2 * ====================================================
3 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
5 * Developed at SunPro, a Sun Microsystems, Inc. business.
6 * Permission to use, copy, modify, and distribute this
7 * software is freely granted, provided that this notice
9 * ====================================================
12 /* Modifications for 128-bit long double are
13 Copyright (C) 2001 Stephen L. Moshier <moshier@na-net.ornl.gov>
14 and are incorporated herein by permission of the author. The author
15 reserves the right to distribute this material elsewhere under different
16 copying permissions. These modifications are distributed here under
19 This library is free software; you can redistribute it and/or
20 modify it under the terms of the GNU Lesser General Public
21 License as published by the Free Software Foundation; either
22 version 2.1 of the License, or (at your option) any later version.
24 This library is distributed in the hope that it will be useful,
25 but WITHOUT ANY WARRANTY; without even the implied warranty of
26 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
27 Lesser General Public License for more details.
29 You should have received a copy of the GNU Lesser General Public
30 License along with this library; if not, see
31 <http://www.gnu.org/licenses/>. */
34 * __ieee754_jn(n, x), __ieee754_yn(n, x)
35 * floating point Bessel's function of the 1st and 2nd kind
39 * y0(0)=y1(0)=yn(n,0) = -inf with division by zero signal;
40 * y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal.
41 * Note 2. About jn(n,x), yn(n,x)
42 * For n=0, j0(x) is called,
43 * for n=1, j1(x) is called,
44 * for n<x, forward recursion us used starting
45 * from values of j0(x) and j1(x).
46 * for n>x, a continued fraction approximation to
47 * j(n,x)/j(n-1,x) is evaluated and then backward
48 * recursion is used starting from a supposed value
49 * for j(n,x). The resulting value of j(0,x) is
50 * compared with the actual value to correct the
51 * supposed value of j(n,x).
53 * yn(n,x) is similar in all respects, except
54 * that forward recursion is used for all
60 #include "math_private.h"
62 static const long double
63 invsqrtpi
= 5.6418958354775628694807945156077258584405E-1L,
70 __ieee754_jnl (int n
, long double x
)
74 long double a
, b
, temp
, di
;
76 ieee854_long_double_shape_type u
;
79 /* J(-n,x) = (-1)^n * J(n, x), J(n, -x) = (-1)^n * J(n, x)
80 * Thus, J(-n,x) = J(n,-x)
87 /* if J(n,NaN) is NaN */
90 if ((u
.parts32
.w0
& 0xfffff) | u
.parts32
.w1
91 | (u
.parts32
.w2
& 0x7fffffff) | u
.parts32
.w3
)
102 return (__ieee754_j0l (x
));
104 return (__ieee754_j1l (x
));
105 sgn
= (n
& 1) & (se
>> 31); /* even n -- 0, odd n -- sign(x) */
108 if (x
== 0.0L || ix
>= 0x7ff00000) /* if x is 0 or inf */
110 else if ((long double) n
<= x
)
112 /* Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x) */
113 if (ix
>= 0x52d00000)
116 /* ??? Could use an expansion for large x here. */
119 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
120 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
121 * Let s=sin(x), c=cos(x),
122 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
124 * n sin(xn)*sqt2 cos(xn)*sqt2
125 * ----------------------------------
133 __sincosl (x
, &s
, &c
);
149 b
= invsqrtpi
* temp
/ __ieee754_sqrtl (x
);
153 a
= __ieee754_j0l (x
);
154 b
= __ieee754_j1l (x
);
155 for (i
= 1; i
< n
; i
++)
158 b
= b
* ((long double) (i
+ i
) / x
) - a
; /* avoid underflow */
167 /* x is tiny, return the first Taylor expansion of J(n,x)
168 * J(n,x) = 1/n!*(x/2)^n - ...
170 if (n
>= 33) /* underflow, result < 10^-300 */
176 for (a
= one
, i
= 2; i
<= n
; i
++)
178 a
*= (long double) i
; /* a = n! */
179 b
*= temp
; /* b = (x/2)^n */
186 /* use backward recurrence */
188 * J(n,x)/J(n-1,x) = ---- ------ ------ .....
