3 /* Long (arbitrary precision) integer object implementation */
5 /* XXX The functional organization of this file is terrible */
8 #include "longintrepr.h"
15 /* For long multiplication, use the O(N**2) school algorithm unless
16 * both operands contain more than KARATSUBA_CUTOFF digits (this
17 * being an internal Python long digit, in base PyLong_BASE).
19 #define KARATSUBA_CUTOFF 70
20 #define KARATSUBA_SQUARE_CUTOFF (2 * KARATSUBA_CUTOFF)
22 /* For exponentiation, use the binary left-to-right algorithm
23 * unless the exponent contains more than FIVEARY_CUTOFF digits.
24 * In that case, do 5 bits at a time. The potential drawback is that
25 * a table of 2**5 intermediate results is computed.
27 #define FIVEARY_CUTOFF 8
29 #define ABS(x) ((x) < 0 ? -(x) : (x))
33 #define MAX(x, y) ((x) < (y) ? (y) : (x))
34 #define MIN(x, y) ((x) > (y) ? (y) : (x))
36 #define SIGCHECK(PyTryBlock) \
37 if (--_Py_Ticker < 0) { \
38 _Py_Ticker = _Py_CheckInterval; \
39 if (PyErr_CheckSignals()) PyTryBlock \
42 /* forward declaration */
43 static int bits_in_digit(digit d
);
45 /* Normalize (remove leading zeros from) a long int object.
46 Doesn't attempt to free the storage--in most cases, due to the nature
47 of the algorithms used, this could save at most be one word anyway. */
50 long_normalize(register PyLongObject
*v
)
52 Py_ssize_t j
= ABS(Py_SIZE(v
));
55 while (i
> 0 && v
->ob_digit
[i
-1] == 0)
58 Py_SIZE(v
) = (Py_SIZE(v
) < 0) ? -(i
) : i
;
62 /* Allocate a new long int object with size digits.
63 Return NULL and set exception if we run out of memory. */
65 #define MAX_LONG_DIGITS \
66 ((PY_SSIZE_T_MAX - offsetof(PyLongObject, ob_digit))/sizeof(digit))
69 _PyLong_New(Py_ssize_t size
)
71 if (size
> (Py_ssize_t
)MAX_LONG_DIGITS
) {
72 PyErr_SetString(PyExc_OverflowError
,
73 "too many digits in integer");
76 /* coverity[ampersand_in_size] */
77 /* XXX(nnorwitz): PyObject_NEW_VAR / _PyObject_VAR_SIZE need to detect
79 return PyObject_NEW_VAR(PyLongObject
, &PyLong_Type
, size
);
83 _PyLong_Copy(PyLongObject
*src
)
92 result
= _PyLong_New(i
);
94 result
->ob_size
= src
->ob_size
;
96 result
->ob_digit
[i
] = src
->ob_digit
[i
];
98 return (PyObject
*)result
;
101 /* Create a new long int object from a C long int */
104 PyLong_FromLong(long ival
)
107 unsigned long abs_ival
;
108 unsigned long t
; /* unsigned so >> doesn't propagate sign bit */
113 /* if LONG_MIN == -LONG_MAX-1 (true on most platforms) then
114 ANSI C says that the result of -ival is undefined when ival
115 == LONG_MIN. Hence the following workaround. */
116 abs_ival
= (unsigned long)(-1-ival
) + 1;
120 abs_ival
= (unsigned long)ival
;
123 /* Count the number of Python digits.
124 We used to pick 5 ("big enough for anything"), but that's a
125 waste of time and space given that 5*15 = 75 bits are rarely
132 v
= _PyLong_New(ndigits
);
134 digit
*p
= v
->ob_digit
;
135 v
->ob_size
= negative
? -ndigits
: ndigits
;
138 *p
++ = (digit
)(t
& PyLong_MASK
);
142 return (PyObject
*)v
;
145 /* Create a new long int object from a C unsigned long int */
148 PyLong_FromUnsignedLong(unsigned long ival
)
154 /* Count the number of Python digits. */
155 t
= (unsigned long)ival
;
160 v
= _PyLong_New(ndigits
);
162 digit
*p
= v
->ob_digit
;
163 Py_SIZE(v
) = ndigits
;
165 *p
++ = (digit
)(ival
& PyLong_MASK
);
166 ival
>>= PyLong_SHIFT
;
169 return (PyObject
*)v
;
172 /* Create a new long int object from a C double */
175 PyLong_FromDouble(double dval
)
179 int i
, ndig
, expo
, neg
;
181 if (Py_IS_INFINITY(dval
)) {
182 PyErr_SetString(PyExc_OverflowError
,
183 "cannot convert float infinity to integer");
186 if (Py_IS_NAN(dval
)) {
187 PyErr_SetString(PyExc_ValueError
,
188 "cannot convert float NaN to integer");
195 frac
= frexp(dval
, &expo
); /* dval = frac*2**expo; 0.0 <= frac < 1.0 */
197 return PyLong_FromLong(0L);
198 ndig
= (expo
-1) / PyLong_SHIFT
+ 1; /* Number of 'digits' in result */
199 v
= _PyLong_New(ndig
);
202 frac
= ldexp(frac
, (expo
-1) % PyLong_SHIFT
+ 1);
203 for (i
= ndig
; --i
>= 0; ) {
204 digit bits
= (digit
)frac
;
205 v
->ob_digit
[i
] = bits
;
206 frac
= frac
- (double)bits
;
207 frac
= ldexp(frac
, PyLong_SHIFT
);
210 Py_SIZE(v
) = -(Py_SIZE(v
));
211 return (PyObject
*)v
;
214 /* Checking for overflow in PyLong_AsLong is a PITA since C doesn't define
215 * anything about what happens when a signed integer operation overflows,
216 * and some compilers think they're doing you a favor by being "clever"
217 * then. The bit pattern for the largest postive signed long is
218 * (unsigned long)LONG_MAX, and for the smallest negative signed long
219 * it is abs(LONG_MIN), which we could write -(unsigned long)LONG_MIN.
220 * However, some other compilers warn about applying unary minus to an
221 * unsigned operand. Hence the weird "0-".
223 #define PY_ABS_LONG_MIN (0-(unsigned long)LONG_MIN)
224 #define PY_ABS_SSIZE_T_MIN (0-(size_t)PY_SSIZE_T_MIN)
226 /* Get a C long int from a long int object.
227 Returns -1 and sets an error condition if overflow occurs. */
230 PyLong_AsLong(PyObject
*vv
)
232 /* This version by Tim Peters */
233 register PyLongObject
*v
;
234 unsigned long x
, prev
;
238 if (vv
== NULL
|| !PyLong_Check(vv
)) {
239 if (vv
!= NULL
&& PyInt_Check(vv
))
240 return PyInt_AsLong(vv
);
241 PyErr_BadInternalCall();
244 v
= (PyLongObject
*)vv
;
254 x
= (x
<< PyLong_SHIFT
) + v
->ob_digit
[i
];
255 if ((x
>> PyLong_SHIFT
) != prev
)
258 /* Haven't lost any bits, but casting to long requires extra care
259 * (see comment above).
261 if (x
<= (unsigned long)LONG_MAX
) {
262 return (long)x
* sign
;
264 else if (sign
< 0 && x
== PY_ABS_LONG_MIN
) {
270 PyErr_SetString(PyExc_OverflowError
,
271 "long int too large to convert to int");
275 /* Get a Py_ssize_t from a long int object.
276 Returns -1 and sets an error condition if overflow occurs. */
279 PyLong_AsSsize_t(PyObject
*vv
) {
280 register PyLongObject
*v
;
285 if (vv
== NULL
|| !PyLong_Check(vv
)) {
286 PyErr_BadInternalCall();
289 v
= (PyLongObject
*)vv
;
299 x
= (x
<< PyLong_SHIFT
) + v
->ob_digit
[i
];
300 if ((x
>> PyLong_SHIFT
) != prev
)
303 /* Haven't lost any bits, but casting to a signed type requires
304 * extra care (see comment above).
306 if (x
<= (size_t)PY_SSIZE_T_MAX
) {
307 return (Py_ssize_t
)x
* sign
;
309 else if (sign
< 0 && x
== PY_ABS_SSIZE_T_MIN
) {
310 return PY_SSIZE_T_MIN
;
315 PyErr_SetString(PyExc_OverflowError
,
316 "long int too large to convert to int");
320 /* Get a C unsigned long int from a long int object.
321 Returns -1 and sets an error condition if overflow occurs. */
324 PyLong_AsUnsignedLong(PyObject
*vv
)
326 register PyLongObject
*v
;
327 unsigned long x
, prev
;
330 if (vv
== NULL
|| !PyLong_Check(vv
)) {
331 if (vv
!= NULL
&& PyInt_Check(vv
)) {
332 long val
= PyInt_AsLong(vv
);
334 PyErr_SetString(PyExc_OverflowError
,
335 "can't convert negative value to unsigned long");
336 return (unsigned long) -1;
340 PyErr_BadInternalCall();
341 return (unsigned long) -1;
343 v
= (PyLongObject
*)vv
;
347 PyErr_SetString(PyExc_OverflowError
,
348 "can't convert negative value to unsigned long");
349 return (unsigned long) -1;
353 x
= (x
<< PyLong_SHIFT
) + v
->ob_digit
[i
];
354 if ((x
>> PyLong_SHIFT
) != prev
) {
355 PyErr_SetString(PyExc_OverflowError
,
356 "long int too large to convert");
357 return (unsigned long) -1;
363 /* Get a C unsigned long int from a long int object, ignoring the high bits.
364 Returns -1 and sets an error condition if an error occurs. */
367 PyLong_AsUnsignedLongMask(PyObject
*vv
)
369 register PyLongObject
*v
;
374 if (vv
== NULL
|| !PyLong_Check(vv
)) {
375 if (vv
!= NULL
&& PyInt_Check(vv
))
376 return PyInt_AsUnsignedLongMask(vv
);
377 PyErr_BadInternalCall();
378 return (unsigned long) -1;
380 v
= (PyLongObject
*)vv
;
389 x
= (x
<< PyLong_SHIFT
) + v
->ob_digit
[i
];
395 _PyLong_Sign(PyObject
*vv
)
397 PyLongObject
*v
= (PyLongObject
*)vv
;
400 assert(PyLong_Check(v
));
402 return Py_SIZE(v
) == 0 ? 0 : (Py_SIZE(v
) < 0 ? -1 : 1);
406 _PyLong_NumBits(PyObject
*vv
)
408 PyLongObject
*v
= (PyLongObject
*)vv
;
413 assert(PyLong_Check(v
));
414 ndigits
= ABS(Py_SIZE(v
));
415 assert(ndigits
== 0 || v
->ob_digit
[ndigits
- 1] != 0);
417 digit msd
= v
->ob_digit
[ndigits
- 1];
419 result
= (ndigits
- 1) * PyLong_SHIFT
;
420 if (result
/ PyLong_SHIFT
!= (size_t)(ndigits
- 1))
432 PyErr_SetString(PyExc_OverflowError
, "long has too many bits "
433 "to express in a platform size_t");
438 _PyLong_FromByteArray(const unsigned char* bytes
, size_t n
,
439 int little_endian
, int is_signed
)
441 const unsigned char* pstartbyte
;/* LSB of bytes */
442 int incr
; /* direction to move pstartbyte */
443 const unsigned char* pendbyte
; /* MSB of bytes */
444 size_t numsignificantbytes
; /* number of bytes that matter */
445 Py_ssize_t ndigits
; /* number of Python long digits */
446 PyLongObject
* v
; /* result */
447 Py_ssize_t idigit
= 0; /* next free index in v->ob_digit */
450 return PyLong_FromLong(0L);
454 pendbyte
= bytes
+ n
- 1;
458 pstartbyte
= bytes
+ n
- 1;
464 is_signed
= *pendbyte
>= 0x80;
466 /* Compute numsignificantbytes. This consists of finding the most
467 significant byte. Leading 0 bytes are insignficant if the number
468 is positive, and leading 0xff bytes if negative. */
471 const unsigned char* p
= pendbyte
;
472 const int pincr
= -incr
; /* search MSB to LSB */
473 const unsigned char insignficant
= is_signed
? 0xff : 0x00;
475 for (i
= 0; i
< n
; ++i
, p
+= pincr
) {
476 if (*p
!= insignficant
)
479 numsignificantbytes
= n
- i
;
480 /* 2's-comp is a bit tricky here, e.g. 0xff00 == -0x0100, so
481 actually has 2 significant bytes. OTOH, 0xff0001 ==
482 -0x00ffff, so we wouldn't *need* to bump it there; but we
483 do for 0xffff = -0x0001. To be safe without bothering to
484 check every case, bump it regardless. */
485 if (is_signed
&& numsignificantbytes
< n
)
486 ++numsignificantbytes
;
489 /* How many Python long digits do we need? We have
490 8*numsignificantbytes bits, and each Python long digit has
491 PyLong_SHIFT bits, so it's the ceiling of the quotient. */
492 /* catch overflow before it happens */
493 if (numsignificantbytes
> (PY_SSIZE_T_MAX
- PyLong_SHIFT
) / 8) {
494 PyErr_SetString(PyExc_OverflowError
,
495 "byte array too long to convert to int");
498 ndigits
= (numsignificantbytes
* 8 + PyLong_SHIFT
- 1) / PyLong_SHIFT
;
499 v
= _PyLong_New(ndigits
);
503 /* Copy the bits over. The tricky parts are computing 2's-comp on
504 the fly for signed numbers, and dealing with the mismatch between
505 8-bit bytes and (probably) 15-bit Python digits.*/
508 twodigits carry
= 1; /* for 2's-comp calculation */
509 twodigits accum
= 0; /* sliding register */
510 unsigned int accumbits
= 0; /* number of bits in accum */
511 const unsigned char* p
= pstartbyte
;
513 for (i
= 0; i
< numsignificantbytes
; ++i
, p
+= incr
) {
514 twodigits thisbyte
= *p
;
515 /* Compute correction for 2's comp, if needed. */
517 thisbyte
= (0xff ^ thisbyte
) + carry
;
518 carry
= thisbyte
>> 8;
521 /* Because we're going LSB to MSB, thisbyte is
522 more significant than what's already in accum,
523 so needs to be prepended to accum. */
524 accum
|= (twodigits
)thisbyte
<< accumbits
;
526 if (accumbits
>= PyLong_SHIFT
) {
527 /* There's enough to fill a Python digit. */
528 assert(idigit
< ndigits
);
529 v
->ob_digit
[idigit
] = (digit
)(accum
&
532 accum
>>= PyLong_SHIFT
;
533 accumbits
-= PyLong_SHIFT
;
534 assert(accumbits
< PyLong_SHIFT
);
537 assert(accumbits
< PyLong_SHIFT
);
539 assert(idigit
< ndigits
);
540 v
->ob_digit
[idigit
] = (digit
)accum
;
545 Py_SIZE(v
) = is_signed
? -idigit
: idigit
;
546 return (PyObject
*)long_normalize(v
);
550 _PyLong_AsByteArray(PyLongObject
* v
,
551 unsigned char* bytes
, size_t n
,
552 int little_endian
, int is_signed
)
554 Py_ssize_t i
; /* index into v->ob_digit */
555 Py_ssize_t ndigits
; /* |v->ob_size| */
556 twodigits accum
; /* sliding register */
557 unsigned int accumbits
; /* # bits in accum */
558 int do_twos_comp
; /* store 2's-comp? is_signed and v < 0 */
559 digit carry
; /* for computing 2's-comp */
560 size_t j
; /* # bytes filled */
561 unsigned char* p
; /* pointer to next byte in bytes */
562 int pincr
; /* direction to move p */
564 assert(v
!= NULL
&& PyLong_Check(v
));
566 if (Py_SIZE(v
) < 0) {
567 ndigits
= -(Py_SIZE(v
));
569 PyErr_SetString(PyExc_OverflowError
,
570 "can't convert negative long to unsigned");
576 ndigits
= Py_SIZE(v
);
589 /* Copy over all the Python digits.
