t7800: use single quotes for test bodies
[alt-git.git] / xdiff / xpatience.c
bloba2d8955537f566458b6e912ff5fb8496fa7fe85a
1 /*
2 * LibXDiff by Davide Libenzi ( File Differential Library )
3 * Copyright (C) 2003-2016 Davide Libenzi, Johannes E. Schindelin
5 * This library is free software; you can redistribute it and/or
6 * modify it under the terms of the GNU Lesser General Public
7 * License as published by the Free Software Foundation; either
8 * version 2.1 of the License, or (at your option) any later version.
10 * This library is distributed in the hope that it will be useful,
11 * but WITHOUT ANY WARRANTY; without even the implied warranty of
12 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
13 * Lesser General Public License for more details.
15 * You should have received a copy of the GNU Lesser General Public
16 * License along with this library; if not, see
17 * <http://www.gnu.org/licenses/>.
19 * Davide Libenzi <davidel@xmailserver.org>
22 #include "xinclude.h"
25 * The basic idea of patience diff is to find lines that are unique in
26 * both files. These are intuitively the ones that we want to see as
27 * common lines.
29 * The maximal ordered sequence of such line pairs (where ordered means
30 * that the order in the sequence agrees with the order of the lines in
31 * both files) naturally defines an initial set of common lines.
33 * Now, the algorithm tries to extend the set of common lines by growing
34 * the line ranges where the files have identical lines.
36 * Between those common lines, the patience diff algorithm is applied
37 * recursively, until no unique line pairs can be found; these line ranges
38 * are handled by the well-known Myers algorithm.
41 #define NON_UNIQUE ULONG_MAX
44 * This is a hash mapping from line hash to line numbers in the first and
45 * second file.
47 struct hashmap {
48 int nr, alloc;
49 struct entry {
50 unsigned long hash;
52 * 0 = unused entry, 1 = first line, 2 = second, etc.
53 * line2 is NON_UNIQUE if the line is not unique
54 * in either the first or the second file.
56 unsigned long line1, line2;
58 * "next" & "previous" are used for the longest common
59 * sequence;
60 * initially, "next" reflects only the order in file1.
62 struct entry *next, *previous;
65 * If 1, this entry can serve as an anchor. See
66 * Documentation/diff-options.txt for more information.
68 unsigned anchor : 1;
69 } *entries, *first, *last;
70 /* were common records found? */
71 unsigned long has_matches;
72 xdfenv_t *env;
73 xpparam_t const *xpp;
76 static int is_anchor(xpparam_t const *xpp, const char *line)
78 int i;
79 for (i = 0; i < xpp->anchors_nr; i++) {
80 if (!strncmp(line, xpp->anchors[i], strlen(xpp->anchors[i])))
81 return 1;
83 return 0;
86 /* The argument "pass" is 1 for the first file, 2 for the second. */
87 static void insert_record(xpparam_t const *xpp, int line, struct hashmap *map,
88 int pass)
90 xrecord_t **records = pass == 1 ?
91 map->env->xdf1.recs : map->env->xdf2.recs;
92 xrecord_t *record = records[line - 1];
94 * After xdl_prepare_env() (or more precisely, due to
95 * xdl_classify_record()), the "ha" member of the records (AKA lines)
96 * is _not_ the hash anymore, but a linearized version of it. In
97 * other words, the "ha" member is guaranteed to start with 0 and
98 * the second record's ha can only be 0 or 1, etc.
100 * So we multiply ha by 2 in the hope that the hashing was
101 * "unique enough".
103 int index = (int)((record->ha << 1) % map->alloc);
105 while (map->entries[index].line1) {
106 if (map->entries[index].hash != record->ha) {
107 if (++index >= map->alloc)
108 index = 0;
109 continue;
111 if (pass == 2)
112 map->has_matches = 1;
113 if (pass == 1 || map->entries[index].line2)
114 map->entries[index].line2 = NON_UNIQUE;
115 else
116 map->entries[index].line2 = line;
117 return;
119 if (pass == 2)
120 return;
121 map->entries[index].line1 = line;
122 map->entries[index].hash = record->ha;
123 map->entries[index].anchor = is_anchor(xpp, map->env->xdf1.recs[line - 1]->ptr);
124 if (!map->first)
125 map->first = map->entries + index;
126 if (map->last) {
127 map->last->next = map->entries + index;
128 map->entries[index].previous = map->last;
130 map->last = map->entries + index;
131 map->nr++;
135 * This function has to be called for each recursion into the inter-hunk
136 * parts, as previously non-unique lines can become unique when being
137 * restricted to a smaller part of the files.
139 * It is assumed that env has been prepared using xdl_prepare().
141 static int fill_hashmap(xpparam_t const *xpp, xdfenv_t *env,
142 struct hashmap *result,
143 int line1, int count1, int line2, int count2)
145 result->xpp = xpp;
146 result->env = env;
148 /* We know exactly how large we want the hash map */
149 result->alloc = count1 * 2;
150 if (!XDL_CALLOC_ARRAY(result->entries, result->alloc))
151 return -1;
153 /* First, fill with entries from the first file */
154 while (count1--)
155 insert_record(xpp, line1++, result, 1);
157 /* Then search for matches in the second file */
158 while (count2--)
159 insert_record(xpp, line2++, result, 2);
161 return 0;
165 * Find the longest sequence with a smaller last element (meaning a smaller
166 * line2, as we construct the sequence with entries ordered by line1).
