tests/inline9.c

   1 struct s {
   2         int a[30][40];
   3         int b[50];
   4 };
   5
   6 void g(struct s *u)
   7 {
   8         for (int i = 0; i < 10; ++i)
   9                 for (int j = 0; j < 10; ++j)
  10                         u->a[10 + i][20 + j] = i + j;
  11         u->b[5] = 1;
  12 }
  13
  14 inline void h(struct s t[20])
  15 {
  16         int a = 0;
  17         for (int i = 0; i < 20; ++i)
  18                 g(&t[i]);
  19 }
  20
  21 void f()
  22 {
  23         struct s s[10][20];
  24
  25 #pragma scop
  26         int a = 1;
  27         for (int i = 0; i < 10; ++i)
  28                 h(s[i]);
  29 #pragma endscop
  30 }