590 It's crucial that every Python digit except for the MSD contribute
591 exactly PyLong_SHIFT bits to the total, so first assert that the long is
593 assert(ndigits
== 0 || v
->ob_digit
[ndigits
- 1] != 0);
597 carry
= do_twos_comp
? 1 : 0;
598 for (i
= 0; i
< ndigits
; ++i
) {
599 digit thisdigit
= v
->ob_digit
[i
];
601 thisdigit
= (thisdigit
^ PyLong_MASK
) + carry
;
602 carry
= thisdigit
>> PyLong_SHIFT
;
603 thisdigit
&= PyLong_MASK
;
605 /* Because we're going LSB to MSB, thisdigit is more
606 significant than what's already in accum, so needs to be
607 prepended to accum. */
608 accum
|= (twodigits
)thisdigit
<< accumbits
;
610 /* The most-significant digit may be (probably is) at least
612 if (i
== ndigits
- 1) {
613 /* Count # of sign bits -- they needn't be stored,
614 * although for signed conversion we need later to
615 * make sure at least one sign bit gets stored. */
616 digit s
= do_twos_comp
? thisdigit
^ PyLong_MASK
:
624 accumbits
+= PyLong_SHIFT
;
626 /* Store as many bytes as possible. */
627 while (accumbits
>= 8) {
631 *p
= (unsigned char)(accum
& 0xff);
638 /* Store the straggler (if any). */
639 assert(accumbits
< 8);
640 assert(carry
== 0); /* else do_twos_comp and *every* digit was 0 */
646 /* Fill leading bits of the byte with sign bits
647 (appropriately pretending that the long had an
648 infinite supply of sign bits). */
649 accum
|= (~(twodigits
)0) << accumbits
;
651 *p
= (unsigned char)(accum
& 0xff);
654 else if (j
== n
&& n
> 0 && is_signed
) {
655 /* The main loop filled the byte array exactly, so the code
656 just above didn't get to ensure there's a sign bit, and the
657 loop below wouldn't add one either. Make sure a sign bit
659 unsigned char msb
= *(p
- pincr
);
660 int sign_bit_set
= msb
>= 0x80;
661 assert(accumbits
== 0);
662 if (sign_bit_set
== do_twos_comp
)
668 /* Fill remaining bytes with copies of the sign bit. */
670 unsigned char signbyte
= do_twos_comp
? 0xffU
: 0U;
671 for ( ; j
< n
; ++j
, p
+= pincr
)
678 PyErr_SetString(PyExc_OverflowError
, "long too big to convert");
684 _PyLong_AsScaledDouble(PyObject
*vv
, int *exponent
)
686 /* NBITS_WANTED should be > the number of bits in a double's precision,
687 but small enough so that 2**NBITS_WANTED is within the normal double
688 range. nbitsneeded is set to 1 less than that because the most-significant
689 Python digit contains at least 1 significant bit, but we don't want to
690 bother counting them (catering to the worst case cheaply).
692 57 is one more than VAX-D double precision; I (Tim) don't know of a double
693 format with more precision than that; it's 1 larger so that we add in at
694 least one round bit to stand in for the ignored least-significant bits.
696 #define NBITS_WANTED 57
699 const double multiplier
= (double)(1L << PyLong_SHIFT
);
704 if (vv
== NULL
|| !PyLong_Check(vv
)) {
705 PyErr_BadInternalCall();
708 v
= (PyLongObject
*)vv
;
720 x
= (double)v
->ob_digit
[i
];
721 nbitsneeded
= NBITS_WANTED
- 1;
722 /* Invariant: i Python digits remain unaccounted for. */
723 while (i
> 0 && nbitsneeded
> 0) {
725 x
= x
* multiplier
+ (double)v
->ob_digit
[i
];
726 nbitsneeded
-= PyLong_SHIFT
;
728 /* There are i digits we didn't shift in. Pretending they're all
729 zeroes, the true value is x * 2**(i*PyLong_SHIFT). */
736 /* Get a C double from a long int object. Rounds to the nearest double,
737 using the round-half-to-even rule in the case of a tie. */
740 PyLong_AsDouble(PyObject
*vv
)
742 PyLongObject
*v
= (PyLongObject
*)vv
;
743 Py_ssize_t rnd_digit
, rnd_bit
, m
, n
;
748 if (vv
== NULL
|| !PyLong_Check(vv
)) {
749 PyErr_BadInternalCall();
753 /* Notes on the method: for simplicity, assume v is positive and >=
754 2**DBL_MANT_DIG. (For negative v we just ignore the sign until the
755 end; for small v no rounding is necessary.) Write n for the number
756 of bits in v, so that 2**(n-1) <= v < 2**n, and n > DBL_MANT_DIG.
758 Some terminology: the *rounding bit* of v is the 1st bit of v that
759 will be rounded away (bit n - DBL_MANT_DIG - 1); the *parity bit*
760 is the bit immediately above. The round-half-to-even rule says
761 that we round up if the rounding bit is set, unless v is exactly
762 halfway between two floats and the parity bit is zero.
764 Write d[0] ... d[m] for the digits of v, least to most significant.
765 Let rnd_bit be the index of the rounding bit, and rnd_digit the
766 index of the PyLong digit containing the rounding bit. Then the
767 bits of the digit d[rnd_digit] look something like:
772 msb -> sssssrttttttttt <- lsb
777 where 's' represents a 'significant bit' that will be included in
778 the mantissa of the result, 'r' is the rounding bit, and 't'
779 represents a 'trailing bit' following the rounding bit. Note that
780 if the rounding bit is at the top of d[rnd_digit] then the parity
781 bit will be the lsb of d[rnd_digit+1]. If we set
783 lsb = 1 << (rnd_bit % PyLong_SHIFT)
785 then d[rnd_digit] & (PyLong_BASE - 2*lsb) selects just the
786 significant bits of d[rnd_digit], d[rnd_digit] & (lsb-1) gets the
787 trailing bits, and d[rnd_digit] & lsb gives the rounding bit.
789 We initialize the double x to the integer given by digits
790 d[rnd_digit:m-1], but with the rounding bit and trailing bits of
791 d[rnd_digit] masked out. So the value of x comes from the top
792 DBL_MANT_DIG bits of v, multiplied by 2*lsb. Note that in the loop
793 that produces x, all floating-point operations are exact (assuming
794 that FLT_RADIX==2). Now if we're rounding down, the value we want
797 x * 2**(PyLong_SHIFT * rnd_digit).
799 and if we're rounding up, it's
801 (x + 2*lsb) * 2**(PyLong_SHIFT * rnd_digit).
803 Under the round-half-to-even rule, we round up if, and only
804 if, the rounding bit is set *and* at least one of the
805 following three conditions is satisfied:
807 (1) the parity bit is set, or
808 (2) at least one of the trailing bits of d[rnd_digit] is set, or
809 (3) at least one of the digits d[i], 0 <= i < rnd_digit
812 Finally, we have to worry about overflow. If v >= 2**DBL_MAX_EXP,
813 or equivalently n > DBL_MAX_EXP, then overflow occurs. If v <
814 2**DBL_MAX_EXP then we're usually safe, but there's a corner case
815 to consider: if v is very close to 2**DBL_MAX_EXP then it's
816 possible that v is rounded up to exactly 2**DBL_MAX_EXP, and then
817 again overflow occurs.
822 m
= ABS(Py_SIZE(v
)) - 1;
824 assert(d
[m
]); /* v should be normalized */
826 /* fast path for case where 0 < abs(v) < 2**DBL_MANT_DIG */
827 if (m
< DBL_MANT_DIG
/ PyLong_SHIFT
||
828 (m
== DBL_MANT_DIG
/ PyLong_SHIFT
&&
829 d
[m
] < (digit
)1 << DBL_MANT_DIG
%PyLong_SHIFT
)) {
832 x
= x
*PyLong_BASE
+ d
[m
];
833 return Py_SIZE(v
) < 0 ? -x
: x
;
836 /* if m is huge then overflow immediately; otherwise, compute the
837 number of bits n in v. The condition below implies n (= #bits) >=
838 m * PyLong_SHIFT + 1 > DBL_MAX_EXP, hence v >= 2**DBL_MAX_EXP. */
839 if (m
> (DBL_MAX_EXP
-1)/PyLong_SHIFT
)
841 n
= m
* PyLong_SHIFT
+ bits_in_digit(d
[m
]);
845 /* find location of rounding bit */
846 assert(n
> DBL_MANT_DIG
); /* dealt with |v| < 2**DBL_MANT_DIG above */
847 rnd_bit
= n
- DBL_MANT_DIG
- 1;
848 rnd_digit
= rnd_bit
/PyLong_SHIFT
;
849 lsb
= (digit
)1 << (rnd_bit
%PyLong_SHIFT
);
851 /* Get top DBL_MANT_DIG bits of v. Assumes PyLong_SHIFT <
852 DBL_MANT_DIG, so we'll need bits from at least 2 digits of v. */
854 assert(m
> rnd_digit
);
855 while (--m
> rnd_digit
)
856 x
= x
*PyLong_BASE
+ d
[m
];
857 x
= x
*PyLong_BASE
+ (d
[m
] & (PyLong_BASE
-2*lsb
));
859 /* decide whether to round up, using round-half-to-even */
860 assert(m
== rnd_digit
);
861 if (d
[m
] & lsb
) { /* if (rounding bit is set) */
863 if (lsb
== PyLong_BASE
/2)
864 parity_bit
= d
[m
+1] & 1;
866 parity_bit
= d
[m
] & 2*lsb
;
869 else if (d
[m
] & (lsb
-1))
881 /* and round up if necessary */
884 if (n
== DBL_MAX_EXP
&&
885 x
== ldexp((double)(2*lsb
), DBL_MANT_DIG
)) {
886 /* overflow corner case */
891 /* shift, adjust for sign, and return */
892 x
= ldexp(x
, rnd_digit
*PyLong_SHIFT
);
893 return Py_SIZE(v
) < 0 ? -x
: x
;
896 PyErr_SetString(PyExc_OverflowError
,
897 "long int too large to convert to float");
901 /* Create a new long (or int) object from a C pointer */
904 PyLong_FromVoidPtr(void *p
)
906 #if SIZEOF_VOID_P <= SIZEOF_LONG
908 return PyLong_FromUnsignedLong((unsigned long)p
);
909 return PyInt_FromLong((long)p
);
912 #ifndef HAVE_LONG_LONG
913 # error "PyLong_FromVoidPtr: sizeof(void*) > sizeof(long), but no long long"
915 #if SIZEOF_LONG_LONG < SIZEOF_VOID_P
916 # error "PyLong_FromVoidPtr: sizeof(PY_LONG_LONG) < sizeof(void*)"
918 /* optimize null pointers */
920 return PyInt_FromLong(0);
921 return PyLong_FromUnsignedLongLong((unsigned PY_LONG_LONG
)p
);
923 #endif /* SIZEOF_VOID_P <= SIZEOF_LONG */
926 /* Get a C pointer from a long object (or an int object in some cases) */
929 PyLong_AsVoidPtr(PyObject
*vv
)
931 /* This function will allow int or long objects. If vv is neither,
932 then the PyLong_AsLong*() functions will raise the exception:
933 PyExc_SystemError, "bad argument to internal function"
935 #if SIZEOF_VOID_P <= SIZEOF_LONG
939 x
= PyInt_AS_LONG(vv
);
940 else if (PyLong_Check(vv
) && _PyLong_Sign(vv
) < 0)
941 x
= PyLong_AsLong(vv
);
943 x
= PyLong_AsUnsignedLong(vv
);
946 #ifndef HAVE_LONG_LONG
947 # error "PyLong_AsVoidPtr: sizeof(void*) > sizeof(long), but no long long"
949 #if SIZEOF_LONG_LONG < SIZEOF_VOID_P
950 # error "PyLong_AsVoidPtr: sizeof(PY_LONG_LONG) < sizeof(void*)"
955 x
= PyInt_AS_LONG(vv
);
956 else if (PyLong_Check(vv
) && _PyLong_Sign(vv
) < 0)
957 x
= PyLong_AsLongLong(vv
);
959 x
= PyLong_AsUnsignedLongLong(vv
);
961 #endif /* SIZEOF_VOID_P <= SIZEOF_LONG */
963 if (x
== -1 && PyErr_Occurred())
968 #ifdef HAVE_LONG_LONG
970 /* Initial PY_LONG_LONG support by Chris Herborth (chrish@qnx.com), later
971 * rewritten to use the newer PyLong_{As,From}ByteArray API.
974 #define IS_LITTLE_ENDIAN (int)*(unsigned char*)&one
976 /* Create a new long int object from a C PY_LONG_LONG int. */
979 PyLong_FromLongLong(PY_LONG_LONG ival
)
982 unsigned PY_LONG_LONG abs_ival
;
983 unsigned PY_LONG_LONG t
; /* unsigned so >> doesn't propagate sign bit */
988 /* avoid signed overflow on negation; see comments
989 in PyLong_FromLong above. */
990 abs_ival
= (unsigned PY_LONG_LONG
)(-1-ival
) + 1;
994 abs_ival
= (unsigned PY_LONG_LONG
)ival
;
997 /* Count the number of Python digits.
