Backout a74bd5095902, Bug 959405 - Please update the Buri Moz-central, 1.3, 1.2 with...
[gecko.git] / config / check_source_count.py
blobe347e7a55e84b8b9c7ac6346c47406df68c5145e
1 #!/usr/bin/env python
2 # This Source Code Form is subject to the terms of the Mozilla Public
3 # License, v. 2.0. If a copy of the MPL was not distributed with this
4 # file, You can obtain one at http://mozilla.org/MPL/2.0/.
7 # Usage: check_source_count.py SEARCH_TERM COUNT ERROR_LOCATION REPLACEMENT [FILES...]
8 # Checks that FILES contains exactly COUNT matches of SEARCH_TERM. If it does
9 # not, an error message is printed, quoting ERROR_LOCATION, which should
10 # probably be the filename and line number of the erroneous call to
11 # check_source_count.py.
12 from __future__ import print_function
13 import sys
14 import os
15 import re
17 search_string = sys.argv[1]
18 expected_count = int(sys.argv[2])
19 error_location = sys.argv[3]
20 replacement = sys.argv[4]
21 files = sys.argv[5:]
23 details = {}
25 count = 0
26 for f in files:
27 text = file(f).read()
28 match = re.findall(search_string, text)
29 if match:
30 num = len(match)
31 count += num
32 details[f] = num
34 if count == expected_count:
35 print("TEST-PASS | check_source_count.py {0} | {1}"
36 .format(search_string, expected_count))
38 else:
39 print("TEST-UNEXPECTED-FAIL | check_source_count.py {0} | "
40 .format(search_string),
41 end='')
42 if count < expected_count:
43 print("There are fewer occurrences of /{0}/ than expected. "
44 "This may mean that you have removed some, but forgotten to "
45 "account for it {1}.".format(search_string, error_location))
46 else:
47 print("There are more occurrences of /{0}/ than expected. We're trying "
48 "to prevent an increase in the number of {1}'s, using {2} if "
49 "possible. If it is unavoidable, you should update the expected "
50 "count {3}.".format(search_string, search_string, replacement,
51 error_location))
53 print("Expected: {0}; found: {1}".format(expected_count, count))
54 for k in sorted(details):
55 print("Found {0} occurences in {1}".format(details[k],k))
56 sys.exit(-1)