and(PyObject *v, PyObject *w)
3404 PyLongObject *a, *b;
3405 PyObject *c;
3406 CONVERT_BINOP(v, w, &a, &b);
3407 c = long_bitwise(a, '&', b);
3408 Py_DECREF(a);
3409 Py_DECREF(b);
3410 return c;
3413 static PyObject *
3414 long_xor(PyObject *v, PyObject *w)
3416 PyLongObject *a, *b;
3417 PyObject *c;
3418 CONVERT_BINOP(v, w, &a, &b);
3419 c = long_bitwise(a, '^', b);
3420 Py_DECREF(a);
3421 Py_DECREF(b);
3422 return c;
3425 static PyObject *
3426 long_or(PyObject *v, PyObject *w)
3428 PyLongObject *a, *b;
3429 PyObject *c;
3430 CONVERT_BINOP(v, w, &a, &b);
3431 c = long_bitwise(a, '|', b);
3432 Py_DECREF(a);
3433 Py_DECREF(b);
3434 return c;
3437 static int
3438 long_coerce(PyObject **pv, PyObject **pw)
3440 if (PyInt_Check(*pw)) {
3441 *pw = PyLong_FromLong(PyInt_AS_LONG(*pw));
3442 if (*pw == NULL)
3443 return -1;
3444 Py_INCREF(*pv);
3445 return 0;
3447 else if (PyLong_Check(*pw)) {
3448 Py_INCREF(*pv);
3449 Py_INCREF(*pw);
3450 return 0;
3452 return 1; /* Can't do it */
3455 static PyObject *
3456 long_long(PyObject *v)
3458 if (PyLong_CheckExact(v))
3459 Py_INCREF(v);
3460 else
3461 v = _PyLong_Copy((PyLongObject *)v);
3462 return v;
3465 static PyObject *
3466 long_int(PyObject *v)
3468 long x;
3469 x = PyLong_AsLong(v);
3470 if (PyErr_Occurred()) {
3471 if (PyErr_ExceptionMatches(PyExc_OverflowError)) {
3472 PyErr_Clear();
3473 if (PyLong_CheckExact(v)) {
3474 Py_INCREF(v);
3475 return v;
3477 else
3478 return _PyLong_Copy((PyLongObject *)v);
3480 else
3481 return NULL;
3483 return PyInt_FromLong(x);
3486 static PyObject *
3487 long_float(PyObject *v)
3489 double result;
3490 result = PyLong_AsDouble(v);
3491 if (result == -1.0 && PyErr_Occurred())
3492 return NULL;
3493 return PyFloat_FromDouble(result);
3496 static PyObject *
3497 long_oct(PyObject *v)
3499 return _PyLong_Format(v, 8, 1, 0);
3502 static PyObject *
3503 long_hex(PyObject *v)
3505 return _PyLong_Format(v, 16, 1, 0);
3508 static PyObject *
3509 long_subtype_new(PyTypeObject *type, PyObject *args, PyObject *kwds);
3511 static PyObject *
3512 long_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
3514 PyObject *x = NULL;
3515 int base = -909; /* unlikely! */
3516 static char *kwlist[] = {"x", "base", 0};
3518 if (type != &PyLong_Type)
3519 return long_subtype_new(type, args, kwds); /* Wimp out */
3520 if (!PyArg_ParseTupleAndKeywords(args, kwds, "|Oi:long", kwlist,
3521 &x, &base))
3522 return NULL;
3523 if (x == NULL)
3524 return PyLong_FromLong(0L);
3525 if (base == -909)
3526 return PyNumber_Long(x);
3527 else if (PyString_Check(x)) {
3528 /* Since PyLong_FromString doesn't have a length parameter,
3529 * check here for possible NULs in the string. */
3530 char *string = PyString_AS_STRING(x);
3531 if (strlen(string) != (size_t)PyString_Size(x)) {
3532 /* create a repr() of the input string,
3533 * just like PyLong_FromString does. */
3534 PyObject *srepr;
3535 srepr = PyObject_Repr(x);
3536 if (srepr == NULL)
3537 return NULL;
3538 PyErr_Format(PyExc_ValueError,
3539 "invalid literal for long() with base %d: %s",
3540 base, PyString_AS_STRING(srepr));
3541 Py_DECREF(srepr);
3542 return NULL;
3544 return PyLong_FromString(PyString_AS_STRING(x), NULL, base);
3546 #ifdef Py_USING_UNICODE
3547 else if (PyUnicode_Check(x))
3548 return PyLong_FromUnicode(PyUnicode_AS_UNICODE(x),
3549 PyUnicode_GET_SIZE(x),
3550 base);
3551 #endif
3552 else {
3553 PyErr_SetString(PyExc_TypeError,
3554 "long() can't convert non-string with explicit base");
3555 return NULL;
3559 /* Wimpy, slow approach to tp_new calls for subtypes of long:
3560 first create a regular long from whatever arguments we got,
3561 then allocate a subtype instance and initialize it from
3562 the regular long. The regular long is then thrown away.