998 We used to pick 5 ("big enough for anything"), but that's a
999 waste of time and space given that 5*15 = 75 bits are rarely
1006 v
= _PyLong_New(ndigits
);
1008 digit
*p
= v
->ob_digit
;
1009 Py_SIZE(v
) = negative
? -ndigits
: ndigits
;
1012 *p
++ = (digit
)(t
& PyLong_MASK
);
1016 return (PyObject
*)v
;
1019 /* Create a new long int object from a C unsigned PY_LONG_LONG int. */
1022 PyLong_FromUnsignedLongLong(unsigned PY_LONG_LONG ival
)
1025 unsigned PY_LONG_LONG t
;
1028 /* Count the number of Python digits. */
1029 t
= (unsigned PY_LONG_LONG
)ival
;
1034 v
= _PyLong_New(ndigits
);
1036 digit
*p
= v
->ob_digit
;
1037 Py_SIZE(v
) = ndigits
;
1039 *p
++ = (digit
)(ival
& PyLong_MASK
);
1040 ival
>>= PyLong_SHIFT
;
1043 return (PyObject
*)v
;
1046 /* Create a new long int object from a C Py_ssize_t. */
1049 PyLong_FromSsize_t(Py_ssize_t ival
)
1051 Py_ssize_t bytes
= ival
;
1053 return _PyLong_FromByteArray(
1054 (unsigned char *)&bytes
,
1055 SIZEOF_SIZE_T
, IS_LITTLE_ENDIAN
, 1);
1058 /* Create a new long int object from a C size_t. */
1061 PyLong_FromSize_t(size_t ival
)
1063 size_t bytes
= ival
;
1065 return _PyLong_FromByteArray(
1066 (unsigned char *)&bytes
,
1067 SIZEOF_SIZE_T
, IS_LITTLE_ENDIAN
, 0);
1070 /* Get a C PY_LONG_LONG int from a long int object.
1071 Return -1 and set an error if overflow occurs. */
1074 PyLong_AsLongLong(PyObject
*vv
)
1081 PyErr_BadInternalCall();
1084 if (!PyLong_Check(vv
)) {
1085 PyNumberMethods
*nb
;
1087 if (PyInt_Check(vv
))
1088 return (PY_LONG_LONG
)PyInt_AsLong(vv
);
1089 if ((nb
= vv
->ob_type
->tp_as_number
) == NULL
||
1090 nb
->nb_int
== NULL
) {
1091 PyErr_SetString(PyExc_TypeError
, "an integer is required");
1094 io
= (*nb
->nb_int
) (vv
);
1097 if (PyInt_Check(io
)) {
1098 bytes
= PyInt_AsLong(io
);
1102 if (PyLong_Check(io
)) {
1103 bytes
= PyLong_AsLongLong(io
);
1108 PyErr_SetString(PyExc_TypeError
, "integer conversion failed");
1112 res
= _PyLong_AsByteArray(
1113 (PyLongObject
*)vv
, (unsigned char *)&bytes
,
1114 SIZEOF_LONG_LONG
, IS_LITTLE_ENDIAN
, 1);
1116 /* Plan 9 can't handle PY_LONG_LONG in ? : expressions */
1118 return (PY_LONG_LONG
)-1;
1123 /* Get a C unsigned PY_LONG_LONG int from a long int object.
1124 Return -1 and set an error if overflow occurs. */
1126 unsigned PY_LONG_LONG
1127 PyLong_AsUnsignedLongLong(PyObject
*vv
)
1129 unsigned PY_LONG_LONG bytes
;
1133 if (vv
== NULL
|| !PyLong_Check(vv
)) {
1134 PyErr_BadInternalCall();
1135 return (unsigned PY_LONG_LONG
)-1;
1138 res
= _PyLong_AsByteArray(
1139 (PyLongObject
*)vv
, (unsigned char *)&bytes
,
1140 SIZEOF_LONG_LONG
, IS_LITTLE_ENDIAN
, 0);
1142 /* Plan 9 can't handle PY_LONG_LONG in ? : expressions */
1144 return (unsigned PY_LONG_LONG
)res
;
1149 /* Get a C unsigned long int from a long int object, ignoring the high bits.
1150 Returns -1 and sets an error condition if an error occurs. */
1152 unsigned PY_LONG_LONG
1153 PyLong_AsUnsignedLongLongMask(PyObject
*vv
)
1155 register PyLongObject
*v
;
1156 unsigned PY_LONG_LONG x
;
1160 if (vv
== NULL
|| !PyLong_Check(vv
)) {
1161 PyErr_BadInternalCall();
1162 return (unsigned long) -1;
1164 v
= (PyLongObject
*)vv
;
1173 x
= (x
<< PyLong_SHIFT
) + v
->ob_digit
[i
];
1177 #undef IS_LITTLE_ENDIAN
1179 #endif /* HAVE_LONG_LONG */
1183 convert_binop(PyObject
*v
, PyObject
*w
, PyLongObject
**a
, PyLongObject
**b
) {
1184 if (PyLong_Check(v
)) {
1185 *a
= (PyLongObject
*) v
;
1188 else if (PyInt_Check(v
)) {
1189 *a
= (PyLongObject
*) PyLong_FromLong(PyInt_AS_LONG(v
));
1194 if (PyLong_Check(w
)) {
1195 *b
= (PyLongObject
*) w
;
1198 else if (PyInt_Check(w
)) {
1199 *b
= (PyLongObject
*) PyLong_FromLong(PyInt_AS_LONG(w
));
1208 #define CONVERT_BINOP(v, w, a, b) \
1209 if (!convert_binop(v, w, a, b)) { \
1210 Py_INCREF(Py_NotImplemented); \
1211 return Py_NotImplemented; \
1214 /* bits_in_digit(d) returns the unique integer k such that 2**(k-1) <= d <
1215 2**k if d is nonzero, else 0. */
1217 static const unsigned char BitLengthTable
[32] = {
1218 0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4,
1219 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
1223 bits_in_digit(digit d
)
1230 d_bits
+= (int)BitLengthTable
[d
];
1234 /* x[0:m] and y[0:n] are digit vectors, LSD first, m >= n required. x[0:n]
1235 * is modified in place, by adding y to it. Carries are propagated as far as
1236 * x[m-1], and the remaining carry (0 or 1) is returned.
1239 v_iadd(digit
*x
, Py_ssize_t m
, digit
*y
, Py_ssize_t n
)
1245 for (i
= 0; i
< n
; ++i
) {
1246 carry
+= x
[i
] + y
[i
];
1247 x
[i
] = carry
& PyLong_MASK
;
1248 carry
>>= PyLong_SHIFT
;
1249 assert((carry
& 1) == carry
);
1251 for (; carry
&& i
< m
; ++i
) {
1253 x
[i
] = carry
& PyLong_MASK
;
1254 carry
>>= PyLong_SHIFT
;
1255 assert((carry
& 1) == carry
);
1260 /* x[0:m] and y[0:n] are digit vectors, LSD first, m >= n required. x[0:n]
1261 * is modified in place, by subtracting y from it. Borrows are propagated as
1262 * far as x[m-1], and the remaining borrow (0 or 1) is returned.
1265 v_isub(digit
*x
, Py_ssize_t m
, digit
*y
, Py_ssize_t n
)
1271 for (i
= 0; i
< n
; ++i
) {
1272 borrow
= x
[i
] - y
[i
] - borrow
;
1273 x
[i
] = borrow
& PyLong_MASK
;
1274 borrow
>>= PyLong_SHIFT
;
1275 borrow
&= 1; /* keep only 1 sign bit */
1277 for (; borrow
&& i
< m
; ++i
) {
1278 borrow
= x
[i
] - borrow
;
1279 x
[i
] = borrow
& PyLong_MASK
;
1280 borrow
>>= PyLong_SHIFT
;
1286 /* Shift digit vector a[0:m] d bits left, with 0 <= d < PyLong_SHIFT. Put
1287 * result in z[0:m], and return the d bits shifted out of the top.
1290 v_lshift(digit
*z
, digit
*a
, Py_ssize_t m
, int d
)
1295 assert(0 <= d
&& d
< PyLong_SHIFT
);
1296 for (i
=0; i
< m
; i
++) {
1297 twodigits acc
= (twodigits
)a
[i
] << d
| carry
;
1298 z
[i
] = (digit
)acc
& PyLong_MASK
;
1299 carry
= (digit
)(acc
>> PyLong_SHIFT
);
1304 /* Shift digit vector a[0:m] d bits right, with 0 <= d < PyLong_SHIFT. Put
1305 * result in z[0:m], and return the d bits shifted out of the bottom.
1308 v_rshift(digit
*z
, digit
*a
, Py_ssize_t m
, int d
)
1312 digit mask
= ((digit
)1 << d
) - 1U;
1314 assert(0 <= d
&& d
< PyLong_SHIFT
);
1315 for (i
=m
; i
-- > 0;) {
1316 twodigits acc
= (twodigits
)carry
<< PyLong_SHIFT
| a
[i
];
1317 carry
= (digit
)acc
& mask
;
1318 z
[i
] = (digit
)(acc
>> d
);
1323 /* Divide long pin, w/ size digits, by non-zero digit n, storing quotient
1324 in pout, and returning the remainder. pin and pout point at the LSD.
1325 It's OK for pin == pout on entry, which saves oodles of mallocs/frees in
1326 _PyLong_Format, but that should be done with great care since longs are
1330 inplace_divrem1(digit
*pout
, digit
*pin
, Py_ssize_t size
, digit n
)
1334 assert(n
> 0 && n
<= PyLong_MASK
);
1337 while (--size
>= 0) {
1339 rem
= (rem
<< PyLong_SHIFT
) + *--pin
;
1340 *--pout
= hi
= (digit
)(rem
/ n
);
1341 rem
-= (twodigits
)hi
* n
;
1346 /* Divide a long integer by a digit, returning both the quotient
1347 (as function result) and the remainder (through *prem).
1348 The sign of a is ignored; n should not be zero. */
1350 static PyLongObject
*
1351 divrem1(PyLongObject
*a
, digit n
, digit
*prem
)
1353 const Py_ssize_t size
= ABS(Py_SIZE(a
));
1356 assert(n
> 0 && n
<= PyLong_MASK
);
1357 z
= _PyLong_New(size
);
1360 *prem
= inplace_divrem1(z
->ob_digit
, a
->ob_digit
, size
, n
);
1361 return long_normalize(z
);
1364 /* Convert a long integer to a base 10 string. Returns a new non-shared
1365 string. (Return value is non-shared so that callers can modify the
1366 returned value if necessary.) */
1369 long_to_decimal_string(PyObject
*aa
, int addL
)
1371 PyLongObject
*scratch
, *a
;
1373 Py_ssize_t size
, strlen
, size_a
, i
, j
;
1374 digit
*pout
, *pin
, rem
, tenpow
;
1378 a
= (PyLongObject
*)aa
;
1379 if (a
== NULL
|| !PyLong_Check(a
)) {
1380 PyErr_BadInternalCall();
1383 size_a
= ABS(Py_SIZE(a
));
1384 negative
= Py_SIZE(a
) < 0;
1386 /* quick and dirty upper bound for the number of digits
1387 required to express a in base _PyLong_DECIMAL_BASE:
1389 #digits = 1 + floor(log2(a) / log2(_PyLong_DECIMAL_BASE))
1391 But log2(a) < size_a * PyLong_SHIFT, and
1392 log2(_PyLong_DECIMAL_BASE) = log2(10) * _PyLong_DECIMAL_SHIFT
1393 > 3 * _PyLong_DECIMAL_SHIFT
1395 if (size_a
> PY_SSIZE_T_MAX
/ PyLong_SHIFT
) {
1396 PyErr_SetString(PyExc_OverflowError
,
1397 "long is too large to format");
1400 /* the expression size_a * PyLong_SHIFT is now safe from overflow */
1401 size
= 1 + size_a
* PyLong_SHIFT
/ (3 * _PyLong_DECIMAL_SHIFT
);
1402 scratch
= _PyLong_New(size
);
1403 if (scratch
== NULL
)
1406 /* convert array of base _PyLong_BASE digits in pin to an array of
1407 base _PyLong_DECIMAL_BASE digits in pout, following Knuth (TAOCP,
1408 Volume 2 (3rd edn), section 4.4, Method 1b). */
1410 pout
= scratch
->ob_digit
;
1412 for (i
= size_a
; --i
>= 0; ) {
1414 for (j
= 0; j
< size
; j
++) {
1415 twodigits z
= (twodigits
)pout
[j
] << PyLong_SHIFT
| hi
;
1416 hi
= z
/ _PyLong_DECIMAL_BASE
;
1417 pout
[j
] = z
- (twodigits
)hi
* _PyLong_DECIMAL_BASE
;
1420 pout
[size
++] = hi
% _PyLong_DECIMAL_BASE
;
1421 hi
/= _PyLong_DECIMAL_BASE
;
1423 /* check for keyboard interrupt */
1429 /* pout should have at least one digit, so that the case when a = 0
1434 /* calculate exact length of output string, and allocate */
1435 strlen
= (addL
!= 0) + negative
+
1436 1 + (size
- 1) * _PyLong_DECIMAL_SHIFT
;
1439 while (rem
>= tenpow
) {
1443 str
= PyString_FromStringAndSize(NULL
, strlen
);
1449 /* fill the string right-to-left */
1450 p
= PyString_AS_STRING(str
) + strlen
;
1454 /* pout[0] through pout[size-2] contribute exactly
1455 _PyLong_DECIMAL_SHIFT digits each */
1456 for (i
=0; i
< size
- 1; i
++) {
1458 for (j
= 0; j
< _PyLong_DECIMAL_SHIFT
; j
++) {
1459 *--p
= '0' + rem
% 10;
1463 /* pout[size-1]: always produce at least one decimal digit */
1466 *--p
= '0' + rem
% 10;
1474 /* check we've counted correctly */
1475 assert(p
== PyString_AS_STRING(str
));
1477 return (PyObject
*)str
;
1480 /* Convert the long to a string object with given base,
1481 appending a base prefix of 0[box] if base is 2, 8 or 16.
