[REGEX_FREE]: Use ((void)0) instead of just (0).
[emacs.git] / src / intervals.c
blobbf51d14d1cd813a001670a841bc5a58338b18bf7
1 /* Code for doing intervals.
2 Copyright (C) 1993, 1994, 1995 Free Software Foundation, Inc.
4 This file is part of GNU Emacs.
6 GNU Emacs is free software; you can redistribute it and/or modify
7 it under the terms of the GNU General Public License as published by
8 the Free Software Foundation; either version 2, or (at your option)
9 any later version.
11 GNU Emacs is distributed in the hope that it will be useful,
12 but WITHOUT ANY WARRANTY; without even the implied warranty of
13 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
14 GNU General Public License for more details.
16 You should have received a copy of the GNU General Public License
17 along with GNU Emacs; see the file COPYING. If not, write to
18 the Free Software Foundation, 675 Mass Ave, Cambridge, MA 02139, USA. */
21 /* NOTES:
23 Have to ensure that we can't put symbol nil on a plist, or some
24 functions may work incorrectly.
26 An idea: Have the owner of the tree keep count of splits and/or
27 insertion lengths (in intervals), and balance after every N.
29 Need to call *_left_hook when buffer is killed.
31 Scan for zero-length, or 0-length to see notes about handling
32 zero length interval-markers.
34 There are comments around about freeing intervals. It might be
35 faster to explicitly free them (put them on the free list) than
36 to GC them.
41 #include <config.h>
42 #include "lisp.h"
43 #include "intervals.h"
44 #include "buffer.h"
45 #include "puresize.h"
46 #include "keyboard.h"
48 /* The rest of the file is within this conditional. */
49 #ifdef USE_TEXT_PROPERTIES
51 /* Test for membership, allowing for t (actually any non-cons) to mean the
52 universal set. */
54 #define TMEM(sym, set) (CONSP (set) ? ! NILP (Fmemq (sym, set)) : ! NILP (set))
56 #define min(x, y) ((x) < (y) ? (x) : (y))
58 Lisp_Object merge_properties_sticky ();
60 /* Utility functions for intervals. */
63 /* Create the root interval of some object, a buffer or string. */
65 INTERVAL
66 create_root_interval (parent)
67 Lisp_Object parent;
69 INTERVAL new;
71 CHECK_IMPURE (parent);
73 new = make_interval ();
75 if (BUFFERP (parent))
77 new->total_length = (BUF_Z (XBUFFER (parent))
78 - BUF_BEG (XBUFFER (parent)));
79 BUF_INTERVALS (XBUFFER (parent)) = new;
81 else if (STRINGP (parent))
83 new->total_length = XSTRING (parent)->size;
84 XSTRING (parent)->intervals = new;
87 new->parent = (INTERVAL) parent;
88 new->position = 1;
90 return new;
93 /* Make the interval TARGET have exactly the properties of SOURCE */
95 void
96 copy_properties (source, target)
97 register INTERVAL source, target;
99 if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
100 return;
102 COPY_INTERVAL_CACHE (source, target);
103 target->plist = Fcopy_sequence (source->plist);
106 /* Merge the properties of interval SOURCE into the properties
107 of interval TARGET. That is to say, each property in SOURCE
108 is added to TARGET if TARGET has no such property as yet. */
110 static void
111 merge_properties (source, target)
112 register INTERVAL source, target;
114 register Lisp_Object o, sym, val;
116 if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
117 return;
119 MERGE_INTERVAL_CACHE (source, target);
121 o = source->plist;
122 while (! EQ (o, Qnil))
124 sym = Fcar (o);
125 val = Fmemq (sym, target->plist);
127 if (NILP (val))
129 o = Fcdr (o);
130 val = Fcar (o);
131 target->plist = Fcons (sym, Fcons (val, target->plist));
132 o = Fcdr (o);
134 else
135 o = Fcdr (Fcdr (o));
139 /* Return 1 if the two intervals have the same properties,
140 0 otherwise. */
143 intervals_equal (i0, i1)
144 INTERVAL i0, i1;
146 register Lisp_Object i0_cdr, i0_sym, i1_val;
147 register i1_len;
149 if (DEFAULT_INTERVAL_P (i0) && DEFAULT_INTERVAL_P (i1))
150 return 1;
152 if (DEFAULT_INTERVAL_P (i0) || DEFAULT_INTERVAL_P (i1))
153 return 0;
155 i1_len = XFASTINT (Flength (i1->plist));
156 if (i1_len & 0x1) /* Paranoia -- plists are always even */
157 abort ();
158 i1_len /= 2;
159 i0_cdr = i0->plist;
160 while (!NILP (i0_cdr))
162 /* Lengths of the two plists were unequal. */
163 if (i1_len == 0)
164 return 0;
166 i0_sym = Fcar (i0_cdr);
167 i1_val = Fmemq (i0_sym, i1->plist);
169 /* i0 has something i1 doesn't. */
170 if (EQ (i1_val, Qnil))
171 return 0;
173 /* i0 and i1 both have sym, but it has different values in each. */
174 i0_cdr = Fcdr (i0_cdr);
175 if (! EQ (Fcar (Fcdr (i1_val)), Fcar (i0_cdr)))
176 return 0;
178 i0_cdr = Fcdr (i0_cdr);
179 i1_len--;
182 /* Lengths of the two plists were unequal. */
183 if (i1_len > 0)
184 return 0;
186 return 1;
189 static int icount;
190 static int idepth;
191 static int zero_length;
193 /* Traverse an interval tree TREE, performing FUNCTION on each node.
194 Pass FUNCTION two args: an interval, and ARG. */
196 void
197 traverse_intervals (tree, position, depth, function, arg)
198 INTERVAL tree;
199 int position, depth;
200 void (* function) ();
201 Lisp_Object arg;
203 if (NULL_INTERVAL_P (tree))
204 return;
206 traverse_intervals (tree->left, position, depth + 1, function, arg);
207 position += LEFT_TOTAL_LENGTH (tree);
208 tree->position = position;
209 (*function) (tree, arg);
210 position += LENGTH (tree);
211 traverse_intervals (tree->right, position, depth + 1, function, arg);
214 #if 0
215 /* These functions are temporary, for debugging purposes only. */
217 INTERVAL search_interval, found_interval;
219 void
220 check_for_interval (i)
221 register INTERVAL i;
223 if (i == search_interval)
225 found_interval = i;
226 icount++;
230 INTERVAL
231 search_for_interval (i, tree)
232 register INTERVAL i, tree;
234 icount = 0;
235 search_interval = i;
236 found_interval = NULL_INTERVAL;
237 traverse_intervals (tree, 1, 0, &check_for_interval, Qnil);
238 return found_interval;
241 static void
242 inc_interval_count (i)
243 INTERVAL i;
245 icount++;
246 if (LENGTH (i) == 0)
247 zero_length++;
248 if (depth > idepth)
249 idepth = depth;
253 count_intervals (i)
254 register INTERVAL i;
256 icount = 0;
257 idepth = 0;
258 zero_length = 0;
259 traverse_intervals (i, 1, 0, &inc_interval_count, Qnil);
261 return icount;
264 static INTERVAL
265 root_interval (interval)
266 INTERVAL interval;
268 register INTERVAL i = interval;
270 while (! ROOT_INTERVAL_P (i))
271 i = i->parent;
273 return i;
275 #endif
277 /* Assuming that a left child exists, perform the following operation:
280 / \ / \
281 B => A
282 / \ / \
286 static INTERVAL
287 rotate_right (interval)
288 INTERVAL interval;
290 INTERVAL i;
291 INTERVAL B = interval->left;
292 int old_total = interval->total_length;
294 /* Deal with any Parent of A; make it point to B. */
295 if (! ROOT_INTERVAL_P (interval))
296 if (AM_LEFT_CHILD (interval))
297 interval->parent->left = B;
298 else
299 interval->parent->right = B;
300 B->parent = interval->parent;
302 /* Make B the parent of A */
303 i = B->right;
304 B->right = interval;
305 interval->parent = B;
307 /* Make A point to c */
308 interval->left = i;
309 if (! NULL_INTERVAL_P (i))
310 i->parent = interval;
312 /* A's total length is decreased by the length of B and its left child. */
313 interval->total_length -= B->total_length - LEFT_TOTAL_LENGTH (interval);
