isl_aff_ceil: compute ceil(e/m) as floor((e + m - 1)/m)
[isl.git] / test_inputs / codegen / cloog / vivien.c
blob29470ed2452ecf3b208bb84e1e7d04c2baa88750
2 for (int c0 = -27 * n + 2; c0 <= 1; c0 += 1)
3 S1(c0 - 1);
4 for (int c0 = 2; c0 <= min(2 * n, n + 29); c0 += 1) {
5 if (2 * n >= c0 + 1 && c0 >= 3)
6 S4(c0 - c0 / 2 - 1, c0 / 2 + 1);
7 if (2 * n >= c0 + 1 && c0 + 2 >= 2 * n) {
8 for (int c2 = 1; c2 < -n + c0; c2 += 1)
9 S5(-n + c0, n, c2);
10 } else if (2 * n >= c0 + 3 && c0 >= 5) {
11 S4(c0 - c0 / 2 - 2, c0 / 2 + 2);
12 for (int c2 = 1; c2 < (c0 + 1) / 2 - 1; c2 += 1)
13 S5(c0 - c0 / 2 - 1, c0 / 2 + 1, c2);
15 for (int c1 = -c0 + c0 / 2 + 3; c1 <= min(n - c0, -1); c1 += 1) {
16 S6(-c1 + 2, c0 + c1 - 2);
17 S4(-c1, c0 + c1);
18 for (int c2 = 1; c2 <= -c1; c2 += 1)
19 S5(-c1 + 1, c0 + c1 - 1, c2);
21 if (c0 >= n + 2 && 2 * n >= c0 + 3) {
22 S6(-n + c0 + 1, n - 1);
23 for (int c2 = 1; c2 < -n + c0; c2 += 1)
24 S5(-n + c0, n, c2);
26 if (2 * n >= c0 + 1 && c0 >= n + 3)
27 S6(-n + c0, n);
28 if (c0 >= n + 3) {
29 S1(c0 - 1);
30 } else if (c0 == n + 2 && n >= 3) {
31 S6(2, n);
32 S1(n + 1);
33 } else {
34 if (c0 >= 5 && n + 1 >= c0) {
35 S6(2, c0 - 2);
36 S1(c0 - 1);
37 } else if (n + 1 >= c0 && c0 >= 3)
38 S1(c0 - 1);
39 if (c0 >= 3 && n + 1 >= c0)
40 S6(1, c0 - 1);
42 if (c0 == 2) {
43 S1(1);
44 } else if (c0 == 4 && n == 2)
45 S1(3);
46 if (c0 % 2 == 0)
47 S3(c0 / 2);
48 for (int c1 = max(-n + c0, 1); c1 < (c0 + 1) / 2; c1 += 1)
49 S2(c0 - c1, c1);
51 for (int c0 = max(-27 * n + 2, 2 * n + 1); c0 <= n + 29; c0 += 1)
52 S1(c0 - 1);
53 for (int c0 = n + 30; c0 <= 2 * n; c0 += 1) {
54 if (2 * n >= c0 + 1) {
55 S4(c0 - c0 / 2 - 1, c0 / 2 + 1);
56 if (c0 + 2 >= 2 * n) {
57 for (int c2 = 1; c2 < -n + c0; c2 += 1)
58 S5(-n + c0, n, c2);
59 } else {
60 S4(c0 - c0 / 2 - 2, c0 / 2 + 2);
61 for (int c2 = 1; c2 < (c0 + 1) / 2 - 1; c2 += 1)
62 S5(c0 - c0 / 2 - 1, c0 / 2 + 1, c2);
64 for (int c1 = -c0 + c0 / 2 + 3; c1 <= n - c0; c1 += 1) {
65 S6(-c1 + 2, c0 + c1 - 2);
66 S4(-c1, c0 + c1);
67 for (int c2 = 1; c2 <= -c1; c2 += 1)
68 S5(-c1 + 1, c0 + c1 - 1, c2);
70 if (2 * n >= c0 + 3) {
71 S6(-n + c0 + 1, n - 1);
72 for (int c2 = 1; c2 < -n + c0; c2 += 1)
73 S5(-n + c0, n, c2);
75 S6(-n + c0, n);
77 if (c0 % 2 == 0)
78 S3(c0 / 2);
79 for (int c1 = -n + c0; c1 < (c0 + 1) / 2; c1 += 1)
80 S2(c0 - c1, c1);