1482 Add a trailing "L" if addL is non-zero.
1483 If newstyle is zero, then use the pre-2.6 behavior of octal having
1484 a leading "0", instead of the prefix "0o" */
1485 PyAPI_FUNC(PyObject
*)
1486 _PyLong_Format(PyObject
*aa
, int base
, int addL
, int newstyle
)
1488 register PyLongObject
*a
= (PyLongObject
*)aa
;
1489 PyStringObject
*str
;
1497 return long_to_decimal_string((PyObject
*)a
, addL
);
1499 if (a
== NULL
|| !PyLong_Check(a
)) {
1500 PyErr_BadInternalCall();
1503 assert(base
>= 2 && base
<= 36);
1504 size_a
= ABS(Py_SIZE(a
));
1506 /* Compute a rough upper bound for the length of the string */
1513 i
= 5 + (addL
? 1 : 0);
1514 /* ensure we don't get signed overflow in sz calculation */
1515 if (size_a
> (PY_SSIZE_T_MAX
- i
) / PyLong_SHIFT
) {
1516 PyErr_SetString(PyExc_OverflowError
,
1517 "long is too large to format");
1520 sz
= i
+ 1 + (size_a
* PyLong_SHIFT
- 1) / bits
;
1522 str
= (PyStringObject
*) PyString_FromStringAndSize((char *)0, sz
);
1525 p
= PyString_AS_STRING(str
) + sz
;
1532 if (a
->ob_size
== 0) {
1535 else if ((base
& (base
- 1)) == 0) {
1536 /* JRH: special case for power-of-2 bases */
1537 twodigits accum
= 0;
1538 int accumbits
= 0; /* # of bits in accum */
1539 int basebits
= 1; /* # of bits in base-1 */
1541 while ((i
>>= 1) > 1)
1544 for (i
= 0; i
< size_a
; ++i
) {
1545 accum
|= (twodigits
)a
->ob_digit
[i
] << accumbits
;
1546 accumbits
+= PyLong_SHIFT
;
1547 assert(accumbits
>= basebits
);
1549 char cdigit
= (char)(accum
& (base
- 1));
1550 cdigit
+= (cdigit
< 10) ? '0' : 'a'-10;
1551 assert(p
> PyString_AS_STRING(str
));
1553 accumbits
-= basebits
;
1555 } while (i
< size_a
-1 ? accumbits
>= basebits
:
1560 /* Not 0, and base not a power of 2. Divide repeatedly by
1561 base, but for speed use the highest power of base that
1563 Py_ssize_t size
= size_a
;
1564 digit
*pin
= a
->ob_digit
;
1565 PyLongObject
*scratch
;
1566 /* powbasw <- largest power of base that fits in a digit. */
1567 digit powbase
= base
; /* powbase == base ** power */
1570 twodigits newpow
= powbase
* (twodigits
)base
;
1571 if (newpow
>> PyLong_SHIFT
)
1572 /* doesn't fit in a digit */
1574 powbase
= (digit
)newpow
;
1578 /* Get a scratch area for repeated division. */
1579 scratch
= _PyLong_New(size
);
1580 if (scratch
== NULL
) {
1585 /* Repeatedly divide by powbase. */
1587 int ntostore
= power
;
1588 digit rem
= inplace_divrem1(scratch
->ob_digit
,
1589 pin
, size
, powbase
);
1590 pin
= scratch
->ob_digit
; /* no need to use a again */
1591 if (pin
[size
- 1] == 0)
1599 /* Break rem into digits. */
1600 assert(ntostore
> 0);
1602 digit nextrem
= (digit
)(rem
/ base
);
1603 char c
= (char)(rem
- nextrem
* base
);
1604 assert(p
> PyString_AS_STRING(str
));
1605 c
+= (c
< 10) ? '0' : 'a'-10;
1609 /* Termination is a bit delicate: must not
1610 store leading zeroes, so must get out if
1611 remaining quotient and rem are both 0. */
1612 } while (ntostore
&& (size
|| rem
));
1613 } while (size
!= 0);
1621 else if (base
== 8) {
1630 else if (base
== 16) {
1634 else if (base
!= 10) {
1636 *--p
= '0' + base
%10;
1638 *--p
= '0' + base
/10;
1642 if (p
!= PyString_AS_STRING(str
)) {
1643 char *q
= PyString_AS_STRING(str
);
1646 } while ((*q
++ = *p
++) != '\0');
1648 _PyString_Resize((PyObject
**)&str
,
1649 (Py_ssize_t
) (q
- PyString_AS_STRING(str
)));
1651 return (PyObject
*)str
;
1654 /* Table of digit values for 8-bit string -> integer conversion.
1655 * '0' maps to 0, ..., '9' maps to 9.
1656 * 'a' and 'A' map to 10, ..., 'z' and 'Z' map to 35.
1657 * All other indices map to 37.
1658 * Note that when converting a base B string, a char c is a legitimate
1659 * base B digit iff _PyLong_DigitValue[Py_CHARMASK(c)] < B.
1661 int _PyLong_DigitValue
[256] = {
1662 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1663 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1664 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1665 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 37, 37, 37, 37, 37, 37,
1666 37, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24,
1667 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 37, 37, 37, 37,
1668 37, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24,
1669 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 37, 37, 37, 37,
1670 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1671 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1672 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1673 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1674 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1675 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1676 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1677 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37, 37,
1680 /* *str points to the first digit in a string of base `base` digits. base
1681 * is a power of 2 (2, 4, 8, 16, or 32). *str is set to point to the first
1682 * non-digit (which may be *str!). A normalized long is returned.
1683 * The point to this routine is that it takes time linear in the number of
1684 * string characters.
1686 static PyLongObject
*
1687 long_from_binary_base(char **str
, int base
)
1698 assert(base
>= 2 && base
<= 32 && (base
& (base
- 1)) == 0);
1700 for (bits_per_char
= -1; n
; ++bits_per_char
)
1702 /* n <- total # of bits needed, while setting p to end-of-string */
1703 while (_PyLong_DigitValue
[Py_CHARMASK(*p
)] < base
)
1706 /* n <- # of Python digits needed, = ceiling(n/PyLong_SHIFT). */
1707 n
= (p
- start
) * bits_per_char
+ PyLong_SHIFT
- 1;
1708 if (n
/ bits_per_char
< p
- start
) {
1709 PyErr_SetString(PyExc_ValueError
,
1710 "long string too large to convert");
1713 n
= n
/ PyLong_SHIFT
;
1717 /* Read string from right, and fill in long from left; i.e.,
1718 * from least to most significant in both.
1722 pdigit
= z
->ob_digit
;
1723 while (--p
>= start
) {
1724 int k
= _PyLong_DigitValue
[Py_CHARMASK(*p
)];
1725 assert(k
>= 0 && k
< base
);
1726 accum
|= (twodigits
)k
<< bits_in_accum
;
1727 bits_in_accum
+= bits_per_char
;
1728 if (bits_in_accum
>= PyLong_SHIFT
) {
1729 *pdigit
++ = (digit
)(accum
& PyLong_MASK
);
1730 assert(pdigit
- z
->ob_digit
<= n
);
1731 accum
>>= PyLong_SHIFT
;
1732 bits_in_accum
-= PyLong_SHIFT
;
1733 assert(bits_in_accum
< PyLong_SHIFT
);
1736 if (bits_in_accum
) {
1737 assert(bits_in_accum
<= PyLong_SHIFT
);
1738 *pdigit
++ = (digit
)accum
;
1739 assert(pdigit
- z
->ob_digit
<= n
);
1741 while (pdigit
- z
->ob_digit
< n
)
1743 return long_normalize(z
);
1747 PyLong_FromString(char *str
, char **pend
, int base
)
1750 char *start
, *orig_str
= str
;
1752 PyObject
*strobj
, *strrepr
;
1755 if ((base
!= 0 && base
< 2) || base
> 36) {
1756 PyErr_SetString(PyExc_ValueError
,
1757 "long() arg 2 must be >= 2 and <= 36");
1760 while (*str
!= '\0' && isspace(Py_CHARMASK(*str
)))
1764 else if (*str
== '-') {
1768 while (*str
!= '\0' && isspace(Py_CHARMASK(*str
)))
1771 /* No base given. Deduce the base from the contents
1775 else if (str
[1] == 'x' || str
[1] == 'X')
1777 else if (str
[1] == 'o' || str
[1] == 'O')
1779 else if (str
[1] == 'b' || str
[1] == 'B')
1782 /* "old" (C-style) octal literal, still valid in
1783 2.x, although illegal in 3.x */
1786 /* Whether or not we were deducing the base, skip leading chars
1788 if (str
[0] == '0' &&
1789 ((base
== 16 && (str
[1] == 'x' || str
[1] == 'X')) ||
1790 (base
== 8 && (str
[1] == 'o' || str
[1] == 'O')) ||
1791 (base
== 2 && (str
[1] == 'b' || str
[1] == 'B'))))
1795 if ((base
& (base
- 1)) == 0)
1796 z
= long_from_binary_base(&str
, base
);
1799 Binary bases can be converted in time linear in the number of digits, because
1800 Python's representation base is binary. Other bases (including decimal!) use
1801 the simple quadratic-time algorithm below, complicated by some speed tricks.
1803 First some math: the largest integer that can be expressed in N base-B digits
1804 is B**N-1. Consequently, if we have an N-digit input in base B, the worst-
1805 case number of Python digits needed to hold it is the smallest integer n s.t.
1807 PyLong_BASE**n-1 >= B**N-1 [or, adding 1 to both sides]
1808 PyLong_BASE**n >= B**N [taking logs to base PyLong_BASE]
1809 n >= log(B**N)/log(PyLong_BASE) = N * log(B)/log(PyLong_BASE)
1811 The static array log_base_PyLong_BASE[base] == log(base)/log(PyLong_BASE) so we can compute
1812 this quickly. A Python long with that much space is reserved near the start,
1813 and the result is computed into it.
1815 The input string is actually treated as being in base base**i (i.e., i digits
1816 are processed at a time), where two more static arrays hold:
1818 convwidth_base[base] = the largest integer i such that base**i <= PyLong_BASE
1819 convmultmax_base[base] = base ** convwidth_base[base]
1821 The first of these is the largest i such that i consecutive input digits
1822 must fit in a single Python digit. The second is effectively the input
1823 base we're really using.
1825 Viewing the input as a sequence <c0, c1, ..., c_n-1> of digits in base
1826 convmultmax_base[base], the result is "simply"
1828 (((c0*B + c1)*B + c2)*B + c3)*B + ... ))) + c_n-1
1830 where B = convmultmax_base[base].
1832 Error analysis: as above, the number of Python digits `n` needed is worst-
1835 n >= N * log(B)/log(PyLong_BASE)
1837 where `N` is the number of input digits in base `B`. This is computed via
1839 size_z = (Py_ssize_t)((scan - str) * log_base_PyLong_BASE[base]) + 1;
1841 below. Two numeric concerns are how much space this can waste, and whether
1842 the computed result can be too small. To be concrete, assume PyLong_BASE = 2**15,
1843 which is the default (and it's unlikely anyone changes that).
1845 Waste isn't a problem: provided the first input digit isn't 0, the difference
1846 between the worst-case input with N digits and the smallest input with N
1847 digits is about a factor of B, but B is small compared to PyLong_BASE so at most
1848 one allocated Python digit can remain unused on that count. If
1849 N*log(B)/log(PyLong_BASE) is mathematically an exact integer, then truncating that
1850 and adding 1 returns a result 1 larger than necessary. However, that can't
1851 happen: whenever B is a power of 2, long_from_binary_base() is called
1852 instead, and it's impossible for B**i to be an integer power of 2**15 when
1853 B is not a power of 2 (i.e., it's impossible for N*log(B)/log(PyLong_BASE) to be
1854 an exact integer when B is not a power of 2, since B**i has a prime factor
1855 other than 2 in that case, but (2**15)**j's only prime factor is 2).
1857 The computed result can be too small if the true value of N*log(B)/log(PyLong_BASE)
1858 is a little bit larger than an exact integer, but due to roundoff errors (in
1859 computing log(B), log(PyLong_BASE), their quotient, and/or multiplying that by N)
1860 yields a numeric result a little less than that integer. Unfortunately, "how
1861 close can a transcendental function get to an integer over some range?"
1862 questions are generally theoretically intractable. Computer analysis via
1863 continued fractions is practical: expand log(B)/log(PyLong_BASE) via continued
1864 fractions, giving a sequence i/j of "the best" rational approximations. Then
1865 j*log(B)/log(PyLong_BASE) is approximately equal to (the integer) i. This shows that
1866 we can get very close to being in trouble, but very rarely. For example,
1867 76573 is a denominator in one of the continued-fraction approximations to
1868 log(10)/log(2**15), and indeed:
1870 >>> log(10)/log(2**15)*76573
1873 is very close to an integer. If we were working with IEEE single-precision,
1874 rounding errors could kill us. Finding worst cases in IEEE double-precision
1875 requires better-than-double-precision log() functions, and Tim didn't bother.
1876 Instead the code checks to see whether the allocated space is enough as each
1877 new Python digit is added, and copies the whole thing to a larger long if not.
1878 This should happen extremely rarely, and in fact I don't have a test case
1879 that triggers it(!). Instead the code was tested by artificially allocating
1880 just 1 digit at the start, so that the copying code was exercised for every
1881 digit beyond the first.
1883 register twodigits c
; /* current input character */
1887 twodigits convmultmax
, convmult
;
1891 static double log_base_PyLong_BASE
[37] = {0.0e0
,};
1892 static int convwidth_base
[37] = {0,};
1893 static twodigits convmultmax_base
[37] = {0,};
1895 if (log_base_PyLong_BASE
[base
] == 0.0) {
1896 twodigits convmax
= base
;
1899 log_base_PyLong_BASE
[base
] = log((double)base
) /
1900 log((double)PyLong_BASE
);
1902 twodigits next
= convmax
* base
;
1903 if (next
> PyLong_BASE
)
1908 convmultmax_base
[base
] = convmax
;
1910 convwidth_base
[base
] = i
;
1913 /* Find length of the string of numeric characters. */
1915 while (_PyLong_DigitValue
[Py_CHARMASK(*scan
)] < base
)
1918 /* Create a long object that can contain the largest possible
1919 * integer with this base and length. Note that there's no
1920 * need to initialize z->ob_digit -- no slot is read up before
1921 * being stored into.
1923 size_z
= (Py_ssize_t
)((scan
- str
) * log_base_PyLong_BASE
[base
]) + 1;
1924 /* Uncomment next line to test exceedingly rare copy code */
1927 z
= _PyLong_New(size_z
);
1932 /* `convwidth` consecutive input digits are treated as a single
1933 * digit in base `convmultmax`.