315 /* B must have the same total length of A. */
316 B->total_length = old_total;
318 return B;
321 /* Assuming that a right child exists, perform the following operation:
323 A B
324 / \ / \
325 B => A
326 / \ / \
330 static INTERVAL
331 rotate_left (interval)
332 INTERVAL interval;
334 INTERVAL i;
335 INTERVAL B = interval->right;
336 int old_total = interval->total_length;
338 /* Deal with any parent of A; make it point to B. */
339 if (! ROOT_INTERVAL_P (interval))
340 if (AM_LEFT_CHILD (interval))
341 interval->parent->left = B;
342 else
343 interval->parent->right = B;
344 B->parent = interval->parent;
346 /* Make B the parent of A */
347 i = B->left;
348 B->left = interval;
349 interval->parent = B;
351 /* Make A point to c */
352 interval->right = i;
353 if (! NULL_INTERVAL_P (i))
354 i->parent = interval;
356 /* A's total length is decreased by the length of B and its right child. */
357 interval->total_length -= B->total_length - RIGHT_TOTAL_LENGTH (interval);
359 /* B must have the same total length of A. */
360 B->total_length = old_total;
362 return B;
365 /* Balance an interval tree with the assumption that the subtrees
366 themselves are already balanced. */
368 static INTERVAL
369 balance_an_interval (i)
370 INTERVAL i;
372 register int old_diff, new_diff;
374 while (1)
376 old_diff = LEFT_TOTAL_LENGTH (i) - RIGHT_TOTAL_LENGTH (i);
377 if (old_diff > 0)
379 new_diff = i->total_length - i->left->total_length
380 + RIGHT_TOTAL_LENGTH (i->left) - LEFT_TOTAL_LENGTH (i->left);
381 if (abs (new_diff) >= old_diff)
382 break;
383 i = rotate_right (i);
384 balance_an_interval (i->right);
386 else if (old_diff < 0)
388 new_diff = i->total_length - i->right->total_length
389 + LEFT_TOTAL_LENGTH (i->right) - RIGHT_TOTAL_LENGTH (i->right);
390 if (abs (new_diff) >= -old_diff)
391 break;
392 i = rotate_left (i);
393 balance_an_interval (i->left);
395 else
396 break;
398 return i;
401 /* Balance INTERVAL, potentially stuffing it back into its parent
402 Lisp Object. */
404 static INLINE INTERVAL
405 balance_possible_root_interval (interval)
406 register INTERVAL interval;
408 Lisp_Object parent;
410 if (interval->parent == NULL_INTERVAL)
411 return interval;
413 parent = (Lisp_Object) (interval->parent);
414 interval = balance_an_interval (interval);
416 if (BUFFERP (parent))
417 BUF_INTERVALS (XBUFFER (parent)) = interval;
418 else if (STRINGP (parent))
419 XSTRING (parent)->intervals = interval;
421 return interval;
424 /* Balance the interval tree TREE. Balancing is by weight
425 (the amount of text). */
427 static INTERVAL
428 balance_intervals_internal (tree)
429 register INTERVAL tree;
431 /* Balance within each side. */
432 if (tree->left)
433 balance_intervals (tree->left);
434 if (tree->right)
435 balance_intervals (tree->right);
436 return balance_an_interval (tree);
439 /* Advertised interface to balance intervals. */
441 INTERVAL
442 balance_intervals (tree)
443 INTERVAL tree;
445 if (tree == NULL_INTERVAL)
446 return NULL_INTERVAL;
448 return balance_intervals_internal (tree);
451 /* Split INTERVAL into two pieces, starting the second piece at
452 character position OFFSET (counting from 0), relative to INTERVAL.
453 INTERVAL becomes the left-hand piece, and the right-hand piece
454 (second, lexicographically) is returned.
456 The size and position fields of the two intervals are set based upon
457 those of the original interval. The property list of the new interval
458 is reset, thus it is up to the caller to do the right thing with the
459 result.
461 Note that this does not change the position of INTERVAL; if it is a root,
462 it is still a root after this operation. */
464 INTERVAL
465 split_interval_right (interval, offset)
466 INTERVAL interval;
467 int offset;
469 INTERVAL new = make_interval ();
470 int position = interval->position;
471 int new_length = LENGTH (interval) - offset;
473 new->position = position + offset;
474 new->parent = interval;
476 if (NULL_RIGHT_CHILD (interval))
478 interval->right = new;
479 new->total_length = new_length;
481 return new;
484 /* Insert the new node between INTERVAL and its right child. */
485 new->right = interval->right;
486 interval->right->parent = new;
487 interval->right = new;
488 new->total_length = new_length + new->right->total_length;
490 balance_an_interval (new);
491 balance_possible_root_interval (interval);
493 return new;
496 /* Split INTERVAL into two pieces, starting the second piece at
497 character position OFFSET (counting from 0), relative to INTERVAL.
498 INTERVAL becomes the right-hand piece, and the left-hand piece
499 (first, lexicographically) is returned.
501 The size and position fields of the two intervals are set based upon
502 those of the original interval. The property list of the new interval
503 is reset, thus it is up to the caller to do the right thing with the
504 result.
506 Note that this does not change the position of INTERVAL; if it is a root,
507 it is still a root after this operation. */
509 INTERVAL
510 split_interval_left (interval, offset)
511 INTERVAL interval;
512 int offset;
514 INTERVAL new = make_interval ();
515 int position = interval->position;
516 int new_length = offset;
518 new->position = interval->position;
519 interval->position = interval->position + offset;
520 new->parent = interval;
522 if (NULL_LEFT_CHILD (interval))
524 interval->left = new;
525 new->total_length = new_length;
527 return new;
530 /* Insert the new node between INTERVAL and its left child. */
531 new->left = interval->left;
532 new->left->parent = new;
533 interval->left = new;
534 new->total_length = new_length + new->left->total_length;
536 balance_an_interval (new);
537 balance_possible_root_interval (interval);
539 return new;
542 /* Find the interval containing text position POSITION in the text
543 represented by the interval tree TREE. POSITION is a buffer
544 position; the earliest position is 1. If POSITION is at the end of
545 the buffer, return the interval containing the last character.
547 The `position' field, which is a cache of an interval's position,
548 is updated in the interval found. Other functions (e.g., next_interval)
549 will update this cache based on the result of find_interval. */
551 INLINE INTERVAL
552 find_interval (tree, position)
553 register INTERVAL tree;
554 register int position;
556 /* The distance from the left edge of the subtree at TREE
557 to POSITION. */
558 register int relative_position = position - BEG;
560 if (NULL_INTERVAL_P (tree))
561 return NULL_INTERVAL;
563 if (relative_position > TOTAL_LENGTH (tree))
564 abort (); /* Paranoia */
566 tree = balance_possible_root_interval (tree);
568 while (1)
570 if (relative_position < LEFT_TOTAL_LENGTH (tree))
572 tree = tree->left;
574 else if (! NULL_RIGHT_CHILD (tree)
575 && relative_position >= (TOTAL_LENGTH (tree)
576 - RIGHT_TOTAL_LENGTH (tree)))
578 relative_position -= (TOTAL_LENGTH (tree)
579 - RIGHT_TOTAL_LENGTH (tree));
580 tree = tree->right;
582 else
584 tree->position =
585 (position - relative_position /* the left edge of *tree */
586 + LEFT_TOTAL_LENGTH (tree)); /* the left edge of this interval */
588 return tree;
593 /* Find the succeeding interval (lexicographically) to INTERVAL.
