S390: Ifunc resolver macro for vector instructions.
[glibc.git] / string / rawmemchr.c
blob228ca9d216d2361825f6a91f1870b6000fe5baef
1 /* Copyright (C) 1991-2015 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
3 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
4 with help from Dan Sahlin (dan@sics.se) and
5 commentary by Jim Blandy (jimb@ai.mit.edu);
6 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
7 and implemented by Roland McGrath (roland@ai.mit.edu).
9 The GNU C Library is free software; you can redistribute it and/or
10 modify it under the terms of the GNU Lesser General Public
11 License as published by the Free Software Foundation; either
12 version 2.1 of the License, or (at your option) any later version.
14 The GNU C Library is distributed in the hope that it will be useful,
15 but WITHOUT ANY WARRANTY; without even the implied warranty of
16 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
17 Lesser General Public License for more details.
19 You should have received a copy of the GNU Lesser General Public
20 License along with the GNU C Library; if not, see
21 <http://www.gnu.org/licenses/>. */
23 #ifdef HAVE_CONFIG_H
24 #include <config.h>
25 #endif
27 #undef __ptr_t
28 #define __ptr_t void *
30 #if defined (_LIBC)
31 # include <string.h>
32 # include <memcopy.h>
33 # include <stdlib.h>
34 #endif
36 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
37 # include <limits.h>
38 #endif
40 #define LONG_MAX_32_BITS 2147483647
42 #ifndef LONG_MAX
43 #define LONG_MAX LONG_MAX_32_BITS
44 #endif
46 #include <sys/types.h>
48 #undef memchr
50 #ifndef RAWMEMCHR
51 # define RAWMEMCHR __rawmemchr
52 #endif
54 /* Find the first occurrence of C in S. */
55 __ptr_t
56 RAWMEMCHR (s, c_in)
57 const __ptr_t s;
58 int c_in;
60 const unsigned char *char_ptr;
61 const unsigned long int *longword_ptr;
62 unsigned long int longword, magic_bits, charmask;
63 unsigned char c;
65 c = (unsigned char) c_in;
67 /* Handle the first few characters by reading one character at a time.
68 Do this until CHAR_PTR is aligned on a longword boundary. */
69 for (char_ptr = (const unsigned char *) s;
70 ((unsigned long int) char_ptr & (sizeof (longword) - 1)) != 0;
71 ++char_ptr)
72 if (*char_ptr == c)
73 return (__ptr_t) char_ptr;
75 /* All these elucidatory comments refer to 4-byte longwords,
76 but the theory applies equally well to 8-byte longwords. */
78 longword_ptr = (unsigned long int *) char_ptr;
80 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
81 the "holes." Note that there is a hole just to the left of
82 each byte, with an extra at the end:
84 bits: 01111110 11111110 11111110 11111111
85 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
87 The 1-bits make sure that carries propagate to the next 0-bit.
88 The 0-bits provide holes for carries to fall into. */
89 magic_bits = -1;
90 magic_bits = magic_bits / 0xff * 0xfe << 1 >> 1 | 1;
92 /* Set up a longword, each of whose bytes is C. */
93 charmask = c | (c << 8);
94 charmask |= charmask << 16;
95 #if LONG_MAX > LONG_MAX_32_BITS
96 charmask |= charmask << 32;
97 #endif
99 /* Instead of the traditional loop which tests each character,
100 we will test a longword at a time. The tricky part is testing
101 if *any of the four* bytes in the longword in question are zero. */
102 while (1)
104 /* We tentatively exit the loop if adding MAGIC_BITS to
105 LONGWORD fails to change any of the hole bits of LONGWORD.
107 1) Is this safe? Will it catch all the zero bytes?
108 Suppose there is a byte with all zeros. Any carry bits
109 propagating from its left will fall into the hole at its
110 least significant bit and stop. Since there will be no
111 carry from its most significant bit, the LSB of the
112 byte to the left will be unchanged, and the zero will be
113 detected.
115 2) Is this worthwhile? Will it ignore everything except
116 zero bytes? Suppose every byte of LONGWORD has a bit set
117 somewhere. There will be a carry into bit 8. If bit 8
118 is set, this will carry into bit 16. If bit 8 is clear,
119 one of bits 9-15 must be set, so there will be a carry
120 into bit 16. Similarly, there will be a carry into bit
121 24. If one of bits 24-30 is set, there will be a carry
122 into bit 31, so all of the hole bits will be changed.
124 The one misfire occurs when bits 24-30 are clear and bit
125 31 is set; in this case, the hole at bit 31 is not
126 changed. If we had access to the processor carry flag,
127 we could close this loophole by putting the fourth hole
128 at bit 32!
130 So it ignores everything except 128's, when they're aligned
131 properly.
133 3) But wait! Aren't we looking for C, not zero?
134 Good point. So what we do is XOR LONGWORD with a longword,
135 each of whose bytes is C. This turns each byte that is C
136 into a zero. */
138 longword = *longword_ptr++ ^ charmask;
140 /* Add MAGIC_BITS to LONGWORD. */
141 if ((((longword + magic_bits)
143 /* Set those bits that were unchanged by the addition. */
144 ^ ~longword)
146 /* Look at only the hole bits. If any of the hole bits
147 are unchanged, most likely one of the bytes was a
148 zero. */
149 & ~magic_bits) != 0)
151 /* Which of the bytes was C? If none of them were, it was
152 a misfire; continue the search. */
154 const unsigned char *cp = (const unsigned char *) (longword_ptr - 1);
156 if (cp[0] == c)
157 return (__ptr_t) cp;
158 if (cp[1] == c)
159 return (__ptr_t) &cp[1];
160 if (cp[2] == c)
161 return (__ptr_t) &cp[2];
162 if (cp[3] == c)
163 return (__ptr_t) &cp[3];
164 #if LONG_MAX > 2147483647
165 if (cp[4] == c)
166 return (__ptr_t) &cp[4];
167 if (cp[5] == c)
168 return (__ptr_t) &cp[5];
169 if (cp[6] == c)
170 return (__ptr_t) &cp[6];
171 if (cp[7] == c)
172 return (__ptr_t) &cp[7];
173 #endif
177 libc_hidden_def (__rawmemchr)
178 weak_alias (__rawmemchr, rawmemchr)