Update copyright for 2022
[pgsql.git] / src / common / d2s.c
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1 /*---------------------------------------------------------------------------
3 * Ryu floating-point output for double precision.
5 * Portions Copyright (c) 2018-2022, PostgreSQL Global Development Group
7 * IDENTIFICATION
8 * src/common/d2s.c
10 * This is a modification of code taken from github.com/ulfjack/ryu under the
11 * terms of the Boost license (not the Apache license). The original copyright
12 * notice follows:
14 * Copyright 2018 Ulf Adams
16 * The contents of this file may be used under the terms of the Apache
17 * License, Version 2.0.
19 * (See accompanying file LICENSE-Apache or copy at
20 * http://www.apache.org/licenses/LICENSE-2.0)
22 * Alternatively, the contents of this file may be used under the terms of the
23 * Boost Software License, Version 1.0.
25 * (See accompanying file LICENSE-Boost or copy at
26 * https://www.boost.org/LICENSE_1_0.txt)
28 * Unless required by applicable law or agreed to in writing, this software is
29 * distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
30 * KIND, either express or implied.
32 *---------------------------------------------------------------------------
36 * Runtime compiler options:
38 * -DRYU_ONLY_64_BIT_OPS Avoid using uint128 or 64-bit intrinsics. Slower,
39 * depending on your compiler.
42 #ifndef FRONTEND
43 #include "postgres.h"
44 #else
45 #include "postgres_fe.h"
46 #endif
48 #include "common/shortest_dec.h"
51 * For consistency, we use 128-bit types if and only if the rest of PG also
52 * does, even though we could use them here without worrying about the
53 * alignment concerns that apply elsewhere.
55 #if !defined(HAVE_INT128) && defined(_MSC_VER) \
56 && !defined(RYU_ONLY_64_BIT_OPS) && defined(_M_X64)
57 #define HAS_64_BIT_INTRINSICS
58 #endif
60 #include "ryu_common.h"
61 #include "digit_table.h"
62 #include "d2s_full_table.h"
63 #include "d2s_intrinsics.h"
65 #define DOUBLE_MANTISSA_BITS 52
66 #define DOUBLE_EXPONENT_BITS 11
67 #define DOUBLE_BIAS 1023
69 #define DOUBLE_POW5_INV_BITCOUNT 122
70 #define DOUBLE_POW5_BITCOUNT 121
73 static inline uint32
74 pow5Factor(uint64 value)
76 uint32 count = 0;
78 for (;;)
80 Assert(value != 0);
81 const uint64 q = div5(value);
82 const uint32 r = (uint32) (value - 5 * q);
84 if (r != 0)
85 break;
87 value = q;
88 ++count;
90 return count;
93 /* Returns true if value is divisible by 5^p. */
94 static inline bool
95 multipleOfPowerOf5(const uint64 value, const uint32 p)
98 * I tried a case distinction on p, but there was no performance
99 * difference.
101 return pow5Factor(value) >= p;
104 /* Returns true if value is divisible by 2^p. */
105 static inline bool
106 multipleOfPowerOf2(const uint64 value, const uint32 p)
108 /* return __builtin_ctzll(value) >= p; */
109 return (value & ((UINT64CONST(1) << p) - 1)) == 0;
113 * We need a 64x128-bit multiplication and a subsequent 128-bit shift.
115 * Multiplication:
117 * The 64-bit factor is variable and passed in, the 128-bit factor comes
118 * from a lookup table. We know that the 64-bit factor only has 55
119 * significant bits (i.e., the 9 topmost bits are zeros). The 128-bit
120 * factor only has 124 significant bits (i.e., the 4 topmost bits are
121 * zeros).
123 * Shift:
125 * In principle, the multiplication result requires 55 + 124 = 179 bits to
126 * represent. However, we then shift this value to the right by j, which is
127 * at least j >= 115, so the result is guaranteed to fit into 179 - 115 =
128 * 64 bits. This means that we only need the topmost 64 significant bits of
129 * the 64x128-bit multiplication.
131 * There are several ways to do this:
133 * 1. Best case: the compiler exposes a 128-bit type.
