refs: change the internal reference-iteration API

refs: change the internal reference-iteration API

Establish an internal API for iterating over references, which gives
the callback functions direct access to the ref_entry structure
describing the reference.  (Do not change the iteration API that is
exposed outside of the module.)

Define a new internal callback signature

   int each_ref_entry_fn(struct ref_entry *entry, void *cb_data)

Change do_for_each_ref_in_dir() and do_for_each_ref_in_dirs() to
accept each_ref_entry_fn callbacks, and rename them to
do_for_each_entry_in_dir() and do_for_each_entry_in_dirs(),
respectively.  Adapt their callers accordingly.

Add a new function do_for_each_entry() analogous to do_for_each_ref()
but using the new callback style.

Change do_one_ref() into an each_ref_entry_fn that does some
bookkeeping and then calls a wrapped each_ref_fn.

Reimplement do_for_each_ref() in terms of do_for_each_entry(), using
do_one_ref() as an adapter.

Please note that the responsibility for setting current_ref remains in
do_one_ref(), which means that current_ref is *not* set when iterating
over references via the new internal API.  This is not a disadvantage,
because current_ref is not needed by callers of the internal API (they
receive a pointer to the current ref_entry anyway).  But more
importantly, this change prevents peel_ref() from returning invalid
results in the following scenario:

When iterating via the external API, the iteration always includes
both packed and loose references, and in particular never presents a
packed ref if there is a loose ref with the same name.  The internal
API, on the other hand, gives the option to iterate over only the
packed references.  During such an iteration, there is no check
whether the packed ref might be hidden by a loose ref of the same
name.  But until now the packed ref was recorded in current_ref during
the iteration.  So if peel_ref() were called with the reference name
corresponding to current ref, it would return the peeled version of
the packed ref even though there might be a loose ref that peels to a
different value.  This scenario doesn't currently occur in the code,
but fix it to prevent things from breaking in a very confusing way in
the future.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>