Revert "Set num_threads to 50 on 32-bit hppa in two libgomp loop tests"
[official-gcc.git] / libgo / go / sync / once.go
blob8844314e7e9dc0bdc5e3855b50cb5789a88ce69f
1 // Copyright 2009 The Go Authors. All rights reserved.
2 // Use of this source code is governed by a BSD-style
3 // license that can be found in the LICENSE file.
5 package sync
7 import (
8 "sync/atomic"
11 // Once is an object that will perform exactly one action.
13 // A Once must not be copied after first use.
14 type Once struct {
15 // done indicates whether the action has been performed.
16 // It is first in the struct because it is used in the hot path.
17 // The hot path is inlined at every call site.
18 // Placing done first allows more compact instructions on some architectures (amd64/386),
19 // and fewer instructions (to calculate offset) on other architectures.
20 done uint32
21 m Mutex
24 // Do calls the function f if and only if Do is being called for the
25 // first time for this instance of Once. In other words, given
26 // var once Once
27 // if once.Do(f) is called multiple times, only the first call will invoke f,
28 // even if f has a different value in each invocation. A new instance of
29 // Once is required for each function to execute.
31 // Do is intended for initialization that must be run exactly once. Since f
32 // is niladic, it may be necessary to use a function literal to capture the
33 // arguments to a function to be invoked by Do:
34 // config.once.Do(func() { config.init(filename) })
36 // Because no call to Do returns until the one call to f returns, if f causes
37 // Do to be called, it will deadlock.
39 // If f panics, Do considers it to have returned; future calls of Do return
40 // without calling f.
42 func (o *Once) Do(f func()) {
43 // Note: Here is an incorrect implementation of Do:
45 // if atomic.CompareAndSwapUint32(&o.done, 0, 1) {
46 // f()
47 // }
49 // Do guarantees that when it returns, f has finished.
50 // This implementation would not implement that guarantee:
51 // given two simultaneous calls, the winner of the cas would
52 // call f, and the second would return immediately, without
53 // waiting for the first's call to f to complete.
54 // This is why the slow path falls back to a mutex, and why
55 // the atomic.StoreUint32 must be delayed until after f returns.
57 if atomic.LoadUint32(&o.done) == 0 {
58 // Outlined slow-path to allow inlining of the fast-path.
59 o.doSlow(f)
63 func (o *Once) doSlow(f func()) {
64 o.m.Lock()
65 defer o.m.Unlock()
66 if o.done == 0 {
67 defer atomic.StoreUint32(&o.done, 1)
68 f()