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[glibc.git] / string / rawmemchr.c
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1 /* Copyright (C) 1991-2014 Free Software Foundation, Inc.
2 This file is part of the GNU C Library.
3 Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
4 with help from Dan Sahlin (dan@sics.se) and
5 commentary by Jim Blandy (jimb@ai.mit.edu);
6 adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
7 and implemented by Roland McGrath (roland@ai.mit.edu).
9 The GNU C Library is free software; you can redistribute it and/or
10 modify it under the terms of the GNU Lesser General Public
11 License as published by the Free Software Foundation; either
12 version 2.1 of the License, or (at your option) any later version.
14 The GNU C Library is distributed in the hope that it will be useful,
15 but WITHOUT ANY WARRANTY; without even the implied warranty of
16 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
17 Lesser General Public License for more details.
19 You should have received a copy of the GNU Lesser General Public
20 License along with the GNU C Library; if not, see
21 <http://www.gnu.org/licenses/>. */
23 #ifdef HAVE_CONFIG_H
24 #include <config.h>
25 #endif
27 #undef __ptr_t
28 #define __ptr_t void *
30 #if defined (_LIBC)
31 # include <string.h>
32 # include <memcopy.h>
33 # include <stdlib.h>
34 #endif
36 #if defined (HAVE_LIMITS_H) || defined (_LIBC)
37 # include <limits.h>
38 #endif
40 #define LONG_MAX_32_BITS 2147483647
42 #ifndef LONG_MAX
43 #define LONG_MAX LONG_MAX_32_BITS
44 #endif
46 #include <sys/types.h>
48 #undef memchr
50 #ifndef RAWMEMCHR
51 # define RAWMEMCHR __rawmemchr
52 #endif
54 /* Find the first occurrence of C in S. */
55 __ptr_t
56 RAWMEMCHR (s, c_in)
57 const __ptr_t s;
58 int c_in;
60 const unsigned char *char_ptr;
61 const unsigned long int *longword_ptr;
62 unsigned long int longword, magic_bits, charmask;
63 unsigned char c;
65 c = (unsigned char) c_in;
67 /* Handle the first few characters by reading one character at a time.
68 Do this until CHAR_PTR is aligned on a longword boundary. */
69 for (char_ptr = (const unsigned char *) s;
70 ((unsigned long int) char_ptr & (sizeof (longword) - 1)) != 0;
71 ++char_ptr)
72 if (*char_ptr == c)
73 return (__ptr_t) char_ptr;
75 /* All these elucidatory comments refer to 4-byte longwords,
76 but the theory applies equally well to 8-byte longwords. */
78 longword_ptr = (unsigned long int *) char_ptr;
80 /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits
81 the "holes." Note that there is a hole just to the left of
82 each byte, with an extra at the end:
84 bits: 01111110 11111110 11111110 11111111
85 bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
87 The 1-bits make sure that carries propagate to the next 0-bit.
88 The 0-bits provide holes for carries to fall into. */
90 if (sizeof (longword) != 4 && sizeof (longword) != 8)
91 abort ();
93 #if LONG_MAX <= LONG_MAX_32_BITS
94 magic_bits = 0x7efefeff;
95 #else
96 magic_bits = ((unsigned long int) 0x7efefefe << 32) | 0xfefefeff;
97 #endif
99 /* Set up a longword, each of whose bytes is C. */
100 charmask = c | (c << 8);
101 charmask |= charmask << 16;
102 #if LONG_MAX > LONG_MAX_32_BITS
103 charmask |= charmask << 32;
104 #endif
106 /* Instead of the traditional loop which tests each character,
107 we will test a longword at a time. The tricky part is testing
108 if *any of the four* bytes in the longword in question are zero. */
109 while (1)
111 /* We tentatively exit the loop if adding MAGIC_BITS to
112 LONGWORD fails to change any of the hole bits of LONGWORD.
114 1) Is this safe? Will it catch all the zero bytes?
115 Suppose there is a byte with all zeros. Any carry bits
116 propagating from its left will fall into the hole at its
117 least significant bit and stop. Since there will be no
118 carry from its most significant bit, the LSB of the
119 byte to the left will be unchanged, and the zero will be
120 detected.
122 2) Is this worthwhile? Will it ignore everything except
123 zero bytes? Suppose every byte of LONGWORD has a bit set
124 somewhere. There will be a carry into bit 8. If bit 8
125 is set, this will carry into bit 16. If bit 8 is clear,
126 one of bits 9-15 must be set, so there will be a carry
127 into bit 16. Similarly, there will be a carry into bit
128 24. If one of bits 24-30 is set, there will be a carry
129 into bit 31, so all of the hole bits will be changed.
131 The one misfire occurs when bits 24-30 are clear and bit
132 31 is set; in this case, the hole at bit 31 is not
133 changed. If we had access to the processor carry flag,
134 we could close this loophole by putting the fourth hole
135 at bit 32!
137 So it ignores everything except 128's, when they're aligned
138 properly.
140 3) But wait! Aren't we looking for C, not zero?
141 Good point. So what we do is XOR LONGWORD with a longword,
142 each of whose bytes is C. This turns each byte that is C
143 into a zero. */
145 longword = *longword_ptr++ ^ charmask;
147 /* Add MAGIC_BITS to LONGWORD. */
148 if ((((longword + magic_bits)
150 /* Set those bits that were unchanged by the addition. */
151 ^ ~longword)
153 /* Look at only the hole bits. If any of the hole bits
154 are unchanged, most likely one of the bytes was a
155 zero. */
156 & ~magic_bits) != 0)
158 /* Which of the bytes was C? If none of them were, it was
159 a misfire; continue the search. */
161 const unsigned char *cp = (const unsigned char *) (longword_ptr - 1);
163 if (cp[0] == c)
164 return (__ptr_t) cp;
165 if (cp[1] == c)
166 return (__ptr_t) &cp[1];
167 if (cp[2] == c)
168 return (__ptr_t) &cp[2];
169 if (cp[3] == c)
170 return (__ptr_t) &cp[3];
171 #if LONG_MAX > 2147483647
172 if (cp[4] == c)
173 return (__ptr_t) &cp[4];
174 if (cp[5] == c)
175 return (__ptr_t) &cp[5];
176 if (cp[6] == c)
177 return (__ptr_t) &cp[6];
178 if (cp[7] == c)
179 return (__ptr_t) &cp[7];
180 #endif
184 libc_hidden_def (__rawmemchr)
185 weak_alias (__rawmemchr, rawmemchr)