1935 convwidth
= convwidth_base
[base
];
1936 convmultmax
= convmultmax_base
[base
];
1939 while (str
< scan
) {
1940 /* grab up to convwidth digits from the input string */
1941 c
= (digit
)_PyLong_DigitValue
[Py_CHARMASK(*str
++)];
1942 for (i
= 1; i
< convwidth
&& str
!= scan
; ++i
, ++str
) {
1943 c
= (twodigits
)(c
* base
+
1944 _PyLong_DigitValue
[Py_CHARMASK(*str
)]);
1945 assert(c
< PyLong_BASE
);
1948 convmult
= convmultmax
;
1949 /* Calculate the shift only if we couldn't get
1952 if (i
!= convwidth
) {
1958 /* Multiply z by convmult, and add c. */
1960 pzstop
= pz
+ Py_SIZE(z
);
1961 for (; pz
< pzstop
; ++pz
) {
1962 c
+= (twodigits
)*pz
* convmult
;
1963 *pz
= (digit
)(c
& PyLong_MASK
);
1966 /* carry off the current end? */
1968 assert(c
< PyLong_BASE
);
1969 if (Py_SIZE(z
) < size_z
) {
1975 /* Extremely rare. Get more space. */
1976 assert(Py_SIZE(z
) == size_z
);
1977 tmp
= _PyLong_New(size_z
+ 1);
1982 memcpy(tmp
->ob_digit
,
1984 sizeof(digit
) * size_z
);
1987 z
->ob_digit
[size_z
] = (digit
)c
;
1998 Py_SIZE(z
) = -(Py_SIZE(z
));
1999 if (*str
== 'L' || *str
== 'l')
2001 while (*str
&& isspace(Py_CHARMASK(*str
)))
2007 return (PyObject
*) z
;
2011 slen
= strlen(orig_str
) < 200 ? strlen(orig_str
) : 200;
2012 strobj
= PyString_FromStringAndSize(orig_str
, slen
);
2015 strrepr
= PyObject_Repr(strobj
);
2017 if (strrepr
== NULL
)
2019 PyErr_Format(PyExc_ValueError
,
2020 "invalid literal for long() with base %d: %s",
2021 base
, PyString_AS_STRING(strrepr
));
2026 #ifdef Py_USING_UNICODE
2028 PyLong_FromUnicode(Py_UNICODE
*u
, Py_ssize_t length
, int base
)
2031 char *buffer
= (char *)PyMem_MALLOC(length
+1);
2036 if (PyUnicode_EncodeDecimal(u
, length
, buffer
, NULL
)) {
2040 result
= PyLong_FromString(buffer
, NULL
, base
);
2047 static PyLongObject
*x_divrem
2048 (PyLongObject
*, PyLongObject
*, PyLongObject
**);
2049 static PyObject
*long_long(PyObject
*v
);
2051 /* Long division with remainder, top-level routine */
2054 long_divrem(PyLongObject
*a
, PyLongObject
*b
,
2055 PyLongObject
**pdiv
, PyLongObject
**prem
)
2057 Py_ssize_t size_a
= ABS(Py_SIZE(a
)), size_b
= ABS(Py_SIZE(b
));
2061 PyErr_SetString(PyExc_ZeroDivisionError
,
2062 "long division or modulo by zero");
2065 if (size_a
< size_b
||
2066 (size_a
== size_b
&&
2067 a
->ob_digit
[size_a
-1] < b
->ob_digit
[size_b
-1])) {
2069 *pdiv
= _PyLong_New(0);
2073 *prem
= (PyLongObject
*) a
;
2078 z
= divrem1(a
, b
->ob_digit
[0], &rem
);
2081 *prem
= (PyLongObject
*) PyLong_FromLong((long)rem
);
2082 if (*prem
== NULL
) {
2088 z
= x_divrem(a
, b
, prem
);
2093 The quotient z has the sign of a*b;
2094 the remainder r has the sign of a,
2096 if ((a
->ob_size
< 0) != (b
->ob_size
< 0))
2097 z
->ob_size
= -(z
->ob_size
);
2098 if (a
->ob_size
< 0 && (*prem
)->ob_size
!= 0)
2099 (*prem
)->ob_size
= -((*prem
)->ob_size
);
2104 /* Unsigned long division with remainder -- the algorithm. The arguments v1
2105 and w1 should satisfy 2 <= ABS(Py_SIZE(w1)) <= ABS(Py_SIZE(v1)). */
2107 static PyLongObject
*
2108 x_divrem(PyLongObject
*v1
, PyLongObject
*w1
, PyLongObject
**prem
)
2110 PyLongObject
*v
, *w
, *a
;
2111 Py_ssize_t i
, k
, size_v
, size_w
;
2113 digit wm1
, wm2
, carry
, q
, r
, vtop
, *v0
, *vk
, *w0
, *ak
;
2118 /* We follow Knuth [The Art of Computer Programming, Vol. 2 (3rd
2119 edn.), section 4.3.1, Algorithm D], except that we don't explicitly
2120 handle the special case when the initial estimate q for a quotient
2121 digit is >= PyLong_BASE: the max value for q is PyLong_BASE+1, and
2122 that won't overflow a digit. */
2124 /* allocate space; w will also be used to hold the final remainder */
2125 size_v
= ABS(Py_SIZE(v1
));
2126 size_w
= ABS(Py_SIZE(w1
));
2127 assert(size_v
>= size_w
&& size_w
>= 2); /* Assert checks by div() */
2128 v
= _PyLong_New(size_v
+1);
2133 w
= _PyLong_New(size_w
);
2140 /* normalize: shift w1 left so that its top digit is >= PyLong_BASE/2.
2141 shift v1 left by the same amount. Results go into w and v. */
2142 d
= PyLong_SHIFT
- bits_in_digit(w1
->ob_digit
[size_w
-1]);
2143 carry
= v_lshift(w
->ob_digit
, w1
->ob_digit
, size_w
, d
);
2145 carry
= v_lshift(v
->ob_digit
, v1
->ob_digit
, size_v
, d
);
2146 if (carry
!= 0 || v
->ob_digit
[size_v
-1] >= w
->ob_digit
[size_w
-1]) {
2147 v
->ob_digit
[size_v
] = carry
;
2151 /* Now v->ob_digit[size_v-1] < w->ob_digit[size_w-1], so quotient has
2152 at most (and usually exactly) k = size_v - size_w digits. */
2153 k
= size_v
- size_w
;
2166 for (vk
= v0
+k
, ak
= a
->ob_digit
+ k
; vk
-- > v0
;) {
2167 /* inner loop: divide vk[0:size_w+1] by w0[0:size_w], giving
2168 single-digit quotient q, remainder in vk[0:size_w]. */
2178 /* estimate quotient digit q; may overestimate by 1 (rare) */
2180 assert(vtop
<= wm1
);
2181 vv
= ((twodigits
)vtop
<< PyLong_SHIFT
) | vk
[size_w
-1];
2182 q
= (digit
)(vv
/ wm1
);
2183 r
= (digit
)(vv
- (twodigits
)wm1
* q
); /* r = vv % wm1 */
2184 while ((twodigits
)wm2
* q
> (((twodigits
)r
<< PyLong_SHIFT
)
2188 if (r
>= PyLong_BASE
)
2191 assert(q
<= PyLong_BASE
);
2193 /* subtract q*w0[0:size_w] from vk[0:size_w+1] */
2195 for (i
= 0; i
< size_w
; ++i
) {
2196 /* invariants: -PyLong_BASE <= -q <= zhi <= 0;
2197 -PyLong_BASE * q <= z < PyLong_BASE */
2198 z
= (sdigit
)vk
[i
] + zhi
-
2199 (stwodigits
)q
* (stwodigits
)w0
[i
];
2200 vk
[i
] = (digit
)z
& PyLong_MASK
;
2201 zhi
= (sdigit
)Py_ARITHMETIC_RIGHT_SHIFT(stwodigits
,
2205 /* add w back if q was too large (this branch taken rarely) */
2206 assert((sdigit
)vtop
+ zhi
== -1 || (sdigit
)vtop
+ zhi
== 0);
2207 if ((sdigit
)vtop
+ zhi
< 0) {
2209 for (i
= 0; i
< size_w
; ++i
) {
2210 carry
+= vk
[i
] + w0
[i
];
2211 vk
[i
] = carry
& PyLong_MASK
;
2212 carry
>>= PyLong_SHIFT
;
2217 /* store quotient digit */
2218 assert(q
< PyLong_BASE
);
2222 /* unshift remainder; we reuse w to store the result */
2223 carry
= v_rshift(w0
, v0
, size_w
, d
);
2227 *prem
= long_normalize(w
);
2228 return long_normalize(a
);
2234 long_dealloc(PyObject
*v
)
2236 Py_TYPE(v
)->tp_free(v
);
2240 long_repr(PyObject
*v
)
2242 return _PyLong_Format(v
, 10, 1, 0);
2246 long_str(PyObject
*v
)
2248 return _PyLong_Format(v
, 10, 0, 0);
2252 long_compare(PyLongObject
*a
, PyLongObject
*b
)
2256 if (Py_SIZE(a
) != Py_SIZE(b
)) {
2257 if (ABS(Py_SIZE(a
)) == 0 && ABS(Py_SIZE(b
)) == 0)
2260 sign
= Py_SIZE(a
) - Py_SIZE(b
);
2263 Py_ssize_t i
= ABS(Py_SIZE(a
));
2264 while (--i
>= 0 && a
->ob_digit
[i
] == b
->ob_digit
[i
])
2269 sign
= (sdigit
)a
->ob_digit
[i
] - (sdigit
)b
->ob_digit
[i
];
2274 return sign
< 0 ? -1 : sign
> 0 ? 1 : 0;
2278 long_hash(PyLongObject
*v
)
2284 /* This is designed so that Python ints and longs with the
2285 same value hash to the same value, otherwise comparisons
2286 of mapping keys will turn out weird */
2294 /* The following loop produces a C unsigned long x such that x is
2295 congruent to the absolute value of v modulo ULONG_MAX. The
2296 resulting x is nonzero if and only if v is. */
2298 /* Force a native long #-bits (32 or 64) circular shift */
2299 x
= (x
>> (8*SIZEOF_LONG
-PyLong_SHIFT
)) | (x
<< PyLong_SHIFT
);
2300 x
+= v
->ob_digit
[i
];
2301 /* If the addition above overflowed we compensate by
2302 incrementing. This preserves the value modulo
2304 if (x
< v
->ob_digit
[i
])
2308 if (x
== (unsigned long)-1)
2309 x
= (unsigned long)-2;
2314 /* Add the absolute values of two long integers. */
2316 static PyLongObject
*
2317 x_add(PyLongObject
*a
, PyLongObject
*b
)
2319 Py_ssize_t size_a
= ABS(Py_SIZE(a
)), size_b
= ABS(Py_SIZE(b
));
2324 /* Ensure a is the larger of the two: */
2325 if (size_a
< size_b
) {
2326 { PyLongObject
*temp
= a
; a
= b
; b
= temp
; }
2327 { Py_ssize_t size_temp
= size_a
;
2329 size_b
= size_temp
; }
2331 z
= _PyLong_New(size_a
+1);
2334 for (i
= 0; i
< size_b
; ++i
) {
2335 carry
+= a
->ob_digit
[i
] + b
->ob_digit
[i
];
2336 z
->ob_digit
[i
] = carry
& PyLong_MASK
;
2337 carry
>>= PyLong_SHIFT
;
2339 for (; i
< size_a
; ++i
) {
2340 carry
+= a
->ob_digit
[i
];
2341 z
->ob_digit
[i
] = carry
& PyLong_MASK
;
2342 carry
>>= PyLong_SHIFT
;
2344 z
->ob_digit
[i
] = carry
;
2345 return long_normalize(z
);
2348 /* Subtract the absolute values of two integers. */
2350 static PyLongObject
*
2351 x_sub(PyLongObject
*a
, PyLongObject
*b
)
2353 Py_ssize_t size_a
= ABS(Py_SIZE(a
)), size_b
= ABS(Py_SIZE(b
));
2359 /* Ensure a is the larger of the two: */
2360 if (size_a
< size_b
) {
2362 { PyLongObject
*temp
= a
; a
= b
; b
= temp
; }
2363 { Py_ssize_t size_temp
= size_a
;
2365 size_b
= size_temp
; }
2367 else if (size_a
== size_b
) {
2368 /* Find highest digit where a and b differ: */
2370 while (--i
>= 0 && a
->ob_digit
[i
] == b
->ob_digit
[i
])
2373 return _PyLong_New(0);
2374 if (a
->ob_digit
[i
] < b
->ob_digit
[i
]) {
2376 { PyLongObject
*temp
= a
; a
= b
; b
= temp
; }
2378 size_a
= size_b
= i
+1;
2380 z
= _PyLong_New(size_a
);
2383 for (i
= 0; i
< size_b
; ++i
) {
2384 /* The following assumes unsigned arithmetic
2385 works module 2**N for some N>PyLong_SHIFT. */
2386 borrow
= a
->ob_digit
[i
] - b
->ob_digit
[i
] - borrow
;
2387 z
->ob_digit
[i
] = borrow
& PyLong_MASK
;
2388 borrow
>>= PyLong_SHIFT
;
2389 borrow
&= 1; /* Keep only one sign bit */
2391 for (; i
< size_a
; ++i
) {
2392 borrow
= a
->ob_digit
[i
] - borrow
;
2393 z
->ob_digit
[i
] = borrow
& PyLong_MASK
;
2394 borrow
>>= PyLong_SHIFT
;
2395 borrow
&= 1; /* Keep only one sign bit */
2397 assert(borrow
== 0);
2399 z
->ob_size
= -(z
->ob_size
);
2400 return long_normalize(z
);
2404 long_add(PyLongObject
*v
, PyLongObject
*w
)
2406 PyLongObject
*a
, *b
, *z
;
2408 CONVERT_BINOP((PyObject
*)v
, (PyObject
*)w
, &a
, &b
);
2410 if (a
->ob_size
< 0) {
2411 if (b
->ob_size
< 0) {
2413 if (z
!= NULL
&& z
->ob_size
!= 0)
2414 z
->ob_size
= -(z
->ob_size
);
2427 return (PyObject
*)z
;
2431 long_sub(PyLongObject
*v
, PyLongObject
*w
)
2433 PyLongObject
*a
, *b
, *z
;
2435 CONVERT_BINOP((PyObject
*)v
, (PyObject
*)w
, &a
, &b
);
2437 if (a
->ob_size
< 0) {
2442 if (z
!= NULL
&& z
->ob_size
!= 0)
2443 z
->ob_size
= -(z
->ob_size
);
2453 return (PyObject
*)z
;
2456 /* Grade school multiplication, ignoring the signs.
2457 * Returns the absolute value of the product, or NULL if error.
2459 static PyLongObject
*
2460 x_mul(PyLongObject
*a
, PyLongObject
*b
)
2463 Py_ssize_t size_a
= ABS(Py_SIZE(a
));
2464 Py_ssize_t size_b
= ABS(Py_SIZE(b
));
2467 z
= _PyLong_New(size_a
+ size_b
);
2471 memset(z
->ob_digit
, 0, Py_SIZE(z
) * sizeof(digit
));
2473 /* Efficient squaring per HAC, Algorithm 14.16:
2474 * http://www.cacr.math.uwaterloo.ca/hac/about/chap14.pdf
2475 * Gives slightly less than a 2x speedup when a == b,
2476 * via exploiting that each entry in the multiplication
2477 * pyramid appears twice (except for the size_a squares).
2479 for (i
= 0; i
< size_a
; ++i
) {
2481 twodigits f
= a
->ob_digit
[i
];
2482 digit
*pz
= z
->ob_digit
+ (i
<< 1);
2483 digit
*pa
= a
->ob_digit
+ i
+ 1;
2484 digit
*paend
= a
->ob_digit
+ size_a
;
2491 carry
= *pz
+ f
* f
;
2492 *pz
++ = (digit
)(carry
& PyLong_MASK
);
2493 carry
>>= PyLong_SHIFT
;
2494 assert(carry
<= PyLong_MASK
);
2496 /* Now f is added in twice in each column of the
2497 * pyramid it appears. Same as adding f<<1 once.
