Fix ldbl-128ibm strtold overflow handling (bug 14551).
[glibc.git] / sysdeps / ieee754 / ldbl-128ibm / mpn2ldbl.c
blob90dae9325de681b898f8a34cf964fd23379f99a1
1 /* Copyright (C) 1995-2015 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
4 The GNU C Library is free software; you can redistribute it and/or
5 modify it under the terms of the GNU Lesser General Public
6 License as published by the Free Software Foundation; either
7 version 2.1 of the License, or (at your option) any later version.
9 The GNU C Library is distributed in the hope that it will be useful,
10 but WITHOUT ANY WARRANTY; without even the implied warranty of
11 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
12 Lesser General Public License for more details.
14 You should have received a copy of the GNU Lesser General Public
15 License along with the GNU C Library; if not, see
16 <http://www.gnu.org/licenses/>. */
18 #include "gmp.h"
19 #include "gmp-impl.h"
20 #include <ieee754.h>
21 #include <errno.h>
22 #include <float.h>
23 #include <math.h>
25 /* Convert a multi-precision integer of the needed number of bits (106
26 for long double) and an integral power of two to a `long double' in
27 IBM extended format. */
29 long double
30 __mpn_construct_long_double (mp_srcptr frac_ptr, int expt, int sign)
32 union ibm_extended_long_double u;
33 unsigned long lzcount;
34 unsigned long long hi, lo;
35 int exponent2;
37 u.d[0].ieee.negative = sign;
38 u.d[1].ieee.negative = sign;
39 u.d[0].ieee.exponent = expt + IEEE754_DOUBLE_BIAS;
40 u.d[1].ieee.exponent = 0;
41 exponent2 = expt - 53 + IEEE754_DOUBLE_BIAS;
43 #if BITS_PER_MP_LIMB == 32
44 /* The low order 53 bits (52 + hidden) go into the lower double */
45 lo = frac_ptr[0];
46 lo |= (frac_ptr[1] & ((1LL << (53 - 32)) - 1)) << 32;
47 /* The high order 53 bits (52 + hidden) go into the upper double */
48 hi = (frac_ptr[1] >> (53 - 32)) & ((1 << 11) - 1);
49 hi |= ((unsigned long long) frac_ptr[2]) << 11;
50 hi |= ((unsigned long long) frac_ptr[3]) << (32 + 11);
51 #elif BITS_PER_MP_LIMB == 64
52 /* The low order 53 bits (52 + hidden) go into the lower double */
53 lo = frac_ptr[0] & (((mp_limb_t) 1 << 53) - 1);
54 /* The high order 53 bits (52 + hidden) go into the upper double */
55 hi = (frac_ptr[0] >> 53) & (((mp_limb_t) 1 << 11) - 1);
56 hi |= (frac_ptr[1] << 11);
57 #else
58 #error "mp_limb size " BITS_PER_MP_LIMB "not accounted for"
59 #endif
61 if ((hi & (1LL << 52)) == 0 && (hi | lo) != 0)
63 /* denormal number */
64 unsigned long long val = hi ? hi : lo;
66 if (sizeof (val) == sizeof (long))
67 lzcount = __builtin_clzl (val);
68 else if ((val >> 32) != 0)
69 lzcount = __builtin_clzl ((long) (val >> 32));
70 else
71 lzcount = __builtin_clzl ((long) val) + 32;
72 if (hi)
73 lzcount = lzcount - (64 - 53);
74 else
75 lzcount = lzcount + 53 - (64 - 53);
77 if (lzcount > u.d[0].ieee.exponent)
79 lzcount = u.d[0].ieee.exponent;
80 u.d[0].ieee.exponent = 0;
81 exponent2 -= lzcount;
83 else
85 u.d[0].ieee.exponent -= (lzcount - 1);
86 exponent2 -= (lzcount - 1);
89 if (lzcount <= 53)
91 hi = (hi << lzcount) | (lo >> (53 - lzcount));
92 lo = (lo << lzcount) & ((1LL << 53) - 1);
94 else
96 hi = lo << (lzcount - 53);
97 lo = 0;
101 if (lo != 0)
103 /* hidden bit of low double controls rounding of the high double.
104 If hidden is '1' and either the explicit mantissa is non-zero
105 or hi is odd, then round up hi and adjust lo (2nd mantissa)
106 plus change the sign of the low double to compensate. */
107 if ((lo & (1LL << 52)) != 0
108 && ((hi & 1) != 0 || (lo & ((1LL << 52) - 1)) != 0))
110 hi++;
111 if ((hi & (1LL << 53)) != 0)
113 hi >>= 1;
114 u.d[0].ieee.exponent++;
115 if (u.d[0].ieee.exponent == IEEE754_DOUBLE_BIAS + DBL_MAX_EXP)
117 /* Overflow. The appropriate overflowed result must
118 be produced (if an infinity, that means the low
119 part must be zero). */
120 __set_errno (ERANGE);
121 return (sign ? -LDBL_MAX : LDBL_MAX) * LDBL_MAX;
124 u.d[1].ieee.negative = !sign;
125 lo = (1LL << 53) - lo;
128 /* Normalize the low double. Shift the mantissa left until
129 the hidden bit is '1' and adjust the exponent accordingly. */
131 if (sizeof (lo) == sizeof (long))
132 lzcount = __builtin_clzl (lo);
133 else if ((lo >> 32) != 0)
134 lzcount = __builtin_clzl ((long) (lo >> 32));
135 else
136 lzcount = __builtin_clzl ((long) lo) + 32;
137 lzcount = lzcount - (64 - 53);
138 lo <<= lzcount;
139 exponent2 -= lzcount;
141 if (exponent2 > 0)
142 u.d[1].ieee.exponent = exponent2;
143 else if (exponent2 > -53)
144 lo >>= 1 - exponent2;
145 else
146 lo = 0;
148 else
149 u.d[1].ieee.negative = 0;
151 u.d[1].ieee.mantissa1 = lo;
152 u.d[1].ieee.mantissa0 = lo >> 32;
153 u.d[0].ieee.mantissa1 = hi;
154 u.d[0].ieee.mantissa0 = hi >> 32;
156 return u.ld;