1 /* Internal header for proving correct grouping in strings of numbers.
2 Copyright (C) 1995, 1996, 1997, 1998, 2000 Free Software Foundation, Inc.
3 Contributed by Ulrich Drepper <drepper@gnu.ai.mit.edu>, 1995.
5 The GNU C Library is free software; you can redistribute it and/or
6 modify it under the terms of the GNU Library General Public License as
7 published by the Free Software Foundation; either version 2 of the
8 License, or (at your option) any later version.
10 The GNU C Library is distributed in the hope that it will be useful,
11 but WITHOUT ANY WARRANTY; without even the implied warranty of
12 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
13 Library General Public License for more details.
15 You should have received a copy of the GNU Library General Public
16 License along with the GNU C Library; see the file COPYING.LIB. If not,
17 write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,
18 Boston, MA 02111-1307, USA. */
23 #define MAX(a,b) ({ typeof(a) _a = (a); typeof(b) _b = (b); \
27 /* Find the maximum prefix of the string between BEGIN and END which
28 satisfies the grouping rules. It is assumed that at least one digit
29 follows BEGIN directly. */
31 static inline const STRING_TYPE
*
32 correctly_grouped_prefix (const STRING_TYPE
*begin
, const STRING_TYPE
*end
,
36 const char *thousands
,
49 thousands_len
= strlen (thousands
);
54 const STRING_TYPE
*cp
= end
- 1;
55 const char *gp
= grouping
;
57 /* Check first group. */
64 if (cp
[thousands_len
- 1] == *thousands
)
66 for (cnt
= 1; thousands
[cnt
] != '\0'; ++cnt
)
67 if (thousands
[cnt
] != cp
[thousands_len
- 1 - cnt
])
69 if (thousands
[cnt
] == '\0')
76 /* We allow the representation to contain no grouping at all even if
77 the locale specifies we can have grouping. */
81 if (end
- cp
== (int) *gp
+ 1)
83 /* This group matches the specification. */
85 const STRING_TYPE
*new_end
;
88 /* There is just one complete group. We are done. */
91 /* CP points to a thousands separator character. The preceding
92 remainder of the string from BEGIN to NEW_END is the part we
93 will consider if there is a grouping error in this trailing
94 portion from CP to END. */
97 /* Loop while the grouping is correct. */
100 /* Get the next grouping rule. */
103 /* If end is reached use last rule. */
106 /* Skip the thousands separator. */
115 /* No more thousands separators are allowed to follow. */
119 if (*cp
== thousands
)
122 for (cnt
= 0; thousands
[cnt
] != '\0'; ++cnt
)
123 if (thousands
[cnt
] != cp
[thousands_len
- cnt
- 1])
125 if (thousands
[cnt
] == '\0')
132 /* OK, only digits followed. */
137 /* Check the next group. */
138 const STRING_TYPE
*group_end
= cp
;
143 if (*cp
== thousands
)
146 for (cnt
= 0; thousands
[cnt
] != '\0'; ++cnt
)
147 if (thousands
[cnt
] != cp
[thousands_len
- cnt
- 1])
149 if (thousands
[cnt
] == '\0')
155 if (cp
< begin
&& group_end
- cp
<= (int) *gp
)
156 /* Final group is correct. */
159 if (cp
< begin
|| group_end
- cp
!= (int) *gp
)
160 /* Incorrect group. Punt. */
165 /* The trailing portion of the string starting at NEW_END
166 contains a grouping error. So we will look for a correctly
167 grouped number in the preceding portion instead. */
172 /* Even the first group was wrong; determine maximum shift. */
173 if (end
- cp
> (int) *gp
+ 1)
174 end
= cp
+ (int) *gp
+ 1;
176 /* This number does not fill the first group, but is correct. */
179 /* CP points to a thousands separator character. */
184 return MAX (begin
, end
);