168 static int binary_search(struct entry **sequence, int longest,
169 struct entry *entry)
171 int left = -1, right = longest;
173 while (left + 1 < right) {
174 int middle = left + (right - left) / 2;
175 /* by construction, no two entries can be equal */
176 if (sequence[middle]->line2 > entry->line2)
177 right = middle;
178 else
179 left = middle;
181 /* return the index in "sequence", _not_ the sequence length */
182 return left;
186 * The idea is to start with the list of common unique lines sorted by
187 * the order in file1. For each of these pairs, the longest (partial)
188 * sequence whose last element's line2 is smaller is determined.
190 * For efficiency, the sequences are kept in a list containing exactly one
191 * item per sequence length: the sequence with the smallest last
192 * element (in terms of line2).
194 static int find_longest_common_sequence(struct hashmap *map, struct entry **res)
196 struct entry **sequence;
197 int longest = 0, i;
198 struct entry *entry;
201 * If not -1, this entry in sequence must never be overridden.
202 * Therefore, overriding entries before this has no effect, so
203 * do not do that either.
205 int anchor_i = -1;
207 if (!XDL_ALLOC_ARRAY(sequence, map->nr))
208 return -1;
210 for (entry = map->first; entry; entry = entry->next) {
211 if (!entry->line2 || entry->line2 == NON_UNIQUE)
212 continue;
213 i = binary_search(sequence, longest, entry);
214 entry->previous = i < 0 ? NULL : sequence[i];
215 ++i;
216 if (i <= anchor_i)
217 continue;
218 sequence[i] = entry;
219 if (entry->anchor) {
220 anchor_i = i;
221 longest = anchor_i + 1;
222 } else if (i == longest) {
223 longest++;
227 /* No common unique lines were found */
228 if (!longest) {
229 *res = NULL;
230 xdl_free(sequence);
231 return 0;
234 /* Iterate starting at the last element, adjusting the "next" members */
235 entry = sequence[longest - 1];
236 entry->next = NULL;
237 while (entry->previous) {
238 entry->previous->next = entry;
239 entry = entry->previous;
241 *res = entry;
242 xdl_free(sequence);
243 return 0;
246 static int match(struct hashmap *map, int line1, int line2)
248 xrecord_t *record1 = map->env->xdf1.recs[line1 - 1];
249 xrecord_t *record2 = map->env->xdf2.recs[line2 - 1];
250 return record1->ha == record2->ha;
253 static int patience_diff(xpparam_t const *xpp, xdfenv_t *env,
254 int line1, int count1, int line2, int count2);
256 static int walk_common_sequence(struct hashmap *map, struct entry *first,
257 int line1, int count1, int line2, int count2)
259 int end1 = line1 + count1, end2 = line2 + count2;
260 int next1, next2;
262 for (;;) {
263 /* Try to grow the line ranges of common lines */
264 if (first) {
265 next1 = first->line1;
266 next2 = first->line2;
267 while (next1 > line1 && next2 > line2 &&
268 match(map, next1 - 1, next2 - 1)) {
269 next1--;
270 next2--;
272 } else {
273 next1 = end1;
274 next2 = end2;
276 while (line1 < next1 && line2 < next2 &&
277 match(map, line1, line2)) {
278 line1++;
279 line2++;
282 /* Recurse */
283 if (next1 > line1 || next2 > line2) {
284 if (patience_diff(map->xpp, map->env,
285 line1, next1 - line1,
286 line2, next2 - line2))
287 return -1;
290 if (!first)
291 return 0;
293 while (first->next &&
294 first->next->line1 == first->line1 + 1 &&
295 first->next->line2 == first->line2 + 1)
296 first = first->next;
298 line1 = first->line1 + 1;
299 line2 = first->line2 + 1;
301 first = first->next;
305 static int fall_back_to_classic_diff(struct hashmap *map,
306 int line1, int count1, int line2, int count2)
308 xpparam_t xpp;
310 memset(&xpp, 0, sizeof(xpp));
311 xpp.flags = map->xpp->flags & ~XDF_DIFF_ALGORITHM_MASK;
313 return xdl_fall_back_diff(map->env, &xpp,
314 line1, count1, line2, count2);
318 * Recursively find the longest common sequence of unique lines,
319 * and if none was found, ask xdl_do_diff() to do the job.
321 * This function assumes that env was prepared with xdl_prepare_env().
323 static int patience_diff(xpparam_t const *xpp, xdfenv_t *env,
324 int line1, int count1, int line2, int count2)
326 struct hashmap map;
327 struct entry *first;
328 int result = 0;
330 /* trivial case: one side is empty */
331 if (!count1) {
332 while(count2--)
333 env->xdf2.rchg[line2++ - 1] = 1;
334 return 0;
335 } else if (!count2) {
336 while(count1--)
337 env->xdf1.rchg[line1++ - 1] = 1;
338 return 0;
341 memset(&map, 0, sizeof(map));
342 if (fill_hashmap(xpp, env, &map,
343 line1, count1, line2, count2))
344 return -1;
346 /* are there any matching lines at all? */
347 if (!map.has_matches) {
348 while(count1--)
349 env->xdf1.rchg[line1++ - 1] = 1;
350 while(count2--)
351 env->xdf2.rchg[line2++ - 1] = 1;
352 xdl_free(map.entries);
353 return 0;
356 result = find_longest_common_sequence(&map, &first);
357 if (result)
358 goto out;
359 if (first)
360 result = walk_common_sequence(&map, first,
361 line1, count1, line2, count2);
362 else
363 result = fall_back_to_classic_diff(&map,
364 line1, count1, line2, count2);
365 out:
366 xdl_free(map.entries);
367 return result;
370 int xdl_do_patience_diff(xpparam_t const *xpp, xdfenv_t *env)
372 return patience_diff(xpp, env, 1, env->xdf1.nrec, 1, env->xdf2.nrec);