1 /* Copyright (C) 1991, 1993 Free Software Foundation, Inc.
2 Based on strlen implemention by Torbjorn Granlund (tege@sics.se),
3 with help from Dan Sahlin (dan@sics.se) and
4 commentary by Jim Blandy (jimb@ai.mit.edu);
5 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
6 and implemented by Roland McGrath (roland@ai.mit.edu).
8 The GNU C Library is free software; you can redistribute it and/or
9 modify it under the terms of the GNU Library General Public License as
10 published by the Free Software Foundation; either version 2 of the
11 License, or (at your option) any later version.
13 The GNU C Library is distributed in the hope that it will be useful,
14 but WITHOUT ANY WARRANTY; without even the implied warranty of
15 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
16 Library General Public License for more details.
18 You should have received a copy of the GNU Library General Public
19 License along with the GNU C Library; see the file COPYING.LIB. If
20 not, write to the Free Software Foundation, Inc., 675 Mass Ave,
21 Cambridge, MA 02139, USA. */
28 #if defined (__cplusplus) || (defined (__STDC__) && __STDC__)
29 # define __ptr_t void *
30 #else /* Not C++ or ANSI C. */
31 # define __ptr_t char *
32 #endif /* C++ or ANSI C. */
34 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
38 #define LONG_MAX_32_BITS 2147483647
41 #define LONG_MAX LONG_MAX_32_BITS
44 #include <sys/types.h>
47 /* Search no more than N bytes of S for C. */
55 const unsigned char *char_ptr
;
56 const unsigned long int *longword_ptr
;
57 unsigned long int longword
, magic_bits
, charmask
;
59 c
= (unsigned char) c
;
61 /* Handle the first few characters by reading one character at a time.
62 Do this until CHAR_PTR is aligned on a longword boundary. */
63 for (char_ptr
= s
; n
> 0 && ((unsigned long int) char_ptr
64 & (sizeof (longword
) - 1)) != 0;
67 return (__ptr_t
) char_ptr
;
69 /* All these elucidatory comments refer to 4-byte longwords,
70 but the theory applies equally well to 8-byte longwords. */
72 longword_ptr
= (unsigned long int *) char_ptr
;
74 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
75 the "holes." Note that there is a hole just to the left of
76 each byte, with an extra at the end:
78 bits: 01111110 11111110 11111110 11111111
79 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
81 The 1-bits make sure that carries propagate to the next 0-bit.
82 The 0-bits provide holes for carries to fall into. */
84 if (sizeof (longword
) != 4 && sizeof (longword
) != 8)
87 #if LONG_MAX <= LONG_MAX_32_BITS
88 magic_bits
= 0x7efefeff;
90 magic_bits
= ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
93 /* Set up a longword, each of whose bytes is C. */
94 charmask
= c
| (c
<< 8);
95 charmask
|= charmask
<< 16;
96 #if LONG_MAX > LONG_MAX_32_BITS
97 charmask
|= charmask
<< 32;
100 /* Instead of the traditional loop which tests each character,
101 we will test a longword at a time. The tricky part is testing
102 if *any of the four* bytes in the longword in question are zero. */
103 while (n
>= sizeof (longword
))
105 /* We tentatively exit the loop if adding MAGIC_BITS to
106 LONGWORD fails to change any of the hole bits of LONGWORD.
108 1) Is this safe? Will it catch all the zero bytes?
109 Suppose there is a byte with all zeros. Any carry bits
110 propagating from its left will fall into the hole at its
111 least significant bit and stop. Since there will be no
112 carry from its most significant bit, the LSB of the
113 byte to the left will be unchanged, and the zero will be
116 2) Is this worthwhile? Will it ignore everything except
117 zero bytes? Suppose every byte of LONGWORD has a bit set
118 somewhere. There will be a carry into bit 8. If bit 8
119 is set, this will carry into bit 16. If bit 8 is clear,
120 one of bits 9-15 must be set, so there will be a carry
121 into bit 16. Similarly, there will be a carry into bit
122 24. If one of bits 24-30 is set, there will be a carry
123 into bit 31, so all of the hole bits will be changed.
125 The one misfire occurs when bits 24-30 are clear and bit
126 31 is set; in this case, the hole at bit 31 is not
127 changed. If we had access to the processor carry flag,
128 we could close this loophole by putting the fourth hole
131 So it ignores everything except 128's, when they're aligned
134 3) But wait! Aren't we looking for C, not zero?
135 Good point. So what we do is XOR LONGWORD with a longword,
136 each of whose bytes is C. This turns each byte that is C
139 longword
= *longword_ptr
++ ^ charmask
;
141 /* Add MAGIC_BITS to LONGWORD. */
142 if ((((longword
+ magic_bits
)
144 /* Set those bits that were unchanged by the addition. */
147 /* Look at only the hole bits. If any of the hole bits
148 are unchanged, most likely one of the bytes was a
152 /* Which of the bytes was C? If none of them were, it was
153 a misfire; continue the search. */
155 const unsigned char *cp
= (const unsigned char *) (longword_ptr
- 1);
160 return (__ptr_t
) &cp
[1];
162 return (__ptr_t
) &cp
[2];
164 return (__ptr_t
) &cp
[3];
165 #if LONG_MAX > 2147483647
167 return (__ptr_t
) &cp
[4];
169 return (__ptr_t
) &cp
[5];
171 return (__ptr_t
) &cp
[6];
173 return (__ptr_t
) &cp
[7];
177 n
-= sizeof (longword
);
180 char_ptr
= (const unsigned char *) longword_ptr
;
185 return (__ptr_t
) char_ptr
;