2500 while (pa
< paend
) {
2501 carry
+= *pz
+ *pa
++ * f
;
2502 *pz
++ = (digit
)(carry
& PyLong_MASK
);
2503 carry
>>= PyLong_SHIFT
;
2504 assert(carry
<= (PyLong_MASK
<< 1));
2508 *pz
++ = (digit
)(carry
& PyLong_MASK
);
2509 carry
>>= PyLong_SHIFT
;
2512 *pz
+= (digit
)(carry
& PyLong_MASK
);
2513 assert((carry
>> PyLong_SHIFT
) == 0);
2516 else { /* a is not the same as b -- gradeschool long mult */
2517 for (i
= 0; i
< size_a
; ++i
) {
2518 twodigits carry
= 0;
2519 twodigits f
= a
->ob_digit
[i
];
2520 digit
*pz
= z
->ob_digit
+ i
;
2521 digit
*pb
= b
->ob_digit
;
2522 digit
*pbend
= b
->ob_digit
+ size_b
;
2529 while (pb
< pbend
) {
2530 carry
+= *pz
+ *pb
++ * f
;
2531 *pz
++ = (digit
)(carry
& PyLong_MASK
);
2532 carry
>>= PyLong_SHIFT
;
2533 assert(carry
<= PyLong_MASK
);
2536 *pz
+= (digit
)(carry
& PyLong_MASK
);
2537 assert((carry
>> PyLong_SHIFT
) == 0);
2540 return long_normalize(z
);
2543 /* A helper for Karatsuba multiplication (k_mul).
2544 Takes a long "n" and an integer "size" representing the place to
2545 split, and sets low and high such that abs(n) == (high << size) + low,
2546 viewing the shift as being by digits. The sign bit is ignored, and
2547 the return values are >= 0.
2548 Returns 0 on success, -1 on failure.
2551 kmul_split(PyLongObject
*n
, Py_ssize_t size
, PyLongObject
**high
, PyLongObject
**low
)
2553 PyLongObject
*hi
, *lo
;
2554 Py_ssize_t size_lo
, size_hi
;
2555 const Py_ssize_t size_n
= ABS(Py_SIZE(n
));
2557 size_lo
= MIN(size_n
, size
);
2558 size_hi
= size_n
- size_lo
;
2560 if ((hi
= _PyLong_New(size_hi
)) == NULL
)
2562 if ((lo
= _PyLong_New(size_lo
)) == NULL
) {
2567 memcpy(lo
->ob_digit
, n
->ob_digit
, size_lo
* sizeof(digit
));
2568 memcpy(hi
->ob_digit
, n
->ob_digit
+ size_lo
, size_hi
* sizeof(digit
));
2570 *high
= long_normalize(hi
);
2571 *low
= long_normalize(lo
);
2575 static PyLongObject
*k_lopsided_mul(PyLongObject
*a
, PyLongObject
*b
);
2577 /* Karatsuba multiplication. Ignores the input signs, and returns the
2578 * absolute value of the product (or NULL if error).
2579 * See Knuth Vol. 2 Chapter 4.3.3 (Pp. 294-295).
2581 static PyLongObject
*
2582 k_mul(PyLongObject
*a
, PyLongObject
*b
)
2584 Py_ssize_t asize
= ABS(Py_SIZE(a
));
2585 Py_ssize_t bsize
= ABS(Py_SIZE(b
));
2586 PyLongObject
*ah
= NULL
;
2587 PyLongObject
*al
= NULL
;
2588 PyLongObject
*bh
= NULL
;
2589 PyLongObject
*bl
= NULL
;
2590 PyLongObject
*ret
= NULL
;
2591 PyLongObject
*t1
, *t2
, *t3
;
2592 Py_ssize_t shift
; /* the number of digits we split off */
2595 /* (ah*X+al)(bh*X+bl) = ah*bh*X*X + (ah*bl + al*bh)*X + al*bl
2596 * Let k = (ah+al)*(bh+bl) = ah*bl + al*bh + ah*bh + al*bl
2597 * Then the original product is
2598 * ah*bh*X*X + (k - ah*bh - al*bl)*X + al*bl
2599 * By picking X to be a power of 2, "*X" is just shifting, and it's
2600 * been reduced to 3 multiplies on numbers half the size.
2603 /* We want to split based on the larger number; fiddle so that b
2606 if (asize
> bsize
) {
2616 /* Use gradeschool math when either number is too small. */
2617 i
= a
== b
? KARATSUBA_SQUARE_CUTOFF
: KARATSUBA_CUTOFF
;
2620 return _PyLong_New(0);
2625 /* If a is small compared to b, splitting on b gives a degenerate
2626 * case with ah==0, and Karatsuba may be (even much) less efficient
2627 * than "grade school" then. However, we can still win, by viewing
2628 * b as a string of "big digits", each of width a->ob_size. That
2629 * leads to a sequence of balanced calls to k_mul.
2631 if (2 * asize
<= bsize
)
2632 return k_lopsided_mul(a
, b
);
2634 /* Split a & b into hi & lo pieces. */
2636 if (kmul_split(a
, shift
, &ah
, &al
) < 0) goto fail
;
2637 assert(Py_SIZE(ah
) > 0); /* the split isn't degenerate */
2645 else if (kmul_split(b
, shift
, &bh
, &bl
) < 0) goto fail
;
2648 * 1. Allocate result space (asize + bsize digits: that's always
2650 * 2. Compute ah*bh, and copy into result at 2*shift.
2651 * 3. Compute al*bl, and copy into result at 0. Note that this
2652 * can't overlap with #2.
2653 * 4. Subtract al*bl from the result, starting at shift. This may
2654 * underflow (borrow out of the high digit), but we don't care:
2655 * we're effectively doing unsigned arithmetic mod
2656 * PyLong_BASE**(sizea + sizeb), and so long as the *final* result fits,
2657 * borrows and carries out of the high digit can be ignored.
2658 * 5. Subtract ah*bh from the result, starting at shift.
2659 * 6. Compute (ah+al)*(bh+bl), and add it into the result starting
2663 /* 1. Allocate result space. */
2664 ret
= _PyLong_New(asize
+ bsize
);
2665 if (ret
== NULL
) goto fail
;
2667 /* Fill with trash, to catch reference to uninitialized digits. */
2668 memset(ret
->ob_digit
, 0xDF, Py_SIZE(ret
) * sizeof(digit
));
2671 /* 2. t1 <- ah*bh, and copy into high digits of result. */
2672 if ((t1
= k_mul(ah
, bh
)) == NULL
) goto fail
;
2673 assert(Py_SIZE(t1
) >= 0);
2674 assert(2*shift
+ Py_SIZE(t1
) <= Py_SIZE(ret
));
2675 memcpy(ret
->ob_digit
+ 2*shift
, t1
->ob_digit
,
2676 Py_SIZE(t1
) * sizeof(digit
));
2678 /* Zero-out the digits higher than the ah*bh copy. */
2679 i
= Py_SIZE(ret
) - 2*shift
- Py_SIZE(t1
);
2681 memset(ret
->ob_digit
+ 2*shift
+ Py_SIZE(t1
), 0,
2684 /* 3. t2 <- al*bl, and copy into the low digits. */
2685 if ((t2
= k_mul(al
, bl
)) == NULL
) {
2689 assert(Py_SIZE(t2
) >= 0);
2690 assert(Py_SIZE(t2
) <= 2*shift
); /* no overlap with high digits */
2691 memcpy(ret
->ob_digit
, t2
->ob_digit
, Py_SIZE(t2
) * sizeof(digit
));
2693 /* Zero out remaining digits. */
2694 i
= 2*shift
- Py_SIZE(t2
); /* number of uninitialized digits */
2696 memset(ret
->ob_digit
+ Py_SIZE(t2
), 0, i
* sizeof(digit
));
2698 /* 4 & 5. Subtract ah*bh (t1) and al*bl (t2). We do al*bl first
2699 * because it's fresher in cache.
2701 i
= Py_SIZE(ret
) - shift
; /* # digits after shift */
2702 (void)v_isub(ret
->ob_digit
+ shift
, i
, t2
->ob_digit
, Py_SIZE(t2
));
2705 (void)v_isub(ret
->ob_digit
+ shift
, i
, t1
->ob_digit
, Py_SIZE(t1
));
2708 /* 6. t3 <- (ah+al)(bh+bl), and add into result. */
2709 if ((t1
= x_add(ah
, al
)) == NULL
) goto fail
;
2718 else if ((t2
= x_add(bh
, bl
)) == NULL
) {
2729 if (t3
== NULL
) goto fail
;
2730 assert(Py_SIZE(t3
) >= 0);
2732 /* Add t3. It's not obvious why we can't run out of room here.
2733 * See the (*) comment after this function.
2735 (void)v_iadd(ret
->ob_digit
+ shift
, i
, t3
->ob_digit
, Py_SIZE(t3
));
2738 return long_normalize(ret
);
2749 /* (*) Why adding t3 can't "run out of room" above.
2751 Let f(x) mean the floor of x and c(x) mean the ceiling of x. Some facts
2754 1. For any integer i, i = c(i/2) + f(i/2). In particular,
2755 bsize = c(bsize/2) + f(bsize/2).
2756 2. shift = f(bsize/2)
2758 4. Since we call k_lopsided_mul if asize*2 <= bsize, asize*2 > bsize in this
2759 routine, so asize > bsize/2 >= f(bsize/2) in this routine.
2761 We allocated asize + bsize result digits, and add t3 into them at an offset
2762 of shift. This leaves asize+bsize-shift allocated digit positions for t3
2763 to fit into, = (by #1 and #2) asize + f(bsize/2) + c(bsize/2) - f(bsize/2) =
2764 asize + c(bsize/2) available digit positions.
2766 bh has c(bsize/2) digits, and bl at most f(size/2) digits. So bh+hl has
2767 at most c(bsize/2) digits + 1 bit.
2769 If asize == bsize, ah has c(bsize/2) digits, else ah has at most f(bsize/2)
2770 digits, and al has at most f(bsize/2) digits in any case. So ah+al has at
2771 most (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 1 bit.
2773 The product (ah+al)*(bh+bl) therefore has at most
2775 c(bsize/2) + (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 2 bits
2777 and we have asize + c(bsize/2) available digit positions. We need to show
2778 this is always enough. An instance of c(bsize/2) cancels out in both, so
2779 the question reduces to whether asize digits is enough to hold
2780 (asize == bsize ? c(bsize/2) : f(bsize/2)) digits + 2 bits. If asize < bsize,
2781 then we're asking whether asize digits >= f(bsize/2) digits + 2 bits. By #4,
2782 asize is at least f(bsize/2)+1 digits, so this in turn reduces to whether 1
2783 digit is enough to hold 2 bits. This is so since PyLong_SHIFT=15 >= 2. If
2784 asize == bsize, then we're asking whether bsize digits is enough to hold
2785 c(bsize/2) digits + 2 bits, or equivalently (by #1) whether f(bsize/2) digits
2786 is enough to hold 2 bits. This is so if bsize >= 2, which holds because
2787 bsize >= KARATSUBA_CUTOFF >= 2.
2789 Note that since there's always enough room for (ah+al)*(bh+bl), and that's
2790 clearly >= each of ah*bh and al*bl, there's always enough room to subtract
2791 ah*bh and al*bl too.
2794 /* b has at least twice the digits of a, and a is big enough that Karatsuba
2795 * would pay off *if* the inputs had balanced sizes. View b as a sequence
2796 * of slices, each with a->ob_size digits, and multiply the slices by a,
2797 * one at a time. This gives k_mul balanced inputs to work with, and is
2798 * also cache-friendly (we compute one double-width slice of the result
2799 * at a time, then move on, never bactracking except for the helpful
2800 * single-width slice overlap between successive partial sums).
2802 static PyLongObject
*
2803 k_lopsided_mul(PyLongObject
*a
, PyLongObject
*b
)
2805 const Py_ssize_t asize
= ABS(Py_SIZE(a
));
2806 Py_ssize_t bsize
= ABS(Py_SIZE(b
));
2807 Py_ssize_t nbdone
; /* # of b digits already multiplied */
2809 PyLongObject
*bslice
= NULL
;
2811 assert(asize
> KARATSUBA_CUTOFF
);
2812 assert(2 * asize
<= bsize
);
2814 /* Allocate result space, and zero it out. */
2815 ret
= _PyLong_New(asize
+ bsize
);
2818 memset(ret
->ob_digit
, 0, Py_SIZE(ret
) * sizeof(digit
));
2820 /* Successive slices of b are copied into bslice. */
2821 bslice
= _PyLong_New(asize
);
2827 PyLongObject
*product
;
2828 const Py_ssize_t nbtouse
= MIN(bsize
, asize
);
2830 /* Multiply the next slice of b by a. */
2831 memcpy(bslice
->ob_digit
, b
->ob_digit
+ nbdone
,
2832 nbtouse
* sizeof(digit
));
2833 Py_SIZE(bslice
) = nbtouse
;
2834 product
= k_mul(a
, bslice
);
2835 if (product
== NULL
)
2838 /* Add into result. */
2839 (void)v_iadd(ret
->ob_digit
+ nbdone
, Py_SIZE(ret
) - nbdone
,
2840 product
->ob_digit
, Py_SIZE(product
));
2848 return long_normalize(ret
);
2857 long_mul(PyLongObject
*v
, PyLongObject
*w
)
2859 PyLongObject
*a
, *b
, *z
;
2861 if (!convert_binop((PyObject
*)v
, (PyObject
*)w
, &a
, &b
)) {
2862 Py_INCREF(Py_NotImplemented
);
2863 return Py_NotImplemented
;
2867 /* Negate if exactly one of the inputs is negative. */
2868 if (((a
->ob_size
^ b
->ob_size
) < 0) && z
)
2869 z
->ob_size
= -(z
->ob_size
);
2872 return (PyObject
*)z
;
2875 /* The / and % operators are now defined in terms of divmod().
2876 The expression a mod b has the value a - b*floor(a/b).
2877 The long_divrem function gives the remainder after division of
2878 |a| by |b|, with the sign of a. This is also expressed
2879 as a - b*trunc(a/b), if trunc truncates towards zero.
2886 So, to get from rem to mod, we have to add b if a and b
2887 have different signs. We then subtract one from the 'div'
2888 part of the outcome to keep the invariant intact. */
2891 * *pdiv, *pmod = divmod(v, w)
2892 * NULL can be passed for pdiv or pmod, in which case that part of
2893 * the result is simply thrown away. The caller owns a reference to
2894 * each of these it requests (does not pass NULL for).
