Merge from lexical-binding branch.
[emacs.git] / src / intervals.c
blob351677ad27e33b98c44469302933916ab36b093e
1 /* Code for doing intervals.
2 Copyright (C) 1993-1995, 1997-1998, 2001-2011 Free Software Foundation, Inc.
4 This file is part of GNU Emacs.
6 GNU Emacs is free software: you can redistribute it and/or modify
7 it under the terms of the GNU General Public License as published by
8 the Free Software Foundation, either version 3 of the License, or
9 (at your option) any later version.
11 GNU Emacs is distributed in the hope that it will be useful,
12 but WITHOUT ANY WARRANTY; without even the implied warranty of
13 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
14 GNU General Public License for more details.
16 You should have received a copy of the GNU General Public License
17 along with GNU Emacs. If not, see <http://www.gnu.org/licenses/>. */
20 /* NOTES:
22 Have to ensure that we can't put symbol nil on a plist, or some
23 functions may work incorrectly.
25 An idea: Have the owner of the tree keep count of splits and/or
26 insertion lengths (in intervals), and balance after every N.
28 Need to call *_left_hook when buffer is killed.
30 Scan for zero-length, or 0-length to see notes about handling
31 zero length interval-markers.
33 There are comments around about freeing intervals. It might be
34 faster to explicitly free them (put them on the free list) than
35 to GC them.
40 #include <config.h>
41 #include <setjmp.h>
42 #include "lisp.h"
43 #include "intervals.h"
44 #include "buffer.h"
45 #include "puresize.h"
46 #include "keyboard.h"
47 #include "keymap.h"
49 /* Test for membership, allowing for t (actually any non-cons) to mean the
50 universal set. */
52 #define TMEM(sym, set) (CONSP (set) ? ! NILP (Fmemq (sym, set)) : ! NILP (set))
54 Lisp_Object merge_properties_sticky (Lisp_Object pleft, Lisp_Object pright);
55 static INTERVAL reproduce_tree (INTERVAL, INTERVAL);
56 static INTERVAL reproduce_tree_obj (INTERVAL, Lisp_Object);
58 /* Utility functions for intervals. */
61 /* Create the root interval of some object, a buffer or string. */
63 INTERVAL
64 create_root_interval (Lisp_Object parent)
66 INTERVAL new;
68 CHECK_IMPURE (parent);
70 new = make_interval ();
72 if (BUFFERP (parent))
74 new->total_length = (BUF_Z (XBUFFER (parent))
75 - BUF_BEG (XBUFFER (parent)));
76 CHECK_TOTAL_LENGTH (new);
77 BUF_INTERVALS (XBUFFER (parent)) = new;
78 new->position = BEG;
80 else if (STRINGP (parent))
82 new->total_length = SCHARS (parent);
83 CHECK_TOTAL_LENGTH (new);
84 STRING_SET_INTERVALS (parent, new);
85 new->position = 0;
88 SET_INTERVAL_OBJECT (new, parent);
90 return new;
93 /* Make the interval TARGET have exactly the properties of SOURCE */
95 void
96 copy_properties (register INTERVAL source, register INTERVAL target)
98 if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
99 return;
101 COPY_INTERVAL_CACHE (source, target);
102 target->plist = Fcopy_sequence (source->plist);
105 /* Merge the properties of interval SOURCE into the properties
106 of interval TARGET. That is to say, each property in SOURCE
107 is added to TARGET if TARGET has no such property as yet. */
109 static void
110 merge_properties (register INTERVAL source, register INTERVAL target)
112 register Lisp_Object o, sym, val;
114 if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
115 return;
117 MERGE_INTERVAL_CACHE (source, target);
119 o = source->plist;
120 while (CONSP (o))
122 sym = XCAR (o);
123 o = XCDR (o);
124 CHECK_CONS (o);
126 val = target->plist;
127 while (CONSP (val) && !EQ (XCAR (val), sym))
129 val = XCDR (val);
130 if (!CONSP (val))
131 break;
132 val = XCDR (val);
135 if (NILP (val))
137 val = XCAR (o);
138 target->plist = Fcons (sym, Fcons (val, target->plist));
140 o = XCDR (o);
144 /* Return 1 if the two intervals have the same properties,
145 0 otherwise. */
148 intervals_equal (INTERVAL i0, INTERVAL i1)
150 register Lisp_Object i0_cdr, i0_sym;
151 register Lisp_Object i1_cdr, i1_val;
153 if (DEFAULT_INTERVAL_P (i0) && DEFAULT_INTERVAL_P (i1))
154 return 1;
156 if (DEFAULT_INTERVAL_P (i0) || DEFAULT_INTERVAL_P (i1))
157 return 0;
159 i0_cdr = i0->plist;
160 i1_cdr = i1->plist;
161 while (CONSP (i0_cdr) && CONSP (i1_cdr))
163 i0_sym = XCAR (i0_cdr);
164 i0_cdr = XCDR (i0_cdr);
165 if (!CONSP (i0_cdr))
166 return 0; /* abort (); */
167 i1_val = i1->plist;
168 while (CONSP (i1_val) && !EQ (XCAR (i1_val), i0_sym))
170 i1_val = XCDR (i1_val);
171 if (!CONSP (i1_val))
172 return 0; /* abort (); */
173 i1_val = XCDR (i1_val);
176 /* i0 has something i1 doesn't. */
177 if (EQ (i1_val, Qnil))
178 return 0;
180 /* i0 and i1 both have sym, but it has different values in each. */
181 if (!CONSP (i1_val)
182 || (i1_val = XCDR (i1_val), !CONSP (i1_val))
183 || !EQ (XCAR (i1_val), XCAR (i0_cdr)))
184 return 0;
186 i0_cdr = XCDR (i0_cdr);
188 i1_cdr = XCDR (i1_cdr);
189 if (!CONSP (i1_cdr))
190 return 0; /* abort (); */
191 i1_cdr = XCDR (i1_cdr);
194 /* Lengths of the two plists were equal. */
195 return (NILP (i0_cdr) && NILP (i1_cdr));
199 /* Traverse an interval tree TREE, performing FUNCTION on each node.
200 No guarantee is made about the order of traversal.
201 Pass FUNCTION two args: an interval, and ARG. */
203 void
204 traverse_intervals_noorder (INTERVAL tree, void (*function) (INTERVAL, Lisp_Object), Lisp_Object arg)
206 /* Minimize stack usage. */
207 while (!NULL_INTERVAL_P (tree))
209 (*function) (tree, arg);
210 if (NULL_INTERVAL_P (tree->right))
211 tree = tree->left;
212 else
214 traverse_intervals_noorder (tree->left, function, arg);
215 tree = tree->right;
220 /* Traverse an interval tree TREE, performing FUNCTION on each node.
221 Pass FUNCTION two args: an interval, and ARG. */
223 void
224 traverse_intervals (INTERVAL tree, EMACS_INT position,
225 void (*function) (INTERVAL, Lisp_Object), Lisp_Object arg)
227 while (!NULL_INTERVAL_P (tree))
229 traverse_intervals (tree->left, position, function, arg);
230 position += LEFT_TOTAL_LENGTH (tree);
231 tree->position = position;
232 (*function) (tree, arg);
233 position += LENGTH (tree); tree = tree->right;
237 #if 0
239 static int icount;
240 static int idepth;
241 static int zero_length;
243 /* These functions are temporary, for debugging purposes only. */
245 INTERVAL search_interval, found_interval;
247 void
248 check_for_interval (i)
249 register INTERVAL i;
251 if (i == search_interval)
253 found_interval = i;
254 icount++;
258 INTERVAL
259 search_for_interval (i, tree)
260 register INTERVAL i, tree;
262 icount = 0;
263 search_interval = i;
264 found_interval = NULL_INTERVAL;
265 traverse_intervals_noorder (tree, &check_for_interval, Qnil);
266 return found_interval;
269 static void
270 inc_interval_count (i)
271 INTERVAL i;
273 icount++;
274 if (LENGTH (i) == 0)
275 zero_length++;
276 if (depth > idepth)
277 idepth = depth;
281 count_intervals (i)
282 register INTERVAL i;
284 icount = 0;
285 idepth = 0;
286 zero_length = 0;
287 traverse_intervals_noorder (i, &inc_interval_count, Qnil);
289 return icount;
292 static INTERVAL
293 root_interval (interval)
294 INTERVAL interval;
296 register INTERVAL i = interval;
298 while (! ROOT_INTERVAL_P (i))
299 i = INTERVAL_PARENT (i);
301 return i;
303 #endif
305 /* Assuming that a left child exists, perform the following operation:
308 / \ / \
309 B => A
310 / \ / \
314 static INLINE INTERVAL
315 rotate_right (INTERVAL interval)
317 INTERVAL i;
318 INTERVAL B = interval->left;
319 EMACS_INT old_total = interval->total_length;
321 /* Deal with any Parent of A; make it point to B. */
322 if (! ROOT_INTERVAL_P (interval))
324 if (AM_LEFT_CHILD (interval))
325 INTERVAL_PARENT (interval)->left = B;
326 else
327 INTERVAL_PARENT (interval)->right = B;
329 COPY_INTERVAL_PARENT (B, interval);
331 /* Make B the parent of A */
332 i = B->right;
333 B->right = interval;
334 SET_INTERVAL_PARENT (interval, B);
336 /* Make A point to c */
337 interval->left = i;
338 if (! NULL_INTERVAL_P (i))
339 SET_INTERVAL_PARENT (i, interval);
341 /* A's total length is decreased by the length of B and its left child. */
342 interval->total_length -= B->total_length - LEFT_TOTAL_LENGTH (interval);
343 CHECK_TOTAL_LENGTH (interval);
345 /* B must have the same total length of A. */
346 B->total_length = old_total;
347 CHECK_TOTAL_LENGTH (B);
349 return B;
352 /* Assuming that a right child exists, perform the following operation:
355 / \ / \
356 B => A
357 / \ / \
361 static INLINE INTERVAL
362 rotate_left (INTERVAL interval)
364 INTERVAL i;
365 INTERVAL B = interval->right;
366 EMACS_INT old_total = interval->total_length;
368 /* Deal with any parent of A; make it point to B. */
369 if (! ROOT_INTERVAL_P (interval))
371 if (AM_LEFT_CHILD (interval))
372 INTERVAL_PARENT (interval)->left = B;
373 else
374 INTERVAL_PARENT (interval)->right = B;
376 COPY_INTERVAL_PARENT (B, interval);
378 /* Make B the parent of A */
379 i = B->left;
380 B->left = interval;
381 SET_INTERVAL_PARENT (interval, B);
383 /* Make A point to c */
384 interval->right = i;
385 if (! NULL_INTERVAL_P (i))
386 SET_INTERVAL_PARENT (i, interval);
388 /* A's total length is decreased by the length of B and its right child. */