594 Sets the `position' field based on that of INTERVAL (see
595 find_interval). */
597 INTERVAL
598 next_interval (interval)
599 register INTERVAL interval;
601 register INTERVAL i = interval;
602 register int next_position;
604 if (NULL_INTERVAL_P (i))
605 return NULL_INTERVAL;
606 next_position = interval->position + LENGTH (interval);
608 if (! NULL_RIGHT_CHILD (i))
610 i = i->right;
611 while (! NULL_LEFT_CHILD (i))
612 i = i->left;
614 i->position = next_position;
615 return i;
618 while (! NULL_PARENT (i))
620 if (AM_LEFT_CHILD (i))
622 i = i->parent;
623 i->position = next_position;
624 return i;
627 i = i->parent;
630 return NULL_INTERVAL;
633 /* Find the preceding interval (lexicographically) to INTERVAL.
634 Sets the `position' field based on that of INTERVAL (see
635 find_interval). */
637 INTERVAL
638 previous_interval (interval)
639 register INTERVAL interval;
641 register INTERVAL i;
642 register position_of_previous;
644 if (NULL_INTERVAL_P (interval))
645 return NULL_INTERVAL;
647 if (! NULL_LEFT_CHILD (interval))
649 i = interval->left;
650 while (! NULL_RIGHT_CHILD (i))
651 i = i->right;
653 i->position = interval->position - LENGTH (i);
654 return i;
657 i = interval;
658 while (! NULL_PARENT (i))
660 if (AM_RIGHT_CHILD (i))
662 i = i->parent;
664 i->position = interval->position - LENGTH (i);
665 return i;
667 i = i->parent;
670 return NULL_INTERVAL;
673 #if 0
674 /* Traverse a path down the interval tree TREE to the interval
675 containing POSITION, adjusting all nodes on the path for
676 an addition of LENGTH characters. Insertion between two intervals
677 (i.e., point == i->position, where i is second interval) means
678 text goes into second interval.
680 Modifications are needed to handle the hungry bits -- after simply
681 finding the interval at position (don't add length going down),
682 if it's the beginning of the interval, get the previous interval
683 and check the hugry bits of both. Then add the length going back up
684 to the root. */
686 static INTERVAL
687 adjust_intervals_for_insertion (tree, position, length)
688 INTERVAL tree;
689 int position, length;
691 register int relative_position;
692 register INTERVAL this;
694 if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
695 abort ();
697 /* If inserting at point-max of a buffer, that position
698 will be out of range */
699 if (position > TOTAL_LENGTH (tree))
700 position = TOTAL_LENGTH (tree);
701 relative_position = position;
702 this = tree;
704 while (1)
706 if (relative_position <= LEFT_TOTAL_LENGTH (this))
708 this->total_length += length;
709 this = this->left;
711 else if (relative_position > (TOTAL_LENGTH (this)
712 - RIGHT_TOTAL_LENGTH (this)))
714 relative_position -= (TOTAL_LENGTH (this)
715 - RIGHT_TOTAL_LENGTH (this));
716 this->total_length += length;
717 this = this->right;
719 else
721 /* If we are to use zero-length intervals as buffer pointers,
722 then this code will have to change. */
723 this->total_length += length;
724 this->position = LEFT_TOTAL_LENGTH (this)
725 + position - relative_position + 1;
726 return tree;
730 #endif
732 /* Effect an adjustment corresponding to the addition of LENGTH characters
733 of text. Do this by finding the interval containing POSITION in the
734 interval tree TREE, and then adjusting all of its ancestors by adding
735 LENGTH to them.
737 If POSITION is the first character of an interval, meaning that point
738 is actually between the two intervals, make the new text belong to
739 the interval which is "sticky".
741 If both intervals are "sticky", then make them belong to the left-most
742 interval. Another possibility would be to create a new interval for
743 this text, and make it have the merged properties of both ends. */
745 static INTERVAL
746 adjust_intervals_for_insertion (tree, position, length)
747 INTERVAL tree;
748 int position, length;
750 register INTERVAL i;
751 register INTERVAL temp;
752 int eobp = 0;
754 if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
755 abort ();
757 /* If inserting at point-max of a buffer, that position will be out
758 of range. Remember that buffer positions are 1-based. */
759 if (position >= BEG + TOTAL_LENGTH (tree)){
760 position = BEG + TOTAL_LENGTH (tree);
761 eobp = 1;
764 i = find_interval (tree, position);
766 /* If in middle of an interval which is not sticky either way,
767 we must not just give its properties to the insertion.
768 So split this interval at the insertion point. */
769 if (! (position == i->position || eobp)
770 && END_NONSTICKY_P (i)
771 && ! FRONT_STICKY_P (i))
773 temp = split_interval_right (i, position - i->position);
774 copy_properties (i, temp);
775 i = temp;
778 /* If we are positioned between intervals, check the stickiness of
779 both of them. We have to do this too, if we are at BEG or Z. */
780 if (position == i->position || eobp)
782 register INTERVAL prev;
784 if (position == BEG)
785 prev = 0;
786 else if (eobp)
788 prev = i;
789 i = 0;
791 else
792 prev = previous_interval (i);
794 /* Even if we are positioned between intervals, we default
795 to the left one if it exists. We extend it now and split
796 off a part later, if stickyness demands it. */
797 for (temp = prev ? prev : i;! NULL_INTERVAL_P (temp); temp = temp->parent)
799 temp->total_length += length;
800 temp = balance_possible_root_interval (temp);
803 /* If at least one interval has sticky properties,
804 we check the stickyness property by property. */
805 if (END_NONSTICKY_P (prev) || FRONT_STICKY_P (i))
807 Lisp_Object pleft, pright;
808 struct interval newi;
810 pleft = NULL_INTERVAL_P (prev) ? Qnil : prev->plist;
811 pright = NULL_INTERVAL_P (i) ? Qnil : i->plist;
812 newi.plist = merge_properties_sticky (pleft, pright);
814 if(! prev) /* i.e. position == BEG */
816 if (! intervals_equal (i, &newi))
818 i = split_interval_left (i, length);
819 i->plist = newi.plist;
822 else if (! intervals_equal (prev, &newi))
824 prev = split_interval_right (prev,
825 position - prev->position);
826 prev->plist = newi.plist;
827 if (! NULL_INTERVAL_P (i)
828 && intervals_equal (prev, i))
829 merge_interval_right (prev);
832 /* We will need to update the cache here later. */
834 else if (! prev && ! NILP (i->plist))
836 /* Just split off a new interval at the left.
837 Since I wasn't front-sticky, the empty plist is ok. */
838 i = split_interval_left (i, length);
842 /* Otherwise just extend the interval. */
843 else
845 for (temp = i; ! NULL_INTERVAL_P (temp); temp = temp->parent)
847 temp->total_length += length;
848 temp = balance_possible_root_interval (temp);
852 return tree;
855 /* Any property might be front-sticky on the left, rear-sticky on the left,
856 front-sticky on the right, or rear-sticky on the right; the 16 combinations
857 can be arranged in a matrix with rows denoting the left conditions and
858 columns denoting the right conditions:
859 _ __ _
860 _ FR FR FR FR
861 FR__ 0 1 2 3
862 _FR 4 5 6 7
863 FR 8 9 A B
864 FR C D E F
866 left-props = '(front-sticky (p8 p9 pa pb pc pd pe pf)
867 rear-nonsticky (p4 p5 p6 p7 p8 p9 pa pb)
868 p0 L p1 L p2 L p3 L p4 L p5 L p6 L p7 L
869 p8 L p9 L pa L pb L pc L pd L pe L pf L)
870 right-props = '(front-sticky (p2 p3 p6 p7 pa pb pe pf)
871 rear-nonsticky (p1 p2 p5 p6 p9 pa pd pe)
872 p0 R p1 R p2 R p3 R p4 R p5 R p6 R p7 R
873 p8 R p9 R pa R pb R pc R pd R pe R pf R)
875 We inherit from whoever has a sticky side facing us. If both sides
876 do (cases 2, 3, E, and F), then we inherit from whichever side has a
877 non-nil value for the current property. If both sides do, then we take
878 from the left.
