b84006b9528c65c89a52358275299654d3696ec2
2 for (int c0
= 1; c0
< (2 * M
+ 2 * N
- 2) / 5; c0
+= 1)
3 for (int c1
= max((c0
+ 1) / 2, c0
- (M
+ 2) / 5); c1
<= min(min((2 * N
+ 5 * c0
+ 1) / 10, c0
), (M
+ 2 * N
) / 5 - 1); c1
+= 1)
4 for (int c2
= max(max(max(max(floord(-N
+ 5 * c0
- 3, 10) + 1, c1
- (N
+ 6) / 5 + 1), c0
- c1
- 1), 0), c0
- (M
+ N
+ 4) / 5 + 1); c2
<= min(min(min(c0
- c1
+ (N
- 1) / 5 + 1, (N
+ 5 * c0
+ 3) / 10), c1
), (M
+ N
- 2) / 5); c2
+= 1)
5 for (int c3
= max(max(max(c1
+ c2
- (N
+ 3) / 5, 2 * c2
- (N
+ 2) / 5), 2 * c1
- (2 * N
+ 5) / 5 + 1), c0
); c3
<= min(min(min(min(min(c0
+ 1, c1
+ c2
+ 1), c2
+ (M
+ N
) / 5), (2 * M
+ 2 * N
- 1) / 5 - 1), c1
+ (M
- 2) / 5 + 1), 2 * c2
+ (N
- 2) / 5 + 1); c3
+= 1)
6 for (int c4
= max(max(max(max(c1
, c0
- c2
), c3
- (M
+ 2) / 5), c0
- (M
+ 6) / 5 + 1), (c3
+ 1) / 2); c4
<= min(min(min(min(min(min(min(c0
- c2
+ N
/ 5 + 1, -c2
+ c3
+ (N
- 1) / 5 + 1), (2 * N
+ 5 * c0
+ 3) / 10), (M
+ 2 * N
+ 1) / 5 - 1), (2 * N
+ 5 * c3
+ 2) / 10), c2
+ (N
+ 2) / 5), c1
+ 1), c0
); c4
+= 1)
7 S1(c0
, c1
, c2
, c3
, c4
, c2
);