389 interval->total_length -= B->total_length - RIGHT_TOTAL_LENGTH (interval);
390 CHECK_TOTAL_LENGTH (interval);
392 /* B must have the same total length of A. */
393 B->total_length = old_total;
394 CHECK_TOTAL_LENGTH (B);
396 return B;
399 /* Balance an interval tree with the assumption that the subtrees
400 themselves are already balanced. */
402 static INTERVAL
403 balance_an_interval (INTERVAL i)
405 register EMACS_INT old_diff, new_diff;
407 while (1)
409 old_diff = LEFT_TOTAL_LENGTH (i) - RIGHT_TOTAL_LENGTH (i);
410 if (old_diff > 0)
412 /* Since the left child is longer, there must be one. */
413 new_diff = i->total_length - i->left->total_length
414 + RIGHT_TOTAL_LENGTH (i->left) - LEFT_TOTAL_LENGTH (i->left);
415 if (eabs (new_diff) >= old_diff)
416 break;
417 i = rotate_right (i);
418 balance_an_interval (i->right);
420 else if (old_diff < 0)
422 /* Since the right child is longer, there must be one. */
423 new_diff = i->total_length - i->right->total_length
424 + LEFT_TOTAL_LENGTH (i->right) - RIGHT_TOTAL_LENGTH (i->right);
425 if (eabs (new_diff) >= -old_diff)
426 break;
427 i = rotate_left (i);
428 balance_an_interval (i->left);
430 else
431 break;
433 return i;
436 /* Balance INTERVAL, potentially stuffing it back into its parent
437 Lisp Object. */
439 static INLINE INTERVAL
440 balance_possible_root_interval (register INTERVAL interval)
442 Lisp_Object parent;
443 int have_parent = 0;
445 if (!INTERVAL_HAS_OBJECT (interval) && !INTERVAL_HAS_PARENT (interval))
446 return interval;
448 if (INTERVAL_HAS_OBJECT (interval))
450 have_parent = 1;
451 GET_INTERVAL_OBJECT (parent, interval);
453 interval = balance_an_interval (interval);
455 if (have_parent)
457 if (BUFFERP (parent))
458 BUF_INTERVALS (XBUFFER (parent)) = interval;
459 else if (STRINGP (parent))
460 STRING_SET_INTERVALS (parent, interval);
463 return interval;
466 /* Balance the interval tree TREE. Balancing is by weight
467 (the amount of text). */
469 static INTERVAL
470 balance_intervals_internal (register INTERVAL tree)
472 /* Balance within each side. */
473 if (tree->left)
474 balance_intervals_internal (tree->left);
475 if (tree->right)
476 balance_intervals_internal (tree->right);
477 return balance_an_interval (tree);
480 /* Advertised interface to balance intervals. */
482 INTERVAL
483 balance_intervals (INTERVAL tree)
485 if (tree == NULL_INTERVAL)
486 return NULL_INTERVAL;
488 return balance_intervals_internal (tree);
491 /* Split INTERVAL into two pieces, starting the second piece at
492 character position OFFSET (counting from 0), relative to INTERVAL.
493 INTERVAL becomes the left-hand piece, and the right-hand piece
494 (second, lexicographically) is returned.
496 The size and position fields of the two intervals are set based upon
497 those of the original interval. The property list of the new interval
498 is reset, thus it is up to the caller to do the right thing with the
499 result.
501 Note that this does not change the position of INTERVAL; if it is a root,
502 it is still a root after this operation. */
504 INTERVAL
505 split_interval_right (INTERVAL interval, EMACS_INT offset)
507 INTERVAL new = make_interval ();
508 EMACS_INT position = interval->position;
509 EMACS_INT new_length = LENGTH (interval) - offset;
511 new->position = position + offset;
512 SET_INTERVAL_PARENT (new, interval);
514 if (NULL_RIGHT_CHILD (interval))
516 interval->right = new;
517 new->total_length = new_length;
518 CHECK_TOTAL_LENGTH (new);
520 else
522 /* Insert the new node between INTERVAL and its right child. */
523 new->right = interval->right;
524 SET_INTERVAL_PARENT (interval->right, new);
525 interval->right = new;
526 new->total_length = new_length + new->right->total_length;
527 CHECK_TOTAL_LENGTH (new);
528 balance_an_interval (new);
531 balance_possible_root_interval (interval);
533 return new;
536 /* Split INTERVAL into two pieces, starting the second piece at
537 character position OFFSET (counting from 0), relative to INTERVAL.
538 INTERVAL becomes the right-hand piece, and the left-hand piece
539 (first, lexicographically) is returned.
541 The size and position fields of the two intervals are set based upon
542 those of the original interval. The property list of the new interval
543 is reset, thus it is up to the caller to do the right thing with the
544 result.
546 Note that this does not change the position of INTERVAL; if it is a root,
547 it is still a root after this operation. */
549 INTERVAL
550 split_interval_left (INTERVAL interval, EMACS_INT offset)
552 INTERVAL new = make_interval ();
553 EMACS_INT new_length = offset;
555 new->position = interval->position;
556 interval->position = interval->position + offset;
557 SET_INTERVAL_PARENT (new, interval);
559 if (NULL_LEFT_CHILD (interval))
561 interval->left = new;
562 new->total_length = new_length;
563 CHECK_TOTAL_LENGTH (new);
565 else
567 /* Insert the new node between INTERVAL and its left child. */
568 new->left = interval->left;
569 SET_INTERVAL_PARENT (new->left, new);
570 interval->left = new;
571 new->total_length = new_length + new->left->total_length;
572 CHECK_TOTAL_LENGTH (new);
573 balance_an_interval (new);
576 balance_possible_root_interval (interval);
578 return new;
581 /* Return the proper position for the first character
582 described by the interval tree SOURCE.
583 This is 1 if the parent is a buffer,
584 0 if the parent is a string or if there is no parent.
586 Don't use this function on an interval which is the child
587 of another interval! */
589 static int
590 interval_start_pos (INTERVAL source)
592 Lisp_Object parent;
594 if (NULL_INTERVAL_P (source))
595 return 0;
597 if (! INTERVAL_HAS_OBJECT (source))
598 return 0;
599 GET_INTERVAL_OBJECT (parent, source);
600 if (BUFFERP (parent))
601 return BUF_BEG (XBUFFER (parent));
602 return 0;
605 /* Find the interval containing text position POSITION in the text
606 represented by the interval tree TREE. POSITION is a buffer
607 position (starting from 1) or a string index (starting from 0).
608 If POSITION is at the end of the buffer or string,
609 return the interval containing the last character.
611 The `position' field, which is a cache of an interval's position,
612 is updated in the interval found. Other functions (e.g., next_interval)
613 will update this cache based on the result of find_interval. */
615 INTERVAL
616 find_interval (register INTERVAL tree, register EMACS_INT position)
618 /* The distance from the left edge of the subtree at TREE
619 to POSITION. */
620 register EMACS_INT relative_position;
622 if (NULL_INTERVAL_P (tree))
623 return NULL_INTERVAL;
625 relative_position = position;
626 if (INTERVAL_HAS_OBJECT (tree))
628 Lisp_Object parent;
629 GET_INTERVAL_OBJECT (parent, tree);
630 if (BUFFERP (parent))
631 relative_position -= BUF_BEG (XBUFFER (parent));
634 if (relative_position > TOTAL_LENGTH (tree))
635 abort (); /* Paranoia */
637 if (!handling_signal)
638 tree = balance_possible_root_interval (tree);
640 while (1)
642 if (relative_position < LEFT_TOTAL_LENGTH (tree))
644 tree = tree->left;
646 else if (! NULL_RIGHT_CHILD (tree)
647 && relative_position >= (TOTAL_LENGTH (tree)
648 - RIGHT_TOTAL_LENGTH (tree)))
650 relative_position -= (TOTAL_LENGTH (tree)
651 - RIGHT_TOTAL_LENGTH (tree));
652 tree = tree->right;
654 else
656 tree->position
657 = (position - relative_position /* left edge of *tree. */
658 + LEFT_TOTAL_LENGTH (tree)); /* left edge of this interval. */
660 return tree;
665 /* Find the succeeding interval (lexicographically) to INTERVAL.
666 Sets the `position' field based on that of INTERVAL (see
667 find_interval). */
669 INTERVAL
670 next_interval (register INTERVAL interval)
672 register INTERVAL i = interval;
673 register EMACS_INT next_position;
675 if (NULL_INTERVAL_P (i))
676 return NULL_INTERVAL;
677 next_position = interval->position + LENGTH (interval);
679 if (! NULL_RIGHT_CHILD (i))
681 i = i->right;
682 while (! NULL_LEFT_CHILD (i))
683 i = i->left;
685 i->position = next_position;
686 return i;
689 while (! NULL_PARENT (i))
691 if (AM_LEFT_CHILD (i))
693 i = INTERVAL_PARENT (i);
694 i->position = next_position;
695 return i;
698 i = INTERVAL_PARENT (i);
701 return NULL_INTERVAL;
704 /* Find the preceding interval (lexicographically) to INTERVAL.
705 Sets the `position' field based on that of INTERVAL (see
706 find_interval). */
708 INTERVAL
709 previous_interval (register INTERVAL interval)
711 register INTERVAL i;
713 if (NULL_INTERVAL_P (interval))
714 return NULL_INTERVAL;
716 if (! NULL_LEFT_CHILD (interval))
718 i = interval->left;
719 while (! NULL_RIGHT_CHILD (i))
720 i = i->right;
722 i->position = interval->position - LENGTH (i);
723 return i;
726 i = interval;
727 while (! NULL_PARENT (i))
729 if (AM_RIGHT_CHILD (i))
731 i = INTERVAL_PARENT (i);
733 i->position = interval->position - LENGTH (i);
734 return i;
736 i = INTERVAL_PARENT (i);
739 return NULL_INTERVAL;
742 /* Find the interval containing POS given some non-NULL INTERVAL
743 in the same tree. Note that we need to update interval->position
744 if we go down the tree.