880 When we inherit a property, we get its stickiness as well as its value.
881 So, when we merge the above two lists, we expect to get this:
883 result = '(front-sticky (p6 p7 pa pb pc pd pe pf)
884 rear-nonsticky (p6 pa)
885 p0 L p1 L p2 L p3 L p6 R p7 R
886 pa R pb R pc L pd L pe L pf L)
888 The optimizable special cases are:
889 left rear-nonsticky = nil, right front-sticky = nil (inherit left)
890 left rear-nonsticky = t, right front-sticky = t (inherit right)
891 left rear-nonsticky = t, right front-sticky = nil (inherit none)
894 Lisp_Object
895 merge_properties_sticky (pleft, pright)
896 Lisp_Object pleft, pright;
898 register Lisp_Object props, front, rear;
899 Lisp_Object lfront, lrear, rfront, rrear;
900 register Lisp_Object tail1, tail2, sym, lval, rval;
901 int use_left, use_right;
903 props = Qnil;
904 front = Qnil;
905 rear = Qnil;
906 lfront = textget (pleft, Qfront_sticky);
907 lrear = textget (pleft, Qrear_nonsticky);
908 rfront = textget (pright, Qfront_sticky);
909 rrear = textget (pright, Qrear_nonsticky);
911 /* Go through each element of PRIGHT. */
912 for (tail1 = pright; ! NILP (tail1); tail1 = Fcdr (Fcdr (tail1)))
914 sym = Fcar (tail1);
916 /* Sticky properties get special treatment. */
917 if (EQ (sym, Qrear_nonsticky) || EQ (sym, Qfront_sticky))
918 continue;
920 rval = Fcar (Fcdr (tail1));
921 for (tail2 = pleft; ! NILP (tail2); tail2 = Fcdr (Fcdr (tail2)))
922 if (EQ (sym, Fcar (tail2)))
923 break;
924 lval = (NILP (tail2) ? Qnil : Fcar( Fcdr (tail2)));
926 use_left = ! TMEM (sym, lrear);
927 use_right = TMEM (sym, rfront);
928 if (use_left && use_right)
930 use_left = ! NILP (lval);
931 use_right = ! NILP (rval);
933 if (use_left)
935 /* We build props as (value sym ...) rather than (sym value ...)
936 because we plan to nreverse it when we're done. */
937 if (! NILP (lval))
938 props = Fcons (lval, Fcons (sym, props));
939 if (TMEM (sym, lfront))
940 front = Fcons (sym, front);
941 if (TMEM (sym, lrear))
942 rear = Fcons (sym, rear);
944 else if (use_right)
946 if (! NILP (rval))
947 props = Fcons (rval, Fcons (sym, props));
948 if (TMEM (sym, rfront))
949 front = Fcons (sym, front);
950 if (TMEM (sym, rrear))
951 rear = Fcons (sym, rear);
955 /* Now go through each element of PLEFT. */
956 for (tail2 = pleft; ! NILP (tail2); tail2 = Fcdr (Fcdr (tail2)))
958 sym = Fcar (tail2);
960 /* Sticky properties get special treatment. */
961 if (EQ (sym, Qrear_nonsticky) || EQ (sym, Qfront_sticky))
962 continue;
964 /* If sym is in PRIGHT, we've already considered it. */
965 for (tail1 = pright; ! NILP (tail1); tail1 = Fcdr (Fcdr (tail1)))
966 if (EQ (sym, Fcar (tail1)))
967 break;
968 if (! NILP (tail1))
969 continue;
971 lval = Fcar (Fcdr (tail2));
973 /* Since rval is known to be nil in this loop, the test simplifies. */
974 if (! TMEM (sym, lrear))
976 if (! NILP (lval))
977 props = Fcons (lval, Fcons (sym, props));
978 if (TMEM (sym, lfront))
979 front = Fcons (sym, front);
981 else if (TMEM (sym, rfront))
983 /* The value is nil, but we still inherit the stickiness
984 from the right. */
985 front = Fcons (sym, front);
986 if (TMEM (sym, rrear))
987 rear = Fcons (sym, rear);
990 props = Fnreverse (props);
991 if (! NILP (rear))
992 props = Fcons (Qrear_nonsticky, Fcons (Fnreverse (rear), props));
993 if (! NILP (front))
994 props = Fcons (Qfront_sticky, Fcons (Fnreverse (front), props));
995 return props;
999 /* Delete an node I from its interval tree by merging its subtrees
1000 into one subtree which is then returned. Caller is responsible for
1001 storing the resulting subtree into its parent. */
1003 static INTERVAL
1004 delete_node (i)
1005 register INTERVAL i;
1007 register INTERVAL migrate, this;
1008 register int migrate_amt;
1010 if (NULL_INTERVAL_P (i->left))
1011 return i->right;
1012 if (NULL_INTERVAL_P (i->right))
1013 return i->left;
1015 migrate = i->left;
1016 migrate_amt = i->left->total_length;
1017 this = i->right;
1018 this->total_length += migrate_amt;
1019 while (! NULL_INTERVAL_P (this->left))
1021 this = this->left;
1022 this->total_length += migrate_amt;
1024 this->left = migrate;
1025 migrate->parent = this;
1027 return i->right;
1030 /* Delete interval I from its tree by calling `delete_node'
1031 and properly connecting the resultant subtree.
1033 I is presumed to be empty; that is, no adjustments are made
1034 for the length of I. */
1036 void
1037 delete_interval (i)
1038 register INTERVAL i;
1040 register INTERVAL parent;
1041 int amt = LENGTH (i);
1043 if (amt > 0) /* Only used on zero-length intervals now. */
1044 abort ();
1046 if (ROOT_INTERVAL_P (i))
1048 Lisp_Object owner;
1049 owner = (Lisp_Object) i->parent;
1050 parent = delete_node (i);
1051 if (! NULL_INTERVAL_P (parent))
1052 parent->parent = (INTERVAL) owner;
1054 if (BUFFERP (owner))
1055 BUF_INTERVALS (XBUFFER (owner)) = parent;
1056 else if (STRINGP (owner))
1057 XSTRING (owner)->intervals = parent;
1058 else
1059 abort ();
1061 return;
1064 parent = i->parent;
1065 if (AM_LEFT_CHILD (i))
1067 parent->left = delete_node (i);
1068 if (! NULL_INTERVAL_P (parent->left))
1069 parent->left->parent = parent;
1071 else
1073 parent->right = delete_node (i);
1074 if (! NULL_INTERVAL_P (parent->right))
1075 parent->right->parent = parent;
1079 /* Find the interval in TREE corresponding to the relative position
1080 FROM and delete as much as possible of AMOUNT from that interval.
1081 Return the amount actually deleted, and if the interval was
1082 zeroed-out, delete that interval node from the tree.
1084 Note that FROM is actually origin zero, aka relative to the
1085 leftmost edge of tree. This is appropriate since we call ourselves
1086 recursively on subtrees.
