Fix use of half-initialized result in getaddrinfo when using nscd (bug 16743)
[glibc.git] / intl / plural.y
blob105fe0d50e25652158d0be142fc4c872c919002b
1 %{
2 /* Expression parsing for plural form selection.
3 Copyright (C) 2000-2014 Free Software Foundation, Inc.
4 This file is part of the GNU C Library.
5 Written by Ulrich Drepper <drepper@cygnus.com>, 2000.
7 The GNU C Library is free software; you can redistribute it and/or
8 modify it under the terms of the GNU Lesser General Public
9 License as published by the Free Software Foundation; either
10 version 2.1 of the License, or (at your option) any later version.
12 The GNU C Library is distributed in the hope that it will be useful,
13 but WITHOUT ANY WARRANTY; without even the implied warranty of
14 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
15 Lesser General Public License for more details.
17 You should have received a copy of the GNU Lesser General Public
18 License along with the GNU C Library; if not, see
19 <http://www.gnu.org/licenses/>. */
21 /* The bison generated parser uses alloca. AIX 3 forces us to put this
22 declaration at the beginning of the file. The declaration in bison's
23 skeleton file comes too late. This must come before <config.h>
24 because <config.h> may include arbitrary system headers. */
25 #if defined _AIX && !defined __GNUC__
26 #pragma alloca
27 #endif
28 #ifdef HAVE_CONFIG_H
29 # include <config.h>
30 #endif
32 #include <stddef.h>
33 #include <stdlib.h>
34 #include <string.h>
35 #include "plural-exp.h"
37 /* The main function generated by the parser is called __gettextparse,
38 but we want it to be called PLURAL_PARSE. */
39 #ifndef _LIBC
40 # define __gettextparse PLURAL_PARSE
41 #endif
43 #define YYLEX_PARAM &((struct parse_args *) arg)->cp
44 #define YYPARSE_PARAM arg
46 %pure_parser
47 %expect 7
49 %union {
50 unsigned long int num;
51 enum operator op;
52 struct expression *exp;
56 /* Prototypes for local functions. */
57 static struct expression *new_exp PARAMS ((int nargs, enum operator op,
58 struct expression * const *args));
59 static inline struct expression *new_exp_0 PARAMS ((enum operator op));
60 static inline struct expression *new_exp_1 PARAMS ((enum operator op,
61 struct expression *right));
62 static struct expression *new_exp_2 PARAMS ((enum operator op,
63 struct expression *left,
64 struct expression *right));
65 static inline struct expression *new_exp_3 PARAMS ((enum operator op,
66 struct expression *bexp,
67 struct expression *tbranch,
68 struct expression *fbranch));
69 static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
70 static void yyerror PARAMS ((const char *str));
72 /* Allocation of expressions. */
74 static struct expression *
75 new_exp (nargs, op, args)
76 int nargs;
77 enum operator op;
78 struct expression * const *args;
80 int i;
81 struct expression *newp;
83 /* If any of the argument could not be malloc'ed, just return NULL. */
84 for (i = nargs - 1; i >= 0; i--)
85 if (args[i] == NULL)
86 goto fail;
88 /* Allocate a new expression. */
89 newp = (struct expression *) malloc (sizeof (*newp));
90 if (newp != NULL)
92 newp->nargs = nargs;
93 newp->operation = op;
94 for (i = nargs - 1; i >= 0; i--)
95 newp->val.args[i] = args[i];
96 return newp;
99 fail:
100 for (i = nargs - 1; i >= 0; i--)
101 FREE_EXPRESSION (args[i]);
103 return NULL;
106 static inline struct expression *
107 new_exp_0 (op)
108 enum operator op;
110 return new_exp (0, op, NULL);
113 static inline struct expression *
114 new_exp_1 (op, right)
115 enum operator op;
116 struct expression *right;
118 struct expression *args[1];
120 args[0] = right;
121 return new_exp (1, op, args);
124 static struct expression *
125 new_exp_2 (op, left, right)
126 enum operator op;
127 struct expression *left;
128 struct expression *right;
130 struct expression *args[2];
132 args[0] = left;
133 args[1] = right;
134 return new_exp (2, op, args);
137 static inline struct expression *
138 new_exp_3 (op, bexp, tbranch, fbranch)
139 enum operator op;
140 struct expression *bexp;
141 struct expression *tbranch;
142 struct expression *fbranch;
144 struct expression *args[3];
146 args[0] = bexp;
147 args[1] = tbranch;
148 args[2] = fbranch;
149 return new_exp (3, op, args);
154 /* This declares that all operators have the same associativity and the
155 precedence order as in C. See [Harbison, Steele: C, A Reference Manual].