745 To speed up the process, we assume that the ->position of
746 I and all its parents is already uptodate. */
747 INTERVAL
748 update_interval (register INTERVAL i, EMACS_INT pos)
750 if (NULL_INTERVAL_P (i))
751 return NULL_INTERVAL;
753 while (1)
755 if (pos < i->position)
757 /* Move left. */
758 if (pos >= i->position - TOTAL_LENGTH (i->left))
760 i->left->position = i->position - TOTAL_LENGTH (i->left)
761 + LEFT_TOTAL_LENGTH (i->left);
762 i = i->left; /* Move to the left child */
764 else if (NULL_PARENT (i))
765 error ("Point before start of properties");
766 else
767 i = INTERVAL_PARENT (i);
768 continue;
770 else if (pos >= INTERVAL_LAST_POS (i))
772 /* Move right. */
773 if (pos < INTERVAL_LAST_POS (i) + TOTAL_LENGTH (i->right))
775 i->right->position = INTERVAL_LAST_POS (i)
776 + LEFT_TOTAL_LENGTH (i->right);
777 i = i->right; /* Move to the right child */
779 else if (NULL_PARENT (i))
780 error ("Point %d after end of properties", pos);
781 else
782 i = INTERVAL_PARENT (i);
783 continue;
785 else
786 return i;
791 #if 0
792 /* Traverse a path down the interval tree TREE to the interval
793 containing POSITION, adjusting all nodes on the path for
794 an addition of LENGTH characters. Insertion between two intervals
795 (i.e., point == i->position, where i is second interval) means
796 text goes into second interval.
798 Modifications are needed to handle the hungry bits -- after simply
799 finding the interval at position (don't add length going down),
800 if it's the beginning of the interval, get the previous interval
801 and check the hungry bits of both. Then add the length going back up
802 to the root. */
804 static INTERVAL
805 adjust_intervals_for_insertion (tree, position, length)
806 INTERVAL tree;
807 int position, length;
809 register int relative_position;
810 register INTERVAL this;
812 if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
813 abort ();
815 /* If inserting at point-max of a buffer, that position
816 will be out of range */
817 if (position > TOTAL_LENGTH (tree))
818 position = TOTAL_LENGTH (tree);
819 relative_position = position;
820 this = tree;
822 while (1)
824 if (relative_position <= LEFT_TOTAL_LENGTH (this))
826 this->total_length += length;
827 CHECK_TOTAL_LENGTH (this);
828 this = this->left;
830 else if (relative_position > (TOTAL_LENGTH (this)
831 - RIGHT_TOTAL_LENGTH (this)))
833 relative_position -= (TOTAL_LENGTH (this)
834 - RIGHT_TOTAL_LENGTH (this));
835 this->total_length += length;
836 CHECK_TOTAL_LENGTH (this);
837 this = this->right;
839 else
841 /* If we are to use zero-length intervals as buffer pointers,
842 then this code will have to change. */
843 this->total_length += length;
844 CHECK_TOTAL_LENGTH (this);
845 this->position = LEFT_TOTAL_LENGTH (this)
846 + position - relative_position + 1;
847 return tree;
851 #endif
853 /* Effect an adjustment corresponding to the addition of LENGTH characters
854 of text. Do this by finding the interval containing POSITION in the
855 interval tree TREE, and then adjusting all of its ancestors by adding
856 LENGTH to them.
858 If POSITION is the first character of an interval, meaning that point
859 is actually between the two intervals, make the new text belong to
860 the interval which is "sticky".
862 If both intervals are "sticky", then make them belong to the left-most
863 interval. Another possibility would be to create a new interval for
864 this text, and make it have the merged properties of both ends. */
866 static INTERVAL
867 adjust_intervals_for_insertion (INTERVAL tree,
868 EMACS_INT position, EMACS_INT length)
870 register INTERVAL i;
871 register INTERVAL temp;
872 int eobp = 0;
873 Lisp_Object parent;
874 EMACS_INT offset;
876 if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
877 abort ();
879 GET_INTERVAL_OBJECT (parent, tree);
880 offset = (BUFFERP (parent) ? BUF_BEG (XBUFFER (parent)) : 0);
882 /* If inserting at point-max of a buffer, that position will be out
883 of range. Remember that buffer positions are 1-based. */
884 if (position >= TOTAL_LENGTH (tree) + offset)
886 position = TOTAL_LENGTH (tree) + offset;
887 eobp = 1;
890 i = find_interval (tree, position);
892 /* If in middle of an interval which is not sticky either way,
893 we must not just give its properties to the insertion.
894 So split this interval at the insertion point.
896 Originally, the if condition here was this:
897 (! (position == i->position || eobp)
898 && END_NONSTICKY_P (i)
899 && FRONT_NONSTICKY_P (i))
900 But, these macros are now unreliable because of introduction of
901 Vtext_property_default_nonsticky. So, we always check properties
902 one by one if POSITION is in middle of an interval. */
903 if (! (position == i->position || eobp))
905 Lisp_Object tail;
906 Lisp_Object front, rear;
908 tail = i->plist;
910 /* Properties font-sticky and rear-nonsticky override
911 Vtext_property_default_nonsticky. So, if they are t, we can
912 skip one by one checking of properties. */
913 rear = textget (i->plist, Qrear_nonsticky);
914 if (! CONSP (rear) && ! NILP (rear))
916 /* All properties are nonsticky. We split the interval. */
917 goto check_done;
919 front = textget (i->plist, Qfront_sticky);
920 if (! CONSP (front) && ! NILP (front))
922 /* All properties are sticky. We don't split the interval. */
923 tail = Qnil;
924 goto check_done;
927 /* Does any actual property pose an actual problem? We break
928 the loop if we find a nonsticky property. */
929 for (; CONSP (tail); tail = Fcdr (XCDR (tail)))
931 Lisp_Object prop, tmp;
932 prop = XCAR (tail);
934 /* Is this particular property front-sticky? */
935 if (CONSP (front) && ! NILP (Fmemq (prop, front)))
936 continue;
938 /* Is this particular property rear-nonsticky? */
939 if (CONSP (rear) && ! NILP (Fmemq (prop, rear)))
940 break;
942 /* Is this particular property recorded as sticky or
943 nonsticky in Vtext_property_default_nonsticky? */
944 tmp = Fassq (prop, Vtext_property_default_nonsticky);
945 if (CONSP (tmp))
947 if (NILP (tmp))
948 continue;
949 break;
952 /* By default, a text property is rear-sticky, thus we
953 continue the loop. */
956 check_done:
957 /* If any property is a real problem, split the interval. */
958 if (! NILP (tail))
960 temp = split_interval_right (i, position - i->position);
961 copy_properties (i, temp);
962 i = temp;
966 /* If we are positioned between intervals, check the stickiness of
967 both of them. We have to do this too, if we are at BEG or Z. */
968 if (position == i->position || eobp)
970 register INTERVAL prev;
972 if (position == BEG)
973 prev = 0;
974 else if (eobp)
976 prev = i;
977 i = 0;
979 else
980 prev = previous_interval (i);
982 /* Even if we are positioned between intervals, we default
983 to the left one if it exists. We extend it now and split
984 off a part later, if stickiness demands it. */
985 for (temp = prev ? prev : i; temp; temp = INTERVAL_PARENT_OR_NULL (temp))
987 temp->total_length += length;
988 CHECK_TOTAL_LENGTH (temp);
989 temp = balance_possible_root_interval (temp);
992 /* If at least one interval has sticky properties,
993 we check the stickiness property by property.
995 Originally, the if condition here was this:
996 (END_NONSTICKY_P (prev) || FRONT_STICKY_P (i))
997 But, these macros are now unreliable because of introduction
998 of Vtext_property_default_nonsticky. So, we always have to
999 check stickiness of properties one by one. If cache of
1000 stickiness is implemented in the future, we may be able to
1001 use those macros again. */
1002 if (1)
1004 Lisp_Object pleft, pright;
1005 struct interval newi;
1007 pleft = NULL_INTERVAL_P (prev) ? Qnil : prev->plist;
1008 pright = NULL_INTERVAL_P (i) ? Qnil : i->plist;
1009 newi.plist = merge_properties_sticky (pleft, pright);
1011 if (! prev) /* i.e. position == BEG */
1013 if (! intervals_equal (i, &newi))
1015 i = split_interval_left (i, length);
1016 i->plist = newi.plist;
1019 else if (! intervals_equal (prev, &newi))
1021 prev = split_interval_right (prev,
1022 position - prev->position);
1023 prev->plist = newi.plist;
1024 if (! NULL_INTERVAL_P (i)
1025 && intervals_equal (prev, i))
1026 merge_interval_right (prev);
1029 /* We will need to update the cache here later. */
1031 else if (! prev && ! NILP (i->plist))
1033 /* Just split off a new interval at the left.
1034 Since I wasn't front-sticky, the empty plist is ok. */
1035 i = split_interval_left (i, length);
1039 /* Otherwise just extend the interval. */
1040 else
1042 for (temp = i; temp; temp = INTERVAL_PARENT_OR_NULL (temp))
1044 temp->total_length += length;
1045 CHECK_TOTAL_LENGTH (temp);
1046 temp = balance_possible_root_interval (temp);
1050 return tree;
1053 /* Any property might be front-sticky on the left, rear-sticky on the left,
1054 front-sticky on the right, or rear-sticky on the right; the 16 combinations
1055 can be arranged in a matrix with rows denoting the left conditions and
1056 columns denoting the right conditions:
1057 _ __ _
1058 _ FR FR FR FR
1059 FR__ 0 1 2 3
1060 _FR 4 5 6 7
1061 FR 8 9 A B
1062 FR C D E F
1064 left-props = '(front-sticky (p8 p9 pa pb pc pd pe pf)
1065 rear-nonsticky (p4 p5 p6 p7 p8 p9 pa pb)
1066 p0 L p1 L p2 L p3 L p4 L p5 L p6 L p7 L
1067 p8 L p9 L pa L pb L pc L pd L pe L pf L)
1068 right-props = '(front-sticky (p2 p3 p6 p7 pa pb pe pf)
1069 rear-nonsticky (p1 p2 p5 p6 p9 pa pd pe)
1070 p0 R p1 R p2 R p3 R p4 R p5 R p6 R p7 R
1071 p8 R p9 R pa R pb R pc R pd R pe R pf R)
1073 We inherit from whoever has a sticky side facing us. If both sides
1074 do (cases 2, 3, E, and F), then we inherit from whichever side has a
1075 non-nil value for the current property. If both sides do, then we take
1076 from the left.
