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33 * $FreeBSD: src/sys/libkern/bcmp.c,v 1.6 1999/08/28 00:46:31 peter Exp $
34 * $DragonFly: src/sys/libkern/bcmp.c,v 1.4 2005/01/04 05:27:47 cpressey Exp $
38 #include <machine/endian.h>
40 typedef const void *cvp
;
41 typedef const unsigned char *ustring
;
42 typedef unsigned long ul
;
43 typedef const unsigned long *culp
;
46 * bcmp -- vax cmpc3 instruction
49 bcmp(const void *b1
, const void *b2
, size_t length
)
51 #if BYTE_ORDER == LITTLE_ENDIAN
53 * The following code is endian specific. Changing it from
54 * little-endian to big-endian is fairly trivial, but making
55 * it do both is more difficult.
57 * Note that this code will reference the entire longword which
58 * includes the final byte to compare. I don't believe this is
59 * a problem since AFAIK, objects are not protected at smaller
60 * than longword boundaries.
62 int shl
, shr
, len
= length
;
63 ustring p1
= b1
, p2
= b2
;
70 * align p1 to a longword boundary
72 while ((long)p1
& (sizeof(long) - 1)) {
80 * align p2 to longword boundary and calculate the shift required to
83 shr
= (long)p2
& (sizeof(long) - 1);
85 p2
-= shr
; /* p2 now longword aligned */
86 shr
<<= 3; /* offset in bits */
87 shl
= (sizeof(long) << 3) - shr
;
92 while ((len
-= sizeof(long)) >= 0) {
95 if (*(culp
)p1
!= (va
>> shr
| vb
<< shl
))
101 * At this point, len is between -sizeof(long) and -1,
102 * representing 0 .. sizeof(long)-1 bytes remaining.
104 if (!(len
+= sizeof(long)))
107 len
<<= 3; /* remaining length in bits */
109 * The following is similar to the `if' condition
110 * inside the above while loop. The ?: is necessary
111 * to avoid accessing the longword after the longword
112 * containing the last byte to be compared.
114 return ((((va
>> shr
| ((shl
< len
) ? *(culp
)p2
<< shl
: 0)) ^
115 *(culp
)p1
) & ((1L << len
) - 1)) != 0);
117 /* p1 and p2 have common alignment so no shifting needed */
118 while ((len
-= sizeof(long)) >= 0) {
119 if (*(culp
)p1
!= *(culp
)p2
)
126 * At this point, len is between -sizeof(long) and -1,
127 * representing 0 .. sizeof(long)-1 bytes remaining.
129 if (!(len
+= sizeof(long)))
132 return (((*(culp
)p1
^ *(culp
)p2
)
133 & ((1L << (len
<< 3)) - 1)) != 0);