156 There is no unary minus and no bitwise operators.
157 Operators with the same syntactic behaviour have been merged into a single
158 token, to save space in the array generated by bison. */
159 %right '?' /* ? */
160 %left '|' /* || */
161 %left '&' /* && */
162 %left EQUOP2 /* == != */
163 %left CMPOP2 /* < > <= >= */
164 %left ADDOP2 /* + - */
165 %left MULOP2 /* * / % */
166 %right '!' /* ! */
168 %token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2
169 %token <num> NUMBER
170 %type <exp> exp
174 start: exp
176 if ($1 == NULL)
177 YYABORT;
178 ((struct parse_args *) arg)->res = $1;
182 exp: exp '?' exp ':' exp
184 $$ = new_exp_3 (qmop, $1, $3, $5);
186 | exp '|' exp
188 $$ = new_exp_2 (lor, $1, $3);
190 | exp '&' exp
192 $$ = new_exp_2 (land, $1, $3);
194 | exp EQUOP2 exp
196 $$ = new_exp_2 ($2, $1, $3);
198 | exp CMPOP2 exp
200 $$ = new_exp_2 ($2, $1, $3);
202 | exp ADDOP2 exp
204 $$ = new_exp_2 ($2, $1, $3);
206 | exp MULOP2 exp
208 $$ = new_exp_2 ($2, $1, $3);
210 | '!' exp
212 $$ = new_exp_1 (lnot, $2);
214 | 'n'
216 $$ = new_exp_0 (var);
218 | NUMBER
220 if (($$ = new_exp_0 (num)) != NULL)
221 $$->val.num = $1;
223 | '(' exp ')'
225 $$ = $2;
231 void
232 internal_function
233 FREE_EXPRESSION (exp)
234 struct expression *exp;
236 if (exp == NULL)
237 return;
239 /* Handle the recursive case. */
240 switch (exp->nargs)
242 case 3:
243 FREE_EXPRESSION (exp->val.args[2]);
244 /* FALLTHROUGH */
245 case 2:
246 FREE_EXPRESSION (exp->val.args[1]);
247 /* FALLTHROUGH */
248 case 1:
249 FREE_EXPRESSION (exp->val.args[0]);
250 /* FALLTHROUGH */
251 default:
252 break;
255 free (exp);
259 static int
260 yylex (lval, pexp)
261 YYSTYPE *lval;
262 const char **pexp;
264 const char *exp = *pexp;
265 int result;
267 while (1)
269 if (exp[0] == '\0')
271 *pexp = exp;
272 return YYEOF;
275 if (exp[0] != ' ' && exp[0] != '\t')
276 break;
278 ++exp;
281 result = *exp++;
282 switch (result)
284 case '0': case '1': case '2': case '3': case '4':
285 case '5': case '6': case '7': case '8': case '9':
287 unsigned long int n = result - '0';
288 while (exp[0] >= '0' && exp[0] <= '9')
290 n *= 10;
291 n += exp[0] - '0';
292 ++exp;
294 lval->num = n;
295 result = NUMBER;
297 break;
299 case '=':
300 if (exp[0] == '=')
302 ++exp;
303 lval->op = equal;
304 result = EQUOP2;
306 else
307 result = YYERRCODE;
308 break;
310 case '!':
311 if (exp[0] == '=')
313 ++exp;
314 lval->op = not_equal;
315 result = EQUOP2;
317 break;
319 case '&':
320 case '|':
321 if (exp[0] == result)
322 ++exp;
323 else
324 result = YYERRCODE;
325 break;
327 case '<':
328 if (exp[0] == '=')
330 ++exp;
331 lval->op = less_or_equal;
333 else
334 lval->op = less_than;
335 result = CMPOP2;
336 break;
338 case '>':
339 if (exp[0] == '=')
341 ++exp;
342 lval->op = greater_or_equal;
344 else
345 lval->op = greater_than;
346 result = CMPOP2;
347 break;
349 case '*':
350 lval->op = mult;
351 result = MULOP2;
352 break;
354 case '/':
355 lval->op = divide;
356 result = MULOP2;
357 break;
359 case '%':
360 lval->op = module;
361 result = MULOP2;
362 break;
364 case '+':
365 lval->op = plus;
366 result = ADDOP2;
367 break;
369 case '-':
370 lval->op = minus;
371 result = ADDOP2;
372 break;
374 case 'n':
375 case '?':
376 case ':':
377 case '(':
378 case ')':
379 /* Nothing, just return the character. */
380 break;
382 case ';':
383 case '\n':
384 case '\0':
385 /* Be safe and let the user call this function again. */
386 --exp;
387 result = YYEOF;
388 break;
390 default:
391 result = YYERRCODE;
392 #if YYDEBUG != 0
393 --exp;
394 #endif
395 break;
398 *pexp = exp;
400 return result;
404 static void
405 yyerror (str)
406 const char *str;
408 /* Do nothing. We don't print error messages here. */