gcc/testsuite/gcc.dg/vect/vect-multitypes-1.c

   1 /* { dg-require-effective-target vect_int } */
   2 /* { dg-add-options bind_pic_locally } */
   3
   4 #include <stdarg.h>
   5 #include "tree-vect.h"
   6
   7 #define N 32
   8
   9 short sa[N];
  10 short sb[N] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,
  11                 16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31};
  12 int ia[N];
  13 int ib[N] = {0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,
  14                0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
  15
  16 /* Current peeling-for-alignment scheme will consider the 'sa[i+7]'
  17    access for peeling, and therefore will examine the option of
  18    using a peeling factor = V-7%V = 1,3 for V=8,4 respectively,
  19    which will also align the access to 'ia[i+3]', and the loop could be
  20    vectorized on all targets that support unaligned loads.  */
  21
  22 __attribute__ ((noinline)) int main1 (int n)
  23 {
  24   int i;
  25
  26   /* Multiple types with different sizes, used in idependent
  27      copmutations. Vectorizable.  */
  28   for (i = 0; i < n; i++)
  29     {
  30       sa[i+7] = sb[i];
  31       ia[i+3] = ib[i+1];
  32     }
  33
  34   /* check results:  */
  35   for (i = 0; i < n; i++)
  36     {
  37       if (sa[i+7] != sb[i] || ia[i+3] != ib[i+1])
  38         abort ();
  39     }
  40
  41   return 0;
  42 }
  43
  44 /* Current peeling-for-alignment scheme will consider the 'ia[i+3]'
  45    access for peeling, and therefore will examine the option of
  46    using a peeling factor = (V-3)%V = 1 for V=2,4.
  47    This will not align the access 'sa[i+3]' (for which we need to
  48    peel 5 iterations). However, 'ia[i+3]' also gets aligned if we peel 5
  49    iterations, so the loop is vectorizable on all targets that support
  50    unaligned loads.  */
  51
  52 __attribute__ ((noinline)) int main2 (int n)
  53 {
  54   int i;
  55
  56   /* Multiple types with different sizes, used in independent
  57      copmutations.  */
  58   for (i = 0; i < n; i++)
  59     {
  60       ia[i+3] = ib[i];
  61       sa[i+3] = sb[i+1];
  62     }
  63
  64   /* check results:  */
  65   for (i = 0; i < n; i++)
  66     {
  67       if (sa[i+3] != sb[i+1] || ia[i+3] != ib[i])
  68         abort ();
  69     }
  70
  71   return 0;
  72 }
  73
  74 int main (void)
  75 {
  76   check_vect ();
  77
  78   main1 (N-7);
  79   main2 (N-3);
  80
  81   return 0;
  82 }
  83
  84 /* { dg-final { scan-tree-dump-times "vectorized 1 loops" 2 "vect" { xfail { vect_no_align && { ! vect_hw_misalign } } } } } */
  85 /* { dg-final { scan-tree-dump-times "Alignment of access forced using peeling" 2 "vect" { xfail {{ vect_no_align && { ! vect_hw_misalign } } || {vect_sizes_32B_16B }}} } } */
  86 /* { dg-final { scan-tree-dump-times "Vectorizing an unaligned access" 4 "vect" { xfail {{ vect_no_align && { ! vect_hw_misalign } } || {vect_sizes_32B_16B }}} } } */
  87