134 * We perform two 64x64-bit multiplications, add the higher 64 bits of the
135 * lower result to the higher result, and shift by j - 64 bits.
137 * We explicitly cast from 64-bit to 128-bit, so the compiler can tell
138 * that these are only 64-bit inputs, and can map these to the best
139 * possible sequence of assembly instructions. x86-64 machines happen to
140 * have matching assembly instructions for 64x64-bit multiplications and
141 * 128-bit shifts.
143 * 2. Second best case: the compiler exposes intrinsics for the x86-64
144 * assembly instructions mentioned in 1.
146 * 3. We only have 64x64 bit instructions that return the lower 64 bits of
147 * the result, i.e., we have to use plain C.
149 * Our inputs are less than the full width, so we have three options:
150 * a. Ignore this fact and just implement the intrinsics manually.
151 * b. Split both into 31-bit pieces, which guarantees no internal
152 * overflow, but requires extra work upfront (unless we change the
153 * lookup table).
154 * c. Split only the first factor into 31-bit pieces, which also
155 * guarantees no internal overflow, but requires extra work since the
156 * intermediate results are not perfectly aligned.
158 #if defined(HAVE_INT128)
160 /* Best case: use 128-bit type. */
161 static inline uint64
162 mulShift(const uint64 m, const uint64 *const mul, const int32 j)
164 const uint128 b0 = ((uint128) m) * mul[0];
165 const uint128 b2 = ((uint128) m) * mul[1];
167 return (uint64) (((b0 >> 64) + b2) >> (j - 64));
170 static inline uint64
171 mulShiftAll(const uint64 m, const uint64 *const mul, const int32 j,
172 uint64 *const vp, uint64 *const vm, const uint32 mmShift)
174 *vp = mulShift(4 * m + 2, mul, j);
175 *vm = mulShift(4 * m - 1 - mmShift, mul, j);
176 return mulShift(4 * m, mul, j);
179 #elif defined(HAS_64_BIT_INTRINSICS)
181 static inline uint64
182 mulShift(const uint64 m, const uint64 *const mul, const int32 j)
184 /* m is maximum 55 bits */
185 uint64 high1;
187 /* 128 */
188 const uint64 low1 = umul128(m, mul[1], &high1);
190 /* 64 */
191 uint64 high0;
192 uint64 sum;
194 /* 64 */
195 umul128(m, mul[0], &high0);
196 /* 0 */
197 sum = high0 + low1;
199 if (sum < high0)
201 ++high1;
202 /* overflow into high1 */
204 return shiftright128(sum, high1, j - 64);
207 static inline uint64
208 mulShiftAll(const uint64 m, const uint64 *const mul, const int32 j,
209 uint64 *const vp, uint64 *const vm, const uint32 mmShift)
211 *vp = mulShift(4 * m + 2, mul, j);
212 *vm = mulShift(4 * m - 1 - mmShift, mul, j);
213 return mulShift(4 * m, mul, j);
216 #else /* // !defined(HAVE_INT128) &&
217 * !defined(HAS_64_BIT_INTRINSICS) */
219 static inline uint64
220 mulShiftAll(uint64 m, const uint64 *const mul, const int32 j,
221 uint64 *const vp, uint64 *const vm, const uint32 mmShift)
223 m <<= 1; /* m is maximum 55 bits */
225 uint64 tmp;
226 const uint64 lo = umul128(m, mul[0], &tmp);
227 uint64 hi;
228 const uint64 mid = tmp + umul128(m, mul[1], &hi);
230 hi += mid < tmp; /* overflow into hi */
232 const uint64 lo2 = lo + mul[0];
233 const uint64 mid2 = mid + mul[1] + (lo2 < lo);
234 const uint64 hi2 = hi + (mid2 < mid);
236 *vp = shiftright128(mid2, hi2, j - 64 - 1);
238 if (mmShift == 1)
240 const uint64 lo3 = lo - mul[0];
241 const uint64 mid3 = mid - mul[1] - (lo3 > lo);
242 const uint64 hi3 = hi - (mid3 > mid);