189 * 2n - 2(n+1) - 2(n+2)
192 * (for large x) = ---- ------ ------ .....
194 * -- - ------ - ------ -
197 * Let w = 2n/x and h=2/x, then the above quotient
198 * is equal to the continued fraction:
200 * = -----------------------
202 * w - -----------------
207 * To determine how many terms needed, let
208 * Q(0) = w, Q(1) = w(w+h) - 1,
209 * Q(k) = (w+k*h)*Q(k-1) - Q(k-2),
210 * When Q(k) > 1e4 good for single
211 * When Q(k) > 1e9 good for double
212 * When Q(k) > 1e17 good for quadruple
216 long double q0
, q1
, h
, tmp
;
218 w
= (n
+ n
) / (long double) x
;
219 h
= 2.0L / (long double) x
;
233 for (t
= zero
, i
= 2 * (n
+ k
); i
>= m
; i
-= 2)
234 t
= one
/ (i
/ x
- t
);
237 /* estimate log((2/x)^n*n!) = n*log(2/x)+n*ln(n)
238 * Hence, if n*(log(2n/x)) > ...
239 * single 8.8722839355e+01
240 * double 7.09782712893383973096e+02
241 * long double 1.1356523406294143949491931077970765006170e+04
242 * then recurrent value may overflow and the result is
243 * likely underflow to zero
247 tmp
= tmp
* __ieee754_logl (fabsl (v
* tmp
));
249 if (tmp
< 1.1356523406294143949491931077970765006170e+04L)
251 for (i
= n
- 1, di
= (long double) (i
+ i
); i
> 0; i
--)
262 for (i
= n
- 1, di
= (long double) (i
+ i
); i
> 0; i
--)
269 /* scale b to avoid spurious overflow */
278 /* j0() and j1() suffer enormous loss of precision at and
279 * near zero; however, we know that their zero points never
280 * coincide, so just choose the one further away from zero.
282 z
= __ieee754_j0l (x
);
283 w
= __ieee754_j1l (x
);
284 if (fabsl (z
) >= fabsl (w
))
295 strong_alias (__ieee754_jnl
, __jnl_finite
)
298 __ieee754_ynl (int n
, long double x
)
303 long double a
, b
, temp
;
304 ieee854_long_double_shape_type u
;
308 ix
= se
& 0x7fffffff;
310 /* if Y(n,NaN) is NaN */
311 if (ix
>= 0x7ff00000)
313 if ((u
.parts32
.w0
& 0xfffff) | u
.parts32
.w1
314 | (u
.parts32
.w2
& 0x7fffffff) | u
.parts32
.w3
)
320 return -HUGE_VALL
+ x
;
322 return zero
/ (zero
* x
);
328 sign
= 1 - ((n
& 1) << 1);
331 return (__ieee754_y0l (x
));
333 return (sign
* __ieee754_y1l (x
));
334 if (ix
>= 0x7ff00000)
336 if (ix
>= 0x52D00000)
339 /* ??? See comment above on the possible futility of this. */
342 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
343 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
344 * Let s=sin(x), c=cos(x),
345 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
347 * n sin(xn)*sqt2 cos(xn)*sqt2
348 * ----------------------------------
356 __sincosl (x
, &s
, &c
);
372 b
= invsqrtpi
* temp
/ __ieee754_sqrtl (x
);
376 a
= __ieee754_y0l (x
);
377 b
= __ieee754_y1l (x
);
378 /* quit if b is -inf */
380 se
= u
.parts32
.w0
& 0xfff00000;
381 for (i
= 1; i
< n
&& se
!= 0xfff00000; i
++)
384 b
= ((long double) (i
+ i
) / x
) * b
- a
;
386 se
= u
.parts32
.w0
& 0xfff00000;
395 strong_alias (__ieee754_ynl
, __ynl_finite
)