2 * linux/arch/arm/mach-integrator/pci-integrator.c
4 * Copyright (C) 1999 ARM Limited
5 * Copyright (C) 2000 Deep Blue Solutions Ltd
7 * This program is free software; you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation; either version 2 of the License, or
10 * (at your option) any later version.
12 * This program is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
15 * GNU General Public License for more details.
17 * You should have received a copy of the GNU General Public License
18 * along with this program; if not, write to the Free Software
19 * Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
22 * PCI functions for Integrator
24 #include <linux/kernel.h>
25 #include <linux/pci.h>
26 #include <linux/interrupt.h>
27 #include <linux/init.h>
30 #include <asm/system.h>
31 #include <asm/mach/pci.h>
32 #include <asm/mach-types.h>
35 * A small note about bridges and interrupts. The DECchip 21050 (and
36 * later) adheres to the PCI-PCI bridge specification. This says that
37 * the interrupts on the other side of a bridge are swizzled in the
40 * Dev Interrupt Interrupt
64 * Where A = pin 1, B = pin 2 and so on and pin=0 = default = A.
65 * Thus, each swizzle is ((pin-1) + (device#-4)) % 4
67 * The following code swizzles for exactly one bridge.
69 static inline int bridge_swizzle(int pin
, unsigned int slot
)
71 return (pin
+ slot
) & 3;
75 * This routine handles multiple bridges.
77 static u8 __init
integrator_swizzle(struct pci_dev
*dev
, u8
*pinp
)
85 while (dev
->bus
->self
) {
86 pin
= bridge_swizzle(pin
, PCI_SLOT(dev
->devfn
));
88 * move up the chain of bridges, swizzling as we go.
94 return PCI_SLOT(dev
->devfn
);
97 static int irq_tab
[4] __initdata
= {
98 IRQ_AP_PCIINT0
, IRQ_AP_PCIINT1
, IRQ_AP_PCIINT2
, IRQ_AP_PCIINT3
102 * map the specified device/slot/pin to an IRQ. This works out such
103 * that slot 9 pin 1 is INT0, pin 2 is INT1, and slot 10 pin 1 is INT1.
105 static int __init
integrator_map_irq(struct pci_dev
*dev
, u8 slot
, u8 pin
)
107 int intnr
= ((slot
- 9) + (pin
- 1)) & 3;
109 return irq_tab
[intnr
];
112 extern void pci_v3_init(void *);
114 static struct hw_pci integrator_pci __initdata
= {
115 .swizzle
= integrator_swizzle
,
116 .map_irq
= integrator_map_irq
,
117 .setup
= pci_v3_setup
,
119 .scan
= pci_v3_scan_bus
,
120 .preinit
= pci_v3_preinit
,
121 .postinit
= pci_v3_postinit
,
124 static int __init
integrator_pci_init(void)
126 if (machine_is_integrator())
127 pci_common_init(&integrator_pci
);
131 subsys_initcall(integrator_pci_init
);