5 int bad0(void) { return __builtin_constant_p(global
); }
6 int bad1(void) { return __builtin_constant_p(global
++); }
7 inline int bad2(int x
) { return __builtin_constant_p(x
++); }
8 inline int bad3(int x
) { return __builtin_constant_p(x
); }
9 inline int bad4(const char *x
) { return __builtin_constant_p(x
); }
10 int bad5(void) { return bad2(1); }
11 inline int bad6(int x
) { return __builtin_constant_p(x
+1); }
12 int bad7(void) { return __builtin_constant_p(func()); }
13 int bad8(void) { char buf
[10]; return __builtin_constant_p(buf
); }
14 int bad9(const char *x
) { return __builtin_constant_p(x
[123456]); }
15 int bad10(void) { return __builtin_constant_p(&global
); }
17 /* These must pass, or we've broken gcc2 functionality. */
18 int good0(void) { return __builtin_constant_p(1); }
19 int good1(void) { return __builtin_constant_p("hi"); }
20 int good2(void) { return __builtin_constant_p((1234 + 45) & ~7); }
22 /* These are extensions to gcc2. Failure indicates an optimization
24 int opt0(void) { return bad3(1); }
25 int opt1(void) { return bad6(1); }
26 int opt2(void) { return __builtin_constant_p("hi"[0]); }
29 * Opt3 is known to fail. It is one of the important cases that glibc
30 * was interested in though, so keep this around as a reminder.
32 * The solution is to add bits to recover bytes from constant pool
33 * elements given nothing but a constant pool label and an offset.
34 * When we can do that, and we can simplify strlen after the fact,
35 * then we can enable recognition of constant pool labels as constants.
38 /* int opt3(void) { return bad4("hi"); } */
41 /* Call through tables so -finline-functions can't screw with us. */
42 int (*bad_t0
[])(void) = {
43 bad0
, bad1
, bad5
, bad7
, bad8
, bad10
46 int (*bad_t1
[])(int x
) = {
50 int (*bad_t2
[])(const char *x
) = {
54 int (*good_t0
[])(void) = {
58 int (*opt_t0
[])(void) = {
59 opt0
, opt1
, opt2
/* , opt3 */
62 #define N(arr) (sizeof(arr)/sizeof(*arr))
68 for (i
= 0; i
< N(bad_t0
); ++i
)
72 for (i
= 0; i
< N(bad_t1
); ++i
)
76 for (i
= 0; i
< N(bad_t2
); ++i
)
77 if ((*bad_t2
[i
])("hi"))
80 for (i
= 0; i
< N(good_t0
); ++i
)
81 if (! (*good_t0
[i
])())
85 for (i
= 0; i
< N(opt_t0
); ++i
)