git-checkout.sh: use the $( ... ) construct for command substitution
commit844cb24f28afd4febcfc1ddc44f9de47130acf4b
authorElia Pinto <gitter.spiros@gmail.com>
Wed, 16 Apr 2014 17:29:47 +0000 (16 10:29 -0700)
committerJunio C Hamano <gitster@pobox.com>
Thu, 17 Apr 2014 18:14:58 +0000 (17 11:14 -0700)
tree890ee2d8873399e1bd521767efdc7929a20ca5f9
parent2c4a050bc60bf7a0633aa1460a8538d18df67848
git-checkout.sh: use the $( ... ) construct for command substitution

The Git CodingGuidelines prefer the $(...) construct for command
substitution instead of using the backquotes `...`.

The backquoted form is the traditional method for command
substitution, and is supported by POSIX.  However, all but the
simplest uses become complicated quickly.  In particular, embedded
command substitutions and/or the use of double quotes require
careful escaping with the backslash character.

The patch was generated by:

for _f in $(find . -name "*.sh")
do
   sed -i 's@`\(.*\)`@$(\1)@g' ${_f}
done

and then carefully proof-read.

Signed-off-by: Elia Pinto <gitter.spiros@gmail.com>
Reviewed-by: Matthieu Moy <Matthieu.Moy@imag.fr>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
contrib/examples/git-checkout.sh