1 /* Copyright (C) 1991,93,96,97,99,2000,2002 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
3 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
4 with help from Dan Sahlin (dan@sics.se) and
5 commentary by Jim Blandy (jimb@ai.mit.edu);
6 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
7 and implemented by Roland McGrath (roland@ai.mit.edu).
9 The GNU C Library is free software; you can redistribute it and/or
10 modify it under the terms of the GNU Lesser General Public
11 License as published by the Free Software Foundation; either
12 version 2.1 of the License, or (at your option) any later version.
14 The GNU C Library is distributed in the hope that it will be useful,
15 but WITHOUT ANY WARRANTY; without even the implied warranty of
16 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
17 Lesser General Public License for more details.
19 You should have received a copy of the GNU Lesser General Public
20 License along with the GNU C Library; if not, write to the Free
21 Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
29 #if defined (__cplusplus) || (defined (__STDC__) && __STDC__)
30 # define __ptr_t void *
31 #else /* Not C++ or ANSI C. */
32 # define __ptr_t char *
33 #endif /* C++ or ANSI C. */
40 # define reg_char char
43 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
47 #define LONG_MAX_32_BITS 2147483647
50 #define LONG_MAX LONG_MAX_32_BITS
53 #include <sys/types.h>
58 /* Find the first occurrence of C in S. */
64 const unsigned char *char_ptr
;
65 const unsigned long int *longword_ptr
;
66 unsigned long int longword
, magic_bits
, charmask
;
69 c
= (unsigned char) c_in
;
71 /* Handle the first few characters by reading one character at a time.
72 Do this until CHAR_PTR is aligned on a longword boundary. */
73 for (char_ptr
= (const unsigned char *) s
;
74 ((unsigned long int) char_ptr
& (sizeof (longword
) - 1)) != 0;
77 return (__ptr_t
) char_ptr
;
79 /* All these elucidatory comments refer to 4-byte longwords,
80 but the theory applies equally well to 8-byte longwords. */
82 longword_ptr
= (unsigned long int *) char_ptr
;
84 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
85 the "holes." Note that there is a hole just to the left of
86 each byte, with an extra at the end:
88 bits: 01111110 11111110 11111110 11111111
89 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
91 The 1-bits make sure that carries propagate to the next 0-bit.
92 The 0-bits provide holes for carries to fall into. */
94 if (sizeof (longword
) != 4 && sizeof (longword
) != 8)
97 #if LONG_MAX <= LONG_MAX_32_BITS
98 magic_bits
= 0x7efefeff;
100 magic_bits
= ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
103 /* Set up a longword, each of whose bytes is C. */
104 charmask
= c
| (c
<< 8);
105 charmask
|= charmask
<< 16;
106 #if LONG_MAX > LONG_MAX_32_BITS
107 charmask
|= charmask
<< 32;
110 /* Instead of the traditional loop which tests each character,
111 we will test a longword at a time. The tricky part is testing
112 if *any of the four* bytes in the longword in question are zero. */
115 /* We tentatively exit the loop if adding MAGIC_BITS to
116 LONGWORD fails to change any of the hole bits of LONGWORD.
118 1) Is this safe? Will it catch all the zero bytes?
119 Suppose there is a byte with all zeros. Any carry bits
120 propagating from its left will fall into the hole at its
121 least significant bit and stop. Since there will be no
122 carry from its most significant bit, the LSB of the
123 byte to the left will be unchanged, and the zero will be
126 2) Is this worthwhile? Will it ignore everything except
127 zero bytes? Suppose every byte of LONGWORD has a bit set
128 somewhere. There will be a carry into bit 8. If bit 8
129 is set, this will carry into bit 16. If bit 8 is clear,
130 one of bits 9-15 must be set, so there will be a carry
131 into bit 16. Similarly, there will be a carry into bit
132 24. If one of bits 24-30 is set, there will be a carry
133 into bit 31, so all of the hole bits will be changed.
135 The one misfire occurs when bits 24-30 are clear and bit
136 31 is set; in this case, the hole at bit 31 is not
137 changed. If we had access to the processor carry flag,
138 we could close this loophole by putting the fourth hole
141 So it ignores everything except 128's, when they're aligned
144 3) But wait! Aren't we looking for C, not zero?
145 Good point. So what we do is XOR LONGWORD with a longword,
146 each of whose bytes is C. This turns each byte that is C
149 longword
= *longword_ptr
++ ^ charmask
;
151 /* Add MAGIC_BITS to LONGWORD. */
152 if ((((longword
+ magic_bits
)
154 /* Set those bits that were unchanged by the addition. */
157 /* Look at only the hole bits. If any of the hole bits
158 are unchanged, most likely one of the bytes was a
162 /* Which of the bytes was C? If none of them were, it was
163 a misfire; continue the search. */
165 const unsigned char *cp
= (const unsigned char *) (longword_ptr
- 1);
170 return (__ptr_t
) &cp
[1];
172 return (__ptr_t
) &cp
[2];
174 return (__ptr_t
) &cp
[3];
175 #if LONG_MAX > 2147483647
177 return (__ptr_t
) &cp
[4];
179 return (__ptr_t
) &cp
[5];
181 return (__ptr_t
) &cp
[6];
183 return (__ptr_t
) &cp
[7];
188 libc_hidden_def (__rawmemchr
)
189 weak_alias (__rawmemchr
, rawmemchr
)