1088 Do this by recursing down TREE to the interval in question, and
1089 deleting the appropriate amount of text. */
1091 static int
1092 interval_deletion_adjustment (tree, from, amount)
1093 register INTERVAL tree;
1094 register int from, amount;
1096 register int relative_position = from;
1098 if (NULL_INTERVAL_P (tree))
1099 return 0;
1101 /* Left branch */
1102 if (relative_position < LEFT_TOTAL_LENGTH (tree))
1104 int subtract = interval_deletion_adjustment (tree->left,
1105 relative_position,
1106 amount);
1107 tree->total_length -= subtract;
1108 return subtract;
1110 /* Right branch */
1111 else if (relative_position >= (TOTAL_LENGTH (tree)
1112 - RIGHT_TOTAL_LENGTH (tree)))
1114 int subtract;
1116 relative_position -= (tree->total_length
1117 - RIGHT_TOTAL_LENGTH (tree));
1118 subtract = interval_deletion_adjustment (tree->right,
1119 relative_position,
1120 amount);
1121 tree->total_length -= subtract;
1122 return subtract;
1124 /* Here -- this node. */
1125 else
1127 /* How much can we delete from this interval? */
1128 int my_amount = ((tree->total_length
1129 - RIGHT_TOTAL_LENGTH (tree))
1130 - relative_position);
1132 if (amount > my_amount)
1133 amount = my_amount;
1135 tree->total_length -= amount;
1136 if (LENGTH (tree) == 0)
1137 delete_interval (tree);
1139 return amount;
1142 /* Never reach here. */
1145 /* Effect the adjustments necessary to the interval tree of BUFFER to
1146 correspond to the deletion of LENGTH characters from that buffer
1147 text. The deletion is effected at position START (which is a
1148 buffer position, i.e. origin 1). */
1150 static void
1151 adjust_intervals_for_deletion (buffer, start, length)
1152 struct buffer *buffer;
1153 int start, length;
1155 register int left_to_delete = length;
1156 register INTERVAL tree = BUF_INTERVALS (buffer);
1157 register int deleted;
1159 if (NULL_INTERVAL_P (tree))
1160 return;
1162 if (start > BEG + TOTAL_LENGTH (tree)
1163 || start + length > BEG + TOTAL_LENGTH (tree))
1164 abort ();
1166 if (length == TOTAL_LENGTH (tree))
1168 BUF_INTERVALS (buffer) = NULL_INTERVAL;
1169 return;
1172 if (ONLY_INTERVAL_P (tree))
1174 tree->total_length -= length;
1175 return;
1178 if (start > BEG + TOTAL_LENGTH (tree))
1179 start = BEG + TOTAL_LENGTH (tree);
1180 while (left_to_delete > 0)
1182 left_to_delete -= interval_deletion_adjustment (tree, start - 1,
1183 left_to_delete);
1184 tree = BUF_INTERVALS (buffer);
1185 if (left_to_delete == tree->total_length)
1187 BUF_INTERVALS (buffer) = NULL_INTERVAL;
1188 return;
1193 /* Make the adjustments necessary to the interval tree of BUFFER to
1194 represent an addition or deletion of LENGTH characters starting
1195 at position START. Addition or deletion is indicated by the sign
1196 of LENGTH. */
1198 INLINE void
1199 offset_intervals (buffer, start, length)
1200 struct buffer *buffer;
1201 int start, length;
1203 if (NULL_INTERVAL_P (BUF_INTERVALS (buffer)) || length == 0)
1204 return;
1206 if (length > 0)
1207 adjust_intervals_for_insertion (BUF_INTERVALS (buffer), start, length);
1208 else
1209 adjust_intervals_for_deletion (buffer, start, -length);
1212 /* Merge interval I with its lexicographic successor. The resulting
1213 interval is returned, and has the properties of the original
1214 successor. The properties of I are lost. I is removed from the
1215 interval tree.
1217 IMPORTANT:
1218 The caller must verify that this is not the last (rightmost)
1219 interval. */
1221 INTERVAL
1222 merge_interval_right (i)
1223 register INTERVAL i;
1225 register int absorb = LENGTH (i);
1226 register INTERVAL successor;
1228 /* Zero out this interval. */
1229 i->total_length -= absorb;
1231 /* Find the succeeding interval. */
1232 if (! NULL_RIGHT_CHILD (i)) /* It's below us. Add absorb
1233 as we descend. */
1235 successor = i->right;
1236 while (! NULL_LEFT_CHILD (successor))
1238 successor->total_length += absorb;
1239 successor = successor->left;
1242 successor->total_length += absorb;
1243 delete_interval (i);
1244 return successor;
1247 successor = i;
1248 while (! NULL_PARENT (successor)) /* It's above us. Subtract as
1249 we ascend. */
1251 if (AM_LEFT_CHILD (successor))
1253 successor = successor->parent;
1254 delete_interval (i);
1255 return successor;
1258 successor = successor->parent;
1259 successor->total_length -= absorb;
1262 /* This must be the rightmost or last interval and cannot
1263 be merged right. The caller should have known. */
1264 abort ();
1267 /* Merge interval I with its lexicographic predecessor. The resulting
1268 interval is returned, and has the properties of the original predecessor.
1269 The properties of I are lost. Interval node I is removed from the tree.
1271 IMPORTANT:
1272 The caller must verify that this is not the first (leftmost) interval. */
1274 INTERVAL
1275 merge_interval_left (i)
1276 register INTERVAL i;
1278 register int absorb = LENGTH (i);
1279 register INTERVAL predecessor;
1281 /* Zero out this interval. */
1282 i->total_length -= absorb;
1284 /* Find the preceding interval. */
1285 if (! NULL_LEFT_CHILD (i)) /* It's below us. Go down,
1286 adding ABSORB as we go. */
1288 predecessor = i->left;
1289 while (! NULL_RIGHT_CHILD (predecessor))
1291 predecessor->total_length += absorb;
1292 predecessor = predecessor->right;
1295 predecessor->total_length += absorb;
1296 delete_interval (i);
1297 return predecessor;
1300 predecessor = i;
1301 while (! NULL_PARENT (predecessor)) /* It's above us. Go up,
1302 subtracting ABSORB. */
1304 if (AM_RIGHT_CHILD (predecessor))
1306 predecessor = predecessor->parent;
1307 delete_interval (i);
1308 return predecessor;
1311 predecessor = predecessor->parent;
1312 predecessor->total_length -= absorb;
1315 /* This must be the leftmost or first interval and cannot
1316 be merged left. The caller should have known. */
1317 abort ();
1320 /* Make an exact copy of interval tree SOURCE which descends from
1321 PARENT. This is done by recursing through SOURCE, copying
1322 the current interval and its properties, and then adjusting
1323 the pointers of the copy. */
1325 static INTERVAL
1326 reproduce_tree (source, parent)
1327 INTERVAL source, parent;
1329 register INTERVAL t = make_interval ();
1331 bcopy (source, t, INTERVAL_SIZE);
1332 copy_properties (source, t);
1333 t->parent = parent;
1334 if (! NULL_LEFT_CHILD (source))
1335 t->left = reproduce_tree (source->left, t);
1336 if (! NULL_RIGHT_CHILD (source))
1337 t->right = reproduce_tree (source->right, t);
1339 return t;
1342 #if 0
1343 /* Nobody calls this. Perhaps it's a vestige of an earlier design. */
1345 /* Make a new interval of length LENGTH starting at START in the
1346 group of intervals INTERVALS, which is actually an interval tree.
1347 Returns the new interval.
1349 Generate an error if the new positions would overlap an existing
1350 interval. */
1352 static INTERVAL
1353 make_new_interval (intervals, start, length)
1354 INTERVAL intervals;
1355 int start, length;
1357 INTERVAL slot;
1359 slot = find_interval (intervals, start);
1360 if (start + length > slot->position + LENGTH (slot))
1361 error ("Interval would overlap");
1363 if (start == slot->position && length == LENGTH (slot))
1364 return slot;
1366 if (slot->position == start)
1368 /* New right node. */
1369 split_interval_right (slot, length);
1370 return slot;
1373 if (slot->position + LENGTH (slot) == start + length)
1375 /* New left node. */
1376 split_interval_left (slot, LENGTH (slot) - length);
1377 return slot;
1380 /* Convert interval SLOT into three intervals. */
1381 split_interval_left (slot, start - slot->position);
1382 split_interval_right (slot, length);
1383 return slot;
1385 #endif
1387 /* Insert the intervals of SOURCE into BUFFER at POSITION.
