isl_aff_ceil: compute ceil(e/m) as floor((e + m - 1)/m)
[isl.git] / test_inputs / codegen / stride5.c
blob080bea07e1c8e990c673449ebde9d744557398e6
1 if (2 * floord(n, 2) == n)
2 for (int c0 = (n + 4 * floord(-n - 1, 4) + 4) / 2; c0 <= 100; c0 += 2)
3 S(c0);