imap-send: include strbuf.h
[git/gitster.git] / match-trees.c
blob6bc8eb76477b75e3b8ed32a1f9770e27f235e80f
1 #include "git-compat-util.h"
2 #include "hex.h"
3 #include "match-trees.h"
4 #include "tree.h"
5 #include "tree-walk.h"
6 #include "object-store.h"
8 static int score_missing(unsigned mode)
10 int score;
12 if (S_ISDIR(mode))
13 score = -1000;
14 else if (S_ISLNK(mode))
15 score = -500;
16 else
17 score = -50;
18 return score;
21 static int score_differs(unsigned mode1, unsigned mode2)
23 int score;
25 if (S_ISDIR(mode1) != S_ISDIR(mode2))
26 score = -100;
27 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
28 score = -50;
29 else
30 score = -5;
31 return score;
34 static int score_matches(unsigned mode1, unsigned mode2)
36 int score;
38 /* Heh, we found SHA-1 collisions between different kind of objects */
39 if (S_ISDIR(mode1) != S_ISDIR(mode2))
40 score = -100;
41 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
42 score = -50;
44 else if (S_ISDIR(mode1))
45 score = 1000;
46 else if (S_ISLNK(mode1))
47 score = 500;
48 else
49 score = 250;
50 return score;
53 static void *fill_tree_desc_strict(struct tree_desc *desc,
54 const struct object_id *hash)
56 void *buffer;
57 enum object_type type;
58 unsigned long size;
60 buffer = repo_read_object_file(the_repository, hash, &type, &size);
61 if (!buffer)
62 die("unable to read tree (%s)", oid_to_hex(hash));
63 if (type != OBJ_TREE)
64 die("%s is not a tree", oid_to_hex(hash));
65 init_tree_desc(desc, buffer, size);
66 return buffer;
69 static int base_name_entries_compare(const struct name_entry *a,
70 const struct name_entry *b)
72 return base_name_compare(a->path, tree_entry_len(a), a->mode,
73 b->path, tree_entry_len(b), b->mode);
77 * Inspect two trees, and give a score that tells how similar they are.
79 static int score_trees(const struct object_id *hash1, const struct object_id *hash2)
81 struct tree_desc one;
82 struct tree_desc two;
83 void *one_buf = fill_tree_desc_strict(&one, hash1);
84 void *two_buf = fill_tree_desc_strict(&two, hash2);
85 int score = 0;
87 for (;;) {
88 int cmp;
90 if (one.size && two.size)
91 cmp = base_name_entries_compare(&one.entry, &two.entry);
92 else if (one.size)
93 /* two lacks this entry */
94 cmp = -1;
95 else if (two.size)
96 /* two has more entries */
97 cmp = 1;
98 else
99 break;
101 if (cmp < 0) {
102 /* path1 does not appear in two */
103 score += score_missing(one.entry.mode);
104 update_tree_entry(&one);
105 } else if (cmp > 0) {
106 /* path2 does not appear in one */
107 score += score_missing(two.entry.mode);
108 update_tree_entry(&two);
109 } else {
110 /* path appears in both */
111 if (!oideq(&one.entry.oid, &two.entry.oid)) {
112 /* they are different */
113 score += score_differs(one.entry.mode,
114 two.entry.mode);
115 } else {
116 /* same subtree or blob */
117 score += score_matches(one.entry.mode,
118 two.entry.mode);
120 update_tree_entry(&one);
121 update_tree_entry(&two);
124 free(one_buf);
125 free(two_buf);
126 return score;
130 * Match one itself and its subtrees with two and pick the best match.
132 static void match_trees(const struct object_id *hash1,
133 const struct object_id *hash2,
134 int *best_score,
135 char **best_match,
136 const char *base,
137 int recurse_limit)
139 struct tree_desc one;
140 void *one_buf = fill_tree_desc_strict(&one, hash1);
142 while (one.size) {
143 const char *path;
144 const struct object_id *elem;
145 unsigned short mode;
146 int score;
148 elem = tree_entry_extract(&one, &path, &mode);
149 if (!S_ISDIR(mode))
150 goto next;
151 score = score_trees(elem, hash2);
152 if (*best_score < score) {
153 free(*best_match);
154 *best_match = xstrfmt("%s%s", base, path);
155 *best_score = score;
157 if (recurse_limit) {
158 char *newbase = xstrfmt("%s%s/", base, path);
159 match_trees(elem, hash2, best_score, best_match,
160 newbase, recurse_limit - 1);
161 free(newbase);
164 next:
165 update_tree_entry(&one);
167 free(one_buf);
171 * A tree "oid1" has a subdirectory at "prefix". Come up with a tree object by
172 * replacing it with another tree "oid2".