244 *vm = shiftright128(mid3, hi3, j - 64 - 1);
246 else
248 const uint64 lo3 = lo + lo;
249 const uint64 mid3 = mid + mid + (lo3 < lo);
250 const uint64 hi3 = hi + hi + (mid3 < mid);
251 const uint64 lo4 = lo3 - mul[0];
252 const uint64 mid4 = mid3 - mul[1] - (lo4 > lo3);
253 const uint64 hi4 = hi3 - (mid4 > mid3);
255 *vm = shiftright128(mid4, hi4, j - 64);
258 return shiftright128(mid, hi, j - 64 - 1);
261 #endif /* // HAS_64_BIT_INTRINSICS */
263 static inline uint32
264 decimalLength(const uint64 v)
266 /* This is slightly faster than a loop. */
267 /* The average output length is 16.38 digits, so we check high-to-low. */
268 /* Function precondition: v is not an 18, 19, or 20-digit number. */
269 /* (17 digits are sufficient for round-tripping.) */
270 Assert(v < 100000000000000000L);
271 if (v >= 10000000000000000L)
273 return 17;
275 if (v >= 1000000000000000L)
277 return 16;
279 if (v >= 100000000000000L)
281 return 15;
283 if (v >= 10000000000000L)
285 return 14;
287 if (v >= 1000000000000L)
289 return 13;
291 if (v >= 100000000000L)
293 return 12;
295 if (v >= 10000000000L)
297 return 11;
299 if (v >= 1000000000L)
301 return 10;
303 if (v >= 100000000L)
305 return 9;
307 if (v >= 10000000L)
309 return 8;
311 if (v >= 1000000L)
313 return 7;
315 if (v >= 100000L)
317 return 6;
319 if (v >= 10000L)
321 return 5;
323 if (v >= 1000L)
325 return 4;
327 if (v >= 100L)
329 return 3;
331 if (v >= 10L)
333 return 2;
335 return 1;
338 /* A floating decimal representing m * 10^e. */
339 typedef struct floating_decimal_64
341 uint64 mantissa;
342 int32 exponent;
343 } floating_decimal_64;
345 static inline floating_decimal_64
346 d2d(const uint64 ieeeMantissa, const uint32 ieeeExponent)
348 int32 e2;
349 uint64 m2;
351 if (ieeeExponent == 0)
353 /* We subtract 2 so that the bounds computation has 2 additional bits. */
354 e2 = 1 - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS - 2;
355 m2 = ieeeMantissa;
357 else
359 e2 = ieeeExponent - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS - 2;
360 m2 = (UINT64CONST(1) << DOUBLE_MANTISSA_BITS) | ieeeMantissa;
363 #if STRICTLY_SHORTEST
364 const bool even = (m2 & 1) == 0;
365 const bool acceptBounds = even;
366 #else
367 const bool acceptBounds = false;
368 #endif
370 /* Step 2: Determine the interval of legal decimal representations. */
371 const uint64 mv = 4 * m2;
373 /* Implicit bool -> int conversion. True is 1, false is 0. */
374 const uint32 mmShift = ieeeMantissa != 0 || ieeeExponent <= 1;
376 /* We would compute mp and mm like this: */
377 /* uint64 mp = 4 * m2 + 2; */
378 /* uint64 mm = mv - 1 - mmShift; */
380 /* Step 3: Convert to a decimal power base using 128-bit arithmetic. */
381 uint64 vr,
384 int32 e10;
385 bool vmIsTrailingZeros = false;
386 bool vrIsTrailingZeros = false;
388 if (e2 >= 0)
391 * I tried special-casing q == 0, but there was no effect on
392 * performance.
394 * This expr is slightly faster than max(0, log10Pow2(e2) - 1).
396 const uint32 q = log10Pow2(e2) - (e2 > 3);
397 const int32 k = DOUBLE_POW5_INV_BITCOUNT + pow5bits(q) - 1;
398 const int32 i = -e2 + q + k;
400 e10 = q;
402 vr = mulShiftAll(m2, DOUBLE_POW5_INV_SPLIT[q], i, &vp, &vm, mmShift);
404 if (q <= 21)
407 * This should use q <= 22, but I think 21 is also safe. Smaller
408 * values may still be safe, but it's more difficult to reason
409 * about them.
