mdate-sh

   1 #!/bin/sh
   2 # mdate-sh - get modifaction time of a file and pretty-print it
   3 # Copyright (C) 1995 Software Foundation, Inc.
   4 # written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
   5 #
   6 # This program is free software; you can redistribute it and/or modify
   7 # it under the terms of the GNU General Public License as published by
   8 # the Free Software Foundation; either version 2, or (at your option)
   9 # any later version.
  10 #
  11 # This program is distributed in the hope that it will be useful,
  12 # but WITHOUT ANY WARRANTY; without even the implied warranty of
  13 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
  14 # GNU General Public License for more details.
  15 #
  16 # You should have received a copy of the GNU General Public License
  17 # along with this program; if not, write to the Free Software
  18 # Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
  19
  20 # Prevent date giving response in another language
  21 LANG=C
  22 export LANG
  23 LC_ALL=C
  24 export LC_ALL
  25 LC_TIME=C
  26 export LC_TIME
  27
  28 # Get the extended ls output of the file
  29 if ls -L /dev/null 1>/dev/null 2>&1; then
  30   set - `ls -L -l $1`
  31 else
  32   set - `ls -l $1`
  33 fi
  34 # The month is at least the fourth argument
  35 # (3 shifts here, the next inside the loop)
  36 shift
  37 shift
  38 shift
  39
  40 # Find the month.  Next argument is day, followed by the year or time
  41 month=
  42 until test $month
  43 do
  44   shift
  45   case $1 in
  46     Jan) month=January; nummonth=1;;
  47     Feb) month=February; nummonth=2;;
  48     Mar) month=March; nummonth=3;;
  49     Apr) month=April; nummonth=4;;
  50     May) month=May; nummonth=5;;
  51     Jun) month=June; nummonth=6;;
  52     Jul) month=July; nummonth=7;;
  53     Aug) month=August; nummonth=8;;
  54     Sep) month=September; nummonth=9;;
  55     Oct) month=October; nummonth=10;;
  56     Nov) month=November; nummonth=11;;
  57     Dec) month=December; nummonth=12;;
  58   esac
  59 done
  60
  61 day=$2
  62
  63 # Here we have to deal with the problem that the ls output gives either
  64 # the time of day or the year.
  65 case $3 in
  66   *:*) set `date`; year=$7
  67        case $2 in
  68          Jan) nummonthtod=1;;
  69          Feb) nummonthtod=2;;
  70          Mar) nummonthtod=3;;
  71          Apr) nummonthtod=4;;
  72          May) nummonthtod=5;;
  73          Jun) nummonthtod=6;;
  74          Jul) nummonthtod=7;;
  75          Aug) nummonthtod=8;;
  76          Sep) nummonthtod=9;;
  77          Oct) nummonthtod=10;;
  78          Nov) nummonthtod=11;;
  79          Dec) nummonthtod=12;;
  80        esac
  81        # For the first six month of the year the time notation can also
  82        # be used for file modified in the last year.
  83        if (expr $nummonth \> $nummonthtod) > /dev/null;
  84        then
  85          year=`expr year - 1`
  86        fi
  87        ;;
  88   *) year=$3;;
  89 esac
  90
  91 # The result.
  92 echo $day $month $year