2 Copyright © 1995-2012, The AROS Development Team. All rights reserved.
5 C99 function strtoull().
8 /* This function requires the use of the long long type. */
9 #include <aros/system.h>
10 #if defined(AROS_HAVE_LONG_LONG)
15 #ifndef AROS_NO_LIMITS_H
18 # define ULLONG_MAX 0xffffffffffffffffULL
21 /*****************************************************************************
26 unsigned long long strtoull (
29 const char * restrict str
,
30 char ** restrict endptr
,
34 Convert a string of digits into an integer according to the
38 str - The string which should be converted. Leading
39 whitespace are ignored. The number may be prefixed
40 by a '+' or '-'. If base is above 10, then the
41 alphabetic characters from 'A' are used to specify
42 digits above 9 (ie. 'A' or 'a' is 10, 'B' or 'b' is
43 11 and so on until 'Z' or 'z' is 35).
44 endptr - If this is non-NULL, then the address of the first
45 character after the number in the string is stored
47 base - The base for the number. May be 0 or between 2 and 36,
48 including both. 0 means to autodetect the base. strtoull()
49 selects the base by inspecting the first characters
50 of the string. If they are "0x", then base 16 is
51 assumed. If they are "0", then base 8 is assumed. Any
52 other digit will assume base 10. This is like in C.
54 If you give base 16, then an optional "0x" may
55 precede the number in the string.
58 The value of the string. The first character after the number
59 is returned in *endptr, if endptr is non-NULL. If no digits can
60 be converted, *endptr contains str (if non-NULL) and 0 is
66 // Returns 1, ptr points to the 0-Byte
67 strtoull (" \t +0x1", &ptr, 0);
69 // Returns 15. ptr points to the a
70 strtoull ("017a", &ptr, 0);
72 // Returns 215 (5*36 + 35)
73 strtoull ("5z", &ptr, 36);
82 ******************************************************************************/
84 unsigned long long val
= 0;
87 unsigned long long cutoff
;
91 if (base
< 0 || base
== 1 || base
> 36)
97 *endptr
= (char *)str
;
102 while (isspace (*str
))
107 if (*str
== '+' || *str
== '-')
111 if (base
== 0 || base
== 16)
113 if (*str
== '0') /* Base 8 or 16 */
116 if (*str
== 'x' || *str
== 'X')
124 else if(base
== 0) /* Any other digit: Base 10 (decimal) */
129 Conversion loop, from FreeBSD's src/lib/libc/stdlib/strtoull.c
131 The previous AROS loop was
132 a) inefficient - it did a division each time around.
133 b) buggy - it returned the wrong value in endptr on overflow.
135 cutoff
= (unsigned long long)ULLONG_MAX
/ (unsigned long long)base
;
136 cutlim
= (unsigned long long)ULLONG_MAX
% (unsigned long long)base
;
149 else if (isalpha(digit
))
150 digit
-= isupper(digit
) ? 'A' - 10 : 'a' - 10;
158 any < 0 when we have overflowed. We still need to find the
159 end of the subject sequence
161 if (any
< 0 || val
> cutoff
|| (val
== cutoff
&& digit
> cutlim
))
168 val
= (val
* base
) + digit
;
188 *endptr
= (char *)str
;
193 #endif /* AROS_HAVE_LONG_LONG */