3564 static PyObject *
3565 long_subtype_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
3567 PyLongObject *tmp, *newobj;
3568 Py_ssize_t i, n;
3570 assert(PyType_IsSubtype(type, &PyLong_Type));
3571 tmp = (PyLongObject *)long_new(&PyLong_Type, args, kwds);
3572 if (tmp == NULL)
3573 return NULL;
3574 assert(PyLong_CheckExact(tmp));
3575 n = Py_SIZE(tmp);
3576 if (n < 0)
3577 n = -n;
3578 newobj = (PyLongObject *)type->tp_alloc(type, n);
3579 if (newobj == NULL) {
3580 Py_DECREF(tmp);
3581 return NULL;
3583 assert(PyLong_Check(newobj));
3584 Py_SIZE(newobj) = Py_SIZE(tmp);
3585 for (i = 0; i < n; i++)
3586 newobj->ob_digit[i] = tmp->ob_digit[i];
3587 Py_DECREF(tmp);
3588 return (PyObject *)newobj;
3591 static PyObject *
3592 long_getnewargs(PyLongObject *v)
3594 return Py_BuildValue("(N)", _PyLong_Copy(v));
3597 static PyObject *
3598 long_get0(PyLongObject *v, void *context) {
3599 return PyLong_FromLong(0L);
3602 static PyObject *
3603 long_get1(PyLongObject *v, void *context) {
3604 return PyLong_FromLong(1L);
3607 static PyObject *
3608 long__format__(PyObject *self, PyObject *args)
3610 PyObject *format_spec;
3612 if (!PyArg_ParseTuple(args, "O:__format__", &format_spec))
3613 return NULL;
3614 if (PyBytes_Check(format_spec))
3615 return _PyLong_FormatAdvanced(self,
3616 PyBytes_AS_STRING(format_spec),
3617 PyBytes_GET_SIZE(format_spec));
3618 if (PyUnicode_Check(format_spec)) {
3619 /* Convert format_spec to a str */
3620 PyObject *result;
3621 PyObject *str_spec = PyObject_Str(format_spec);
3623 if (str_spec == NULL)
3624 return NULL;
3626 result = _PyLong_FormatAdvanced(self,
3627 PyBytes_AS_STRING(str_spec),
3628 PyBytes_GET_SIZE(str_spec));
3630 Py_DECREF(str_spec);
3631 return result;
3633 PyErr_SetString(PyExc_TypeError, "__format__ requires str or unicode");
3634 return NULL;
3637 static PyObject *
3638 long_sizeof(PyLongObject *v)
3640 Py_ssize_t res;
3642 res = v->ob_type->tp_basicsize + ABS(Py_SIZE(v))*sizeof(digit);
3643 return PyInt_FromSsize_t(res);
3646 static PyObject *
3647 long_bit_length(PyLongObject *v)
3649 PyLongObject *result, *x, *y;
3650 Py_ssize_t ndigits, msd_bits = 0;
3651 digit msd;
3653 assert(v != NULL);
3654 assert(PyLong_Check(v));
3656 ndigits = ABS(Py_SIZE(v));
3657 if (ndigits == 0)
3658 return PyInt_FromLong(0);
3660 msd = v->ob_digit[ndigits-1];
3661 while (msd >= 32) {
3662 msd_bits += 6;
3663 msd >>= 6;
3665 msd_bits += (long)(BitLengthTable[msd]);
3667 if (ndigits <= PY_SSIZE_T_MAX/PyLong_SHIFT)
3668 return PyInt_FromSsize_t((ndigits-1)*PyLong_SHIFT + msd_bits);
3670 /* expression above may overflow; use Python integers instead */
3671 result = (PyLongObject *)PyLong_FromSsize_t(ndigits - 1);
3672 if (result == NULL)
3673 return NULL;
3674 x = (PyLongObject *)PyLong_FromLong(PyLong_SHIFT);
3675 if (x == NULL)
3676 goto error;
3677 y = (PyLongObject *)long_mul(result, x);
3678 Py_DECREF(x);
3679 if (y == NULL)
3680 goto error;
3681 Py_DECREF(result);
3682 result = y;
3684 x = (PyLongObject *)PyLong_FromLong(msd_bits);
3685 if (x == NULL)
3686 goto error;
3687 y = (PyLongObject *)long_add(result, x);