411 * Only one of mp, mv, and mm can be a multiple of 5, if any.
413 const uint32 mvMod5 = (uint32) (mv - 5 * div5(mv));
415 if (mvMod5 == 0)
417 vrIsTrailingZeros = multipleOfPowerOf5(mv, q);
419 else if (acceptBounds)
421 /*----
422 * Same as min(e2 + (~mm & 1), pow5Factor(mm)) >= q
423 * <=> e2 + (~mm & 1) >= q && pow5Factor(mm) >= q
424 * <=> true && pow5Factor(mm) >= q, since e2 >= q.
425 *----
427 vmIsTrailingZeros = multipleOfPowerOf5(mv - 1 - mmShift, q);
429 else
431 /* Same as min(e2 + 1, pow5Factor(mp)) >= q. */
432 vp -= multipleOfPowerOf5(mv + 2, q);
436 else
439 * This expression is slightly faster than max(0, log10Pow5(-e2) - 1).
441 const uint32 q = log10Pow5(-e2) - (-e2 > 1);
442 const int32 i = -e2 - q;
443 const int32 k = pow5bits(i) - DOUBLE_POW5_BITCOUNT;
444 const int32 j = q - k;
446 e10 = q + e2;
448 vr = mulShiftAll(m2, DOUBLE_POW5_SPLIT[i], j, &vp, &vm, mmShift);
450 if (q <= 1)
453 * {vr,vp,vm} is trailing zeros if {mv,mp,mm} has at least q
454 * trailing 0 bits.
456 /* mv = 4 * m2, so it always has at least two trailing 0 bits. */
457 vrIsTrailingZeros = true;
458 if (acceptBounds)
461 * mm = mv - 1 - mmShift, so it has 1 trailing 0 bit iff
462 * mmShift == 1.
464 vmIsTrailingZeros = mmShift == 1;
466 else
469 * mp = mv + 2, so it always has at least one trailing 0 bit.
471 --vp;
474 else if (q < 63)
476 /* TODO(ulfjack):Use a tighter bound here. */
478 * We need to compute min(ntz(mv), pow5Factor(mv) - e2) >= q - 1
480 /* <=> ntz(mv) >= q - 1 && pow5Factor(mv) - e2 >= q - 1 */
481 /* <=> ntz(mv) >= q - 1 (e2 is negative and -e2 >= q) */
482 /* <=> (mv & ((1 << (q - 1)) - 1)) == 0 */
485 * We also need to make sure that the left shift does not
486 * overflow.
488 vrIsTrailingZeros = multipleOfPowerOf2(mv, q - 1);
493 * Step 4: Find the shortest decimal representation in the interval of
494 * legal representations.
496 uint32 removed = 0;
497 uint8 lastRemovedDigit = 0;
498 uint64 output;
500 /* On average, we remove ~2 digits. */
501 if (vmIsTrailingZeros || vrIsTrailingZeros)
503 /* General case, which happens rarely (~0.7%). */
504 for (;;)
506 const uint64 vpDiv10 = div10(vp);
507 const uint64 vmDiv10 = div10(vm);
509 if (vpDiv10 <= vmDiv10)
510 break;
512 const uint32 vmMod10 = (uint32) (vm - 10 * vmDiv10);
513 const uint64 vrDiv10 = div10(vr);
514 const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
516 vmIsTrailingZeros &= vmMod10 == 0;
517 vrIsTrailingZeros &= lastRemovedDigit == 0;
518 lastRemovedDigit = (uint8) vrMod10;
519 vr = vrDiv10;
520 vp = vpDiv10;
521 vm = vmDiv10;
522 ++removed;
525 if (vmIsTrailingZeros)
527 for (;;)
529 const uint64 vmDiv10 = div10(vm);
530 const uint32 vmMod10 = (uint32) (vm - 10 * vmDiv10);
532 if (vmMod10 != 0)
533 break;
535 const uint64 vpDiv10 = div10(vp);
536 const uint64 vrDiv10 = div10(vr);
537 const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
539 vrIsTrailingZeros &= lastRemovedDigit == 0;
540 lastRemovedDigit = (uint8) vrMod10;
541 vr = vrDiv10;
542 vp = vpDiv10;
543 vm = vmDiv10;
544 ++removed;
548 if (vrIsTrailingZeros && lastRemovedDigit == 5 && vr % 2 == 0)
550 /* Round even if the exact number is .....50..0. */
551 lastRemovedDigit = 4;
555 * We need to take vr + 1 if vr is outside bounds or we need to round
556 * up.