1388 LENGTH is the length of the text in SOURCE.
1390 This is used in insdel.c when inserting Lisp_Strings into the
1391 buffer. The text corresponding to SOURCE is already in the buffer
1392 when this is called. The intervals of new tree are a copy of those
1393 belonging to the string being inserted; intervals are never
1394 shared.
1396 If the inserted text had no intervals associated, and we don't
1397 want to inherit the surrounding text's properties, this function
1398 simply returns -- offset_intervals should handle placing the
1399 text in the correct interval, depending on the sticky bits.
1401 If the inserted text had properties (intervals), then there are two
1402 cases -- either insertion happened in the middle of some interval,
1403 or between two intervals.
1405 If the text goes into the middle of an interval, then new
1406 intervals are created in the middle with only the properties of
1407 the new text, *unless* the macro MERGE_INSERTIONS is true, in
1408 which case the new text has the union of its properties and those
1409 of the text into which it was inserted.
1411 If the text goes between two intervals, then if neither interval
1412 had its appropriate sticky property set (front_sticky, rear_sticky),
1413 the new text has only its properties. If one of the sticky properties
1414 is set, then the new text "sticks" to that region and its properties
1415 depend on merging as above. If both the preceding and succeeding
1416 intervals to the new text are "sticky", then the new text retains
1417 only its properties, as if neither sticky property were set. Perhaps
1418 we should consider merging all three sets of properties onto the new
1419 text... */
1421 void
1422 graft_intervals_into_buffer (source, position, length, buffer, inherit)
1423 INTERVAL source;
1424 int position, length;
1425 struct buffer *buffer;
1426 int inherit;
1428 register INTERVAL under, over, this, prev;
1429 register INTERVAL tree;
1430 int middle;
1432 tree = BUF_INTERVALS (buffer);
1434 /* If the new text has no properties, it becomes part of whatever
1435 interval it was inserted into. */
1436 if (NULL_INTERVAL_P (source))
1438 Lisp_Object buf;
1439 if (!inherit && ! NULL_INTERVAL_P (tree))
1441 XSETBUFFER (buf, buffer);
1442 Fset_text_properties (make_number (position),
1443 make_number (position + length),
1444 Qnil, buf);
1446 if (! NULL_INTERVAL_P (BUF_INTERVALS (buffer)))
1447 BUF_INTERVALS (buffer) = balance_an_interval (BUF_INTERVALS (buffer));
1448 return;
1451 if (NULL_INTERVAL_P (tree))
1453 /* The inserted text constitutes the whole buffer, so
1454 simply copy over the interval structure. */
1455 if ((BUF_Z (buffer) - BUF_BEG (buffer)) == TOTAL_LENGTH (source))
1457 Lisp_Object buf;
1458 XSETBUFFER (buf, buffer);
1459 BUF_INTERVALS (buffer) = reproduce_tree (source, buf);
1460 /* Explicitly free the old tree here. */
1462 return;
1465 /* Create an interval tree in which to place a copy
1466 of the intervals of the inserted string. */
1468 Lisp_Object buf;
1469 XSETBUFFER (buf, buffer);
1470 tree = create_root_interval (buf);
1473 else if (TOTAL_LENGTH (tree) == TOTAL_LENGTH (source))
1474 /* If the buffer contains only the new string, but
1475 there was already some interval tree there, then it may be
1476 some zero length intervals. Eventually, do something clever
1477 about inserting properly. For now, just waste the old intervals. */
1479 BUF_INTERVALS (buffer) = reproduce_tree (source, tree->parent);
1480 /* Explicitly free the old tree here. */
1482 return;
1484 /* Paranoia -- the text has already been added, so this buffer
1485 should be of non-zero length. */
1486 else if (TOTAL_LENGTH (tree) == 0)
1487 abort ();
1489 this = under = find_interval (tree, position);
1490 if (NULL_INTERVAL_P (under)) /* Paranoia */
1491 abort ();
1492 over = find_interval (source, 1);
1494 /* Here for insertion in the middle of an interval.
1495 Split off an equivalent interval to the right,
1496 then don't bother with it any more. */
1498 if (position > under->position)
1500 INTERVAL end_unchanged
1501 = split_interval_left (this, position - under->position);
1502 copy_properties (under, end_unchanged);
1503 under->position = position;
1504 prev = 0;
1505 middle = 1;
1507 else
1509 prev = previous_interval (under);
1510 if (prev && !END_NONSTICKY_P (prev))
1511 prev = 0;
1514 /* Insertion is now at beginning of UNDER. */
1516 /* The inserted text "sticks" to the interval `under',
1517 which means it gets those properties.
1518 The properties of under are the result of
1519 adjust_intervals_for_insertion, so stickyness has
1520 already been taken care of. */
1522 while (! NULL_INTERVAL_P (over))
1524 if (LENGTH (over) < LENGTH (under))
1526 this = split_interval_left (under, LENGTH (over));
1527 copy_properties (under, this);
1529 else
1530 this = under;
1531 copy_properties (over, this);
1532 if (inherit)
1533 merge_properties (over, this);
1534 else
1535 copy_properties (over, this);
1536 over = next_interval (over);
1539 if (! NULL_INTERVAL_P (BUF_INTERVALS (buffer)))
1540 BUF_INTERVALS (buffer) = balance_an_interval (BUF_INTERVALS (buffer));
1541 return;
1544 /* Get the value of property PROP from PLIST,
1545 which is the plist of an interval.
1546 We check for direct properties, for categories with property PROP,
1547 and for PROP appearing on the default-text-properties list. */
1549 Lisp_Object
1550 textget (plist, prop)
1551 Lisp_Object plist;
1552 register Lisp_Object prop;
1554 register Lisp_Object tail, fallback;
1555 fallback = Qnil;
1557 for (tail = plist; !NILP (tail); tail = Fcdr (Fcdr (tail)))
1559 register Lisp_Object tem;
1560 tem = Fcar (tail);
1561 if (EQ (prop, tem))
1562 return Fcar (Fcdr (tail));
1563 if (EQ (tem, Qcategory))
1565 tem = Fcar (Fcdr (tail));
1566 if (SYMBOLP (tem))
1567 fallback = Fget (tem, prop);
1571 if (! NILP (fallback))
1572 return fallback;
1573 if (CONSP (Vdefault_text_properties))
1574 return Fplist_get (Vdefault_text_properties, prop);
1575 return Qnil;
1579 /* Set point in BUFFER to POSITION. If the target position is
1580 before an intangible character, move to an ok place. */
1582 void
1583 set_point (position, buffer)
1584 register int position;
1585 register struct buffer *buffer;
1587 register INTERVAL to, from, toprev, fromprev, target;
1588 int buffer_point;
1589 register Lisp_Object obj;
1590 int backwards = (position < BUF_PT (buffer)) ? 1 : 0;
1591 int old_position = BUF_PT (buffer);
1593 buffer->point_before_scroll = Qnil;
1595 if (position == BUF_PT (buffer))
1596 return;
1598 /* Check this now, before checking if the buffer has any intervals.
1599 That way, we can catch conditions which break this sanity check
1600 whether or not there are intervals in the buffer. */
1601 if (position > BUF_Z (buffer) || position < BUF_BEG (buffer))
1602 abort ();
1604 if (NULL_INTERVAL_P (BUF_INTERVALS (buffer)))
1607 BUF_PT (buffer) = position;
1608 return;
1611 /* Set TO to the interval containing the char after POSITION,
1612 and TOPREV to the interval containing the char before POSITION.
1613 Either one may be null. They may be equal. */
1614 to = find_interval (BUF_INTERVALS (buffer), position);
1615 if (position == BUF_BEGV (buffer))
1616 toprev = 0;
1617 else if (to->position == position)
1618 toprev = previous_interval (to);
1619 else
1620 toprev = to;
1622 buffer_point = (BUF_PT (buffer) == BUF_ZV (buffer)
1623 ? BUF_ZV (buffer) - 1
1624 : BUF_PT (buffer));
1626 /* Set FROM to the interval containing the char after PT,
1627 and FROMPREV to the interval containing the char before PT.