3688 Py_DECREF(x);
3689 if (y == NULL)
3690 goto error;
3691 Py_DECREF(result);
3692 result = y;
3694 return (PyObject *)result;
3696 error:
3697 Py_DECREF(result);
3698 return NULL;
3701 PyDoc_STRVAR(long_bit_length_doc,
3702 "long.bit_length() -> int or long\n\
3704 Number of bits necessary to represent self in binary.\n\
3705 >>> bin(37L)\n\
3706 '0b100101'\n\
3707 >>> (37L).bit_length()\n\
3708 6");
3710 #if 0
3711 static PyObject *
3712 long_is_finite(PyObject *v)
3714 Py_RETURN_TRUE;
3716 #endif
3718 static PyMethodDef long_methods[] = {
3719 {"conjugate", (PyCFunction)long_long, METH_NOARGS,
3720 "Returns self, the complex conjugate of any long."},
3721 {"bit_length", (PyCFunction)long_bit_length, METH_NOARGS,
3722 long_bit_length_doc},
3723 #if 0
3724 {"is_finite", (PyCFunction)long_is_finite, METH_NOARGS,
3725 "Returns always True."},
3726 #endif
3727 {"__trunc__", (PyCFunction)long_long, METH_NOARGS,
3728 "Truncating an Integral returns itself."},
3729 {"__getnewargs__", (PyCFunction)long_getnewargs, METH_NOARGS},
3730 {"__format__", (PyCFunction)long__format__, METH_VARARGS},
3731 {"__sizeof__", (PyCFunction)long_sizeof, METH_NOARGS,
3732 "Returns size in memory, in bytes"},
3733 {NULL, NULL} /* sentinel */
3736 static PyGetSetDef long_getset[] = {
3737 {"real",
3738 (getter)long_long, (setter)NULL,
3739 "the real part of a complex number",
3740 NULL},
3741 {"imag",
3742 (getter)long_get0, (setter)NULL,
3743 "the imaginary part of a complex number",
3744 NULL},
3745 {"numerator",
3746 (getter)long_long, (setter)NULL,
3747 "the numerator of a rational number in lowest terms",
3748 NULL},
3749 {"denominator",
3750 (getter)long_get1, (setter)NULL,
3751 "the denominator of a rational number in lowest terms",
3752 NULL},
3753 {NULL} /* Sentinel */
3756 PyDoc_STRVAR(long_doc,
3757 "long(x[, base]) -> integer\n\
3759 Convert a string or number to a long integer, if possible. A floating\n\
3760 point argument will be truncated towards zero (this does not include a\n\
3761 string representation of a floating point number!) When converting a\n\
3762 string, use the optional base. It is an error to supply a base when\n\
3763 converting a non-string.");
3765 static PyNumberMethods long_as_number = {
3766 (binaryfunc) long_add, /*nb_add*/
3767 (binaryfunc) long_sub, /*nb_subtract*/
3768 (binaryfunc) long_mul, /*nb_multiply*/
3769 long_classic_div, /*nb_divide*/
3770 long_mod, /*nb_remainder*/
3771 long_divmod, /*nb_divmod*/
3772 long_pow, /*nb_power*/
3773 (unaryfunc) long_neg, /*nb_negative*/
3774 (unaryfunc) long_long, /*tp_positive*/
3775 (unaryfunc) long_abs, /*tp_absolute*/
3776 (inquiry) long_nonzero, /*tp_nonzero*/
3777 (unaryfunc) long_invert, /*nb_invert*/
3778 long_lshift, /*nb_lshift*/
3779 (binaryfunc) long_rshift, /*nb_rshift*/
3780 long_and, /*nb_and*/
3781 long_xor, /*nb_xor*/
3782 long_or, /*nb_or*/
3783 long_coerce, /*nb_coerce*/
3784 long_int, /*nb_int*/
3785 long_long, /*nb_long*/
3786 long_float, /*nb_float*/
3787 long_oct, /*nb_oct*/
3788 long_hex, /*nb_hex*/
3789 0, /* nb_inplace_add */