1078 When we inherit a property, we get its stickiness as well as its value.
1079 So, when we merge the above two lists, we expect to get this:
1081 result = '(front-sticky (p6 p7 pa pb pc pd pe pf)
1082 rear-nonsticky (p6 pa)
1083 p0 L p1 L p2 L p3 L p6 R p7 R
1084 pa R pb R pc L pd L pe L pf L)
1086 The optimizable special cases are:
1087 left rear-nonsticky = nil, right front-sticky = nil (inherit left)
1088 left rear-nonsticky = t, right front-sticky = t (inherit right)
1089 left rear-nonsticky = t, right front-sticky = nil (inherit none)
1092 Lisp_Object
1093 merge_properties_sticky (Lisp_Object pleft, Lisp_Object pright)
1095 register Lisp_Object props, front, rear;
1096 Lisp_Object lfront, lrear, rfront, rrear;
1097 register Lisp_Object tail1, tail2, sym, lval, rval, cat;
1098 int use_left, use_right;
1099 int lpresent;
1101 props = Qnil;
1102 front = Qnil;
1103 rear = Qnil;
1104 lfront = textget (pleft, Qfront_sticky);
1105 lrear = textget (pleft, Qrear_nonsticky);
1106 rfront = textget (pright, Qfront_sticky);
1107 rrear = textget (pright, Qrear_nonsticky);
1109 /* Go through each element of PRIGHT. */
1110 for (tail1 = pright; CONSP (tail1); tail1 = Fcdr (XCDR (tail1)))
1112 Lisp_Object tmp;
1114 sym = XCAR (tail1);
1116 /* Sticky properties get special treatment. */
1117 if (EQ (sym, Qrear_nonsticky) || EQ (sym, Qfront_sticky))
1118 continue;
1120 rval = Fcar (XCDR (tail1));
1121 for (tail2 = pleft; CONSP (tail2); tail2 = Fcdr (XCDR (tail2)))
1122 if (EQ (sym, XCAR (tail2)))
1123 break;
1125 /* Indicate whether the property is explicitly defined on the left.
1126 (We know it is defined explicitly on the right
1127 because otherwise we don't get here.) */
1128 lpresent = ! NILP (tail2);
1129 lval = (NILP (tail2) ? Qnil : Fcar (Fcdr (tail2)));
1131 /* Even if lrear or rfront say nothing about the stickiness of
1132 SYM, Vtext_property_default_nonsticky may give default
1133 stickiness to SYM. */
1134 tmp = Fassq (sym, Vtext_property_default_nonsticky);
1135 use_left = (lpresent
1136 && ! (TMEM (sym, lrear)
1137 || (CONSP (tmp) && ! NILP (XCDR (tmp)))));
1138 use_right = (TMEM (sym, rfront)
1139 || (CONSP (tmp) && NILP (XCDR (tmp))));
1140 if (use_left && use_right)
1142 if (NILP (lval))
1143 use_left = 0;
1144 else if (NILP (rval))
1145 use_right = 0;
1147 if (use_left)
1149 /* We build props as (value sym ...) rather than (sym value ...)
1150 because we plan to nreverse it when we're done. */
1151 props = Fcons (lval, Fcons (sym, props));
1152 if (TMEM (sym, lfront))
1153 front = Fcons (sym, front);
1154 if (TMEM (sym, lrear))
1155 rear = Fcons (sym, rear);
1157 else if (use_right)
1159 props = Fcons (rval, Fcons (sym, props));
1160 if (TMEM (sym, rfront))
1161 front = Fcons (sym, front);
1162 if (TMEM (sym, rrear))
1163 rear = Fcons (sym, rear);
1167 /* Now go through each element of PLEFT. */
1168 for (tail2 = pleft; CONSP (tail2); tail2 = Fcdr (XCDR (tail2)))
1170 Lisp_Object tmp;
1172 sym = XCAR (tail2);
1174 /* Sticky properties get special treatment. */
1175 if (EQ (sym, Qrear_nonsticky) || EQ (sym, Qfront_sticky))
1176 continue;
1178 /* If sym is in PRIGHT, we've already considered it. */
1179 for (tail1 = pright; CONSP (tail1); tail1 = Fcdr (XCDR (tail1)))
1180 if (EQ (sym, XCAR (tail1)))
1181 break;
1182 if (! NILP (tail1))
1183 continue;
1185 lval = Fcar (XCDR (tail2));
1187 /* Even if lrear or rfront say nothing about the stickiness of
1188 SYM, Vtext_property_default_nonsticky may give default
1189 stickiness to SYM. */
1190 tmp = Fassq (sym, Vtext_property_default_nonsticky);
1192 /* Since rval is known to be nil in this loop, the test simplifies. */
1193 if (! (TMEM (sym, lrear) || (CONSP (tmp) && ! NILP (XCDR (tmp)))))
1195 props = Fcons (lval, Fcons (sym, props));
1196 if (TMEM (sym, lfront))
1197 front = Fcons (sym, front);
1199 else if (TMEM (sym, rfront) || (CONSP (tmp) && NILP (XCDR (tmp))))
1201 /* The value is nil, but we still inherit the stickiness
1202 from the right. */
1203 front = Fcons (sym, front);
1204 if (TMEM (sym, rrear))
1205 rear = Fcons (sym, rear);
1208 props = Fnreverse (props);
1209 if (! NILP (rear))
1210 props = Fcons (Qrear_nonsticky, Fcons (Fnreverse (rear), props));
1212 cat = textget (props, Qcategory);
1213 if (! NILP (front)
1215 /* If we have inherited a front-stick category property that is t,
1216 we don't need to set up a detailed one. */
1217 ! (! NILP (cat) && SYMBOLP (cat)
1218 && EQ (Fget (cat, Qfront_sticky), Qt)))
1219 props = Fcons (Qfront_sticky, Fcons (Fnreverse (front), props));
1220 return props;
1224 /* Delete a node I from its interval tree by merging its subtrees
1225 into one subtree which is then returned. Caller is responsible for
1226 storing the resulting subtree into its parent. */
1228 static INTERVAL
1229 delete_node (register INTERVAL i)
1231 register INTERVAL migrate, this;
1232 register EMACS_INT migrate_amt;
1234 if (NULL_INTERVAL_P (i->left))
1235 return i->right;
1236 if (NULL_INTERVAL_P (i->right))
1237 return i->left;
1239 migrate = i->left;
1240 migrate_amt = i->left->total_length;
1241 this = i->right;
1242 this->total_length += migrate_amt;
1243 while (! NULL_INTERVAL_P (this->left))
1245 this = this->left;
1246 this->total_length += migrate_amt;
1248 CHECK_TOTAL_LENGTH (this);
1249 this->left = migrate;
1250 SET_INTERVAL_PARENT (migrate, this);
1252 return i->right;
1255 /* Delete interval I from its tree by calling `delete_node'
1256 and properly connecting the resultant subtree.
1258 I is presumed to be empty; that is, no adjustments are made
1259 for the length of I. */
1261 void
1262 delete_interval (register INTERVAL i)
1264 register INTERVAL parent;
1265 EMACS_INT amt = LENGTH (i);
1267 if (amt > 0) /* Only used on zero-length intervals now. */
1268 abort ();
1270 if (ROOT_INTERVAL_P (i))
1272 Lisp_Object owner;
1273 GET_INTERVAL_OBJECT (owner, i);
1274 parent = delete_node (i);
1275 if (! NULL_INTERVAL_P (parent))
1276 SET_INTERVAL_OBJECT (parent, owner);
1278 if (BUFFERP (owner))
1279 BUF_INTERVALS (XBUFFER (owner)) = parent;
1280 else if (STRINGP (owner))
1281 STRING_SET_INTERVALS (owner, parent);
1282 else
1283 abort ();
1285 return;
1288 parent = INTERVAL_PARENT (i);
1289 if (AM_LEFT_CHILD (i))
1291 parent->left = delete_node (i);
1292 if (! NULL_INTERVAL_P (parent->left))
1293 SET_INTERVAL_PARENT (parent->left, parent);
1295 else
1297 parent->right = delete_node (i);
1298 if (! NULL_INTERVAL_P (parent->right))
1299 SET_INTERVAL_PARENT (parent->right, parent);
1303 /* Find the interval in TREE corresponding to the relative position
1304 FROM and delete as much as possible of AMOUNT from that interval.
1305 Return the amount actually deleted, and if the interval was
1306 zeroed-out, delete that interval node from the tree.
1308 Note that FROM is actually origin zero, aka relative to the
1309 leftmost edge of tree. This is appropriate since we call ourselves
1310 recursively on subtrees.