1628 Either one may be null. They may be equal. */
1629 /* We could cache this and save time. */
1630 from = find_interval (BUF_INTERVALS (buffer), buffer_point);
1631 if (buffer_point == BUF_BEGV (buffer))
1632 fromprev = 0;
1633 else if (from->position == BUF_PT (buffer))
1634 fromprev = previous_interval (from);
1635 else if (buffer_point != BUF_PT (buffer))
1636 fromprev = from, from = 0;
1637 else
1638 fromprev = from;
1640 /* Moving within an interval. */
1641 if (to == from && toprev == fromprev && INTERVAL_VISIBLE_P (to))
1643 BUF_PT (buffer) = position;
1644 return;
1647 /* If the new position is between two intangible characters
1648 with the same intangible property value,
1649 move forward or backward until a change in that property. */
1650 if (NILP (Vinhibit_point_motion_hooks) && ! NULL_INTERVAL_P (to)
1651 && ! NULL_INTERVAL_P (toprev))
1653 if (backwards)
1655 Lisp_Object intangible_propval;
1656 intangible_propval = textget (to->plist, Qintangible);
1658 /* If following char is intangible,
1659 skip back over all chars with matching intangible property. */
1660 if (! NILP (intangible_propval))
1661 while (to == toprev
1662 || ((! NULL_INTERVAL_P (toprev)
1663 && EQ (textget (toprev->plist, Qintangible),
1664 intangible_propval))))
1666 to = toprev;
1667 toprev = previous_interval (toprev);
1668 if (NULL_INTERVAL_P (toprev))
1669 position = BUF_BEGV (buffer);
1670 else
1671 /* This is the only line that's not
1672 dual to the following loop.
1673 That's because we want the position
1674 at the end of TOPREV. */
1675 position = to->position;
1678 else
1680 Lisp_Object intangible_propval;
1681 intangible_propval = textget (toprev->plist, Qintangible);
1683 /* If previous char is intangible,
1684 skip fwd over all chars with matching intangible property. */
1685 if (! NILP (intangible_propval))
1686 while (to == toprev
1687 || ((! NULL_INTERVAL_P (to)
1688 && EQ (textget (to->plist, Qintangible),
1689 intangible_propval))))
1691 toprev = to;
1692 to = next_interval (to);
1693 if (NULL_INTERVAL_P (to))
1694 position = BUF_ZV (buffer);
1695 else
1696 position = to->position;
1701 /* Here TO is the interval after the stopping point
1702 and TOPREV is the interval before the stopping point.
1703 One or the other may be null. */
1705 BUF_PT (buffer) = position;
1707 /* We run point-left and point-entered hooks here, iff the
1708 two intervals are not equivalent. These hooks take
1709 (old_point, new_point) as arguments. */
1710 if (NILP (Vinhibit_point_motion_hooks)
1711 && (! intervals_equal (from, to)
1712 || ! intervals_equal (fromprev, toprev)))
1714 Lisp_Object leave_after, leave_before, enter_after, enter_before;
1716 if (fromprev)
1717 leave_after = textget (fromprev->plist, Qpoint_left);
1718 else
1719 leave_after = Qnil;
1720 if (from)
1721 leave_before = textget (from->plist, Qpoint_left);
1722 else
1723 leave_before = Qnil;
1725 if (toprev)
1726 enter_after = textget (toprev->plist, Qpoint_entered);
1727 else
1728 enter_after = Qnil;
1729 if (to)
1730 enter_before = textget (to->plist, Qpoint_entered);
1731 else
1732 enter_before = Qnil;
1734 if (! EQ (leave_before, enter_before) && !NILP (leave_before))
1735 call2 (leave_before, old_position, position);
1736 if (! EQ (leave_after, enter_after) && !NILP (leave_after))
1737 call2 (leave_after, old_position, position);
1739 if (! EQ (enter_before, leave_before) && !NILP (enter_before))
1740 call2 (enter_before, old_position, position);
1741 if (! EQ (enter_after, leave_after) && !NILP (enter_after))
1742 call2 (enter_after, old_position, position);
1746 /* Set point temporarily, without checking any text properties. */
1748 INLINE void
1749 temp_set_point (position, buffer)
1750 int position;
1751 struct buffer *buffer;
1753 BUF_PT (buffer) = position;
1756 /* Return the proper local map for position POSITION in BUFFER.
1757 Use the map specified by the local-map property, if any.
1758 Otherwise, use BUFFER's local map. */
1760 Lisp_Object
1761 get_local_map (position, buffer)
1762 register int position;
1763 register struct buffer *buffer;
1765 Lisp_Object prop, tem, lispy_position, lispy_buffer;
1766 int old_begv, old_zv;
1768 /* Perhaps we should just change `position' to the limit. */
1769 if (position > BUF_Z (buffer) || position < BUF_BEG (buffer))
1770 abort ();
1772 /* Ignore narrowing, so that a local map continues to be valid even if
1773 the visible region contains no characters and hence no properties. */
1774 old_begv = BUF_BEGV (buffer);
1775 old_zv = BUF_ZV (buffer);
1776 BUF_BEGV (buffer) = BUF_BEG (buffer);
1777 BUF_ZV (buffer) = BUF_Z (buffer);
1779 /* There are no properties at the end of the buffer, so in that case
1780 check for a local map on the last character of the buffer instead. */
1781 if (position == BUF_Z (buffer) && BUF_Z (buffer) > BUF_BEG (buffer))
1782 --position;
1783 XSETFASTINT (lispy_position, position);
1784 XSETBUFFER (lispy_buffer, buffer);
1785 prop = Fget_char_property (lispy_position, Qlocal_map, lispy_buffer);
1787 BUF_BEGV (buffer) = old_begv;
1788 BUF_ZV (buffer) = old_zv;
1790 /* Use the local map only if it is valid. */
1791 if (!NILP (prop)
1792 && (tem = Fkeymapp (prop), !NILP (tem)))
1793 return prop;
1795 return buffer->keymap;
1798 /* Call the modification hook functions in LIST, each with START and END. */
1800 static void
1801 call_mod_hooks (list, start, end)
1802 Lisp_Object list, start, end;
1804 struct gcpro gcpro1;
1805 GCPRO1 (list);
1806 while (!NILP (list))
1808 call2 (Fcar (list), start, end);
1809 list = Fcdr (list);
1811 UNGCPRO;
1814 /* Check for read-only intervals and signal an error if we find one.
1815 Then check for any modification hooks in the range START up to
1816 (but not including) END. Create a list of all these hooks in
1817 lexicographic order, eliminating consecutive extra copies of the
1818 same hook. Then call those hooks in order, with START and END - 1
1819 as arguments. */
1821 void
1822 verify_interval_modification (buf, start, end)
1823 struct buffer *buf;
1824 int start, end;
1826 register INTERVAL intervals = BUF_INTERVALS (buf);
1827 register INTERVAL i, prev;
1828 Lisp_Object hooks;
1829 register Lisp_Object prev_mod_hooks;
1830 Lisp_Object mod_hooks;
1831 struct gcpro gcpro1;
1833 hooks = Qnil;
1834 prev_mod_hooks = Qnil;
1835 mod_hooks = Qnil;
1837 if (NULL_INTERVAL_P (intervals))
1838 return;
1840 if (start > end)
1842 int temp = start;
1843 start = end;
1844 end = temp;
1847 /* For an insert operation, check the two chars around the position. */
1848 if (start == end)
1850 INTERVAL prev;
1851 Lisp_Object before, after;
1853 /* Set I to the interval containing the char after START,
1854 and PREV to the interval containing the char before START.