3790 0, /* nb_inplace_subtract */
3791 0, /* nb_inplace_multiply */
3792 0, /* nb_inplace_divide */
3793 0, /* nb_inplace_remainder */
3794 0, /* nb_inplace_power */
3795 0, /* nb_inplace_lshift */
3796 0, /* nb_inplace_rshift */
3797 0, /* nb_inplace_and */
3798 0, /* nb_inplace_xor */
3799 0, /* nb_inplace_or */
3800 long_div, /* nb_floor_divide */
3801 long_true_divide, /* nb_true_divide */
3802 0, /* nb_inplace_floor_divide */
3803 0, /* nb_inplace_true_divide */
3804 long_long, /* nb_index */
3807 PyTypeObject PyLong_Type = {
3808 PyObject_HEAD_INIT(&PyType_Type)
3809 0, /* ob_size */
3810 "long", /* tp_name */
3811 offsetof(PyLongObject, ob_digit), /* tp_basicsize */
3812 sizeof(digit), /* tp_itemsize */
3813 long_dealloc, /* tp_dealloc */
3814 0, /* tp_print */
3815 0, /* tp_getattr */
3816 0, /* tp_setattr */
3817 (cmpfunc)long_compare, /* tp_compare */
3818 long_repr, /* tp_repr */
3819 &long_as_number, /* tp_as_number */
3820 0, /* tp_as_sequence */
3821 0, /* tp_as_mapping */
3822 (hashfunc)long_hash, /* tp_hash */
3823 0, /* tp_call */
3824 long_str, /* tp_str */
3825 PyObject_GenericGetAttr, /* tp_getattro */
3826 0, /* tp_setattro */
3827 0, /* tp_as_buffer */
3828 Py_TPFLAGS_DEFAULT | Py_TPFLAGS_CHECKTYPES |
3829 Py_TPFLAGS_BASETYPE | Py_TPFLAGS_LONG_SUBCLASS, /* tp_flags */
3830 long_doc, /* tp_doc */
3831 0, /* tp_traverse */
3832 0, /* tp_clear */
3833 0, /* tp_richcompare */
3834 0, /* tp_weaklistoffset */
3835 0, /* tp_iter */
3836 0, /* tp_iternext */
3837 long_methods, /* tp_methods */
3838 0, /* tp_members */
3839 long_getset, /* tp_getset */
3840 0, /* tp_base */
3841 0, /* tp_dict */
3842 0, /* tp_descr_get */
3843 0, /* tp_descr_set */
3844 0, /* tp_dictoffset */
3845 0, /* tp_init */
3846 0, /* tp_alloc */
3847 long_new, /* tp_new */
3848 PyObject_Del, /* tp_free */
3851 static PyTypeObject Long_InfoType;
3853 PyDoc_STRVAR(long_info__doc__,
3854 "sys.long_info\n\
3856 A struct sequence that holds information about Python's\n\
3857 internal representation of integers. The attributes are read only.");
3859 static PyStructSequence_Field long_info_fields[] = {
3860 {"bits_per_digit", "size of a digit in bits"},
3861 {"sizeof_digit", "size in bytes of the C type used to "
3862 "represent a digit"},
3863 {NULL, NULL}
3866 static PyStructSequence_Desc long_info_desc = {
3867 "sys.long_info", /* name */
3868 long_info__doc__, /* doc */
3869 long_info_fields, /* fields */
3870 2 /* number of fields */
3873 PyObject *
3874 PyLong_GetInfo(void)
3876 PyObject* long_info;
3877 int field = 0;
3878 long_info = PyStructSequence_New(&Long_InfoType);
3879 if (long_info == NULL)
3880 return NULL;
3881 PyStructSequence_SET_ITEM(long_info, field++,
3882 PyInt_FromLong(PyLong_SHIFT));
3883 PyStructSequence_SET_ITEM(long_info, field++,
3884 PyInt_FromLong(sizeof(digit)));
3885 if (PyErr_Occurred()) {
3886 Py_CLEAR(long_info);
3887 return NULL;
3889 return long_info;
3893 _PyLong_Init(void)
3895 /* initialize long_info */
3896 if (Long_InfoType.tp_name == 0)
3897 PyStructSequence_InitType(&Long_InfoType, &long_info_desc);
3898 return 1;