1312 Do this by recursing down TREE to the interval in question, and
1313 deleting the appropriate amount of text. */
1315 static EMACS_INT
1316 interval_deletion_adjustment (register INTERVAL tree, register EMACS_INT from,
1317 register EMACS_INT amount)
1319 register EMACS_INT relative_position = from;
1321 if (NULL_INTERVAL_P (tree))
1322 return 0;
1324 /* Left branch */
1325 if (relative_position < LEFT_TOTAL_LENGTH (tree))
1327 EMACS_INT subtract = interval_deletion_adjustment (tree->left,
1328 relative_position,
1329 amount);
1330 tree->total_length -= subtract;
1331 CHECK_TOTAL_LENGTH (tree);
1332 return subtract;
1334 /* Right branch */
1335 else if (relative_position >= (TOTAL_LENGTH (tree)
1336 - RIGHT_TOTAL_LENGTH (tree)))
1338 EMACS_INT subtract;
1340 relative_position -= (tree->total_length
1341 - RIGHT_TOTAL_LENGTH (tree));
1342 subtract = interval_deletion_adjustment (tree->right,
1343 relative_position,
1344 amount);
1345 tree->total_length -= subtract;
1346 CHECK_TOTAL_LENGTH (tree);
1347 return subtract;
1349 /* Here -- this node. */
1350 else
1352 /* How much can we delete from this interval? */
1353 EMACS_INT my_amount = ((tree->total_length
1354 - RIGHT_TOTAL_LENGTH (tree))
1355 - relative_position);
1357 if (amount > my_amount)
1358 amount = my_amount;
1360 tree->total_length -= amount;
1361 CHECK_TOTAL_LENGTH (tree);
1362 if (LENGTH (tree) == 0)
1363 delete_interval (tree);
1365 return amount;
1368 /* Never reach here. */
1371 /* Effect the adjustments necessary to the interval tree of BUFFER to
1372 correspond to the deletion of LENGTH characters from that buffer
1373 text. The deletion is effected at position START (which is a
1374 buffer position, i.e. origin 1). */
1376 static void
1377 adjust_intervals_for_deletion (struct buffer *buffer,
1378 EMACS_INT start, EMACS_INT length)
1380 register EMACS_INT left_to_delete = length;
1381 register INTERVAL tree = BUF_INTERVALS (buffer);
1382 Lisp_Object parent;
1383 EMACS_INT offset;
1385 GET_INTERVAL_OBJECT (parent, tree);
1386 offset = (BUFFERP (parent) ? BUF_BEG (XBUFFER (parent)) : 0);
1388 if (NULL_INTERVAL_P (tree))
1389 return;
1391 if (start > offset + TOTAL_LENGTH (tree)
1392 || start + length > offset + TOTAL_LENGTH (tree))
1393 abort ();
1395 if (length == TOTAL_LENGTH (tree))
1397 BUF_INTERVALS (buffer) = NULL_INTERVAL;
1398 return;
1401 if (ONLY_INTERVAL_P (tree))
1403 tree->total_length -= length;
1404 CHECK_TOTAL_LENGTH (tree);
1405 return;
1408 if (start > offset + TOTAL_LENGTH (tree))
1409 start = offset + TOTAL_LENGTH (tree);
1410 while (left_to_delete > 0)
1412 left_to_delete -= interval_deletion_adjustment (tree, start - offset,
1413 left_to_delete);
1414 tree = BUF_INTERVALS (buffer);
1415 if (left_to_delete == tree->total_length)
1417 BUF_INTERVALS (buffer) = NULL_INTERVAL;
1418 return;
1423 /* Make the adjustments necessary to the interval tree of BUFFER to
1424 represent an addition or deletion of LENGTH characters starting
1425 at position START. Addition or deletion is indicated by the sign
1426 of LENGTH. */
1428 INLINE void
1429 offset_intervals (struct buffer *buffer, EMACS_INT start, EMACS_INT length)
1431 if (NULL_INTERVAL_P (BUF_INTERVALS (buffer)) || length == 0)
1432 return;
1434 if (length > 0)
1435 adjust_intervals_for_insertion (BUF_INTERVALS (buffer), start, length);
1436 else
1437 adjust_intervals_for_deletion (buffer, start, -length);
1440 /* Merge interval I with its lexicographic successor. The resulting
1441 interval is returned, and has the properties of the original
1442 successor. The properties of I are lost. I is removed from the
1443 interval tree.
1445 IMPORTANT:
1446 The caller must verify that this is not the last (rightmost)
1447 interval. */
1449 INTERVAL
1450 merge_interval_right (register INTERVAL i)
1452 register EMACS_INT absorb = LENGTH (i);
1453 register INTERVAL successor;
1455 /* Zero out this interval. */
1456 i->total_length -= absorb;
1457 CHECK_TOTAL_LENGTH (i);
1459 /* Find the succeeding interval. */
1460 if (! NULL_RIGHT_CHILD (i)) /* It's below us. Add absorb
1461 as we descend. */
1463 successor = i->right;
1464 while (! NULL_LEFT_CHILD (successor))
1466 successor->total_length += absorb;
1467 CHECK_TOTAL_LENGTH (successor);
1468 successor = successor->left;
1471 successor->total_length += absorb;
1472 CHECK_TOTAL_LENGTH (successor);
1473 delete_interval (i);
1474 return successor;
1477 successor = i;
1478 while (! NULL_PARENT (successor)) /* It's above us. Subtract as
1479 we ascend. */
1481 if (AM_LEFT_CHILD (successor))
1483 successor = INTERVAL_PARENT (successor);
1484 delete_interval (i);
1485 return successor;
1488 successor = INTERVAL_PARENT (successor);
1489 successor->total_length -= absorb;
1490 CHECK_TOTAL_LENGTH (successor);
1493 /* This must be the rightmost or last interval and cannot
1494 be merged right. The caller should have known. */
1495 abort ();
1498 /* Merge interval I with its lexicographic predecessor. The resulting
1499 interval is returned, and has the properties of the original predecessor.
1500 The properties of I are lost. Interval node I is removed from the tree.
1502 IMPORTANT:
1503 The caller must verify that this is not the first (leftmost) interval. */
1505 INTERVAL
1506 merge_interval_left (register INTERVAL i)
1508 register EMACS_INT absorb = LENGTH (i);
1509 register INTERVAL predecessor;
1511 /* Zero out this interval. */
1512 i->total_length -= absorb;
1513 CHECK_TOTAL_LENGTH (i);
1515 /* Find the preceding interval. */
1516 if (! NULL_LEFT_CHILD (i)) /* It's below us. Go down,
1517 adding ABSORB as we go. */
1519 predecessor = i->left;
1520 while (! NULL_RIGHT_CHILD (predecessor))
1522 predecessor->total_length += absorb;
1523 CHECK_TOTAL_LENGTH (predecessor);
1524 predecessor = predecessor->right;
1527 predecessor->total_length += absorb;
1528 CHECK_TOTAL_LENGTH (predecessor);
1529 delete_interval (i);
1530 return predecessor;
1533 predecessor = i;
1534 while (! NULL_PARENT (predecessor)) /* It's above us. Go up,
1535 subtracting ABSORB. */
1537 if (AM_RIGHT_CHILD (predecessor))
1539 predecessor = INTERVAL_PARENT (predecessor);
1540 delete_interval (i);
1541 return predecessor;
1544 predecessor = INTERVAL_PARENT (predecessor);
1545 predecessor->total_length -= absorb;
1546 CHECK_TOTAL_LENGTH (predecessor);
1549 /* This must be the leftmost or first interval and cannot
1550 be merged left. The caller should have known. */
1551 abort ();
1554 /* Make an exact copy of interval tree SOURCE which descends from
1555 PARENT. This is done by recursing through SOURCE, copying
1556 the current interval and its properties, and then adjusting
1557 the pointers of the copy. */
1559 static INTERVAL
1560 reproduce_tree (INTERVAL source, INTERVAL parent)
1562 register INTERVAL t = make_interval ();
1564 memcpy (t, source, INTERVAL_SIZE);
1565 copy_properties (source, t);
1566 SET_INTERVAL_PARENT (t, parent);
1567 if (! NULL_LEFT_CHILD (source))
1568 t->left = reproduce_tree (source->left, t);
1569 if (! NULL_RIGHT_CHILD (source))
1570 t->right = reproduce_tree (source->right, t);
1572 return t;
1575 static INTERVAL
1576 reproduce_tree_obj (INTERVAL source, Lisp_Object parent)
1578 register INTERVAL t = make_interval ();
1580 memcpy (t, source, INTERVAL_SIZE);
1581 copy_properties (source, t);
1582 SET_INTERVAL_OBJECT (t, parent);
1583 if (! NULL_LEFT_CHILD (source))
1584 t->left = reproduce_tree (source->left, t);
1585 if (! NULL_RIGHT_CHILD (source))
1586 t->right = reproduce_tree (source->right, t);
1588 return t;
1591 #if 0
1592 /* Nobody calls this. Perhaps it's a vestige of an earlier design. */
1594 /* Make a new interval of length LENGTH starting at START in the
1595 group of intervals INTERVALS, which is actually an interval tree.
1596 Returns the new interval.
1598 Generate an error if the new positions would overlap an existing
1599 interval. */
1601 static INTERVAL
1602 make_new_interval (intervals, start, length)
1603 INTERVAL intervals;
1604 EMACS_INT start, length;
1606 INTERVAL slot;
1608 slot = find_interval (intervals, start);
1609 if (start + length > slot->position + LENGTH (slot))
1610 error ("Interval would overlap");
1612 if (start == slot->position && length == LENGTH (slot))
1613 return slot;
1615 if (slot->position == start)
1617 /* New right node. */
1618 split_interval_right (slot, length);
1619 return slot;
1622 if (slot->position + LENGTH (slot) == start + length)
1624 /* New left node. */
1625 split_interval_left (slot, LENGTH (slot) - length);
1626 return slot;
1629 /* Convert interval SLOT into three intervals. */
1630 split_interval_left (slot, start - slot->position);
1631 split_interval_right (slot, length);
1632 return slot;
1634 #endif
1636 /* Insert the intervals of SOURCE into BUFFER at POSITION.
1637 LENGTH is the length of the text in SOURCE.
1639 The `position' field of the SOURCE intervals is assumed to be
1640 consistent with its parent; therefore, SOURCE must be an
1641 interval tree made with copy_interval or must be the whole
1642 tree of a buffer or a string.
1644 This is used in insdel.c when inserting Lisp_Strings into the
1645 buffer. The text corresponding to SOURCE is already in the buffer
1646 when this is called. The intervals of new tree are a copy of those
1647 belonging to the string being inserted; intervals are never
1648 shared.
1650 If the inserted text had no intervals associated, and we don't
1651 want to inherit the surrounding text's properties, this function
1652 simply returns -- offset_intervals should handle placing the
1653 text in the correct interval, depending on the sticky bits.
1655 If the inserted text had properties (intervals), then there are two
1656 cases -- either insertion happened in the middle of some interval,
1657 or between two intervals.
1659 If the text goes into the middle of an interval, then new
1660 intervals are created in the middle with only the properties of
1661 the new text, *unless* the macro MERGE_INSERTIONS is true, in
1662 which case the new text has the union of its properties and those
1663 of the text into which it was inserted.
1665 If the text goes between two intervals, then if neither interval
1666 had its appropriate sticky property set (front_sticky, rear_sticky),
1667 the new text has only its properties. If one of the sticky properties
1668 is set, then the new text "sticks" to that region and its properties
1669 depend on merging as above. If both the preceding and succeeding
1670 intervals to the new text are "sticky", then the new text retains
1671 only its properties, as if neither sticky property were set. Perhaps
1672 we should consider merging all three sets of properties onto the new
1673 text... */
1675 void
1676 graft_intervals_into_buffer (INTERVAL source, EMACS_INT position,
1677 EMACS_INT length, struct buffer *buffer,
1678 int inherit)
1680 register INTERVAL under, over, this, prev;
1681 register INTERVAL tree;
1682 EMACS_INT over_used;
1684 tree = BUF_INTERVALS (buffer);
1686 /* If the new text has no properties, then with inheritance it
1687 becomes part of whatever interval it was inserted into.
