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40 /* @(#)e_exp.c 1.3 95/01/18 */
42 * ====================================================
43 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
45 * Developed at SunSoft, a Sun Microsystems, Inc. business.
46 * Permission to use, copy, modify, and distribute this
47 * software is freely granted, provided that this notice
49 * ====================================================
53 * Returns the exponential of x.
56 * 1. Argument reduction:
57 * Reduce x to an r so that |r| <= 0.5*ln2 ~ 0.34658.
58 * Given x, find r and integer k such that
60 * x = k*ln2 + r, |r| <= 0.5*ln2.
62 * Here r will be represented as r = hi-lo for better
65 * 2. Approximation of exp(r) by a special rational function on
66 * the interval [0,0.34658]:
68 * R(r**2) = r*(exp(r)+1)/(exp(r)-1) = 2 + r*r/6 - r**4/360 + ...
69 * We use a special Reme algorithm on [0,0.34658] to generate
70 * a polynomial of degree 5 to approximate R. The maximum error
71 * of this polynomial approximation is bounded by 2**-59. In
73 * R(z) ~ 2.0 + P1*z + P2*z**2 + P3*z**3 + P4*z**4 + P5*z**5
74 * (where z=r*r, and the values of P1 to P5 are listed below)
77 * | 2.0+P1*z+...+P5*z - R(z) | <= 2
79 * The computation of exp(r) thus becomes
81 * exp(r) = 1 + -------
84 * = 1 + r + ----------- (for better accuracy)
88 * R1(r) = r - (P1*r + P2*r + ... + P5*r ).
90 * 3. Scale back to obtain exp(x):
91 * From step 1, we have
92 * exp(x) = 2^k * exp(r)
95 * exp(INF) is INF, exp(NaN) is NaN;
97 * for finite argument, only exp(0)=1 is exact.
100 * according to an error analysis, the error is always less than
101 * 1 ulp (unit in the last place).
105 * if x > 7.09782712893383973096e+02 then exp(x) overflow
106 * if x < -7.45133219101941108420e+02 then exp(x) underflow
109 * The hexadecimal values are the intended ones for the following
110 * constants. The decimal values may be used, provided that the
111 * compiler will convert from decimal to binary accurately enough
112 * to produce the hexadecimal values shown.
123 halF
[2] = {0.5,-0.5,},
124 really_big
= 1.0e+300,
125 twom1000
= 9.33263618503218878990e-302, /* 2**-1000=0x01700000,0*/
126 o_threshold
= 7.09782712893383973096e+02, /* 0x40862E42, 0xFEFA39EF */
127 u_threshold
= -7.45133219101941108420e+02, /* 0xc0874910, 0xD52D3051 */
128 ln2HI
[2] ={ 6.93147180369123816490e-01, /* 0x3fe62e42, 0xfee00000 */
129 -6.93147180369123816490e-01,},/* 0xbfe62e42, 0xfee00000 */
130 ln2LO
[2] ={ 1.90821492927058770002e-10, /* 0x3dea39ef, 0x35793c76 */
131 -1.90821492927058770002e-10,},/* 0xbdea39ef, 0x35793c76 */
132 invln2
= 1.44269504088896338700e+00, /* 0x3ff71547, 0x652b82fe */
133 P1
= 1.66666666666666019037e-01, /* 0x3FC55555, 0x5555553E */
134 P2
= -2.77777777770155933842e-03, /* 0xBF66C16C, 0x16BEBD93 */
135 P3
= 6.61375632143793436117e-05, /* 0x3F11566A, 0xAF25DE2C */
136 P4
= -1.65339022054652515390e-06, /* 0xBEBBBD41, 0xC5D26BF1 */
137 P5
= 4.13813679705723846039e-08; /* 0x3E663769, 0x72BEA4D0 */
141 double __ieee754_exp(double x
) /* default IEEE double exp */
143 double __ieee754_exp(x
) /* default IEEE double exp */
153 hx
= __HI(u
); /* high word of x */
154 xsb
= (hx
>>31)&1; /* sign bit of x */
155 hx
&= 0x7fffffff; /* high word of |x| */
157 /* filter out non-finite argument */
158 if(hx
>= 0x40862E42) { /* if |x|>=709.78... */
161 if(((hx
&0xfffff)|__LO(u
))!=0)
162 return x
+x
; /* NaN */
163 else return (xsb
==0)? x
:0.0; /* exp(+-inf)={inf,0} */
165 if(x
> o_threshold
) return really_big
*really_big
; /* overflow */
166 if(x
< u_threshold
) return twom1000
*twom1000
; /* underflow */
169 /* argument reduction */
170 if(hx
> 0x3fd62e42) { /* if |x| > 0.5 ln2 */
171 if(hx
< 0x3FF0A2B2) { /* and |x| < 1.5 ln2 */
172 hi
= x
-ln2HI
[xsb
]; lo
=ln2LO
[xsb
]; k
= 1-xsb
-xsb
;
174 k
= (int)(invln2
*x
+halF
[xsb
]);
176 hi
= x
- t
*ln2HI
[0]; /* t*ln2HI is exact here */
181 else if(hx
< 0x3e300000) { /* when |x|<2**-28 */
182 if(really_big
+x
>one
) return one
+x
;/* trigger inexact */
186 /* x is now in primary range */
188 c
= x
- t
*(P1
+t
*(P2
+t
*(P3
+t
*(P4
+t
*P5
))));
189 if(k
==0) return one
-((x
*c
)/(c
-2.0)-x
);
190 else y
= one
-((lo
-(x
*c
)/(2.0-c
))-hi
);
193 __HI(u
) += (k
<<20); /* add k to y's exponent */
198 __HI(u
) += ((k
+1000)<<20);/* add k to y's exponent */