1855 Either one may be null. They may be equal. */
1856 i = find_interval (intervals, start);
1858 if (start == BUF_BEGV (buf))
1859 prev = 0;
1860 else if (i->position == start)
1861 prev = previous_interval (i);
1862 else if (i->position < start)
1863 prev = i;
1864 if (start == BUF_ZV (buf))
1865 i = 0;
1867 /* If Vinhibit_read_only is set and is not a list, we can
1868 skip the read_only checks. */
1869 if (NILP (Vinhibit_read_only) || CONSP (Vinhibit_read_only))
1871 /* If I and PREV differ we need to check for the read-only
1872 property together with its stickyness. If either I or
1873 PREV are 0, this check is all we need.
1874 We have to take special care, since read-only may be
1875 indirectly defined via the category property. */
1876 if (i != prev)
1878 if (! NULL_INTERVAL_P (i))
1880 after = textget (i->plist, Qread_only);
1882 /* If interval I is read-only and read-only is
1883 front-sticky, inhibit insertion.
1884 Check for read-only as well as category. */
1885 if (! NILP (after)
1886 && NILP (Fmemq (after, Vinhibit_read_only)))
1888 Lisp_Object tem;
1890 tem = textget (i->plist, Qfront_sticky);
1891 if (TMEM (Qread_only, tem)
1892 || (NILP (Fplist_get (i->plist, Qread_only))
1893 && TMEM (Qcategory, tem)))
1894 error ("Attempt to insert within read-only text");
1898 if (! NULL_INTERVAL_P (prev))
1900 before = textget (prev->plist, Qread_only);
1902 /* If interval PREV is read-only and read-only isn't
1903 rear-nonsticky, inhibit insertion.
1904 Check for read-only as well as category. */
1905 if (! NILP (before)
1906 && NILP (Fmemq (before, Vinhibit_read_only)))
1908 Lisp_Object tem;
1910 tem = textget (prev->plist, Qrear_nonsticky);
1911 if (! TMEM (Qread_only, tem)
1912 && (! NILP (Fplist_get (prev->plist,Qread_only))
1913 || ! TMEM (Qcategory, tem)))
1914 error ("Attempt to insert within read-only text");
1918 else if (! NULL_INTERVAL_P (i))
1920 after = textget (i->plist, Qread_only);
1922 /* If interval I is read-only and read-only is
1923 front-sticky, inhibit insertion.
1924 Check for read-only as well as category. */
1925 if (! NILP (after) && NILP (Fmemq (after, Vinhibit_read_only)))
1927 Lisp_Object tem;
1929 tem = textget (i->plist, Qfront_sticky);
1930 if (TMEM (Qread_only, tem)
1931 || (NILP (Fplist_get (i->plist, Qread_only))
1932 && TMEM (Qcategory, tem)))
1933 error ("Attempt to insert within read-only text");
1935 tem = textget (prev->plist, Qrear_nonsticky);
1936 if (! TMEM (Qread_only, tem)
1937 && (! NILP (Fplist_get (prev->plist, Qread_only))
1938 || ! TMEM (Qcategory, tem)))
1939 error ("Attempt to insert within read-only text");
1944 /* Run both insert hooks (just once if they're the same). */
1945 if (!NULL_INTERVAL_P (prev))
1946 prev_mod_hooks = textget (prev->plist, Qinsert_behind_hooks);
1947 if (!NULL_INTERVAL_P (i))
1948 mod_hooks = textget (i->plist, Qinsert_in_front_hooks);
1949 GCPRO1 (mod_hooks);
1950 if (! NILP (prev_mod_hooks))
1951 call_mod_hooks (prev_mod_hooks, make_number (start),
1952 make_number (end));
1953 UNGCPRO;
1954 if (! NILP (mod_hooks) && ! EQ (mod_hooks, prev_mod_hooks))
1955 call_mod_hooks (mod_hooks, make_number (start), make_number (end));
1957 else
1959 /* Loop over intervals on or next to START...END,
1960 collecting their hooks. */
1962 i = find_interval (intervals, start);
1965 if (! INTERVAL_WRITABLE_P (i))
1966 error ("Attempt to modify read-only text");
1968 mod_hooks = textget (i->plist, Qmodification_hooks);
1969 if (! NILP (mod_hooks) && ! EQ (mod_hooks, prev_mod_hooks))
1971 hooks = Fcons (mod_hooks, hooks);
1972 prev_mod_hooks = mod_hooks;
1975 i = next_interval (i);
1977 /* Keep going thru the interval containing the char before END. */
1978 while (! NULL_INTERVAL_P (i) && i->position < end);
1980 GCPRO1 (hooks);
1981 hooks = Fnreverse (hooks);
1982 while (! EQ (hooks, Qnil))
1984 call_mod_hooks (Fcar (hooks), make_number (start),
1985 make_number (end));
1986 hooks = Fcdr (hooks);
1988 UNGCPRO;
1992 /* Produce an interval tree reflecting the intervals in
1993 TREE from START to START + LENGTH. */
1995 INTERVAL
1996 copy_intervals (tree, start, length)
1997 INTERVAL tree;
1998 int start, length;
2000 register INTERVAL i, new, t;
2001 register int got, prevlen;
2003 if (NULL_INTERVAL_P (tree) || length <= 0)
2004 return NULL_INTERVAL;
2006 i = find_interval (tree, start);
2007 if (NULL_INTERVAL_P (i) || LENGTH (i) == 0)
2008 abort ();
2010 /* If there is only one interval and it's the default, return nil. */
2011 if ((start - i->position + 1 + length) < LENGTH (i)
2012 && DEFAULT_INTERVAL_P (i))
2013 return NULL_INTERVAL;
2015 new = make_interval ();
2016 new->position = 1;
2017 got = (LENGTH (i) - (start - i->position));
2018 new->total_length = length;
2019 copy_properties (i, new);
2021 t = new;
2022 prevlen = got;
2023 while (got < length)
2025 i = next_interval (i);
2026 t = split_interval_right (t, prevlen);
2027 copy_properties (i, t);
2028 prevlen = LENGTH (i);
2029 got += prevlen;
2032 return balance_an_interval (new);
2035 /* Give STRING the properties of BUFFER from POSITION to LENGTH. */
2037 INLINE void
2038 copy_intervals_to_string (string, buffer, position, length)
2039 Lisp_Object string, buffer;
2040 int position, length;
2042 INTERVAL interval_copy = copy_intervals (BUF_INTERVALS (XBUFFER (buffer)),
2043 position, length);
2044 if (NULL_INTERVAL_P (interval_copy))
2045 return;
2047 interval_copy->parent = (INTERVAL) string;
2048 XSTRING (string)->intervals = interval_copy;
2051 /* Return 1 if string S1 and S2 have identical properties; 0 otherwise.
2052 Assume they have identical characters. */
2055 compare_string_intervals (s1, s2)
2056 Lisp_Object s1, s2;
2058 INTERVAL i1, i2;
2059 int pos = 1;
2060 int end = XSTRING (s1)->size + 1;
2062 /* We specify 1 as position because the interval functions
2063 always use positions starting at 1. */
2064 i1 = find_interval (XSTRING (s1)->intervals, 1);
2065 i2 = find_interval (XSTRING (s2)->intervals, 1);
2067 while (pos < end)
2069 /* Determine how far we can go before we reach the end of I1 or I2. */
2070 int len1 = (i1 != 0 ? INTERVAL_LAST_POS (i1) : end) - pos;
2071 int len2 = (i2 != 0 ? INTERVAL_LAST_POS (i2) : end) - pos;
2072 int distance = min (len1, len2);
2074 /* If we ever find a mismatch between the strings,
2075 they differ. */
2076 if (! intervals_equal (i1, i2))
2077 return 0;
2079 /* Advance POS till the end of the shorter interval,
2080 and advance one or both interval pointers for the new position. */
2081 pos += distance;
2082 if (len1 == distance)
2083 i1 = next_interval (i1);
2084 if (len2 == distance)
2085 i2 = next_interval (i2);
2087 return 1;
2090 #endif /* USE_TEXT_PROPERTIES */