C++: simplify output from suggest_alternatives_for
[official-gcc.git] / libgomp / testsuite / libgomp.oacc-c-c++-common / reduction-cplx-dbl.c
blob8fd4db97cb64d380173928b75d76b5de0e33af64
2 #if !defined(__hppa__) || !defined(__hpux__)
3 #include <complex.h>
4 #endif
6 /* Double float has 53 bits of fraction. */
7 #define FRAC (1.0 / (1LL << 48))
8 typedef double _Complex Type;
10 int close_enough (Type a, Type b)
12 Type diff = a - b;
13 double mag2_a = __real__(a) * __real__ (a) + __imag__ (a) * __imag__ (a);
14 double mag2_diff = (__real__(diff) * __real__ (diff)
15 + __imag__ (diff) * __imag__ (diff));
17 return mag2_diff / mag2_a < (FRAC * FRAC);
20 #define N 100
22 static int __attribute__ ((noinline))
23 vector (Type ary[N], Type sum, Type prod)
25 Type tsum = 0, tprod = 1;
27 #pragma acc parallel vector_length(32) copyin(ary[0:N])
29 #pragma acc loop vector reduction(+:tsum) reduction (*:tprod)
30 for (int ix = 0; ix < N; ix++)
32 tsum += ary[ix];
33 tprod *= ary[ix];
37 if (!close_enough (sum, tsum))
38 return 1;
40 if (!close_enough (prod, tprod))
41 return 1;
43 return 0;
46 static int __attribute__ ((noinline))
47 worker (Type ary[N], Type sum, Type prod)
49 Type tsum = 0, tprod = 1;
51 #pragma acc parallel num_workers(32) copyin(ary[0:N])
53 #pragma acc loop worker reduction(+:tsum) reduction (*:tprod)
54 for (int ix = 0; ix < N; ix++)
56 tsum += ary[ix];
57 tprod *= ary[ix];
61 if (!close_enough (sum, tsum))
62 return 1;
64 if (!close_enough (prod, tprod))
65 return 1;
67 return 0;
70 static int __attribute__ ((noinline))
71 gang (Type ary[N], Type sum, Type prod)
73 Type tsum = 0, tprod = 1;
75 #pragma acc parallel num_gangs (32) copyin(ary[0:N])
77 #pragma acc loop gang reduction(+:tsum) reduction (*:tprod)
78 for (int ix = 0; ix < N; ix++)
80 tsum += ary[ix];
81 tprod *= ary[ix];
85 if (!close_enough (sum, tsum))
86 return 1;
88 if (!close_enough (prod, tprod))
89 return 1;
91 return 0;
94 int main (void)
96 Type ary[N], sum = 0, prod = 1;
98 for (int ix = 0; ix < N; ix++)
100 double frac = ix * (1.0 / 1024) + 1.0;
102 ary[ix] = frac + frac * 2.0j - 1.0j;
103 sum += ary[ix];
104 prod *= ary[ix];
107 if (vector (ary, sum, prod))
108 return 1;
110 if (worker (ary, sum, prod))
111 return 1;
113 if (gang (ary, sum, prod))
114 return 1;
116 return 0;