1688 To prevent inheritance, we must clear out the properties
1689 of the newly inserted text. */
1690 if (NULL_INTERVAL_P (source))
1692 Lisp_Object buf;
1693 if (!inherit && !NULL_INTERVAL_P (tree) && length > 0)
1695 XSETBUFFER (buf, buffer);
1696 set_text_properties_1 (make_number (position),
1697 make_number (position + length),
1698 Qnil, buf, 0);
1700 if (! NULL_INTERVAL_P (BUF_INTERVALS (buffer)))
1701 /* Shouldn't be necessary. -stef */
1702 BUF_INTERVALS (buffer) = balance_an_interval (BUF_INTERVALS (buffer));
1703 return;
1706 if (NULL_INTERVAL_P (tree))
1708 /* The inserted text constitutes the whole buffer, so
1709 simply copy over the interval structure. */
1710 if ((BUF_Z (buffer) - BUF_BEG (buffer)) == TOTAL_LENGTH (source))
1712 Lisp_Object buf;
1713 XSETBUFFER (buf, buffer);
1714 BUF_INTERVALS (buffer) = reproduce_tree_obj (source, buf);
1715 BUF_INTERVALS (buffer)->position = BEG;
1716 BUF_INTERVALS (buffer)->up_obj = 1;
1718 /* Explicitly free the old tree here? */
1720 return;
1723 /* Create an interval tree in which to place a copy
1724 of the intervals of the inserted string. */
1726 Lisp_Object buf;
1727 XSETBUFFER (buf, buffer);
1728 tree = create_root_interval (buf);
1731 else if (TOTAL_LENGTH (tree) == TOTAL_LENGTH (source))
1732 /* If the buffer contains only the new string, but
1733 there was already some interval tree there, then it may be
1734 some zero length intervals. Eventually, do something clever
1735 about inserting properly. For now, just waste the old intervals. */
1737 BUF_INTERVALS (buffer) = reproduce_tree (source, INTERVAL_PARENT (tree));
1738 BUF_INTERVALS (buffer)->position = BEG;
1739 BUF_INTERVALS (buffer)->up_obj = 1;
1740 /* Explicitly free the old tree here. */
1742 return;
1744 /* Paranoia -- the text has already been added, so this buffer
1745 should be of non-zero length. */
1746 else if (TOTAL_LENGTH (tree) == 0)
1747 abort ();
1749 this = under = find_interval (tree, position);
1750 if (NULL_INTERVAL_P (under)) /* Paranoia */
1751 abort ();
1752 over = find_interval (source, interval_start_pos (source));
1754 /* Here for insertion in the middle of an interval.
1755 Split off an equivalent interval to the right,
1756 then don't bother with it any more. */
1758 if (position > under->position)
1760 INTERVAL end_unchanged
1761 = split_interval_left (this, position - under->position);
1762 copy_properties (under, end_unchanged);
1763 under->position = position;
1765 else
1767 /* This call may have some effect because previous_interval may
1768 update `position' fields of intervals. Thus, don't ignore it
1769 for the moment. Someone please tell me the truth (K.Handa). */
1770 prev = previous_interval (under);
1771 #if 0
1772 /* But, this code surely has no effect. And, anyway,
1773 END_NONSTICKY_P is unreliable now. */
1774 if (prev && !END_NONSTICKY_P (prev))
1775 prev = 0;
1776 #endif /* 0 */
1779 /* Insertion is now at beginning of UNDER. */
1781 /* The inserted text "sticks" to the interval `under',
1782 which means it gets those properties.
1783 The properties of under are the result of
1784 adjust_intervals_for_insertion, so stickiness has
1785 already been taken care of. */
1787 /* OVER is the interval we are copying from next.
1788 OVER_USED says how many characters' worth of OVER
1789 have already been copied into target intervals.
1790 UNDER is the next interval in the target. */
1791 over_used = 0;
1792 while (! NULL_INTERVAL_P (over))
1794 /* If UNDER is longer than OVER, split it. */
1795 if (LENGTH (over) - over_used < LENGTH (under))
1797 this = split_interval_left (under, LENGTH (over) - over_used);
1798 copy_properties (under, this);
1800 else
1801 this = under;
1803 /* THIS is now the interval to copy or merge into.
1804 OVER covers all of it. */
1805 if (inherit)
1806 merge_properties (over, this);
1807 else
1808 copy_properties (over, this);
1810 /* If THIS and OVER end at the same place,
1811 advance OVER to a new source interval. */
1812 if (LENGTH (this) == LENGTH (over) - over_used)
1814 over = next_interval (over);
1815 over_used = 0;
1817 else
1818 /* Otherwise just record that more of OVER has been used. */
1819 over_used += LENGTH (this);
1821 /* Always advance to a new target interval. */
1822 under = next_interval (this);
1825 if (! NULL_INTERVAL_P (BUF_INTERVALS (buffer)))
1826 BUF_INTERVALS (buffer) = balance_an_interval (BUF_INTERVALS (buffer));
1827 return;
1830 /* Get the value of property PROP from PLIST,
1831 which is the plist of an interval.
1832 We check for direct properties, for categories with property PROP,
1833 and for PROP appearing on the default-text-properties list. */
1835 Lisp_Object
1836 textget (Lisp_Object plist, register Lisp_Object prop)
1838 return lookup_char_property (plist, prop, 1);
1841 Lisp_Object
1842 lookup_char_property (Lisp_Object plist, register Lisp_Object prop, int textprop)
1844 register Lisp_Object tail, fallback = Qnil;
1846 for (tail = plist; CONSP (tail); tail = Fcdr (XCDR (tail)))
1848 register Lisp_Object tem;
1849 tem = XCAR (tail);
1850 if (EQ (prop, tem))
1851 return Fcar (XCDR (tail));
1852 if (EQ (tem, Qcategory))
1854 tem = Fcar (XCDR (tail));
1855 if (SYMBOLP (tem))
1856 fallback = Fget (tem, prop);
1860 if (! NILP (fallback))
1861 return fallback;
1862 /* Check for alternative properties */
1863 tail = Fassq (prop, Vchar_property_alias_alist);
1864 if (! NILP (tail))
1866 tail = XCDR (tail);
1867 for (; NILP (fallback) && CONSP (tail); tail = XCDR (tail))
1868 fallback = Fplist_get (plist, XCAR (tail));
1871 if (textprop && NILP (fallback) && CONSP (Vdefault_text_properties))
1872 fallback = Fplist_get (Vdefault_text_properties, prop);
1873 return fallback;
1877 /* Set point in BUFFER "temporarily" to CHARPOS, which corresponds to
1878 byte position BYTEPOS. */
1880 INLINE void
1881 temp_set_point_both (struct buffer *buffer,
1882 EMACS_INT charpos, EMACS_INT bytepos)
1884 /* In a single-byte buffer, the two positions must be equal. */
1885 if (BUF_ZV (buffer) == BUF_ZV_BYTE (buffer)
1886 && charpos != bytepos)
1887 abort ();
1889 if (charpos > bytepos)
1890 abort ();
1892 if (charpos > BUF_ZV (buffer) || charpos < BUF_BEGV (buffer))
1893 abort ();
1895 SET_BUF_PT_BOTH (buffer, charpos, bytepos);
1898 /* Set point "temporarily", without checking any text properties. */
1900 INLINE void
1901 temp_set_point (struct buffer *buffer, EMACS_INT charpos)
1903 temp_set_point_both (buffer, charpos,
1904 buf_charpos_to_bytepos (buffer, charpos));
1907 /* Set point in BUFFER to CHARPOS. If the target position is
1908 before an intangible character, move to an ok place. */
1910 void
1911 set_point (EMACS_INT charpos)
1913 set_point_both (charpos, buf_charpos_to_bytepos (current_buffer, charpos));
1916 /* If there's an invisible character at position POS + TEST_OFFS in the
1917 current buffer, and the invisible property has a `stickiness' such that
1918 inserting a character at position POS would inherit the property it,
1919 return POS + ADJ, otherwise return POS. If TEST_INTANG is non-zero,
1920 then intangibility is required as well as invisibleness.
1922 TEST_OFFS should be either 0 or -1, and ADJ should be either 1 or -1.
1924 Note that `stickiness' is determined by overlay marker insertion types,
1925 if the invisible property comes from an overlay. */
1927 static EMACS_INT
1928 adjust_for_invis_intang (EMACS_INT pos, EMACS_INT test_offs, EMACS_INT adj,
1929 int test_intang)
1931 Lisp_Object invis_propval, invis_overlay;
1932 Lisp_Object test_pos;
1934 if ((adj < 0 && pos + adj < BEGV) || (adj > 0 && pos + adj > ZV))
1935 /* POS + ADJ would be beyond the buffer bounds, so do no adjustment. */
1936 return pos;
1938 test_pos = make_number (pos + test_offs);
1940 invis_propval
1941 = get_char_property_and_overlay (test_pos, Qinvisible, Qnil,
1942 &invis_overlay);
1944 if ((!test_intang
1945 || ! NILP (Fget_char_property (test_pos, Qintangible, Qnil)))
1946 && TEXT_PROP_MEANS_INVISIBLE (invis_propval)
1947 /* This next test is true if the invisible property has a stickiness
1948 such that an insertion at POS would inherit it. */
1949 && (NILP (invis_overlay)
1950 /* Invisible property is from a text-property. */
1951 ? (text_property_stickiness (Qinvisible, make_number (pos), Qnil)
1952 == (test_offs == 0 ? 1 : -1))
1953 /* Invisible property is from an overlay. */
1954 : (test_offs == 0
1955 ? XMARKER (OVERLAY_START (invis_overlay))->insertion_type == 0
1956 : XMARKER (OVERLAY_END (invis_overlay))->insertion_type == 1)))
1957 pos += adj;
1959 return pos;
1962 /* Set point in BUFFER to CHARPOS, which corresponds to byte
1963 position BYTEPOS. If the target position is
1964 before an intangible character, move to an ok place. */
1966 void
1967 set_point_both (EMACS_INT charpos, EMACS_INT bytepos)
1969 register INTERVAL to, from, toprev, fromprev;
1970 EMACS_INT buffer_point;
1971 EMACS_INT old_position = PT;
1972 /* This ensures that we move forward past intangible text when the
1973 initial position is the same as the destination, in the rare
1974 instances where this is important, e.g. in line-move-finish
1975 (simple.el). */
1976 int backwards = (charpos < old_position ? 1 : 0);
1977 int have_overlays;
1978 EMACS_INT original_position;
1980 BVAR (current_buffer, point_before_scroll) = Qnil;
1982 if (charpos == PT)
1983 return;
1985 /* In a single-byte buffer, the two positions must be equal. */
1986 eassert (ZV != ZV_BYTE || charpos == bytepos);
1988 /* Check this now, before checking if the buffer has any intervals.