2897 l_divmod(PyLongObject
*v
, PyLongObject
*w
,
2898 PyLongObject
**pdiv
, PyLongObject
**pmod
)
2900 PyLongObject
*div
, *mod
;
2902 if (long_divrem(v
, w
, &div
, &mod
) < 0)
2904 if ((Py_SIZE(mod
) < 0 && Py_SIZE(w
) > 0) ||
2905 (Py_SIZE(mod
) > 0 && Py_SIZE(w
) < 0)) {
2908 temp
= (PyLongObject
*) long_add(mod
, w
);
2915 one
= (PyLongObject
*) PyLong_FromLong(1L);
2917 (temp
= (PyLongObject
*) long_sub(div
, one
)) == NULL
) {
2941 long_div(PyObject
*v
, PyObject
*w
)
2943 PyLongObject
*a
, *b
, *div
;
2945 CONVERT_BINOP(v
, w
, &a
, &b
);
2946 if (l_divmod(a
, b
, &div
, NULL
) < 0)
2950 return (PyObject
*)div
;
2954 long_classic_div(PyObject
*v
, PyObject
*w
)
2956 PyLongObject
*a
, *b
, *div
;
2958 CONVERT_BINOP(v
, w
, &a
, &b
);
2959 if (Py_DivisionWarningFlag
&&
2960 PyErr_Warn(PyExc_DeprecationWarning
, "classic long division") < 0)
2962 else if (l_divmod(a
, b
, &div
, NULL
) < 0)
2966 return (PyObject
*)div
;
2970 long_true_divide(PyObject
*v
, PyObject
*w
)
2972 PyLongObject
*a
, *b
;
2974 int failed
, aexp
= -1, bexp
= -1;
2976 CONVERT_BINOP(v
, w
, &a
, &b
);
2977 ad
= _PyLong_AsScaledDouble((PyObject
*)a
, &aexp
);
2978 bd
= _PyLong_AsScaledDouble((PyObject
*)b
, &bexp
);
2979 failed
= (ad
== -1.0 || bd
== -1.0) && PyErr_Occurred();
2984 /* 'aexp' and 'bexp' were initialized to -1 to silence gcc-4.0.x,
2985 but should really be set correctly after sucessful calls to
2986 _PyLong_AsScaledDouble() */
2987 assert(aexp
>= 0 && bexp
>= 0);
2990 PyErr_SetString(PyExc_ZeroDivisionError
,
2991 "long division or modulo by zero");
2995 /* True value is very close to ad/bd * 2**(PyLong_SHIFT*(aexp-bexp)) */
2996 ad
/= bd
; /* overflow/underflow impossible here */
2998 if (aexp
> INT_MAX
/ PyLong_SHIFT
)
3000 else if (aexp
< -(INT_MAX
/ PyLong_SHIFT
))
3001 return PyFloat_FromDouble(0.0); /* underflow to 0 */
3003 ad
= ldexp(ad
, aexp
* PyLong_SHIFT
);
3004 if (Py_OVERFLOWED(ad
)) /* ignore underflow to 0.0 */
3006 return PyFloat_FromDouble(ad
);
3009 PyErr_SetString(PyExc_OverflowError
,
3010 "long/long too large for a float");
3016 long_mod(PyObject
*v
, PyObject
*w
)
3018 PyLongObject
*a
, *b
, *mod
;
3020 CONVERT_BINOP(v
, w
, &a
, &b
);
3022 if (l_divmod(a
, b
, NULL
, &mod
) < 0)
3026 return (PyObject
*)mod
;
3030 long_divmod(PyObject
*v
, PyObject
*w
)
3032 PyLongObject
*a
, *b
, *div
, *mod
;
3035 CONVERT_BINOP(v
, w
, &a
, &b
);
3037 if (l_divmod(a
, b
, &div
, &mod
) < 0) {
3044 PyTuple_SetItem(z
, 0, (PyObject
*) div
);
3045 PyTuple_SetItem(z
, 1, (PyObject
*) mod
);
3058 long_pow(PyObject
*v
, PyObject
*w
, PyObject
*x
)
3060 PyLongObject
*a
, *b
, *c
; /* a,b,c = v,w,x */
3061 int negativeOutput
= 0; /* if x<0 return negative output */
3063 PyLongObject
*z
= NULL
; /* accumulated result */
3064 Py_ssize_t i
, j
, k
; /* counters */
3065 PyLongObject
*temp
= NULL
;
3067 /* 5-ary values. If the exponent is large enough, table is
3068 * precomputed so that table[i] == a**i % c for i in range(32).
3070 PyLongObject
*table
[32] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
3071 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
3073 /* a, b, c = v, w, x */
3074 CONVERT_BINOP(v
, w
, &a
, &b
);
3075 if (PyLong_Check(x
)) {
3076 c
= (PyLongObject
*)x
;
3079 else if (PyInt_Check(x
)) {
3080 c
= (PyLongObject
*)PyLong_FromLong(PyInt_AS_LONG(x
));
3084 else if (x
== Py_None
)
3089 Py_INCREF(Py_NotImplemented
);
3090 return Py_NotImplemented
;
3093 if (Py_SIZE(b
) < 0) { /* if exponent is negative */
3095 PyErr_SetString(PyExc_TypeError
, "pow() 2nd argument "
3096 "cannot be negative when 3rd argument specified");
3100 /* else return a float. This works because we know
3101 that this calls float_pow() which converts its
3102 arguments to double. */
3105 return PyFloat_Type
.tp_as_number
->nb_power(v
, w
, x
);
3111 raise ValueError() */
3112 if (Py_SIZE(c
) == 0) {
3113 PyErr_SetString(PyExc_ValueError
,
3114 "pow() 3rd argument cannot be 0");
3119 negativeOutput = True
3120 modulus = -modulus */
3121 if (Py_SIZE(c
) < 0) {
3123 temp
= (PyLongObject
*)_PyLong_Copy(c
);
3129 c
->ob_size
= - c
->ob_size
;
3134 if ((Py_SIZE(c
) == 1) && (c
->ob_digit
[0] == 1)) {
3135 z
= (PyLongObject
*)PyLong_FromLong(0L);
3140 base = base % modulus
3141 Having the base positive just makes things easier. */
3142 if (Py_SIZE(a
) < 0) {
3143 if (l_divmod(a
, c
, NULL
, &temp
) < 0)
3151 /* At this point a, b, and c are guaranteed non-negative UNLESS
3152 c is NULL, in which case a may be negative. */
3154 z
= (PyLongObject
*)PyLong_FromLong(1L);
3158 /* Perform a modular reduction, X = X % c, but leave X alone if c
3163 if (l_divmod(X, c, NULL, &temp) < 0) \
3170 /* Multiply two values, then reduce the result:
3171 result = X*Y % c. If c is NULL, skip the mod. */
3172 #define MULT(X, Y, result) \
3174 temp = (PyLongObject *)long_mul(X, Y); \
3177 Py_XDECREF(result); \
3183 if (Py_SIZE(b
) <= FIVEARY_CUTOFF
) {
3184 /* Left-to-right binary exponentiation (HAC Algorithm 14.79) */
3185 /* http://www.cacr.math.uwaterloo.ca/hac/about/chap14.pdf */
3186 for (i
= Py_SIZE(b
) - 1; i
>= 0; --i
) {
3187 digit bi
= b
->ob_digit
[i
];
3189 for (j
= (digit
)1 << (PyLong_SHIFT
-1); j
!= 0; j
>>= 1) {
3197 /* Left-to-right 5-ary exponentiation (HAC Algorithm 14.82) */
3198 Py_INCREF(z
); /* still holds 1L */
3200 for (i
= 1; i
< 32; ++i
)
3201 MULT(table
[i
-1], a
, table
[i
])
3203 for (i
= Py_SIZE(b
) - 1; i
>= 0; --i
) {
3204 const digit bi
= b
->ob_digit
[i
];
3206 for (j
= PyLong_SHIFT
- 5; j
>= 0; j
-= 5) {
3207 const int index
= (bi
>> j
) & 0x1f;
3208 for (k
= 0; k
< 5; ++k
)
3211 MULT(z
, table
[index
], z
)
3216 if (negativeOutput
&& (Py_SIZE(z
) != 0)) {
3217 temp
= (PyLongObject
*)long_sub(z
, c
);
3233 if (Py_SIZE(b
) > FIVEARY_CUTOFF
) {
3234 for (i
= 0; i
< 32; ++i
)
3235 Py_XDECREF(table
[i
]);
3241 return (PyObject
*)z
;
3245 long_invert(PyLongObject
*v
)
3247 /* Implement ~x as -(x+1) */
3250 w
= (PyLongObject
*)PyLong_FromLong(1L);
3253 x
= (PyLongObject
*) long_add(v
, w
);
3257 Py_SIZE(x
) = -(Py_SIZE(x
));
3258 return (PyObject
*)x
;
3262 long_neg(PyLongObject
*v
)
3265 if (v
->ob_size
== 0 && PyLong_CheckExact(v
)) {
3268 return (PyObject
*) v
;
3270 z
= (PyLongObject
*)_PyLong_Copy(v
);
3272 z
->ob_size
= -(v
->ob_size
);
3273 return (PyObject
*)z
;
3277 long_abs(PyLongObject
*v
)
3282 return long_long((PyObject
*)v
);
3286 long_nonzero(PyLongObject
*v
)
3288 return ABS(Py_SIZE(v
)) != 0;
3292 long_rshift(PyLongObject
*v
, PyLongObject
*w
)
3294 PyLongObject
*a
, *b
;
3295 PyLongObject
*z
= NULL
;
3297 Py_ssize_t newsize
, wordshift
, loshift
, hishift
, i
, j
;
3298 digit lomask
, himask
;
3300 CONVERT_BINOP((PyObject
*)v
, (PyObject
*)w
, &a
, &b
);
3302 if (Py_SIZE(a
) < 0) {
3303 /* Right shifting negative numbers is harder */
3304 PyLongObject
*a1
, *a2
;
3305 a1
= (PyLongObject
*) long_invert(a
);
3308 a2
= (PyLongObject
*) long_rshift(a1
, b
);
3312 z
= (PyLongObject
*) long_invert(a2
);
3317 shiftby
= PyLong_AsLong((PyObject
*)b
);
3318 if (shiftby
== -1L && PyErr_Occurred())
3321 PyErr_SetString(PyExc_ValueError
,
3322 "negative shift count");
3325 wordshift
= shiftby
/ PyLong_SHIFT
;
3326 newsize
= ABS(Py_SIZE(a
)) - wordshift
;
3331 return (PyObject
*)z
;
3333 loshift
= shiftby
% PyLong_SHIFT
;
3334 hishift
= PyLong_SHIFT
- loshift
;
3335 lomask
= ((digit
)1 << hishift
) - 1;
3336 himask
= PyLong_MASK
^ lomask
;
3337 z
= _PyLong_New(newsize
);
3341 Py_SIZE(z
) = -(Py_SIZE(z
));
3342 for (i
= 0, j
= wordshift
; i
< newsize
; i
++, j
++) {
3343 z
->ob_digit
[i
] = (a
->ob_digit
[j
] >> loshift
) & lomask
;
3346 (a
->ob_digit
[j
+1] << hishift
) & himask
;
3348 z
= long_normalize(z
);
3353 return (PyObject
*) z
;
3358 long_lshift(PyObject
*v
, PyObject
*w
)
3360 /* This version due to Tim Peters */
3361 PyLongObject
*a
, *b
;
3362 PyLongObject
*z
= NULL
;
3364 Py_ssize_t oldsize
, newsize
, wordshift
, remshift
, i
, j
;
3367 CONVERT_BINOP(v
, w
, &a
, &b
);
3369 shiftby
= PyLong_AsLong((PyObject
*)b
);
3370 if (shiftby
== -1L && PyErr_Occurred())
3373 PyErr_SetString(PyExc_ValueError
, "negative shift count");
3376 if ((long)(int)shiftby
!= shiftby
) {
3377 PyErr_SetString(PyExc_ValueError
,
3378 "outrageous left shift count");
3381 /* wordshift, remshift = divmod(shiftby, PyLong_SHIFT) */
3382 wordshift
= (int)shiftby
/ PyLong_SHIFT
;
3383 remshift
= (int)shiftby
- wordshift
* PyLong_SHIFT
;
3385 oldsize
= ABS(a
->ob_size
);
3386 newsize
= oldsize
+ wordshift
;
3389 z
= _PyLong_New(newsize
);
3393 z
->ob_size
= -(z
->ob_size
);
3394 for (i
= 0; i
< wordshift
; i
++)
3397 for (i
= wordshift
, j
= 0; j
< oldsize
; i
++, j
++) {
3398 accum
|= (twodigits
)a
->ob_digit
[j
] << remshift
;
3399 z
->ob_digit
[i
] = (digit
)(accum
& PyLong_MASK
);
3400 accum
>>= PyLong_SHIFT
;
3403 z
->ob_digit
[newsize
-1] = (digit
)accum
;
3406 z
= long_normalize(z
);
3410 return (PyObject
*) z
;
3414 /* Bitwise and/xor/or operations */
3417 long_bitwise(PyLongObject
*a
,
3418 int op
, /* '&', '|', '^' */
3421 digit maska
, maskb
; /* 0 or PyLong_MASK */
3423 Py_ssize_t size_a
, size_b
, size_z
, i
;
3428 if (Py_SIZE(a
) < 0) {
3429 a
= (PyLongObject
*) long_invert(a
);
3432 maska
= PyLong_MASK
;
3438 if (Py_SIZE(b
) < 0) {
3439 b
= (PyLongObject
*) long_invert(b
);
3444 maskb
= PyLong_MASK
;
3454 if (maska
!= maskb
) {
3455 maska
^= PyLong_MASK
;
3460 if (maska
&& maskb
) {
3462 maska
^= PyLong_MASK
;
3463 maskb
^= PyLong_MASK
;
3468 if (maska
|| maskb
) {
3470 maska
^= PyLong_MASK
;
3471 maskb
^= PyLong_MASK
;
3477 /* JRH: The original logic here was to allocate the result value (z)
3478 as the longer of the two operands. However, there are some cases
3479 where the result is guaranteed to be shorter than that: AND of two
3480 positives, OR of two negatives: use the shorter number. AND with
3481 mixed signs: use the positive number. OR with mixed signs: use the
3482 negative number. After the transformations above, op will be '&'
3483 iff one of these cases applies, and mask will be non-0 for operands
3484 whose length should be ignored.
