1 /* Copyright (C) 1991,93,96,97,99,2000,2002,2012 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
3 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
4 with help from Dan Sahlin (dan@sics.se) and
5 commentary by Jim Blandy (jimb@ai.mit.edu);
6 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
7 and implemented by Roland McGrath (roland@ai.mit.edu).
9 The GNU C Library is free software; you can redistribute it and/or
10 modify it under the terms of the GNU Lesser General Public
11 License as published by the Free Software Foundation; either
12 version 2.1 of the License, or (at your option) any later version.
14 The GNU C Library is distributed in the hope that it will be useful,
15 but WITHOUT ANY WARRANTY; without even the implied warranty of
16 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
17 Lesser General Public License for more details.
19 You should have received a copy of the GNU Lesser General Public
20 License along with the GNU C Library; if not, see
21 <http://www.gnu.org/licenses/>. */
28 #define __ptr_t void *
36 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
40 #define LONG_MAX_32_BITS 2147483647
43 #define LONG_MAX LONG_MAX_32_BITS
46 #include <sys/types.h>
51 /* Find the first occurrence of C in S. */
57 const unsigned char *char_ptr
;
58 const unsigned long int *longword_ptr
;
59 unsigned long int longword
, magic_bits
, charmask
;
62 c
= (unsigned char) c_in
;
64 /* Handle the first few characters by reading one character at a time.
65 Do this until CHAR_PTR is aligned on a longword boundary. */
66 for (char_ptr
= (const unsigned char *) s
;
67 ((unsigned long int) char_ptr
& (sizeof (longword
) - 1)) != 0;
70 return (__ptr_t
) char_ptr
;
72 /* All these elucidatory comments refer to 4-byte longwords,
73 but the theory applies equally well to 8-byte longwords. */
75 longword_ptr
= (unsigned long int *) char_ptr
;
77 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
78 the "holes." Note that there is a hole just to the left of
79 each byte, with an extra at the end:
81 bits: 01111110 11111110 11111110 11111111
82 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
84 The 1-bits make sure that carries propagate to the next 0-bit.
85 The 0-bits provide holes for carries to fall into. */
87 if (sizeof (longword
) != 4 && sizeof (longword
) != 8)
90 #if LONG_MAX <= LONG_MAX_32_BITS
91 magic_bits
= 0x7efefeff;
93 magic_bits
= ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
96 /* Set up a longword, each of whose bytes is C. */
97 charmask
= c
| (c
<< 8);
98 charmask
|= charmask
<< 16;
99 #if LONG_MAX > LONG_MAX_32_BITS
100 charmask
|= charmask
<< 32;
103 /* Instead of the traditional loop which tests each character,
104 we will test a longword at a time. The tricky part is testing
105 if *any of the four* bytes in the longword in question are zero. */
108 /* We tentatively exit the loop if adding MAGIC_BITS to
109 LONGWORD fails to change any of the hole bits of LONGWORD.
111 1) Is this safe? Will it catch all the zero bytes?
112 Suppose there is a byte with all zeros. Any carry bits
113 propagating from its left will fall into the hole at its
114 least significant bit and stop. Since there will be no
115 carry from its most significant bit, the LSB of the
116 byte to the left will be unchanged, and the zero will be
119 2) Is this worthwhile? Will it ignore everything except
120 zero bytes? Suppose every byte of LONGWORD has a bit set
121 somewhere. There will be a carry into bit 8. If bit 8
122 is set, this will carry into bit 16. If bit 8 is clear,
123 one of bits 9-15 must be set, so there will be a carry
124 into bit 16. Similarly, there will be a carry into bit
125 24. If one of bits 24-30 is set, there will be a carry
126 into bit 31, so all of the hole bits will be changed.
128 The one misfire occurs when bits 24-30 are clear and bit
129 31 is set; in this case, the hole at bit 31 is not
130 changed. If we had access to the processor carry flag,
131 we could close this loophole by putting the fourth hole
134 So it ignores everything except 128's, when they're aligned
137 3) But wait! Aren't we looking for C, not zero?
138 Good point. So what we do is XOR LONGWORD with a longword,
139 each of whose bytes is C. This turns each byte that is C
142 longword
= *longword_ptr
++ ^ charmask
;
144 /* Add MAGIC_BITS to LONGWORD. */
145 if ((((longword
+ magic_bits
)
147 /* Set those bits that were unchanged by the addition. */
150 /* Look at only the hole bits. If any of the hole bits
151 are unchanged, most likely one of the bytes was a
155 /* Which of the bytes was C? If none of them were, it was
156 a misfire; continue the search. */
158 const unsigned char *cp
= (const unsigned char *) (longword_ptr
- 1);
163 return (__ptr_t
) &cp
[1];
165 return (__ptr_t
) &cp
[2];
167 return (__ptr_t
) &cp
[3];
168 #if LONG_MAX > 2147483647
170 return (__ptr_t
) &cp
[4];
172 return (__ptr_t
) &cp
[5];
174 return (__ptr_t
) &cp
[6];
176 return (__ptr_t
) &cp
[7];
181 libc_hidden_def (__rawmemchr
)
182 weak_alias (__rawmemchr
, rawmemchr
)