558 output = vr + ((vr == vm && (!acceptBounds || !vmIsTrailingZeros)) || lastRemovedDigit >= 5);
560 else
563 * Specialized for the common case (~99.3%). Percentages below are
564 * relative to this.
566 bool roundUp = false;
567 const uint64 vpDiv100 = div100(vp);
568 const uint64 vmDiv100 = div100(vm);
570 if (vpDiv100 > vmDiv100)
572 /* Optimization:remove two digits at a time(~86.2 %). */
573 const uint64 vrDiv100 = div100(vr);
574 const uint32 vrMod100 = (uint32) (vr - 100 * vrDiv100);
576 roundUp = vrMod100 >= 50;
577 vr = vrDiv100;
578 vp = vpDiv100;
579 vm = vmDiv100;
580 removed += 2;
583 /*----
584 * Loop iterations below (approximately), without optimization
585 * above:
587 * 0: 0.03%, 1: 13.8%, 2: 70.6%, 3: 14.0%, 4: 1.40%, 5: 0.14%,
588 * 6+: 0.02%
590 * Loop iterations below (approximately), with optimization
591 * above:
593 * 0: 70.6%, 1: 27.8%, 2: 1.40%, 3: 0.14%, 4+: 0.02%
594 *----
596 for (;;)
598 const uint64 vpDiv10 = div10(vp);
599 const uint64 vmDiv10 = div10(vm);
601 if (vpDiv10 <= vmDiv10)
602 break;
604 const uint64 vrDiv10 = div10(vr);
605 const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
607 roundUp = vrMod10 >= 5;
608 vr = vrDiv10;
609 vp = vpDiv10;
610 vm = vmDiv10;
611 ++removed;
615 * We need to take vr + 1 if vr is outside bounds or we need to round
616 * up.
618 output = vr + (vr == vm || roundUp);
621 const int32 exp = e10 + removed;
623 floating_decimal_64 fd;
625 fd.exponent = exp;
626 fd.mantissa = output;
627 return fd;
630 static inline int
631 to_chars_df(const floating_decimal_64 v, const uint32 olength, char *const result)
633 /* Step 5: Print the decimal representation. */
634 int index = 0;
636 uint64 output = v.mantissa;
637 int32 exp = v.exponent;
639 /*----
640 * On entry, mantissa * 10^exp is the result to be output.
641 * Caller has already done the - sign if needed.
643 * We want to insert the point somewhere depending on the output length
644 * and exponent, which might mean adding zeros:
646 * exp | format
647 * 1+ | ddddddddd000000
648 * 0 | ddddddddd
649 * -1 .. -len+1 | dddddddd.d to d.ddddddddd
650 * -len ... | 0.ddddddddd to 0.000dddddd
652 uint32 i = 0;
653 int32 nexp = exp + olength;
655 if (nexp <= 0)
657 /* -nexp is number of 0s to add after '.' */
658 Assert(nexp >= -3);
659 /* 0.000ddddd */
660 index = 2 - nexp;
661 /* won't need more than this many 0s */
662 memcpy(result, "0.000000", 8);
664 else if (exp < 0)
667 * dddd.dddd; leave space at the start and move the '.' in after
669 index = 1;
671 else
674 * We can save some code later by pre-filling with zeros. We know that
675 * there can be no more than 16 output digits in this form, otherwise
676 * we would not choose fixed-point output.
