3 ! With format "PE", 0.0 must still have "+00" as exponent
4 character(len
=10) :: c1
, c2
5 write(c1
,"(1pe9.2)") 0.0
6 write(c2
,"(1pe9.2)") 1.0
7 if (trim(adjustl(c1
)) .ne
. "0.00E+00") call abort()
8 if (trim(adjustl(c2
)) .ne
. "1.00E+00") call abort()