3487 size_a
= Py_SIZE(a
);
3488 size_b
= Py_SIZE(b
);
3492 : (maskb
? size_a
: MIN(size_a
, size_b
)))
3493 : MAX(size_a
, size_b
);
3494 z
= _PyLong_New(size_z
);
3501 for (i
= 0; i
< size_z
; ++i
) {
3502 diga
= (i
< size_a
? a
->ob_digit
[i
] : 0) ^ maska
;
3503 digb
= (i
< size_b
? b
->ob_digit
[i
] : 0) ^ maskb
;
3505 case '&': z
->ob_digit
[i
] = diga
& digb
; break;
3506 case '|': z
->ob_digit
[i
] = diga
| digb
; break;
3507 case '^': z
->ob_digit
[i
] = diga
^ digb
; break;
3513 z
= long_normalize(z
);
3515 return (PyObject
*) z
;
3522 long_and(PyObject
*v
, PyObject
*w
)
3524 PyLongObject
*a
, *b
;
3526 CONVERT_BINOP(v
, w
, &a
, &b
);
3527 c
= long_bitwise(a
, '&', b
);
3534 long_xor(PyObject
*v
, PyObject
*w
)
3536 PyLongObject
*a
, *b
;
3538 CONVERT_BINOP(v
, w
, &a
, &b
);
3539 c
= long_bitwise(a
, '^', b
);
3546 long_or(PyObject
*v
, PyObject
*w
)
3548 PyLongObject
*a
, *b
;
3550 CONVERT_BINOP(v
, w
, &a
, &b
);
3551 c
= long_bitwise(a
, '|', b
);
3558 long_coerce(PyObject
**pv
, PyObject
**pw
)
3560 if (PyInt_Check(*pw
)) {
3561 *pw
= PyLong_FromLong(PyInt_AS_LONG(*pw
));
3567 else if (PyLong_Check(*pw
)) {
3572 return 1; /* Can't do it */
3576 long_long(PyObject
*v
)
3578 if (PyLong_CheckExact(v
))
3581 v
= _PyLong_Copy((PyLongObject
*)v
);
3586 long_int(PyObject
*v
)
3589 x
= PyLong_AsLong(v
);
3590 if (PyErr_Occurred()) {
3591 if (PyErr_ExceptionMatches(PyExc_OverflowError
)) {
3593 if (PyLong_CheckExact(v
)) {
3598 return _PyLong_Copy((PyLongObject
*)v
);
3603 return PyInt_FromLong(x
);
3607 long_float(PyObject
*v
)
3610 result
= PyLong_AsDouble(v
);
3611 if (result
== -1.0 && PyErr_Occurred())
3613 return PyFloat_FromDouble(result
);
3617 long_oct(PyObject
*v
)
3619 return _PyLong_Format(v
, 8, 1, 0);
3623 long_hex(PyObject
*v
)
3625 return _PyLong_Format(v
, 16, 1, 0);
3629 long_subtype_new(PyTypeObject
*type
, PyObject
*args
, PyObject
*kwds
);
3632 long_new(PyTypeObject
*type
, PyObject
*args
, PyObject
*kwds
)
3635 int base
= -909; /* unlikely! */
3636 static char *kwlist
[] = {"x", "base", 0};
3638 if (type
!= &PyLong_Type
)
3639 return long_subtype_new(type
, args
, kwds
); /* Wimp out */
3640 if (!PyArg_ParseTupleAndKeywords(args
, kwds
, "|Oi:long", kwlist
,
3644 return PyLong_FromLong(0L);
3646 return PyNumber_Long(x
);
3647 else if (PyString_Check(x
)) {
3648 /* Since PyLong_FromString doesn't have a length parameter,
3649 * check here for possible NULs in the string. */
3650 char *string
= PyString_AS_STRING(x
);
3651 if (strlen(string
) != (size_t)PyString_Size(x
)) {
3652 /* create a repr() of the input string,
3653 * just like PyLong_FromString does. */
3655 srepr
= PyObject_Repr(x
);
3658 PyErr_Format(PyExc_ValueError
,
3659 "invalid literal for long() with base %d: %s",
3660 base
, PyString_AS_STRING(srepr
));
3664 return PyLong_FromString(PyString_AS_STRING(x
), NULL
, base
);
3666 #ifdef Py_USING_UNICODE
3667 else if (PyUnicode_Check(x
))
3668 return PyLong_FromUnicode(PyUnicode_AS_UNICODE(x
),
3669 PyUnicode_GET_SIZE(x
),
3673 PyErr_SetString(PyExc_TypeError
,
3674 "long() can't convert non-string with explicit base");
3679 /* Wimpy, slow approach to tp_new calls for subtypes of long:
3680 first create a regular long from whatever arguments we got,
3681 then allocate a subtype instance and initialize it from
3682 the regular long. The regular long is then thrown away.
3685 long_subtype_new(PyTypeObject
*type
, PyObject
*args
, PyObject
*kwds
)
3687 PyLongObject
*tmp
, *newobj
;
3690 assert(PyType_IsSubtype(type
, &PyLong_Type
));
3691 tmp
= (PyLongObject
*)long_new(&PyLong_Type
, args
, kwds
);
3694 assert(PyLong_CheckExact(tmp
));
3698 newobj
= (PyLongObject
*)type
->tp_alloc(type
, n
);
3699 if (newobj
== NULL
) {
3703 assert(PyLong_Check(newobj
));
3704 Py_SIZE(newobj
) = Py_SIZE(tmp
);
3705 for (i
= 0; i
< n
; i
++)
3706 newobj
->ob_digit
[i
] = tmp
->ob_digit
[i
];
3708 return (PyObject
*)newobj
;
3712 long_getnewargs(PyLongObject
*v
)
3714 return Py_BuildValue("(N)", _PyLong_Copy(v
));
3718 long_get0(PyLongObject
*v
, void *context
) {
3719 return PyLong_FromLong(0L);
3723 long_get1(PyLongObject
*v
, void *context
) {
3724 return PyLong_FromLong(1L);
3728 long__format__(PyObject
*self
, PyObject
*args
)
3730 PyObject
*format_spec
;
3732 if (!PyArg_ParseTuple(args
, "O:__format__", &format_spec
))
3734 if (PyBytes_Check(format_spec
))
3735 return _PyLong_FormatAdvanced(self
,
3736 PyBytes_AS_STRING(format_spec
),
3737 PyBytes_GET_SIZE(format_spec
));
3738 if (PyUnicode_Check(format_spec
)) {
3739 /* Convert format_spec to a str */
3741 PyObject
*str_spec
= PyObject_Str(format_spec
);
3743 if (str_spec
== NULL
)
3746 result
= _PyLong_FormatAdvanced(self
,
3747 PyBytes_AS_STRING(str_spec
),
3748 PyBytes_GET_SIZE(str_spec
));
3750 Py_DECREF(str_spec
);
3753 PyErr_SetString(PyExc_TypeError
, "__format__ requires str or unicode");
3758 long_sizeof(PyLongObject
*v
)
3762 res
= v
->ob_type
->tp_basicsize
+ ABS(Py_SIZE(v
))*sizeof(digit
);
3763 return PyInt_FromSsize_t(res
);
3767 long_bit_length(PyLongObject
*v
)
3769 PyLongObject
*result
, *x
, *y
;
3770 Py_ssize_t ndigits
, msd_bits
= 0;
3774 assert(PyLong_Check(v
));
3776 ndigits
= ABS(Py_SIZE(v
));
3778 return PyInt_FromLong(0);
3780 msd
= v
->ob_digit
[ndigits
-1];
3785 msd_bits
+= (long)(BitLengthTable
[msd
]);
3787 if (ndigits
<= PY_SSIZE_T_MAX
/PyLong_SHIFT
)
3788 return PyInt_FromSsize_t((ndigits
-1)*PyLong_SHIFT
+ msd_bits
);
3790 /* expression above may overflow; use Python integers instead */
3791 result
= (PyLongObject
*)PyLong_FromSsize_t(ndigits
- 1);
3794 x
= (PyLongObject
*)PyLong_FromLong(PyLong_SHIFT
);
3797 y
= (PyLongObject
*)long_mul(result
, x
);
3804 x
= (PyLongObject
*)PyLong_FromLong(msd_bits
);
3807 y
= (PyLongObject
*)long_add(result
, x
);
3814 return (PyObject
*)result
;
3821 PyDoc_STRVAR(long_bit_length_doc
,
3822 "long.bit_length() -> int or long\n\
3824 Number of bits necessary to represent self in binary.\n\
3827 >>> (37L).bit_length()\n\
3832 long_is_finite(PyObject
*v
)
3838 static PyMethodDef long_methods
[] = {
3839 {"conjugate", (PyCFunction
)long_long
, METH_NOARGS
,
3840 "Returns self, the complex conjugate of any long."},
3841 {"bit_length", (PyCFunction
)long_bit_length
, METH_NOARGS
,
3842 long_bit_length_doc
},
3844 {"is_finite", (PyCFunction
)long_is_finite
, METH_NOARGS
,
3845 "Returns always True."},
3847 {"__trunc__", (PyCFunction
)long_long
, METH_NOARGS
,
3848 "Truncating an Integral returns itself."},
3849 {"__getnewargs__", (PyCFunction
)long_getnewargs
, METH_NOARGS
},
3850 {"__format__", (PyCFunction
)long__format__
, METH_VARARGS
},
3851 {"__sizeof__", (PyCFunction
)long_sizeof
, METH_NOARGS
,
3852 "Returns size in memory, in bytes"},
3853 {NULL
, NULL
} /* sentinel */
3856 static PyGetSetDef long_getset
[] = {
3858 (getter
)long_long
, (setter
)NULL
,
3859 "the real part of a complex number",
3862 (getter
)long_get0
, (setter
)NULL
,
3863 "the imaginary part of a complex number",
3866 (getter
)long_long
, (setter
)NULL
,
3867 "the numerator of a rational number in lowest terms",
3870 (getter
)long_get1
, (setter
)NULL
,
3871 "the denominator of a rational number in lowest terms",
3873 {NULL
} /* Sentinel */
3876 PyDoc_STRVAR(long_doc
,
3877 "long(x[, base]) -> integer\n\
3879 Convert a string or number to a long integer, if possible. A floating\n\
3880 point argument will be truncated towards zero (this does not include a\n\
3881 string representation of a floating point number!) When converting a\n\
3882 string, use the optional base. It is an error to supply a base when\n\
3883 converting a non-string.");
3885 static PyNumberMethods long_as_number
= {
3886 (binaryfunc
) long_add
, /*nb_add*/
3887 (binaryfunc
) long_sub
, /*nb_subtract*/
3888 (binaryfunc
) long_mul
, /*nb_multiply*/
3889 long_classic_div
, /*nb_divide*/
3890 long_mod
, /*nb_remainder*/
3891 long_divmod
, /*nb_divmod*/
3892 long_pow
, /*nb_power*/
3893 (unaryfunc
) long_neg
, /*nb_negative*/
3894 (unaryfunc
) long_long
, /*tp_positive*/
3895 (unaryfunc
) long_abs
, /*tp_absolute*/
3896 (inquiry
) long_nonzero
, /*tp_nonzero*/
3897 (unaryfunc
) long_invert
, /*nb_invert*/
3898 long_lshift
, /*nb_lshift*/
3899 (binaryfunc
) long_rshift
, /*nb_rshift*/
3900 long_and
, /*nb_and*/
3901 long_xor
, /*nb_xor*/
3903 long_coerce
, /*nb_coerce*/
3904 long_int
, /*nb_int*/
3905 long_long
, /*nb_long*/
3906 long_float
, /*nb_float*/
3907 long_oct
, /*nb_oct*/
3908 long_hex
, /*nb_hex*/
3909 0, /* nb_inplace_add */
3910 0, /* nb_inplace_subtract */
3911 0, /* nb_inplace_multiply */
3912 0, /* nb_inplace_divide */
3913 0, /* nb_inplace_remainder */
3914 0, /* nb_inplace_power */
3915 0, /* nb_inplace_lshift */
3916 0, /* nb_inplace_rshift */
3917 0, /* nb_inplace_and */
3918 0, /* nb_inplace_xor */
3919 0, /* nb_inplace_or */
3920 long_div
, /* nb_floor_divide */
3921 long_true_divide
, /* nb_true_divide */
3922 0, /* nb_inplace_floor_divide */
3923 0, /* nb_inplace_true_divide */
3924 long_long
, /* nb_index */
3927 PyTypeObject PyLong_Type
= {
3928 PyObject_HEAD_INIT(&PyType_Type
)
3930 "long", /* tp_name */
3931 offsetof(PyLongObject
, ob_digit
), /* tp_basicsize */
3932 sizeof(digit
), /* tp_itemsize */
3933 long_dealloc
, /* tp_dealloc */
3937 (cmpfunc
)long_compare
, /* tp_compare */
3938 long_repr
, /* tp_repr */
3939 &long_as_number
, /* tp_as_number */
3940 0, /* tp_as_sequence */
3941 0, /* tp_as_mapping */
3942 (hashfunc
)long_hash
, /* tp_hash */
3944 long_str
, /* tp_str */
3945 PyObject_GenericGetAttr
, /* tp_getattro */
3946 0, /* tp_setattro */
3947 0, /* tp_as_buffer */
3948 Py_TPFLAGS_DEFAULT
| Py_TPFLAGS_CHECKTYPES
|
3949 Py_TPFLAGS_BASETYPE
| Py_TPFLAGS_LONG_SUBCLASS
, /* tp_flags */
3950 long_doc
, /* tp_doc */
3951 0, /* tp_traverse */
3953 0, /* tp_richcompare */
3954 0, /* tp_weaklistoffset */
3956 0, /* tp_iternext */
3957 long_methods
, /* tp_methods */
3959 long_getset
, /* tp_getset */
3962 0, /* tp_descr_get */
3963 0, /* tp_descr_set */
3964 0, /* tp_dictoffset */
3967 long_new
, /* tp_new */
3968 PyObject_Del
, /* tp_free */
3971 static PyTypeObject Long_InfoType
;
3973 PyDoc_STRVAR(long_info__doc__
,
3976 A struct sequence that holds information about Python's\n\
3977 internal representation of integers. The attributes are read only.");
3979 static PyStructSequence_Field long_info_fields
[] = {
3980 {"bits_per_digit", "size of a digit in bits"},
3981 {"sizeof_digit", "size in bytes of the C type used to "
3982 "represent a digit"},
3986 static PyStructSequence_Desc long_info_desc
= {
3987 "sys.long_info", /* name */
3988 long_info__doc__
, /* doc */
3989 long_info_fields
, /* fields */
3990 2 /* number of fields */
3994 PyLong_GetInfo(void)
3996 PyObject
* long_info
;
3998 long_info
= PyStructSequence_New(&Long_InfoType
);
3999 if (long_info
== NULL
)
4001 PyStructSequence_SET_ITEM(long_info
, field
++,
4002 PyInt_FromLong(PyLong_SHIFT
));
4003 PyStructSequence_SET_ITEM(long_info
, field
++,
4004 PyInt_FromLong(sizeof(digit
)));
4005 if (PyErr_Occurred()) {
4006 Py_CLEAR(long_info
);
4015 /* initialize long_info */
4016 if (Long_InfoType
.tp_name
== 0)
4017 PyStructSequence_InitType(&Long_InfoType
, &long_info_desc
);