174 static int splice_tree(const struct object_id *oid1, const char *prefix,
175 const struct object_id *oid2, struct object_id *result)
177 char *subpath;
178 int toplen;
179 char *buf;
180 unsigned long sz;
181 struct tree_desc desc;
182 unsigned char *rewrite_here;
183 const struct object_id *rewrite_with;
184 struct object_id subtree;
185 enum object_type type;
186 int status;
188 subpath = strchrnul(prefix, '/');
189 toplen = subpath - prefix;
190 if (*subpath)
191 subpath++;
193 buf = repo_read_object_file(the_repository, oid1, &type, &sz);
194 if (!buf)
195 die("cannot read tree %s", oid_to_hex(oid1));
196 init_tree_desc(&desc, buf, sz);
198 rewrite_here = NULL;
199 while (desc.size) {
200 const char *name;
201 unsigned short mode;
203 tree_entry_extract(&desc, &name, &mode);
204 if (strlen(name) == toplen &&
205 !memcmp(name, prefix, toplen)) {
206 if (!S_ISDIR(mode))
207 die("entry %s in tree %s is not a tree", name,
208 oid_to_hex(oid1));
211 * We cast here for two reasons:
213 * - to flip the "char *" (for the path) to "unsigned
214 * char *" (for the hash stored after it)
216 * - to discard the "const"; this is OK because we
217 * know it points into our non-const "buf"
219 rewrite_here = (unsigned char *)(desc.entry.path +
220 strlen(desc.entry.path) +
222 break;
224 update_tree_entry(&desc);
226 if (!rewrite_here)
227 die("entry %.*s not found in tree %s", toplen, prefix,
228 oid_to_hex(oid1));
229 if (*subpath) {
230 struct object_id tree_oid;
231 oidread(&tree_oid, rewrite_here);
232 status = splice_tree(&tree_oid, subpath, oid2, &subtree);
233 if (status)
234 return status;
235 rewrite_with = &subtree;
236 } else {
237 rewrite_with = oid2;
239 hashcpy(rewrite_here, rewrite_with->hash);
240 status = write_object_file(buf, sz, OBJ_TREE, result);
241 free(buf);
242 return status;
246 * We are trying to come up with a merge between one and two that
247 * results in a tree shape similar to one. The tree two might
248 * correspond to a subtree of one, in which case it needs to be
249 * shifted down by prefixing otherwise empty directories. On the
250 * other hand, it could cover tree one and we might need to pick a
251 * subtree of it.
253 void shift_tree(struct repository *r,
254 const struct object_id *hash1,
255 const struct object_id *hash2,
256 struct object_id *shifted,
257 int depth_limit)
259 char *add_prefix;
260 char *del_prefix;
261 int add_score, del_score;
264 * NEEDSWORK: this limits the recursion depth to hardcoded
265 * value '2' to avoid excessive overhead.
267 if (!depth_limit)
268 depth_limit = 2;
270 add_score = del_score = score_trees(hash1, hash2);
271 add_prefix = xcalloc(1, 1);
272 del_prefix = xcalloc(1, 1);
275 * See if one's subtree resembles two; if so we need to prefix
276 * two with a few fake trees to match the prefix.
278 match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit);
281 * See if two's subtree resembles one; if so we need to
282 * pick only subtree of two.
284 match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit);
286 /* Assume we do not have to do any shifting */
287 oidcpy(shifted, hash2);
289 if (add_score < del_score) {
290 /* We need to pick a subtree of two */
291 unsigned short mode;
293 if (!*del_prefix)
294 return;
296 if (get_tree_entry(r, hash2, del_prefix, shifted, &mode))
297 die("cannot find path %s in tree %s",
298 del_prefix, oid_to_hex(hash2));
299 return;
302 if (!*add_prefix)
303 return;
305 splice_tree(hash1, add_prefix, hash2, shifted);
309 * The user says the trees will be shifted by this much.
310 * Unfortunately we cannot fundamentally tell which one to
311 * be prefixed, as recursive merge can work in either direction.
313 void shift_tree_by(struct repository *r,
314 const struct object_id *hash1,
315 const struct object_id *hash2,
316 struct object_id *shifted,
317 const char *shift_prefix)
319 struct object_id sub1, sub2;
320 unsigned short mode1, mode2;
321 unsigned candidate = 0;
323 /* Can hash2 be a tree at shift_prefix in tree hash1? */
324 if (!get_tree_entry(r, hash1, shift_prefix, &sub1, &mode1) &&
325 S_ISDIR(mode1))
326 candidate |= 1;
328 /* Can hash1 be a tree at shift_prefix in tree hash2? */
329 if (!get_tree_entry(r, hash2, shift_prefix, &sub2, &mode2) &&
330 S_ISDIR(mode2))
331 candidate |= 2;
333 if (candidate == 3) {
334 /* Both are plausible -- we need to evaluate the score */
335 int best_score = score_trees(hash1, hash2);
336 int score;
338 candidate = 0;
339 score = score_trees(&sub1, hash2);
340 if (score > best_score) {
341 candidate = 1;
342 best_score = score;
344 score = score_trees(&sub2, hash1);
345 if (score > best_score)
346 candidate = 2;
349 if (!candidate) {
350 /* Neither is plausible -- do not shift */
351 oidcpy(shifted, hash2);
352 return;
355 if (candidate == 1)
357 * shift tree2 down by adding shift_prefix above it
358 * to match tree1.
360 splice_tree(hash1, shift_prefix, hash2, shifted);
361 else
363 * shift tree2 up by removing shift_prefix from it
364 * to match tree1.
366 oidcpy(shifted, &sub2);