1989 That way, we can catch conditions which break this sanity check
1990 whether or not there are intervals in the buffer. */
1991 eassert (charpos <= ZV && charpos >= BEGV);
1993 have_overlays = (current_buffer->overlays_before
1994 || current_buffer->overlays_after);
1996 /* If we have no text properties and overlays,
1997 then we can do it quickly. */
1998 if (NULL_INTERVAL_P (BUF_INTERVALS (current_buffer)) && ! have_overlays)
2000 temp_set_point_both (current_buffer, charpos, bytepos);
2001 return;
2004 /* Set TO to the interval containing the char after CHARPOS,
2005 and TOPREV to the interval containing the char before CHARPOS.
2006 Either one may be null. They may be equal. */
2007 to = find_interval (BUF_INTERVALS (current_buffer), charpos);
2008 if (charpos == BEGV)
2009 toprev = 0;
2010 else if (to && to->position == charpos)
2011 toprev = previous_interval (to);
2012 else
2013 toprev = to;
2015 buffer_point = (PT == ZV ? ZV - 1 : PT);
2017 /* Set FROM to the interval containing the char after PT,
2018 and FROMPREV to the interval containing the char before PT.
2019 Either one may be null. They may be equal. */
2020 /* We could cache this and save time. */
2021 from = find_interval (BUF_INTERVALS (current_buffer), buffer_point);
2022 if (buffer_point == BEGV)
2023 fromprev = 0;
2024 else if (from && from->position == PT)
2025 fromprev = previous_interval (from);
2026 else if (buffer_point != PT)
2027 fromprev = from, from = 0;
2028 else
2029 fromprev = from;
2031 /* Moving within an interval. */
2032 if (to == from && toprev == fromprev && INTERVAL_VISIBLE_P (to)
2033 && ! have_overlays)
2035 temp_set_point_both (current_buffer, charpos, bytepos);
2036 return;
2039 original_position = charpos;
2041 /* If the new position is between two intangible characters
2042 with the same intangible property value,
2043 move forward or backward until a change in that property. */
2044 if (NILP (Vinhibit_point_motion_hooks)
2045 && ((! NULL_INTERVAL_P (to) && ! NULL_INTERVAL_P (toprev))
2046 || have_overlays)
2047 /* Intangibility never stops us from positioning at the beginning
2048 or end of the buffer, so don't bother checking in that case. */
2049 && charpos != BEGV && charpos != ZV)
2051 Lisp_Object pos;
2052 Lisp_Object intangible_propval;
2054 if (backwards)
2056 /* If the preceding character is both intangible and invisible,
2057 and the invisible property is `rear-sticky', perturb it so
2058 that the search starts one character earlier -- this ensures
2059 that point can never move to the end of an invisible/
2060 intangible/rear-sticky region. */
2061 charpos = adjust_for_invis_intang (charpos, -1, -1, 1);
2063 XSETINT (pos, charpos);
2065 /* If following char is intangible,
2066 skip back over all chars with matching intangible property. */
2068 intangible_propval = Fget_char_property (pos, Qintangible, Qnil);
2070 if (! NILP (intangible_propval))
2072 while (XINT (pos) > BEGV
2073 && EQ (Fget_char_property (make_number (XINT (pos) - 1),
2074 Qintangible, Qnil),
2075 intangible_propval))
2076 pos = Fprevious_char_property_change (pos, Qnil);
2078 /* Set CHARPOS from POS, and if the final intangible character
2079 that we skipped over is also invisible, and the invisible
2080 property is `front-sticky', perturb it to be one character
2081 earlier -- this ensures that point can never move to the
2082 beginning of an invisible/intangible/front-sticky region. */
2083 charpos = adjust_for_invis_intang (XINT (pos), 0, -1, 0);
2086 else
2088 /* If the following character is both intangible and invisible,
2089 and the invisible property is `front-sticky', perturb it so
2090 that the search starts one character later -- this ensures
2091 that point can never move to the beginning of an
2092 invisible/intangible/front-sticky region. */
2093 charpos = adjust_for_invis_intang (charpos, 0, 1, 1);
2095 XSETINT (pos, charpos);
2097 /* If preceding char is intangible,
2098 skip forward over all chars with matching intangible property. */
2100 intangible_propval = Fget_char_property (make_number (charpos - 1),
2101 Qintangible, Qnil);
2103 if (! NILP (intangible_propval))
2105 while (XINT (pos) < ZV
2106 && EQ (Fget_char_property (pos, Qintangible, Qnil),
2107 intangible_propval))
2108 pos = Fnext_char_property_change (pos, Qnil);
2110 /* Set CHARPOS from POS, and if the final intangible character
2111 that we skipped over is also invisible, and the invisible
2112 property is `rear-sticky', perturb it to be one character
2113 later -- this ensures that point can never move to the
2114 end of an invisible/intangible/rear-sticky region. */
2115 charpos = adjust_for_invis_intang (XINT (pos), -1, 1, 0);
2119 bytepos = buf_charpos_to_bytepos (current_buffer, charpos);
2122 if (charpos != original_position)
2124 /* Set TO to the interval containing the char after CHARPOS,
2125 and TOPREV to the interval containing the char before CHARPOS.
2126 Either one may be null. They may be equal. */
2127 to = find_interval (BUF_INTERVALS (current_buffer), charpos);
2128 if (charpos == BEGV)
2129 toprev = 0;
2130 else if (to && to->position == charpos)
2131 toprev = previous_interval (to);
2132 else
2133 toprev = to;
2136 /* Here TO is the interval after the stopping point
2137 and TOPREV is the interval before the stopping point.
2138 One or the other may be null. */
2140 temp_set_point_both (current_buffer, charpos, bytepos);
2142 /* We run point-left and point-entered hooks here, if the
2143 two intervals are not equivalent. These hooks take
2144 (old_point, new_point) as arguments. */
2145 if (NILP (Vinhibit_point_motion_hooks)
2146 && (! intervals_equal (from, to)
2147 || ! intervals_equal (fromprev, toprev)))
2149 Lisp_Object leave_after, leave_before, enter_after, enter_before;
2151 if (fromprev)
2152 leave_before = textget (fromprev->plist, Qpoint_left);
2153 else
2154 leave_before = Qnil;
2156 if (from)
2157 leave_after = textget (from->plist, Qpoint_left);
2158 else
2159 leave_after = Qnil;
2161 if (toprev)
2162 enter_before = textget (toprev->plist, Qpoint_entered);
2163 else
2164 enter_before = Qnil;
2166 if (to)
2167 enter_after = textget (to->plist, Qpoint_entered);
2168 else
2169 enter_after = Qnil;
2171 if (! EQ (leave_before, enter_before) && !NILP (leave_before))
2172 call2 (leave_before, make_number (old_position),
2173 make_number (charpos));
2174 if (! EQ (leave_after, enter_after) && !NILP (leave_after))
2175 call2 (leave_after, make_number (old_position),
2176 make_number (charpos));
2178 if (! EQ (enter_before, leave_before) && !NILP (enter_before))
2179 call2 (enter_before, make_number (old_position),
2180 make_number (charpos));
2181 if (! EQ (enter_after, leave_after) && !NILP (enter_after))
2182 call2 (enter_after, make_number (old_position),
2183 make_number (charpos));
2187 /* Move point to POSITION, unless POSITION is inside an intangible
2188 segment that reaches all the way to point. */
2190 void
2191 move_if_not_intangible (EMACS_INT position)
2193 Lisp_Object pos;
2194 Lisp_Object intangible_propval;
2196 XSETINT (pos, position);
2198 if (! NILP (Vinhibit_point_motion_hooks))
2199 /* If intangible is inhibited, always move point to POSITION. */
2201 else if (PT < position && XINT (pos) < ZV)
2203 /* We want to move forward, so check the text before POSITION. */
2205 intangible_propval = Fget_char_property (pos,
2206 Qintangible, Qnil);
2208 /* If following char is intangible,
2209 skip back over all chars with matching intangible property. */
2210 if (! NILP (intangible_propval))
2211 while (XINT (pos) > BEGV
2212 && EQ (Fget_char_property (make_number (XINT (pos) - 1),
2213 Qintangible, Qnil),
2214 intangible_propval))
2215 pos = Fprevious_char_property_change (pos, Qnil);
2217 else if (XINT (pos) > BEGV)
2219 /* We want to move backward, so check the text after POSITION. */
2221 intangible_propval = Fget_char_property (make_number (XINT (pos) - 1),
2222 Qintangible, Qnil);
2224 /* If following char is intangible,
2225 skip forward over all chars with matching intangible property. */
2226 if (! NILP (intangible_propval))
2227 while (XINT (pos) < ZV
2228 && EQ (Fget_char_property (pos, Qintangible, Qnil),
2229 intangible_propval))
2230 pos = Fnext_char_property_change (pos, Qnil);
2233 else if (position < BEGV)
2234 position = BEGV;
2235 else if (position > ZV)
2236 position = ZV;
2238 /* If the whole stretch between PT and POSITION isn't intangible,
2239 try moving to POSITION (which means we actually move farther
2240 if POSITION is inside of intangible text). */
2242 if (XINT (pos) != PT)
2243 SET_PT (position);
2246 /* If text at position POS has property PROP, set *VAL to the property
2247 value, *START and *END to the beginning and end of a region that
2248 has the same property, and return 1. Otherwise return 0.