678 Assert(exp < 16 && exp + olength <= 16);
679 memset(result, '0', 16);
683 * We prefer 32-bit operations, even on 64-bit platforms. We have at most
684 * 17 digits, and uint32 can store 9 digits. If output doesn't fit into
685 * uint32, we cut off 8 digits, so the rest will fit into uint32.
687 if ((output >> 32) != 0)
689 /* Expensive 64-bit division. */
690 const uint64 q = div1e8(output);
691 uint32 output2 = (uint32) (output - 100000000 * q);
692 const uint32 c = output2 % 10000;
694 output = q;
695 output2 /= 10000;
697 const uint32 d = output2 % 10000;
698 const uint32 c0 = (c % 100) << 1;
699 const uint32 c1 = (c / 100) << 1;
700 const uint32 d0 = (d % 100) << 1;
701 const uint32 d1 = (d / 100) << 1;
703 memcpy(result + index + olength - i - 2, DIGIT_TABLE + c0, 2);
704 memcpy(result + index + olength - i - 4, DIGIT_TABLE + c1, 2);
705 memcpy(result + index + olength - i - 6, DIGIT_TABLE + d0, 2);
706 memcpy(result + index + olength - i - 8, DIGIT_TABLE + d1, 2);
707 i += 8;
710 uint32 output2 = (uint32) output;
712 while (output2 >= 10000)
714 const uint32 c = output2 - 10000 * (output2 / 10000);
715 const uint32 c0 = (c % 100) << 1;
716 const uint32 c1 = (c / 100) << 1;
718 output2 /= 10000;
719 memcpy(result + index + olength - i - 2, DIGIT_TABLE + c0, 2);
720 memcpy(result + index + olength - i - 4, DIGIT_TABLE + c1, 2);
721 i += 4;
723 if (output2 >= 100)
725 const uint32 c = (output2 % 100) << 1;
727 output2 /= 100;
728 memcpy(result + index + olength - i - 2, DIGIT_TABLE + c, 2);
729 i += 2;
731 if (output2 >= 10)
733 const uint32 c = output2 << 1;
735 memcpy(result + index + olength - i - 2, DIGIT_TABLE + c, 2);
737 else
739 result[index] = (char) ('0' + output2);
742 if (index == 1)
745 * nexp is 1..15 here, representing the number of digits before the
746 * point. A value of 16 is not possible because we switch to
747 * scientific notation when the display exponent reaches 15.
749 Assert(nexp < 16);
750 /* gcc only seems to want to optimize memmove for small 2^n */
751 if (nexp & 8)
753 memmove(result + index - 1, result + index, 8);
754 index += 8;
756 if (nexp & 4)
758 memmove(result + index - 1, result + index, 4);
759 index += 4;
761 if (nexp & 2)
763 memmove(result + index - 1, result + index, 2);
764 index += 2;
766 if (nexp & 1)
768 result[index - 1] = result[index];
770 result[nexp] = '.';
771 index = olength + 1;
773 else if (exp >= 0)
775 /* we supplied the trailing zeros earlier, now just set the length. */
776 index = olength + exp;
778 else
780 index = olength + (2 - nexp);
783 return index;
786 static inline int
787 to_chars(floating_decimal_64 v, const bool sign, char *const result)
789 /* Step 5: Print the decimal representation. */
790 int index = 0;
792 uint64 output = v.mantissa;
793 uint32 olength = decimalLength(output);
794 int32 exp = v.exponent + olength - 1;
796 if (sign)
798 result[index++] = '-';
802 * The thresholds for fixed-point output are chosen to match printf
803 * defaults. Beware that both the code of to_chars_df and the value of
804 * DOUBLE_SHORTEST_DECIMAL_LEN are sensitive to these thresholds.
806 if (exp >= -4 && exp < 15)
807 return to_chars_df(v, olength, result + index) + sign;
810 * If v.exponent is exactly 0, we might have reached here via the small
811 * integer fast path, in which case v.mantissa might contain trailing
812 * (decimal) zeros. For scientific notation we need to move these zeros
813 * into the exponent. (For fixed point this doesn't matter, which is why
814 * we do this here rather than above.)
816 * Since we already calculated the display exponent (exp) above based on
817 * the old decimal length, that value does not change here. Instead, we
818 * just reduce the display length for each digit removed.
