detect more forms of modulo expressions when extracting a function
[isl.git] / test_inputs / codegen / cloog / vivien.c
blob9e96236e904a4c4becc2326761138ffc995d2f37
1 for (int c0 = -27 * n + 2; c0 <= 1; c0 += 1)
2 S1(c0 - 1);
3 for (int c0 = 2; c0 <= min(2 * n, n + 29); c0 += 1) {
4 if (c0 >= 3) {
5 if (2 * n >= c0 + 1) {
6 S4((c0 + 1) / 2 - 1, c0 - (c0 + 1) / 2 + 1);
7 if (c0 + 2 >= 2 * n) {
8 for (int c2 = 1; c2 < -n + c0; c2 += 1)
9 S5(-n + c0, n, c2);
10 } else if (c0 >= 5) {
11 S4((c0 + 1) / 2 - 2, c0 - (c0 + 1) / 2 + 2);
12 for (int c2 = 1; c2 < (c0 + 1) / 2 - 1; c2 += 1)
13 S5((c0 + 1) / 2 - 1, c0 - (c0 + 1) / 2 + 1, c2);
16 for (int c1 = -c0 + c0 / 2 + 3; c1 <= min(-1, n - c0); c1 += 1) {
17 S4(-c1, c0 + c1);
18 S6(-c1 + 2, c0 + c1 - 2);
19 for (int c2 = 1; c2 <= -c1; c2 += 1)
20 S5(-c1 + 1, c0 + c1 - 1, c2);
22 if (2 * n >= c0 + 3 && c0 >= n + 2) {
23 S6(-n + c0 + 1, n - 1);
24 for (int c2 = 1; c2 < -n + c0; c2 += 1)
25 S5(-n + c0, n, c2);
27 if (c0 >= n + 3 && 2 * n >= c0 + 1)
28 S6(-n + c0, n);
29 if (c0 >= n + 3) {
30 S1(c0 - 1);
31 } else {
32 if (n + 1 >= c0 && c0 <= 4) {
33 S1(c0 - 1);
34 } else if (c0 >= 5 && n + 1 >= c0) {
35 S1(c0 - 1);
36 S6(2, c0 - 2);
38 if (n + 1 >= c0) {
39 S6(1, c0 - 1);
40 } else if (n >= 3) {
41 S1(n + 1);
42 S6(2, n);
45 if (n == 2 && c0 == 4)
46 S1(3);
47 } else {
48 S1(1);
50 if (c0 % 2 == 0)
51 S3(c0 / 2);
52 for (int c1 = max(1, -n + c0); c1 < (c0 + 1) / 2; c1 += 1)
53 S2(c0 - c1, c1);
55 for (int c0 = max(2 * n + 1, -27 * n + 2); c0 <= n + 29; c0 += 1)
56 S1(c0 - 1);
57 for (int c0 = n + 30; c0 <= 2 * n; c0 += 1) {
58 if (2 * n >= c0 + 1) {
59 S4((c0 + 1) / 2 - 1, c0 - (c0 + 1) / 2 + 1);
60 if (c0 + 2 >= 2 * n) {
61 for (int c2 = 1; c2 < -n + c0; c2 += 1)
62 S5(-n + c0, n, c2);
63 } else {
64 S4((c0 + 1) / 2 - 2, c0 - (c0 + 1) / 2 + 2);
65 for (int c2 = 1; c2 < (c0 + 1) / 2 - 1; c2 += 1)
66 S5((c0 + 1) / 2 - 1, c0 - (c0 + 1) / 2 + 1, c2);
68 for (int c1 = -c0 + c0 / 2 + 3; c1 <= n - c0; c1 += 1) {
69 S4(-c1, c0 + c1);
70 S6(-c1 + 2, c0 + c1 - 2);
71 for (int c2 = 1; c2 <= -c1; c2 += 1)
72 S5(-c1 + 1, c0 + c1 - 1, c2);
74 if (2 * n >= c0 + 3) {
75 S6(-n + c0 + 1, n - 1);
76 for (int c2 = 1; c2 < -n + c0; c2 += 1)
77 S5(-n + c0, n, c2);
79 S6(-n + c0, n);
81 if (c0 % 2 == 0)
82 S3(c0 / 2);
83 for (int c1 = -n + c0; c1 < (c0 + 1) / 2; c1 += 1)
84 S2(c0 - c1, c1);