2250 OBJECT is the string or buffer to look for the property in;
2251 nil means the current buffer. */
2254 get_property_and_range (EMACS_INT pos, Lisp_Object prop, Lisp_Object *val,
2255 EMACS_INT *start, EMACS_INT *end, Lisp_Object object)
2257 INTERVAL i, prev, next;
2259 if (NILP (object))
2260 i = find_interval (BUF_INTERVALS (current_buffer), pos);
2261 else if (BUFFERP (object))
2262 i = find_interval (BUF_INTERVALS (XBUFFER (object)), pos);
2263 else if (STRINGP (object))
2264 i = find_interval (STRING_INTERVALS (object), pos);
2265 else
2266 abort ();
2268 if (NULL_INTERVAL_P (i) || (i->position + LENGTH (i) <= pos))
2269 return 0;
2270 *val = textget (i->plist, prop);
2271 if (NILP (*val))
2272 return 0;
2274 next = i; /* remember it in advance */
2275 prev = previous_interval (i);
2276 while (! NULL_INTERVAL_P (prev)
2277 && EQ (*val, textget (prev->plist, prop)))
2278 i = prev, prev = previous_interval (prev);
2279 *start = i->position;
2281 next = next_interval (i);
2282 while (! NULL_INTERVAL_P (next)
2283 && EQ (*val, textget (next->plist, prop)))
2284 i = next, next = next_interval (next);
2285 *end = i->position + LENGTH (i);
2287 return 1;
2290 /* Return the proper local keymap TYPE for position POSITION in
2291 BUFFER; TYPE should be one of `keymap' or `local-map'. Use the map
2292 specified by the PROP property, if any. Otherwise, if TYPE is
2293 `local-map' use BUFFER's local map.
2295 POSITION must be in the accessible part of BUFFER. */
2297 Lisp_Object
2298 get_local_map (register EMACS_INT position, register struct buffer *buffer,
2299 Lisp_Object type)
2301 Lisp_Object prop, lispy_position, lispy_buffer;
2302 EMACS_INT old_begv, old_zv, old_begv_byte, old_zv_byte;
2304 /* Perhaps we should just change `position' to the limit. */
2305 if (position > BUF_ZV (buffer) || position < BUF_BEGV (buffer))
2306 abort ();
2308 /* Ignore narrowing, so that a local map continues to be valid even if
2309 the visible region contains no characters and hence no properties. */
2310 old_begv = BUF_BEGV (buffer);
2311 old_zv = BUF_ZV (buffer);
2312 old_begv_byte = BUF_BEGV_BYTE (buffer);
2313 old_zv_byte = BUF_ZV_BYTE (buffer);
2315 SET_BUF_BEGV_BOTH (buffer, BUF_BEG (buffer), BUF_BEG_BYTE (buffer));
2316 SET_BUF_ZV_BOTH (buffer, BUF_Z (buffer), BUF_Z_BYTE (buffer));
2318 XSETFASTINT (lispy_position, position);
2319 XSETBUFFER (lispy_buffer, buffer);
2320 /* First check if the CHAR has any property. This is because when
2321 we click with the mouse, the mouse pointer is really pointing
2322 to the CHAR after POS. */
2323 prop = Fget_char_property (lispy_position, type, lispy_buffer);
2324 /* If not, look at the POS's properties. This is necessary because when
2325 editing a field with a `local-map' property, we want insertion at the end
2326 to obey the `local-map' property. */
2327 if (NILP (prop))
2328 prop = get_pos_property (lispy_position, type, lispy_buffer);
2330 SET_BUF_BEGV_BOTH (buffer, old_begv, old_begv_byte);
2331 SET_BUF_ZV_BOTH (buffer, old_zv, old_zv_byte);
2333 /* Use the local map only if it is valid. */
2334 prop = get_keymap (prop, 0, 0);
2335 if (CONSP (prop))
2336 return prop;
2338 if (EQ (type, Qkeymap))
2339 return Qnil;
2340 else
2341 return BVAR (buffer, keymap);
2344 /* Produce an interval tree reflecting the intervals in
2345 TREE from START to START + LENGTH.
2346 The new interval tree has no parent and has a starting-position of 0. */
2348 INTERVAL
2349 copy_intervals (INTERVAL tree, EMACS_INT start, EMACS_INT length)
2351 register INTERVAL i, new, t;
2352 register EMACS_INT got, prevlen;
2354 if (NULL_INTERVAL_P (tree) || length <= 0)
2355 return NULL_INTERVAL;
2357 i = find_interval (tree, start);
2358 if (NULL_INTERVAL_P (i) || LENGTH (i) == 0)
2359 abort ();
2361 /* If there is only one interval and it's the default, return nil. */
2362 if ((start - i->position + 1 + length) < LENGTH (i)
2363 && DEFAULT_INTERVAL_P (i))
2364 return NULL_INTERVAL;
2366 new = make_interval ();
2367 new->position = 0;
2368 got = (LENGTH (i) - (start - i->position));
2369 new->total_length = length;
2370 CHECK_TOTAL_LENGTH (new);
2371 copy_properties (i, new);
2373 t = new;
2374 prevlen = got;
2375 while (got < length)
2377 i = next_interval (i);
2378 t = split_interval_right (t, prevlen);
2379 copy_properties (i, t);
2380 prevlen = LENGTH (i);
2381 got += prevlen;
2384 return balance_an_interval (new);
2387 /* Give STRING the properties of BUFFER from POSITION to LENGTH. */
2389 INLINE void
2390 copy_intervals_to_string (Lisp_Object string, struct buffer *buffer,
2391 EMACS_INT position, EMACS_INT length)
2393 INTERVAL interval_copy = copy_intervals (BUF_INTERVALS (buffer),
2394 position, length);
2395 if (NULL_INTERVAL_P (interval_copy))
2396 return;
2398 SET_INTERVAL_OBJECT (interval_copy, string);
2399 STRING_SET_INTERVALS (string, interval_copy);
2402 /* Return 1 if strings S1 and S2 have identical properties; 0 otherwise.
2403 Assume they have identical characters. */
2406 compare_string_intervals (Lisp_Object s1, Lisp_Object s2)
2408 INTERVAL i1, i2;
2409 EMACS_INT pos = 0;
2410 EMACS_INT end = SCHARS (s1);
2412 i1 = find_interval (STRING_INTERVALS (s1), 0);
2413 i2 = find_interval (STRING_INTERVALS (s2), 0);
2415 while (pos < end)
2417 /* Determine how far we can go before we reach the end of I1 or I2. */
2418 EMACS_INT len1 = (i1 != 0 ? INTERVAL_LAST_POS (i1) : end) - pos;
2419 EMACS_INT len2 = (i2 != 0 ? INTERVAL_LAST_POS (i2) : end) - pos;
2420 EMACS_INT distance = min (len1, len2);
2422 /* If we ever find a mismatch between the strings,
2423 they differ. */
2424 if (! intervals_equal (i1, i2))
2425 return 0;
2427 /* Advance POS till the end of the shorter interval,
2428 and advance one or both interval pointers for the new position. */
2429 pos += distance;
2430 if (len1 == distance)
2431 i1 = next_interval (i1);
2432 if (len2 == distance)
2433 i2 = next_interval (i2);
2435 return 1;
2438 /* Recursively adjust interval I in the current buffer
2439 for setting enable_multibyte_characters to MULTI_FLAG.
2440 The range of interval I is START ... END in characters,
2441 START_BYTE ... END_BYTE in bytes. */
2443 static void
2444 set_intervals_multibyte_1 (INTERVAL i, int multi_flag,
2445 EMACS_INT start, EMACS_INT start_byte,
2446 EMACS_INT end, EMACS_INT end_byte)
2448 /* Fix the length of this interval. */
2449 if (multi_flag)
2450 i->total_length = end - start;
2451 else
2452 i->total_length = end_byte - start_byte;
2453 CHECK_TOTAL_LENGTH (i);
2455 if (TOTAL_LENGTH (i) == 0)
2457 delete_interval (i);
2458 return;
2461 /* Recursively fix the length of the subintervals. */
2462 if (i->left)
2464 EMACS_INT left_end, left_end_byte;
2466 if (multi_flag)
2468 EMACS_INT temp;
2469 left_end_byte = start_byte + LEFT_TOTAL_LENGTH (i);
2470 left_end = BYTE_TO_CHAR (left_end_byte);
2472 temp = CHAR_TO_BYTE (left_end);
2474 /* If LEFT_END_BYTE is in the middle of a character,
2475 adjust it and LEFT_END to a char boundary. */
2476 if (left_end_byte > temp)
2478 left_end_byte = temp;
2480 if (left_end_byte < temp)
2482 left_end--;
2483 left_end_byte = CHAR_TO_BYTE (left_end);
2486 else
2488 left_end = start + LEFT_TOTAL_LENGTH (i);
2489 left_end_byte = CHAR_TO_BYTE (left_end);
2492 set_intervals_multibyte_1 (i->left, multi_flag, start, start_byte,
2493 left_end, left_end_byte);
2495 if (i->right)
2497 EMACS_INT right_start_byte, right_start;
2499 if (multi_flag)
2501 EMACS_INT temp;
2503 right_start_byte = end_byte - RIGHT_TOTAL_LENGTH (i);
2504 right_start = BYTE_TO_CHAR (right_start_byte);
2506 /* If RIGHT_START_BYTE is in the middle of a character,
2507 adjust it and RIGHT_START to a char boundary. */
2508 temp = CHAR_TO_BYTE (right_start);
2510 if (right_start_byte < temp)
2512 right_start_byte = temp;
2514 if (right_start_byte > temp)
2516 right_start++;
2517 right_start_byte = CHAR_TO_BYTE (right_start);
2520 else
2522 right_start = end - RIGHT_TOTAL_LENGTH (i);
2523 right_start_byte = CHAR_TO_BYTE (right_start);
2526 set_intervals_multibyte_1 (i->right, multi_flag,
2527 right_start, right_start_byte,
2528 end, end_byte);
2531 /* Rounding to char boundaries can theoretically ake this interval
2532 spurious. If so, delete one child, and copy its property list
2533 to this interval. */
2534 if (LEFT_TOTAL_LENGTH (i) + RIGHT_TOTAL_LENGTH (i) >= TOTAL_LENGTH (i))
2536 if ((i)->left)
2538 (i)->plist = (i)->left->plist;
2539 (i)->left->total_length = 0;
2540 delete_interval ((i)->left);
2542 else
2544 (i)->plist = (i)->right->plist;
2545 (i)->right->total_length = 0;
2546 delete_interval ((i)->right);
2551 /* Update the intervals of the current buffer
2552 to fit the contents as multibyte (if MULTI_FLAG is 1)
2553 or to fit them as non-multibyte (if MULTI_FLAG is 0). */
2555 void
2556 set_intervals_multibyte (int multi_flag)
2558 if (BUF_INTERVALS (current_buffer))
2559 set_intervals_multibyte_1 (BUF_INTERVALS (current_buffer), multi_flag,
2560 BEG, BEG_BYTE, Z, Z_BYTE);