820 * If we didn't get here via the fast path, the raw exponent will not
821 * usually be 0, and there will be no trailing zeros, so we pay no more
822 * than one div10/multiply extra cost. We claw back half of that by
823 * checking for divisibility by 2 before dividing by 10.
825 if (v.exponent == 0)
827 while ((output & 1) == 0)
829 const uint64 q = div10(output);
830 const uint32 r = (uint32) (output - 10 * q);
832 if (r != 0)
833 break;
834 output = q;
835 --olength;
839 /*----
840 * Print the decimal digits.
842 * The following code is equivalent to:
844 * for (uint32 i = 0; i < olength - 1; ++i) {
845 * const uint32 c = output % 10; output /= 10;
846 * result[index + olength - i] = (char) ('0' + c);
848 * result[index] = '0' + output % 10;
849 *----
852 uint32 i = 0;
855 * We prefer 32-bit operations, even on 64-bit platforms. We have at most
856 * 17 digits, and uint32 can store 9 digits. If output doesn't fit into
857 * uint32, we cut off 8 digits, so the rest will fit into uint32.
859 if ((output >> 32) != 0)
861 /* Expensive 64-bit division. */
862 const uint64 q = div1e8(output);
863 uint32 output2 = (uint32) (output - 100000000 * q);
865 output = q;
867 const uint32 c = output2 % 10000;
869 output2 /= 10000;
871 const uint32 d = output2 % 10000;
872 const uint32 c0 = (c % 100) << 1;
873 const uint32 c1 = (c / 100) << 1;
874 const uint32 d0 = (d % 100) << 1;
875 const uint32 d1 = (d / 100) << 1;
877 memcpy(result + index + olength - i - 1, DIGIT_TABLE + c0, 2);
878 memcpy(result + index + olength - i - 3, DIGIT_TABLE + c1, 2);
879 memcpy(result + index + olength - i - 5, DIGIT_TABLE + d0, 2);
880 memcpy(result + index + olength - i - 7, DIGIT_TABLE + d1, 2);
881 i += 8;
884 uint32 output2 = (uint32) output;
886 while (output2 >= 10000)
888 const uint32 c = output2 - 10000 * (output2 / 10000);
890 output2 /= 10000;
892 const uint32 c0 = (c % 100) << 1;
893 const uint32 c1 = (c / 100) << 1;
895 memcpy(result + index + olength - i - 1, DIGIT_TABLE + c0, 2);
896 memcpy(result + index + olength - i - 3, DIGIT_TABLE + c1, 2);
897 i += 4;
899 if (output2 >= 100)
901 const uint32 c = (output2 % 100) << 1;
903 output2 /= 100;
904 memcpy(result + index + olength - i - 1, DIGIT_TABLE + c, 2);
905 i += 2;
907 if (output2 >= 10)
909 const uint32 c = output2 << 1;
912 * We can't use memcpy here: the decimal dot goes between these two
913 * digits.
915 result[index + olength - i] = DIGIT_TABLE[c + 1];
916 result[index] = DIGIT_TABLE[c];
918 else
920 result[index] = (char) ('0' + output2);
923 /* Print decimal point if needed. */
924 if (olength > 1)
926 result[index + 1] = '.';
927 index += olength + 1;
929 else
931 ++index;
934 /* Print the exponent. */
935 result[index++] = 'e';
936 if (exp < 0)
938 result[index++] = '-';
939 exp = -exp;
941 else
942 result[index++] = '+';
944 if (exp >= 100)
946 const int32 c = exp % 10;
948 memcpy(result + index, DIGIT_TABLE + 2 * (exp / 10), 2);
949 result[index + 2] = (char) ('0' + c);
950 index += 3;
952 else
954 memcpy(result + index, DIGIT_TABLE + 2 * exp, 2);
955 index += 2;
958 return index;
961 static inline bool
962 d2d_small_int(const uint64 ieeeMantissa,
963 const uint32 ieeeExponent,
964 floating_decimal_64 *v)
966 const int32 e2 = (int32) ieeeExponent - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS;
969 * Avoid using multiple "return false;" here since it tends to provoke the
970 * compiler into inlining multiple copies of d2d, which is undesirable.
