Optimize handling of denormals in logb/logbf/logbl
[glibc.git] / stdlib / div.c
bloba388080ed285279269b0b85ac18b050f2763cc4c
1 /* Copyright (C) 1992, 1997, 1999 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
4 The GNU C Library is free software; you can redistribute it and/or
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15 License along with the GNU C Library; if not, see
16 <http://www.gnu.org/licenses/>. */
19 * Copyright (c) 1990 Regents of the University of California.
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22 * This code is derived from software contributed to Berkeley by
23 * Chris Torek.
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50 #include <stdlib.h>
52 /* Return the `div_t' representation of NUMER over DENOM. */
53 div_t
54 div (numer, denom)
55 int numer, denom;
57 div_t result;
59 result.quot = numer / denom;
60 result.rem = numer % denom;
62 /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
63 NUMER / DENOM is to be computed in infinite precision. In
64 other words, we should always truncate the quotient towards
65 zero, never -infinity. Machine division and remainer may
66 work either way when one or both of NUMER or DENOM is
67 negative. If only one is negative and QUOT has been
68 truncated towards -infinity, REM will have the same sign as
69 DENOM and the opposite sign of NUMER; if both are negative
70 and QUOT has been truncated towards -infinity, REM will be
71 positive (will have the opposite sign of NUMER). These are
72 considered `wrong'. If both are NUM and DENOM are positive,
73 RESULT will always be positive. This all boils down to: if
74 NUMER >= 0, but REM < 0, we got the wrong answer. In that
75 case, to get the right answer, add 1 to QUOT and subtract
76 DENOM from REM. */
78 if (numer >= 0 && result.rem < 0)
80 ++result.quot;
81 result.rem -= denom;
84 return result;