973 if (e2 >= -DOUBLE_MANTISSA_BITS && e2 <= 0)
975 /*----
976 * Since 2^52 <= m2 < 2^53 and 0 <= -e2 <= 52:
977 * 1 <= f = m2 / 2^-e2 < 2^53.
979 * Test if the lower -e2 bits of the significand are 0, i.e. whether
980 * the fraction is 0. We can use ieeeMantissa here, since the implied
981 * 1 bit can never be tested by this; the implied 1 can only be part
982 * of a fraction if e2 < -DOUBLE_MANTISSA_BITS which we already
983 * checked. (e.g. 0.5 gives ieeeMantissa == 0 and e2 == -53)
985 const uint64 mask = (UINT64CONST(1) << -e2) - 1;
986 const uint64 fraction = ieeeMantissa & mask;
988 if (fraction == 0)
990 /*----
991 * f is an integer in the range [1, 2^53).
992 * Note: mantissa might contain trailing (decimal) 0's.
993 * Note: since 2^53 < 10^16, there is no need to adjust
994 * decimalLength().
996 const uint64 m2 = (UINT64CONST(1) << DOUBLE_MANTISSA_BITS) | ieeeMantissa;
998 v->mantissa = m2 >> -e2;
999 v->exponent = 0;
1000 return true;
1004 return false;
1008 * Store the shortest decimal representation of the given double as an
1009 * UNTERMINATED string in the caller's supplied buffer (which must be at least
1010 * DOUBLE_SHORTEST_DECIMAL_LEN-1 bytes long).
1012 * Returns the number of bytes stored.
1015 double_to_shortest_decimal_bufn(double f, char *result)
1018 * Step 1: Decode the floating-point number, and unify normalized and
1019 * subnormal cases.
1021 const uint64 bits = double_to_bits(f);
1023 /* Decode bits into sign, mantissa, and exponent. */
1024 const bool ieeeSign = ((bits >> (DOUBLE_MANTISSA_BITS + DOUBLE_EXPONENT_BITS)) & 1) != 0;
1025 const uint64 ieeeMantissa = bits & ((UINT64CONST(1) << DOUBLE_MANTISSA_BITS) - 1);
1026 const uint32 ieeeExponent = (uint32) ((bits >> DOUBLE_MANTISSA_BITS) & ((1u << DOUBLE_EXPONENT_BITS) - 1));
1028 /* Case distinction; exit early for the easy cases. */
1029 if (ieeeExponent == ((1u << DOUBLE_EXPONENT_BITS) - 1u) || (ieeeExponent == 0 && ieeeMantissa == 0))
1031 return copy_special_str(result, ieeeSign, (ieeeExponent != 0), (ieeeMantissa != 0));
1034 floating_decimal_64 v;
1035 const bool isSmallInt = d2d_small_int(ieeeMantissa, ieeeExponent, &v);
1037 if (!isSmallInt)
1039 v = d2d(ieeeMantissa, ieeeExponent);
1042 return to_chars(v, ieeeSign, result);
1046 * Store the shortest decimal representation of the given double as a
1047 * null-terminated string in the caller's supplied buffer (which must be at
1048 * least DOUBLE_SHORTEST_DECIMAL_LEN bytes long).
1050 * Returns the string length.
1053 double_to_shortest_decimal_buf(double f, char *result)
1055 const int index = double_to_shortest_decimal_bufn(f, result);
1057 /* Terminate the string. */
1058 Assert(index < DOUBLE_SHORTEST_DECIMAL_LEN);
1059 result[index] = '\0';
1060 return index;
1064 * Return the shortest decimal representation as a null-terminated palloc'd
1065 * string (outside the backend, uses malloc() instead).
1067 * Caller is responsible for freeing the result.
1069 char *
1070 double_to_shortest_decimal(double f)
1072 char *const result = (char *) palloc(DOUBLE_SHORTEST_DECIMAL_LEN);
1074 double_to_shortest_decimal_buf(f, result);
1075 return result;